CBSE Class 8 Mathematics Power Play MCQs Set 11

Practice MCQs for Class 8 Mathematics Ganita Prakash Part 1 Chapter 02 Power Play

Explore reliable objective questions for Ganita Prakash Part 1 Chapter 02 Power Play tailored for Class 8 learners. Utilizing these Mathematics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Access Ganita Prakash Part 1 Chapter 02 Power Play Questions and Solutions

View or download the dedicated Ganita Prakash Part 1 Chapter 02 Power Play MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: In the power 96, which of the following statements is correct?
(a) 9 is the exponent and 6 is the base
(b) 9 is the base and 6 is the exponent
(c) Both 9 and 6 are exponents
(d) 96 is another way of writing 9 × 6
Show Answer & Explanation

Answer: (b) 9 is the base and 6 is the exponent

Explanation:
1. In a power, the big number written on the line is the base and the small raised number is the exponent.
2. So in 96 the base is 9 and the exponent is 6.
3. 96 means 9 multiplied by itself 6 times, which is not the same as 9 × 6.

Teacher's Note:
1. Base sits on the line; exponent sits up high.
2. The exponent counts how many times the base is used as a factor.

Question 2: The value of 34 is
(a) 12
(b) 27
(c) 64
(d) 81
Show Answer & Explanation

Answer: (d) 81

Explanation:
1. 34 = 3 × 3 × 3 × 3.
2. 3 × 3 = 9, 9 × 3 = 27, 27 × 3 = 81.
3. 12 is 3 × 4 and 27 is 33, so those options are wrong.

Teacher's Note:
1. Never multiply the base by the exponent.
2. Multiply step by step and count the factors.

Question 3: For any non-zero number n, the value of n0 is
(a) 0
(b) 1
(c) n
(d) not defined
Show Answer & Explanation

Answer: (b) 1

Explanation:
1. By the division law, na ÷ na = na − a = n0.
2. But any non-zero number divided by itself is 1.
3. So n0 = 1.

Teacher's Note:
1. The zero power of any non-zero number is 1, not 0.
2. This comes straight from dividing a power by itself.

Question 4: Written as a fraction, 2−3 is equal to
(a) \( -\frac{1}{8} \)
(b) \( \frac{1}{6} \)
(c) \( \frac{1}{8} \)
(d) −8
Show Answer & Explanation

Answer: (c) \( \frac{1}{8} \)

Explanation:
1. A negative exponent means the reciprocal: 2−3 = \( \frac{1}{2^{3}} \).
2. 23 = 8, so 2−3 = \( \frac{1}{8} \).
3. The minus sign in the exponent does not make the number negative.

Teacher's Note:
1. Negative exponent means 'one over', not 'negative'.
2. Students often pick −8 or \( \frac{1}{6} \); check with the rule.

Question 5: For a non-zero base n and counting numbers a and b, the product \( n^{a} \times n^{b} \) is equal to
(a) \( n^{a \times b} \)
(b) \( n^{a-b} \)
(c) \( n^{a+b} \)
(d) \( n^{a} + n^{b} \)
Show Answer & Explanation

Answer: (c) \( n^{a+b} \)

Explanation:
1. na has a factors of n and nb has b factors of n.
2. Multiplying puts all the factors together: a + b factors.
3. So \( n^{a} \times n^{b} = n^{a+b} \), which is option (c).

Teacher's Note:
1. Same base, multiply: add the exponents.
2. Multiplying exponents is for a power of a power.

Question 6: The value of 24 × 23 is
(a) 128
(b) 64
(c) 256
(d) 4096
Show Answer & Explanation

Answer: (a) 128

Explanation:
1. The bases are the same, so add the exponents: 24 × 23 = 24+3 = 27.
2. 27 = 128.
3. Multiplying the exponents (212 = 4096) is the common mistake.

Teacher's Note:
1. Check: 16 × 8 = 128.
2. Add exponents when multiplying powers of the same base.

