Score better in Mathematics with these CBSE Class 8 MCQs, ready for 2026-27. Built chapter by chapter, they help Class 8 students get comfortable with the current exam pattern and sharpen problem-solving.
Benefits of Mathematics MCQ Practice for Class 8
- Strictly based on the 2026 CBSE Mathematics textbook, and guidelines issued by CBSE.
- A wide range of Class 8 Assertion and Reasoning, Case-based, and Fill-in-the-blanks questions for Mathematics.
- Organized sets that test your understanding of every important Mathematics topic, chapter by chapter.
- Answers are explained clearly for every Mathematics question, so the reasoning actually makes sense.
Browse Class 8 Mathematics MCQs by Chapter
The 2026-27 Mathematics sets below are ready to use. Try them for self-assessment, and to see which topics need extra revision before exams.
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Quick Practice - Class 8 Mathematics (Ganita Prakash Part I & II) Select any chapter below to test your mathematical reasoning with interactive questions, instant key checks, and verified step-by-step solutions. Q1.Which of the following numbers can never be a perfect square based on its units digit? Answer: (c) 1057. Perfect square numbers only end with unit digits 0, 1, 4, 5, 6, or 9. Any number ending with 2, 3, 7, or 8 is never a perfect square.
Q2.What is the smallest natural number by which 72 must be multiplied so that the product becomes a perfect cube? Answer: (b) 3. Prime factorisation of $72 = 2 \times 2 \times 2 \times 3 \times 3 = 2^3 \times 3^2$. To complete the triplet of 3s, it must be multiplied by one more 3 ($72 \times 3 = 216 = 6^3$).
Q3.How many non-square natural numbers lie between $12^2$ and $13^2$? Answer: (a) 24. There are $2n$ non-perfect square numbers between consecutive squares $n^2$ and $(n+1)^2$. For $n = 12$, count $= 2 \times 12 = 24$.
Q4.What is the value of $\sqrt{1 + 3 + 5 + 7 + 9 + 11 + 13 + 15}$? Answer: (d) 8. The sum of the first $n$ consecutive odd natural numbers is $n^2$. Here $n = 8$ terms, so $\text{Sum} = 8^2 = 64$, and $\sqrt{64} = 8$.
Q5.The unit digit of the cube of any number ending with the digit 7 is always: Answer: (b) 3. Since $7^3 = 343$, the unit digit of any number ending in 7 cubed is always 3.
Q1.What is the value of $(5^{-1} \times 2^{-1}) \div 6^{-1}$? Answer: (a) 3/5. $(5^{-1} \times 2^{-1}) = \frac{1}{10}$. Then $\frac{1}{10} \div \frac{1}{6} = \frac{1}{10} \times 6 = \frac{6}{10} = \frac{3}{5}$.
Q2.The scientific standard form of the microscopic number 0.0000035 is written as: Answer: (c) $3.5 \times 10^{-6}$. Shifting the decimal point 6 places to the right gives $3.5 \times 10^{-6}$.
Q3.If $3^{2x-1} = 27$, then the value of $x$ is: Answer: (b) 2. Express with identical base: $3^{2x-1} = 3^3 \implies 2x - 1 = 3 \implies 2x = 4 \implies x = 2$.
Q4.What is the evaluated result of $(3^0 + 4^{-1}) \times 2^2$? Answer: (a) 5. $(1 + \frac{1}{4}) \times 4 = \frac{5}{4} \times 4 = 5$.
Q5.Which law of exponents correctly represents $(a^m)^n$? Answer: (d) $a^{m \cdot n}$. Raising a power to another power multiplies the exponents: $(a^m)^n = a^{mn}$.
Q1.Which arithmetic operation is NOT closed for the set of rational numbers? Answer: (d) Division (due to division by zero). Division of any rational number by 0 is undefined, so the set of rational numbers is not closed under division.
