CBSE Class 8 Mathematics Tales by Dots and Lines MCQs Set 11

Multiple Choice Questions (MCQs) for Class 8 Mathematics: Ganita Prakash Part 2 Chapter 05 Tales by Dots and Lines

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Practice Ganita Prakash Part 2 Chapter 05 Tales by Dots and Lines MCQs for Class 8 Mathematics

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Multiple Choice Questions

Question 1: The mean of a data set is obtained by
(a) dividing the sum of all the values by the number of values
(b) choosing the middle value of the sorted data
(c) subtracting the smallest value from the largest value
(d) counting how many times each value occurs
Show Answer & Explanation

Answer: (a) dividing the sum of all the values by the number of values

Explanation:
1. Mean = (sum of all the values) ÷ (number of values).
2. Option (b) describes the median, not the mean.
3. Options (c) and (d) do not give an average at all.

Teacher's Note:
1. Mean means 'add all, then share equally'.
2. Keep the words mean and median separate in your mind.

Question 2: The median of a data set is
(a) the value that occurs most often
(b) the difference between the largest and the smallest value
(c) the middle value when the data is arranged in order
(d) the sum of the values divided by their number
Show Answer & Explanation

Answer: (c) the middle value when the data is arranged in order

Explanation:
1. First arrange the data in order.
2. The value in the middle position is the median.
3. For an even number of values, the median is the mean of the two middle values.

Teacher's Note:
1. Always sort the data before picking the middle.
2. Median depends on position, not on the size of the extreme values.

Question 3: The mean of 6, 11, 9 and 14 is
(a) 9
(b) 10
(c) 10.5
(d) 11
Show Answer & Explanation

Answer: (b) 10

Explanation:
1. Sum = 6 + 11 + 9 + 14 = 40.
2. There are 4 values.
3. Mean = 40 ÷ 4 = 10.

Teacher's Note:
1. Count the values carefully before dividing.
2. A quick check: the mean must lie between the smallest and largest value.

Question 4: The mean is called the balance point of a data set because
(a) it is always exactly halfway between the smallest and the largest value
(b) there are always as many values below it as above it
(c) it is always one of the values in the data
(d) the total of the distances of the values below it equals the total of the distances of the values above it
Show Answer & Explanation

Answer: (d) the total of the distances of the values below it equals the total of the distances of the values above it

Explanation:
1. Add up how far each value below the mean is from it, and do the same for the values above it.
2. These two totals are always equal, so the data 'balances' at the mean, like a see-saw.
3. The mean need not be the midpoint of the extremes, need not be a data value, and need not have equal numbers of values on each side.

Teacher's Note:
1. Think of the values as equal weights on a see-saw.
2. The mean is the point where the see-saw balances.

Question 5: A line graph is generally used to show
(a) how a quantity changes over time
(b) the share of each part in a whole
(c) a picture symbol standing for a fixed number
(d) the shape of a solid from different directions
Show Answer & Explanation

Answer: (a) how a quantity changes over time

Explanation:
1. A line graph plots points and joins them with line segments in time order.
2. The rise and fall of the line shows how the quantity changes as time passes.

Teacher's Note:
1. Time usually goes along the horizontal axis.
2. Line graphs are best for trends over days, months or years.

Question 6: Read the two statements.
Statement I: For a data set with an even number of values, the median is the mean of the two middle values.
Statement II: The median of a data set is always one of the values present in the data.
(a) Both statements are true.
(b) Only Statement I is true.
(c) Only Statement II is true.
(d) Neither statement is true.
Show Answer & Explanation

Answer: (b) Only Statement I is true.

Explanation:
1. Statement I is the correct rule for an even number of values.
2. Statement II is false: for 8, 11 the median is \( \frac{8 + 11}{2} \) = 9.5, which is not in the data.
3. So only Statement I is true.

Teacher's Note:
1. With an even count, the median is often a value not in the list.
2. One counter-example is enough to show a statement is false.

Question 7:
Assertion (A): The mean of a collection of just two numbers is exactly halfway between them.
Reason (R): The mean is the value for which the total distance to the values below it equals the total distance to the values above it.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. R is the balance property of the mean, which is true.
2. With only two numbers, the point at equal distance from both is the halfway point.
3. So by R, the mean of two numbers is exactly halfway between them. A is true and R explains it.

