CBSE Class 10 Mathematics Probability Worksheet Set C

Probability
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Read and download free pdf of CBSE Class 10 Mathematics Probability Worksheet Set C. Students and teachers of Class 10 Mathematics can get free printable Worksheets for Class 10 Mathematics Chapter 15 Probability in PDF format prepared as per the latest syllabus and examination pattern in your schools. Class 10 students should practice questions and answers given here for Mathematics in Class 10 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 10 Mathematics Worksheets prepared by school teachers as per the latest NCERT, CBSE, KVS books and syllabus issued this academic year and solve important problems with solutions on daily basis to get more score in school exams and tests

Worksheet for Class 10 Mathematics Chapter 15 Probability

Class 10 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 15 Probability in Class 10. This test paper with questions and answers for Class 10 will be very useful for exams and help you to score good marks

Class 10 Mathematics Worksheet for Chapter 15 Probability

Case Study Based Questions

I. Five friends make up their minds to play a game by using a spinner. They put a spinner down on the ground and set around themselves to play. A spinner contains eight regions, numbered through 8, as shown in the figure, the arrow has an equally likely chance of landing on any of the eight regions. If the arrow lands on a line, the result is not counted and the arrow spun again.

""CBSE-Class-10-Mathematics-Probability-Worksheet-Set-C

Question. How many possible outcomes are in the sample spaces?
(a) 4
(b) 6
(c) 8
(d) 10
Answer : C

Question. What is the probability that the arrow lands on 4?
(a) 1/4
(b) 1/6
(c) 1/2
(d) 1/8
Answer : D

Question. The set of possible outcomes for event A, in which the arrow lands on an even number is
(a) 2, 4, 6, 8
(b) 2, 4, 6, 10
(c) 2, 6, 8, 10
(d) 4, 6, 8, 10
Answer : A

Question. The probability that the arrow lands on an even number is
(a) 1/4
(b) 1/6
(c) 1/8
(d) 1/2
Answer : D

Question. The probability that the arrow will point at any factor of 8 is
(a) 1/2
(b) 1/4
(c) 1/6
(d) 1/8
Answer : A

II. Some boys are playing with numbers. There is a box which contains 90 discs. They are numbered from 1 to 90. The boys are drawing disc one by one from the box at random and want to find the probability of a particular number.

Question. If one disc is drawn at random from the box, the probability that it bears a two-digit number is
(a) 9/10
(b) 8/90
(c) 89/90
(d) 79/90
Answer : A

Question. Then they put the disc into the box and draw another disc at random. They want to know the probability that it bears a perfect square number. So, the probability of perfect square number is
(a) 8/90
(b) 3/10
(c) 1/10
(d) 1/9
Answer : C

Question. They put the disc into the box and another boy draws another disc at random, and wants to know the probability that it bears a number divisible by 5. So the probability is
(a) 2/5
(b) 3/5
(c) 4/5
(d) 1/5
Answer : D

Question. After putting the disc into the box, the next boy draws a disc at random and wants to know the probability that it bears a prime number. The probability is
(a) 5/18
(b) 4/15
(c) 2/15
(d) 13/45
Answer : C

Question. The boys put all the disc together into the box and next boy draws a disc at random and find the probability that the disc bears a number divisible by 7.
(a) 1/15
(b) 2/15
(c) 4/15
(d) 1/5
Answer : B
 

Q.-Two dice are thrown at a time. Find the probability of the following -
(i) these numbers shown are equal;
(ii) the difference of numbers shown is 1. 
Answer : The sample space in a throw of two dice
s = {1, 2, 3, 4, 5, 6} ×{1, 2, 3, 4, 5, 6}.
total no. of cases n (s) = 6 × 6 = 36.
(i) Here E1 = the event of showing equal number on both dice
= {(1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6) }
∴ n (E1 ) = 6
∴ P (E1) =n(E1 )/n(s) =6/36 =1/6
(ii) Here E2 = the event of showing numbers whose difference is 1.
= {(1, 2) (2, 1) (2, 3) (3, 2) (3, 4) (4, 3)  (4, 5) (5, 4) (5, 6) (6, 5)}
∴  n (E2) = 10
∴ p (E2) = n(E2)/n(s) =10/36= 5/18