Q2.What is the additive inverse of $-7/19$? Answer: (b) 7/19. The additive inverse of $a$ is $-a$ such that $a + (-a) = 0$. Hence $-(-7/19) = 7/19$.
Q3.What is the multiplicative inverse (reciprocal) of $-13/17$? Answer: (a) -17/13. The reciprocal of $p/q$ is $q/p$ keeping the same sign: $\left(-\frac{13}{17}\right) \times \left(-\frac{17}{13}\right) = 1$.
Q4.Which rational number is its own additive inverse? Answer: (c) 0. Since $0 + 0 = 0$ and $-0 = 0$, zero is its own additive inverse.
Q5.How many rational numbers exist between any two distinct rational numbers $a$ and $b$? Answer: (d) Infinitely many. The density property of rational numbers guarantees infinite numbers between any two distinct rationals.
Q1.What is the sum of all interior angles in any simple convex quadrilateral? Answer: (b) 360°. Using angle sum formula $(n-2) \times 180^\circ$: for $n = 4$, $(4-2) \times 180^\circ = 360^\circ$.
Q2.In a parallelogram $ABCD$, if $\angle A = 70^\circ$, then the measure of its adjacent angle $\angle B$ is: Answer: (c) 110°. Adjacent angles in any parallelogram are supplementary: $\angle A + \angle B = 180^\circ \implies \angle B = 180^\circ - 70^\circ = 110^\circ$.
Q3.Which quadrilateral has all four sides equal in length and diagonals that bisect each other at right angles (90°)? Answer: (a) Rhombus (and Square). A rhombus is defined by four equal sides and perpendicular bisecting diagonals.
Q4.What is the measure of each exterior angle of a regular octagon (8-sided polygon)? Answer: (b) 45°. $\text{Exterior angle of a regular polygon} = 360^\circ / n = 360^\circ / 8 = 45^\circ$.
Q5.A parallelogram having equal diagonals and all four interior right angles is a: Answer: (d) Rectangle (or Square). Equal diagonals in a parallelogram guarantee that all four corner angles are $90^\circ$ (a rectangle).
Q1.If the 3-digit number $24x$ is divisible by 9, what is the value of the single digit $x$? Answer: (b) 3. Divisibility rule for 9 requires the sum of digits to be a multiple of 9: $2 + 4 + x = 6 + x \implies 6 + 3 = 9$, so $x = 3$.
Q2.What is the generalized expanded algebraic form of a 2-digit number with tens digit $a$ and units digit $b$? Answer: (c) $10a + b$. A place-value representation of any 2-digit number $ab$ is $10 \times a + 1 \times b = 10a + b$.
Q3.In the cryptarithm addition: $3A + 25 = B2$, what are the values of digits $A$ and $B$? Answer: (a) $A = 7, B = 6$. $A + 5$ must end in 2, so $A + 5 = 12 \implies A = 7$. Carrying over 1: $1 + 3 + 2 = 6 = B$. Thus $37 + 25 = 62$.
Q4.The difference between a 2-digit number $(10a + b)$ and its reversed number $(10b + a)$ is always divisible by: Answer: (d) 9. $(10a + b) - (10b + a) = 9a - 9b = 9(a - b)$, which is always a multiple of 9.
Q5.If a number is divisible by both 2 and 3, it is guaranteed to be divisible by: Answer: (b) 6. Since 2 and 3 are co-prime, any integer divisible by both is divisible by their product $2 \times 3 = 6$.
Q1.Applying the distributive law, the product of $(2x + 3)$ and $(3x - 5)$ expands to: Answer: (a) $6x^2 - x - 15$. $2x(3x - 5) + 3(3x - 5) = 6x^2 - 10x + 9x - 15 = 6x^2 - x - 15$.
Q2.What is the value of the algebraic expression $3x(4x - 5) + 3$ when $x = 2$? Answer: (c) 21. Substitute $x = 2$: $3(2)[4(2) - 5] + 3 = 6[8 - 5] + 3 = 6(3) + 3 = 18 + 3 = 21$.