Teacher's Note:
1. For two numbers, mean = midpoint.
2. For three or more numbers this is usually not true.

Question 8: The dot plot shows the number of hours each student of a group spent playing outdoors last Sunday. Each dot stands for one student.
How many students played outdoors for more than 3 hours?
1 2 3 4 5 Hours spent playing outdoors on Sunday Each dot = 1 student (a) 2
(b) 4
(c) 6
(d) 10
Show Answer & Explanation

Answer: (c) 6

Explanation:
1. 'More than 3 hours' means 4 hours or 5 hours.
2. There are 4 dots above 4 and 2 dots above 5.
3. Number of students = 4 + 2 = 6.

Teacher's Note:
1. 'More than 3' does not include 3 itself.
2. Count the dots in each column carefully.

Question 9: In a spreadsheet, the formula that gives the average of the numbers stored in the cells B2 to B9 is
(a) =SUM(B2:B9)
(b) =AVERAGE(B2, B9)
(c) =AVERAGE(B2:B9)
(d) =MEDIAN(B2:B9)
Show Answer & Explanation

Answer: (c) =AVERAGE(B2:B9)

Explanation:
1. The range of cells from B2 to B9 is written B2:B9.
2. The AVERAGE function gives the mean of the cells in a range.
3. =AVERAGE(B2, B9) would average only the two cells B2 and B9.

Teacher's Note:
1. A colon means 'from … to'; a comma lists separate cells.
2. SUM adds; AVERAGE finds the mean.

Question 10: Match each data display in Column I with its description in Column II.
Column IColumn II
(i) Line graph(p) each value is shown as a dot placed above a number line
(ii) Dot plot(q) a day is divided into equal time boxes, each coloured by activity
(iii) Clustered-column graph(r) points are joined by segments to show change over time
(iv) Activity strip(s) bars for two or more groups are placed side by side for each category

(a) (i)-(p), (ii)-(r), (iii)-(s), (iv)-(q)
(b) (i)-(r), (ii)-(p), (iii)-(q), (iv)-(s)
(c) (i)-(s), (ii)-(p), (iii)-(r), (iv)-(q)
(d) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
Show Answer & Explanation

Answer: (d) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)

Explanation:
1. Line graph: points joined by segments to show change over time, so (i)-(r).
2. Dot plot: a dot for each value above a number line, so (ii)-(p).
3. Clustered-column graph: bars of different groups side by side, so (iii)-(s).
4. Activity strip: a day in equal coloured time boxes, so (iv)-(q).

Teacher's Note:
1. Match the easiest pair first and cross out options.
2. Here (i)-(r) and (ii)-(p) already narrow it to (b) or (d).

Question 11: The median of 7, 3, 12, 9 and 5 is
(a) 5
(b) 9
(c) 12
(d) 7
Show Answer & Explanation

Answer: (d) 7

Explanation:
1. In order: 3, 5, 7, 9, 12.
2. There are 5 values, so the middle one is the 3rd value.
3. Median = 7.

Teacher's Note:
1. Never pick the middle of the unsorted list.
2. For 5 values the median is the 3rd value.

Question 12: Manoj records one whole day, from midnight to midnight, by colouring a paper strip of 48 equal boxes. Each box stands for
(a) 15 minutes
(b) 30 minutes
(c) 45 minutes
(d) 1 hour
Show Answer & Explanation

Answer: (b) 30 minutes

Explanation:
1. One day = 24 hours = 24 × 60 = 1440 minutes.
2. 1440 ÷ 48 = 30.
3. So each box stands for 30 minutes.

Teacher's Note:
1. Convert to minutes before dividing.
2. Two boxes make one hour.

Question 13: In a spreadsheet, the expression B3:G3 stands for
(a) the two cells B3 and G3 only
(b) all the cells from B3 to G3 lying in row 3
(c) all the cells from B3 to B7 lying in column B
(d) the sum of the numbers in cells B3 and G3
Show Answer & Explanation

Answer: (b) all the cells from B3 to G3 lying in row 3

Explanation:
1. A block of cells is written as Start:End.
2. B3 and G3 are both in row 3.
3. So B3:G3 means every cell of row 3 from column B to column G.

Teacher's Note:
1. The letter is the column; the number is the row.
2. A range is a block of cells, not a calculation.