Question 7: Read the two statements given below.
Statement I: (−1)7 = −1.
Statement II: (−2)4 = −16.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (a) Only Statement I is true

Explanation:
1. (−1)7 has 7 negative factors; an odd number of negative factors gives a negative product, so (−1)7 = −1. Statement I is true.
2. (−2)4 has 4 negative factors; they pair up, so (−2)4 = +16. Statement II is false.
3. So only Statement I is true.

Teacher's Note:
1. Odd exponent on a negative base: negative answer. Even exponent: positive answer.
2. Watch the brackets: (−2)4 is not the same as −24.

Question 8: Read the two statements given below.
Statement I: 4 + 4 + 4 = 43.
Statement II: 4 × 4 × 4 = 43.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (b) Only Statement II is true

Explanation:
1. 4 + 4 + 4 = 12, which is 3 × 4, not 43 = 64. Statement I is false.
2. 4 × 4 × 4 = 64 = 43. Statement II is true.
3. So only Statement II is true.

Teacher's Note:
1. Repeated addition gives a product; repeated multiplication gives a power.
2. 43 = 64, while 3 × 4 = 12.

Question 9:
Assertion (A): A sheet of paper of thickness 0.001 cm, folded 46 times, would become more than 7,00,000 km thick.
Reason (R): Each fold adds 0.001 cm to the thickness of the paper.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. After 46 folds the thickness is 0.001 × 246 cm ≈ 7.04 × 1010 cm ≈ 7,03,687 km, which is more than 7,00,000 km. A is true.
2. Each fold doubles the thickness; it does not add a fixed 0.001 cm. R is false.
3. So A is true but R is false.

Teacher's Note:
1. Folding is multiplicative growth, not additive growth.
2. Adding 0.001 cm 46 times would give only 0.047 cm.

Question 10:
Assertion (A): 00 is equal to 1.
Reason (R): In the rule \( n^{a} \div n^{b} = n^{a-b} \), the base n must not be 0.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. 00 would come from 0a ÷ 0a = 0 ÷ 0, which is not defined. So A is false.
2. R is true: the division rule needs n ≠ 0.
3. So A is false but R is true.

Teacher's Note:
1. n0 = 1 holds only for a non-zero base.
2. Division by 0 is never allowed.

Question 11: Match each power in Column I with its value in Column II.
Column IColumn II
(i) 25(p) 125
(ii) 53(q) 16
(iii) 42(r) 81
(iv) 34(s) 32

(a) (i)-(q), (ii)-(p), (iii)-(s), (iv)-(r)
(b) (i)-(s), (ii)-(p), (iii)-(q), (iv)-(r)
(c) (i)-(s), (ii)-(r), (iii)-(q), (iv)-(p)
(d) (i)-(q), (ii)-(r), (iii)-(s), (iv)-(p)
Show Answer & Explanation

Answer: (b) (i)-(s), (ii)-(p), (iii)-(q), (iv)-(r)

Explanation:
1. 25 = 32: (i)-(s).
2. 53 = 125: (ii)-(p).
3. 42 = 16: (iii)-(q).
4. 34 = 81: (iv)-(r). So the answer is (b).

Teacher's Note:
1. Work out each power first, then match.
2. Only option (b) has (i)-(s) and (ii)-(p) together.

Question 12: The bar graph shows the thickness of a sheet of paper of initial thickness 0.001 cm after it has been folded in half a given number of times. After which fold does the thickness first become more than 1 cm?
0.0 0.5 1.0 1.5 2.0 0.064 6 0.128 7 0.256 8 0.512 9 1.024 10 2.048 11 1 cm Number of folds Thickness (cm) (a) 7th fold
(b) 8th fold
(c) 9th fold
(d) 10th fold
Show Answer & Explanation

Answer: (d) 10th fold

Explanation:
1. Thickness after n folds = 0.001 × 2n cm.
2. After the 9th fold it is 0.001 × 512 = 0.512 cm, still below 1 cm.
3. After the 10th fold it is 0.001 × 1024 = 1.024 cm, the first bar above the 1 cm line. So the answer is the 10th fold.

Teacher's Note:
1. Look for the first bar that crosses the red dashed line.
2. 210 = 1024 is worth remembering.