Q3.Factorizing the expression $12a^2b + 15ab^2$ completely yields: Answer: (b) $3ab(4a + 5b)$. Taking the highest common monomial factor $3ab$ out gives $3ab(4a + 5b)$.
Q4.The algebraic identity $(a + b)^2$ is identically equal to: Answer: (a) $a^2 + 2ab + b^2$. $(a + b)(a + b) = a(a + b) + b(a + b) = a^2 + ab + ba + b^2 = a^2 + 2ab + b^2$.
Q5.What is the product of $(a - b)(a + b)$? Answer: (d) $a^2 - b^2$. Expanding: $a^2 + ab - ab - b^2 = a^2 - b^2$ (difference of two squares).
Q1.If 15 metres of uniform cloth costs ₹450, what is the cost of 8 metres of the same cloth? Answer: (c) ₹240. Direct proportion: $\frac{450}{15} = ₹30\text{ per metre}$. Cost for $8\text{ m} = 8 \times 30 = ₹240$.
Q2.If 12 workers can construct a boundary wall in 8 days, how many days will 16 workers take working at the same pace? Answer: (a) 6 days. Inverse proportion: $x_1 y_1 = x_2 y_2 \implies 12 \times 8 = 16 \times d \implies 96 = 16d \implies d = 6\text{ days}$.
Q3.On a geographic map with scale $1\text{ cm} : 50\text{ km}$, two cities are $3.5\text{ cm}$ apart. The actual distance between them is: Answer: (b) 175 km. $\text{Actual distance} = 3.5 \times 50 = 175\text{ km}$.
Q4.When two quantities $x$ and $y$ are in inverse proportion, which mathematical relation stays constant? Answer: (a) $x \times y = k$ (Constant). In inverse proportion, the product of corresponding values of the two variables remains constant.
Q5.A car travels 84 km on 6 litres of petrol. How far can it travel on 10 litres of petrol? Answer: (c) 140 km. Distance per litre $= 84 / 6 = 14\text{ km/L}$. For 10 litres: $10 \times 14 = 140\text{ km}$.
Q1.What is the fraction equivalent of the recurring decimal $0.\bar{6} = 0.666...$ in lowest terms? Answer: (b) 2/3. Let $x = 0.666... \implies 10x = 6.666... \implies 9x = 6 \implies x = 6/9 = 2/3$.
Q2.Which rational fraction produces a non-terminating repeating decimal expansion? Answer: (c) 5/6. A fraction terminates if and only if its denominator's prime factors are solely 2s and 5s. In $5/6$, the denominator contains 3 ($6 = 2 \times 3$), so it repeats ($0.8333...$).
Q3.Expressing the fraction $7/40$ as a decimal yields: Answer: (a) 0.175. $\frac{7}{40} = \frac{7 \times 25}{40 \times 25} = \frac{175}{1000} = 0.175$.
Q4.What is the fraction form of the percentage $37.5\%$? Answer: (d) 3/8. $37.5\% = \frac{375}{1000} = \frac{3}{8}$.
Q5.Which of the following is equivalent to the ratio $4 : 5$? Answer: (b) 80% (or 0.8). $4/5 = 0.8 = 80\%$.
Q1.In a right-angled triangle with legs of length 6 cm and 8 cm, what is the length of the hypotenuse? Answer: (a) 10 cm. By Baudhayana-Pythagoras theorem: $c = \sqrt{a^2 + b^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10\text{ cm}$.
Q2.Which of the following sets of numbers forms a valid Pythagorean triplet? Answer: (c) (5, 12, 13). Checking: $5^2 + 12^2 = 25 + 144 = 169 = 13^2$.
Q3.A 13 m long ladder reaches a window 12 m high on a vertical wall. The distance of the ladder's foot from the wall is: Answer: (b) 5 m. $\text{Base} = \sqrt{\text{Hypotenuse}^2 - \text{Height}^2} = \sqrt{13^2 - 12^2} = \sqrt{169 - 144} = \sqrt{25} = 5\text{ m}$.