Question 14: In a line graph drawn against time, a steeper line segment between two consecutive points means that
(a) the readings were taken more often in that interval
(b) the quantity stayed the same in that interval
(c) the quantity changed by a greater amount in that interval
(d) the scale chosen for the vertical axis is wrong
Show Answer & Explanation

Answer: (c) the quantity changed by a greater amount in that interval

Explanation:
1. Consecutive points are the same time-gap apart.
2. A steeper segment covers a bigger vertical distance in that same gap.
3. So the quantity changed by a greater amount.

Teacher's Note:
1. Steep = big change; flat = little or no change.
2. Upward steep means a big rise, downward steep a big fall.

Question 15: In the graphs of monthly average rainfall of the six coastal cities studied in the chapter, the months January to March are
(a) dry months with low rainfall for all six cities
(b) the peak rainfall months for all six cities
(c) the peak rainfall months only for Rameswaram
(d) months for which no rainfall data was collected
Show Answer & Explanation

Answer: (a) dry months with low rainfall for all six cities

Explanation:
1. In all six graphs the values for January, February and March are very low.
2. The peak months differ from city to city and come later in the year.
3. So January to March are dry months for all six cities.

Teacher's Note:
1. Look for what is common to all the graphs.
2. Low values mean little rain, not missing data.

Question 16: The mean of 7, 11, x, 18 and 14 is 12.4. The value of x is
(a) 9
(b) 10
(c) 14
(d) 12
Show Answer & Explanation

Answer: (d) 12

Explanation:
1. Sum of the five values = 12.4 × 5 = 62.
2. Sum of the known values = 7 + 11 + 18 + 14 = 50.
3. x = 62 − 50 = 12.

Teacher's Note:
1. Mean × number of values gives the total.
2. Subtract the known values to get the missing one.

Question 17: The mean of 12 numbers is 23.5. If every number is increased by 6, the new mean is
(a) 23.5
(b) 141
(c) 29.5
(d) 35.5
Show Answer & Explanation

Answer: (c) 29.5

Explanation:
1. Adding 6 to each of 12 numbers adds 6 × 12 = 72 to the total.
2. The mean increases by 72 ÷ 12 = 6.
3. New mean = 23.5 + 6 = 29.5.

Teacher's Note:
1. Adding a fixed number to every value adds the same number to the mean.
2. No need to find the total first.

Question 18: The line graph shows the average number of customers visiting a shop and the average number actually purchasing something, on each day of a week.
On which day is the gap between the number visiting and the number purchasing the greatest?
0 5 10 15 20 25 30 35 40 Mon Tue Wed Thu Fri Sat Sun Day of the week Average number of customers Visiting Purchasing (a) Saturday
(b) Sunday
(c) Friday
(d) Thursday
Show Answer & Explanation

Answer: (a) Saturday

Explanation:
1. Read the two lines day by day: Visiting 18, 15, 12, 20, 26, 34, 30; Purchasing 11, 9, 8, 13, 18, 22, 21.
2. Gaps (Mon to Sun): 7, 6, 4, 7, 8, 12, 9.
3. The greatest gap is 12, on Saturday (34 − 22).

Teacher's Note:
1. The gap is the vertical distance between the two lines.
2. Do not confuse the highest point with the biggest gap.

Question 19:
Assertion (A): The mean of the collection 10, 10, 11, 17 is 12.
Reason (R): The median of the collection 10, 10, 11, 17 is 10.5.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. Mean = (10 + 10 + 11 + 17) ÷ 4 = 48 ÷ 4 = 12, so A is true.
2. Median = \( \frac{10 + 11}{2} \) = 10.5, so R is true.
3. The median does not tell us how the mean was found, so R does not explain A.

Teacher's Note:
1. Check each statement separately first.
2. Then ask: does R give the reason for A?

Question 20:
Assertion (A): To show the yearly launch counts of four different groups over thirteen years, a line graph is easier to read than a clustered-column graph.
Reason (R): A line graph can be drawn only when the data is collected over time.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. A clustered-column graph would need 13 × 4 = 52 bars and look crowded, so A is true.
2. A line graph is generally used for data over time, but 'only' makes R too strong, so R is false.