Question 13: Which one of the following is NOT equal to 46?
(a) (42)3
(b) (43)2
(c) 42 × 43
(d) 44 × 42
Show Answer & Explanation

Answer: (c) 42 × 43

Explanation:
1. (42)3 = 42×3 = 46 and (43)2 = 43×2 = 46.
2. 44 × 42 = 44+2 = 46.
3. But 42 × 43 = 42+3 = 45, so (c) is not equal to 46.

Teacher's Note:
1. Power of a power: multiply exponents. Product: add exponents.
2. Check each option before choosing.

Question 14: The standard form of the number 5,07,00,000 is
(a) 5.07 × 107
(b) 50.7 × 106
(c) 5.07 × 108
(d) 0.507 × 108
Show Answer & Explanation

Answer: (a) 5.07 × 107

Explanation:
1. 5,07,00,000 = 50700000 has 8 digits, so the decimal point moves 7 places to the left.
2. 5,07,00,000 = 5.07 × 107.
3. 50.7 × 106 and 0.507 × 108 have the same value, but their coefficients are not between 1 and 10, so they are not in standard form.

Teacher's Note:
1. In standard form the coefficient must satisfy 1 ≤ x < 10.
2. Count the places the decimal point moves.

Question 15: In the Indian system of number names, one kharab is written as a power of 10 as
(a) 107
(b) 109
(c) 1013
(d) 1011
Show Answer & Explanation

Answer: (d) 1011

Explanation:
1. 1 crore = 107, and a hundred crores make 1 arab = 109.
2. A hundred arabs make 1 kharab = 102 × 109 = 1011.

Teacher's Note:
1. Lakh, crore, arab, kharab, neel: each is 100 times the previous one.
2. So the exponents go 5, 7, 9, 11, 13.

Question 16: The value of 5−3 × 57 ÷ 52 is
(a) 25
(b) 125
(c) 5
(d) 625
Show Answer & Explanation

Answer: (a) 25

Explanation:
1. Same base, so add and subtract the exponents: −3 + 7 − 2 = 2.
2. 5−3 × 57 ÷ 52 = 52 = 25.

Teacher's Note:
1. The laws work for negative exponents too.
2. Handle the signs of the exponents carefully.

Question 17: A padlock has 4 slots, and each slot can be set to any one of the 26 letters A to Z. The number of different passcodes possible on this lock is
(a) 426
(b) 264
(c) 26 × 4
(d) 2626
Show Answer & Explanation

Answer: (b) 264

Explanation:
1. Each of the 4 slots can be filled in 26 ways, independently of the others.
2. Total = 26 × 26 × 26 × 26 = 264.

Teacher's Note:
1. The number of choices per slot is the base; the number of slots is the exponent.
2. 264 = 4,56,976 codes.

Question 18: Read the two statements given below.
Statement I: 210 = (25)2.
Statement II: 210 = (22)5.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (c) Both statements are true

Explanation:
1. Using (na)b = nab: (25)2 = 210, so Statement I is true.
2. (22)5 = 210 as well, since 2 × 5 = 5 × 2 = 10. Statement II is true.
3. So both statements are true.

Teacher's Note:
1. The order of the two exponents does not matter in a power of a power.
2. Check: 322 = 1024 and 45 = 1024.

Question 19: Read the two statements given below.
Statement I: The standard form of 5900 is 59 × 102.
Statement II: The standard form of 5900 is 5.9 × 103.
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (b) Only Statement II is true

Explanation:
1. In standard form the coefficient x must satisfy 1 ≤ x < 10.
2. 59 is not less than 10, so 59 × 102 is not standard form. Statement I is false.
3. 5900 = 5.9 × 103 is correct standard form. So only Statement II is true.

Teacher's Note:
1. A correct value is not enough; the form must also be right.
2. Exactly one non-zero digit comes before the decimal point.

Question 20:
Assertion (A): 24 × 34 = 64.
Reason (R): When two powers have the same exponent, \( m^{a} \times n^{a} = (mn)^{a} \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. 24 × 34 = (2 × 3) × (2 × 3) × (2 × 3) × (2 × 3) = 64 = 1296. A is true.
2. R is the general rule for powers with the same exponent, and it is true.
3. A is just R with m = 2, n = 3, a = 4, so R correctly explains A.