Q4.The ancient Indian text 'Baudhayana Sulba Sutra' stated the geometric property of diagonal squares around: Answer: (a) 800 BCE. Sage Baudhayana formulated the theorem in the Sulba Sutras centuries prior to Pythagoras.
Q5.What is the length of the diagonal of a square with side length 7 cm? Answer: (d) $7\sqrt{2}\text{ cm}$. Diagonal $d = \sqrt{s^2 + s^2} = s\sqrt{2} = 7\sqrt{2}\text{ cm}$.
Q1.An article bought for ₹800 is sold at a profit of 15%. What is its selling price (SP)? Answer: (b) ₹920. $\text{Profit} = 15\% \text{ of } 800 = \frac{15}{100} \times 800 = ₹120$. $\text{SP} = 800 + 120 = ₹920$.
Q2.What is the compound interest on a principal of ₹10,000 at 10% per annum compounded annually for 2 years? Answer: (a) ₹2,100. $A = P(1 + r/100)^t = 10000(1.10)^2 = 10000 \times 1.21 = ₹12,100$. $\text{CI} = A - P = 12100 - 10000 = ₹2,100$.
Q3.A shop offers a discount of 20% on a jacket marked at ₹2,500. The customer pays: Answer: (c) ₹2,000. $\text{Discount} = 20\% \text{ of } 2500 = ₹500$. $\text{Net Price} = 2500 - 500 = ₹2,000$.
Q4.If Goods and Services Tax (GST) is 18%, what is the billed amount on an electronic device priced at ₹5,000? Answer: (a) ₹5,900. $\text{GST} = \frac{18}{100} \times 5000 = ₹900$. $\text{Total Bill} = 5000 + 900 = ₹5,900$.
Q5.A population of 50,000 grows at 4% per annum. Its population after 1 year will be: Answer: (b) 52,000. $\text{Increase} = \frac{4}{100} \times 50000 = 2000$. New population $= 50000 + 2000 = 52,000$.
Q1.What is the order of rotational symmetry of a regular pentagon? Answer: (c) 5. A regular polygon with $n$ sides has rotational symmetry of order $n$. For a regular pentagon, order $= 5$.
Q2.According to Euler's formula for convex polyhedrons ($F + V - E = 2$), a polyhedron with 6 faces and 8 vertices has: Answer: (b) 12 edges. $6 + 8 - E = 2 \implies 14 - E = 2 \implies E = 12\text{ edges}$ (e.g., a standard cube).
Q3.How many lines of reflection symmetry does an equilateral triangle possess? Answer: (a) 3. An equilateral triangle has three axes of symmetry, each passing through a vertex and the midpoint of the opposite side.
Q4.A 3D solid having 2 identical parallel circular bases connected by a curved surface is a: Answer: (d) Cylinder. A right circular cylinder consists of two congruent circular bases joined by a smooth curved boundary.
Q5.What is the minimum angle of rotation for a regular hexagon to look identical to its original position? Answer: (b) 60°. $\text{Angle of rotation} = 360^\circ / 6 = 60^\circ$.
Q1.The coordinates of the origin point where the horizontal $x$-axis and vertical $y$-axis intersect are: Answer: (a) (0, 0). The origin $O$ is the intersection reference point with coordinates $(0, 0)$.
Q2.In which quadrant of the Cartesian plane does the coordinate point $P(-3, 4)$ lie? Answer: (b) Quadrant II. Points with negative $x$ and positive $y$ coordinates $(-, +)$ lie in Quadrant II.
Q3.Any point lying on the $x$-axis has its $y$-coordinate (ordinate) equal to: Answer: (c) 0. Every point on the $x$-axis has coordinates of the form $(x, 0)$.
Q4.A line graph that displays data that changes continuously over time intervals is a: Answer: (a) Time-series Line Graph. Line graphs connect continuous sequential data points to show trends over time.