Teacher's Note:
1. Watch for strong words like 'only', 'always', 'never'.
2. Four lines are much easier to follow than 52 bars.

Question 21:
Assertion (A): When data is given along with frequencies, the mean is found by adding the distinct values and dividing by the number of distinct values.
Reason (R): In such data, every value must be counted as many times as its frequency.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. For data with frequencies, Mean = \( \frac{\sum (\text{value} \times \text{frequency})}{\sum \text{frequency}} \).
2. Averaging only the distinct values ignores the frequencies, so A is false.
3. R states the correct principle, so R is true.

Teacher's Note:
1. Each value counts as many times as it occurs.
2. Divide by the total frequency, not by the number of distinct values.

Question 22: Read the two statements about the 2023 monthly maximum temperature line graph of Kerala and Punjab.
Statement I: Punjab’s monthly maximum temperature changed much more over the year than Kerala’s.
Statement II: Kerala’s monthly maximum temperature was at its lowest, about 29°C, in July.
(a) Only Statement I is true.
(b) Only Statement II is true.
(c) Both statements are true.
(d) Neither statement is true.
Show Answer & Explanation

Answer: (c) Both statements are true.

Explanation:
1. Punjab goes from about 19°C in January up to about 38°C in June, a large change.
2. Kerala stays almost flat; its lowest value, about 29°C, comes in July.
3. So both statements agree with the graph.

Teacher's Note:
1. A flat line means small change; a hilly line means large change.
2. Read the lowest point of each line carefully.

Question 23: Read the two statements about the infographic that compares the preference for rice and wheat across states.
Statement I: A state marked +100 on the colour scale consumes no wheat at all.
Statement II: A state marked +100 has the largest difference between its per capita rice consumption and its per capita wheat consumption.
(a) Only Statement I is true.
(b) Only Statement II is true.
(c) Both statements are true.
(d) Neither statement is true.
Show Answer & Explanation

Answer: (b) Only Statement II is true.

Explanation:
1. The colour scale shows the difference between per capita rice and wheat consumption.
2. +100 means this difference is the largest, in favour of rice, so Statement II is true.
3. It does not mean that no wheat is eaten, so Statement I is false.

Teacher's Note:
1. Always check what the scale actually measures.
2. A difference scale compares two things; it does not give either amount.

Question 24: Match each data set in Column I with its median in Column II.
Column IColumn II
(i) 4, 7, 9, 13, 20(p) 6.5
(ii) 2, 5, 8, 11(q) 6
(iii) 3, 3, 10, 12, 20(r) 9
(iv) 1, 6, 6, 9(s) 10

(a) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)
(b) (i)-(s), (ii)-(p), (iii)-(r), (iv)-(q)
(c) (i)-(r), (ii)-(q), (iii)-(s), (iv)-(p)
(d) (i)-(s), (ii)-(q), (iii)-(r), (iv)-(p)
Show Answer & Explanation

Answer: (a) (i)-(r), (ii)-(p), (iii)-(s), (iv)-(q)

Explanation:
1. (i) 5 values: the 3rd value is 9, so (r).
2. (ii) \( \frac{5 + 8}{2} \) = 6.5, so (p).
3. (iii) 5 values: the 3rd value is 10, so (s).
4. (iv) \( \frac{6 + 6}{2} \) = 6, so (q).

Teacher's Note:
1. Odd count: take the middle value; even count: average the two middle values.
2. All four lists are already in order here.

Question 25: Read the two statements.
Statement I: Removing from a collection one value that is smaller than the mean raises the mean.
Statement II: Removing from a collection one value that is smaller than the median lowers the median.
(a) Both statements are true.
(b) Only Statement II is true.
(c) Neither statement is true.
(d) Only Statement I is true.
Show Answer & Explanation

Answer: (d) Only Statement I is true.

Explanation:
1. Taking away a value that pulled the balance point down lets the mean rise, so Statement I is true.
2. Removing a value below the median moves the middle position towards larger values, so the median rises or stays the same; it never falls.
3. So Statement II is false; only Statement I is true.

Teacher's Note:
1. Removing a small value is like adding a large one, for the mean.
2. For the median, think about which value now sits in the middle.