Teacher's Note:
1. Same exponent: multiply the bases and keep the exponent.
2. Check: 16 × 81 = 1296 = 64.

Question 21:
Assertion (A): (−2)6 is a positive number.
Reason (R): (−2)6 = 64, and 64 is a perfect cube.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. The exponent 6 is even, so the six negative signs pair up and (−2)6 = +64. A is true.
2. (−2)6 = 64 and 64 = 43, so R is true.
3. But being a perfect cube has nothing to do with the sign; A holds because the exponent is even. So R is not the correct explanation of A.

Teacher's Note:
1. Ask whether the reason actually gives the cause of the assertion.
2. The sign of a power of a negative base depends on whether the exponent is odd or even.

Question 22:
Assertion (A): 10−4 is greater than 10−3.
Reason (R): 10−n = \( \frac{1}{10^{n}} \) for every counting number n.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. 10−4 = \( \frac{1}{10000} \) = 0.0001 and 10−3 = \( \frac{1}{1000} \) = 0.001.
2. 0.0001 < 0.001, so A is false.
3. R is the correct meaning of a negative exponent, so R is true. So A is false but R is true.

Teacher's Note:
1. With negative exponents, the more negative the exponent, the smaller the number.
2. Write both as decimals to compare.

Question 23: Match each expression in Column I with its value in Column II.
Column IColumn II
(i) 3−2(p) 1
(ii) 10−3(q) \( \frac{1}{4} \)
(iii) (−2)−2(r) \( \frac{1}{9} \)
(iv) 70(s) 0.001

(a) (i)-(q), (ii)-(s), (iii)-(r), (iv)-(p)
(b) (i)-(r), (ii)-(q), (iii)-(s), (iv)-(p)
(c) (i)-(p), (ii)-(s), (iii)-(q), (iv)-(r)
(d) (i)-(r), (ii)-(s), (iii)-(q), (iv)-(p)
Show Answer & Explanation

Answer: (d) (i)-(r), (ii)-(s), (iii)-(q), (iv)-(p)

Explanation:
1. 3−2 = \( \frac{1}{9} \): (i)-(r).
2. 10−3 = \( \frac{1}{1000} \) = 0.001: (ii)-(s).
3. (−2)−2 = \( \frac{1}{(-2)^{2}} \) = \( \frac{1}{4} \): (iii)-(q).
4. 70 = 1: (iv)-(p). So the answer is (d).

Teacher's Note:
1. (−2)−2 is positive because the exponent is even.
2. Any non-zero number to the power 0 is 1.

Question 24: The power line of 3 is shown below. Each step to the right divides the previous number by 3. Which number should be written in place of the question mark at the position marked P?
3 3 ÷3 3 2 ÷3 3 1 ÷3 3 0 ÷3 3 −1 ÷3 P 27 9 3 1 1 3 ? (a) \( \frac{1}{9} \)
(b) \( \frac{1}{6} \)
(c) −9
(d) \( \frac{1}{27} \)
Show Answer & Explanation

Answer: (a) \( \frac{1}{9} \)

Explanation:
1. The entry before P is 3−1 = \( \frac{1}{3} \).
2. One more step to the right divides by 3: \( \frac{1}{3} \) ÷ 3 = \( \frac{1}{9} \).
3. So P is 3−2 = \( \frac{1}{9} \).

Teacher's Note:
1. Moving right lowers the exponent by 1.
2. A negative exponent gives a small positive fraction, never a negative number.

Question 25: The units digit of the value of 320 ÷ 97 is
(a) 1
(b) 3
(c) 7
(d) 9
Show Answer & Explanation

Answer: (d) 9

Explanation:
1. 9 = 32, so 97 = (32)7 = 314.
2. 320 ÷ 314 = 36 = 729.
3. The units digit is 9.

Teacher's Note:
1. Bring both powers to the same base first.
2. 36 = 729 is small enough to work out fully.