Q5.What is the distance of the point $A(5, -12)$ from the origin $(0, 0)$? Answer: (d) 13 units. $\text{Distance} = \sqrt{x^2 + y^2} = \sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13\text{ units}$.
Q1.Solving the linear equation $5x - 7 = 2x + 8$ gives $x =$ Answer: (a) 5. Group like terms: $5x - 2x = 8 + 7 \implies 3x = 15 \implies x = 5$.
Q2.The sum of three consecutive multiples of 5 is 75. The largest multiple is: Answer: (b) 30. Let the multiples be $x, x+5, x+10$. Their sum: $3x + 15 = 75 \implies 3x = 60 \implies x = 20$. The largest multiple is $20 + 10 = 30$.
Q3.Factorizing the quadratic expression $x^2 + 7x + 12$ gives: Answer: (c) $(x + 3)(x + 4)$. Split middle term: $x^2 + 3x + 4x + 12 = x(x + 3) + 4(x + 3) = (x + 3)(x + 4)$.
Q4.Factorization of $49x^2 - 36$ using difference of squares identity results in: Answer: (a) $(7x - 6)(7x + 6)$. $(7x)^2 - (6)^2 = (7x - 6)(7x + 6)$.
Q5.What is the solution to the equation $\frac{x}{3} + \frac{1}{2} = \frac{x}{2} - \frac{1}{3}$? Answer: (d) $x = 5$. Multiply entire equation by 6: $2x + 3 = 3x - 2 \implies 3 + 2 = 3x - 2x \implies x = 5$.
Q1.What is the area of a trapezium with parallel sides of length 14 cm and 10 cm and perpendicular height 6 cm? Answer: (a) 72 cm². $\text{Area} = \frac{1}{2}(a + b)h = \frac{1}{2}(14 + 10) \times 6 = \frac{1}{2}(24) \times 6 = 12 \times 6 = 72\text{ cm}^2$.
Q2.What is the area of a rhombus whose diagonals measure 16 cm and 12 cm? Answer: (b) 96 cm². $\text{Area of Rhombus} = \frac{1}{2} d_1 d_2 = \frac{1}{2} \times 16 \times 12 = 8 \times 12 = 96\text{ cm}^2$.
Q3.What is the total surface area of a closed cylinder with base radius $r = 7\text{ cm}$ and height $h = 10\text{ cm}$? ($\pi = 22/7$) Answer: (c) 748 cm². $\text{TSA} = 2\pi r(r + h) = 2 \times \frac{22}{7} \times 7 \times (7 + 10) = 44 \times 17 = 748\text{ cm}^2$.
Q4.What is the volume of a rectangular cuboid measuring $12\text{ cm} \times 8\text{ cm} \times 5\text{ cm}$? Answer: (a) 480 cm³. $\text{Volume} = l \times b \times h = 12 \times 8 \times 5 = 480\text{ cm}^3$.
Q5.If each edge of a cube is doubled, its volume increases by a factor of: Answer: (d) 8 times. Original volume $V = s^3$. New volume $V' = (2s)^3 = 8s^3 = 8V$.
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FAQs
For the 2026-27 session, MCQs and objective-type questions carry around 20% weightage. CBSE has introduced 30% competency based questions as MCQs and they are important part of the Class 8 Mathematics paper.
You can access the latest chapter-wise MCQs for Class 8 Mathematics for free from StudiesToday.com. All questions are based on the latest syllabus and current academic year.
Yes, our Mathematics practice bank includes the new pattern of Assertion Reasoning and Case Study based MCQs. They have been designed to test the analytical skills of Class 8 students.
Solving Class 8 Mathematics MCQs regularly improves speed and accuracy as these are objective questions can get you 100% marks if your understanding of the topic is clear.
Yes, all Class 8 Mathematics MCQs and answers are accessible on any device at your convenience.
No, all Mathematics Multiple Choice Questions (MCQs), practice papers, and solutions for Class 8 are available for free for students to get more marks school exams.