Question 26: In an archery practice, the number of arrows each student needed to hit the target for the first time is recorded below.
Number of arrows345678
Number of students2591284
By how much does the median of this data exceed its mean?
(a) 0.225
(b) 0.275
(c) 0.775
(d) 1.225
Show Answer & Explanation

Answer: (a) 0.225

Explanation:
1. Number of students = 2 + 5 + 9 + 12 + 8 + 4 = 40.
2. Total arrows = 6 + 20 + 45 + 72 + 56 + 32 = 231, so mean = 231 ÷ 40 = 5.775.
3. Running totals 2, 7, 16, 28: the 20th and 21st values are both 6, so median = 6.
4. Difference = 6 − 5.775 = 0.225.

Teacher's Note:
1. Multiply each value by its frequency before adding.
2. Use running totals to locate the middle positions.

Question 27:
Assertion (A): The median of 6, 11, 15, 20, 24, 29, 33, 38, 38, 45, 50, 57 is 33.
Reason (R): When a data set has an even number of values, its median is the mean of the two middle values.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. R is the correct rule, so R is true.
2. There are 12 values, so the middle values are the 6th (29) and the 7th (33).
3. Median = \( \frac{29 + 33}{2} \) = 31, not 33. So A is false.

Teacher's Note:
1. Count the values before choosing the middle.
2. With an even count, average the two middle values.

Question 28:
Assertion (A): If every value of a collection is doubled, the mean of the collection is also doubled.
Reason (R): Doubling each of the n values doubles their total, and twice the total divided by n is twice the original mean.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Let the total of the n values be S, so the mean is \( \frac{S}{n} \).
2. After doubling, the total is 2S and the new mean is \( \frac{2S}{n} \) = 2 × \( \frac{S}{n} \).
3. So A is true and R gives exactly the reason.

Teacher's Note:
1. Multiplying every value by k multiplies the mean by k.
2. R is the algebra behind A.

Question 29: Match each change made to a collection of data in Column I with its effect on the mean in Column II.
Column IColumn II
(i) A value equal to the mean is included(p) the mean becomes 4 times as large
(ii) Every value is increased by 4(q) the mean stays the same
(iii) Every value is multiplied by 4(r) the mean increases by 4
(iv) A value smaller than the mean is removed(s) the mean increases

(a) (i)-(q), (ii)-(p), (iii)-(r), (iv)-(s)
(b) (i)-(q), (ii)-(r), (iii)-(p), (iv)-(s)
(c) (i)-(s), (ii)-(r), (iii)-(p), (iv)-(q)
(d) (i)-(q), (ii)-(r), (iii)-(s), (iv)-(p)
Show Answer & Explanation

Answer: (b) (i)-(q), (ii)-(r), (iii)-(p), (iv)-(s)

Explanation:
1. Including a value equal to the mean keeps the balance, so the mean stays the same: (i)-(q).
2. Adding 4 to every value adds 4n to the total, so the mean increases by 4: (ii)-(r).
3. Multiplying every value by 4 multiplies the total and the mean by 4: (iii)-(p).
4. Removing a value below the mean raises the mean: (iv)-(s).

Teacher's Note:
1. 'Increases by 4' and '4 times as large' are different.
2. Adding shifts the mean; multiplying scales it.

Question 30: The line graph shows the monthly average rainfall, in millimetres, of three cities X, Y and Z.
Which of the following is a valid inference from this graph?
0 100 200 300 400 500 600 700 800 900 1000 Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Month Monthly average rainfall (mm) City X City Y City Z (a) City Y receives no rain at all between January and May.
(b) January to March are the wettest months for all three cities.
(c) Cities X and Z both have their peak rainfall in July, while City Y peaks in November.
(d) The three cities receive the same total rainfall over the year.
Show Answer & Explanation

Answer: (c) Cities X and Z both have their peak rainfall in July, while City Y peaks in November.

Explanation:
1. The highest point of X (about 920 mm) and of Z (about 260 mm) are both over July.
2. The highest point of Y (about 350 mm) is over November. So (c) is valid.
3. (a) fails: Y's line stays above zero; (b) fails: January to March are the driest months; (d) fails: X's line is far above the others for most of the year.

Teacher's Note:
1. Find the highest marker on each line.
2. Reject any option the graph contradicts.

Ganita Prakash Part 2 Chapter 05 Tales by Dots and Lines Objective Questions & Solutions for Class 8 Mathematics

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