Question 26: Which one of the following numbers is the greatest?
(a) 230
(b) 320
(c) 415
(d) 512
Show Answer & Explanation

Answer: (b) 320

Explanation:
1. 230 = 415 = 1,07,37,41,824.
2. 512 = 24,41,40,625.
3. 320 = 3,48,67,84,401, the largest. So 320 is the greatest.

Teacher's Note:
1. A bigger base does not always give a bigger power.
2. Writing 415 as (22)15 = 230 saves work.

Question 27: Read the two statements given below.
Statement I: (7−3)−2 = 76.
Statement II: \( p^{4}q^{10}(pq)^{6} = p^{10}q^{16} \).
(a) Only Statement I is true
(b) Only Statement II is true
(c) Both statements are true
(d) Neither statement is true
Show Answer & Explanation

Answer: (c) Both statements are true

Explanation:
1. (7−3)−2 = 7(−3)×(−2) = 76. Statement I is true.
2. \( p^{4}q^{10}(pq)^{6} = p^{4}q^{10} \times p^{6}q^{6} = p^{10}q^{16} \). Statement II is true.
3. So both statements are true.

Teacher's Note:
1. (−3) × (−2) = +6.
2. Open (pq)6 first, then add exponents of the same letter.

Question 28:
Assertion (A): A counting number that is both a perfect square and a perfect cube must be the sixth power of some counting number.
Reason (R): n6 can be written both as (n3)2 and as (n2)3.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. A is true: in the prime factorisation of a square every exponent is a multiple of 2, and in a cube every exponent is a multiple of 3. If both hold, every exponent is a multiple of 6, so the number is a sixth power (for example 64 = 82 = 43 = 26).
2. R is true: (n3)2 = (n2)3 = n6.
3. But R only shows that every sixth power is a square and a cube, which is the reverse of A. So both are true, but R is not the correct explanation of A.

Teacher's Note:
1. A statement and its converse are different claims.
2. The real reason for A is the prime-factor exponents being multiples of both 2 and 3.

Question 29: Match each expression in Column I with its simplest exponential form in Column II.
Column IColumn II
(i) 23 × 2−5(p) 20
(ii) (22)3 ÷ 26(q) 28
(iii) 2−4 × 43(r) 2−2
(iv) 82 ÷ 2−2(s) 22

(a) (i)-(p), (ii)-(r), (iii)-(s), (iv)-(q)
(b) (i)-(r), (ii)-(p), (iii)-(q), (iv)-(s)
(c) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
(d) (i)-(s), (ii)-(q), (iii)-(p), (iv)-(r)
Show Answer & Explanation

Answer: (c) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)

Explanation:
1. 23 × 2−5 = 2−2: (i)-(r).
2. (22)3 ÷ 26 = 26−6 = 20: (ii)-(p).
3. 2−4 × 43 = 2−4 × 26 = 22: (iii)-(s).
4. 82 ÷ 2−2 = 26 ÷ 2−2 = 26+2 = 28: (iv)-(q). So the answer is (c).

Teacher's Note:
1. Write 4 as 22 and 8 as 23 first.
2. Dividing by a negative power adds to the exponent.

Question 30: The scale below places four estimated counts on a line of powers of 10. Using the estimates shown, about how many trees are there on Earth for each human?
10 0 10 5 10 10 10 15 10 20 10 25 Humans 8 × 10 9 Trees 3 × 10 12 Ants 2 × 10 16 Stars 2 × 10 23 (a) 3.75 × 102
(b) 3.75 × 103
(c) 2.67 × 103
(d) 3.75 × 1021
Show Answer & Explanation

Answer: (a) 3.75 × 102

Explanation:
1. Trees per human = \( \frac{3 \times 10^{12}}{8 \times 10^{9}} \).
2. Divide the coefficients and subtract the exponents: 0.375 × 103.
3. In standard form this is 3.75 × 102, about 375 trees for each person.

Teacher's Note:
1. Divide coefficients, subtract exponents.
2. Re-adjust the coefficient so that it lies between 1 and 10.

Practice MCQs for Class 8 Mathematics Ganita Prakash Part 1 Chapter 02 Power Play

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