Q.- Three coins are tossed together -
(i) Find the probability of getting exactly two heads,
(ii) Find the probability of getting at least two tails.
Answer : The sample space in tossing three coins
S = (H, T) × (H, T) × (H, T)
∴ Total no. of cases n (s) = 2 × 2 × 2 = 8
(i) Here E1 = the event of getting exactly two heads
= {HHT, HTH, THH}
∴ n (E1) = 3
∴ P (E1) =n(E1 )/n(s) = 3/8
(ii) E2 = {HTT, THT, TTH, TTT}
∴ n (E2) = 4,
∴ P(E2) =n(E2 )/n(s) =4/8 =1/2
 
Q.- Find the probability of throwing (a) 3, (b) an even number with an ordinary six faced die.
Answer : (a) There are 6 possible ways in which the die can
fall and there is only one way of throwing 3.
∴ The required probability
= Number of favourable outcomes/Total number of possible outcomes = 1/6
(b) Total number of outcomes of throwing a die = 6.
Number of outcomes of falling even number
i.e. 2, 4, 6 = 3.
The required probability = 3/6 =1/2
 
Q.- A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card nor a queen.
Answer : There are 26 red cards (including 2 red queens) and 2 more queens are there. Thus, we have to set aside 28 cards.
And, we have to draw 1 card out of the remaining (52 – 28) = 24 cards.
∴ Required probability = 24/52 = 6/13.
 
Q.-  Find the probability of getting a number less than 5 in a single throw of a die.
Answer : There are 4 numbers which are less than 5, i.e. 1, 2, 3 and 4.
Number of such favourable outcomes = 4.
 The number marked on all the faces of a die are 1, 2, 3, 4, 5 or 6
∴ Total number of possible outcomes = 6
∴ P(a number less than 5)=4/6=2/3
 
Q.-  If the probability of winning a game is 0.3,what is the probability of lossing it ?
Answer : Probability of winning a game = 0.3.
Probability of losing it = q (say).
=> 0.3 + q = 1
=> q = 1 – 0.3
=> q = 0.7
 
Q.- On tossing three coins at a time, find -
(i) All possible outcomes.
(ii) events of occurence of 3 heads, 2 heads, 1 head and 0 head.
(iii) probabilty of getting 3 heads, 2 heads, 1 head and no head.
Answer : Let H denotes head and T denotes tail. On tossing three coins at a time,
(i) All possible outcomes = {HHH, HHT, HTH,THH, HTT, THT, TTH, TTT}. These are the 8 possible outcomes.
(ii) An event of occurence of 3 heads = (HHH) = 1
An event of occurence of 2 heads = {HHT, HTH, THH} = 3
An event of occurence of 1 head = {HTT, THT, TTH} = 3
An event of occurence of O head = {TTT} =1
(iii) Now, probability of getting 3 heads = P (HHH)
 probability notes 1
 
Q.-  One card is drawn from a well-shiffled deck of 52 cards. Find the probability of drawing:
(i) an ace
(ii) ‘2’ of spades
(iii) ‘10’ of black suit
Answer : (i) There are 4 aces in deck.
∴ Number of such favourable outcomes = 4
 Total number of cards in deck = 52.
∴ Total number of possible outcomes = 52.
∴ P(an ace) = 4/52=1/13.
(ii) Number of ‘2’ of spades = 1
Number of favourable outcomes = 1
Total number of possible outcomes = 52
∴ P(‘2’ of spades) =1/52
(iii) There are 2 ‘10’ of black suits (i.e. spade and club)
∴ Number of favourable outcomes = 2
Total number of possible outcomes = 52
∴ P(‘10’ of a black suit) =2/52=1/26
 

Please click the below link to access CBSE Class 10 Mathematics Probability Worksheet Set C

Chapter 15 Probability
CBSE Class 10 Mathematics Probability Worksheet Set A
CBSE Class 10 Mathematics Probability Worksheet Set C
CBSE Class 10 Mathematics Probability Worksheet Set G

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CBSE Class 10 Mathematics Chapter 15 Probability Worksheet

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Worksheet for Mathematics CBSE Class 10 Chapter 15 Probability

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Chapter 15 Probability CBSE Class 10 Mathematics Worksheet

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