CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set B

Read and download the CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set B in PDF format. We have provided exhaustive and printable Class 10 Mathematics worksheets for Chapter 5 Arithmetic Progression, designed by expert teachers. These resources align with the 2025-26 syllabus and examination patterns issued by NCERT, CBSE, and KVS, helping students master all important chapter topics.

Chapter-wise Worksheet for Class 10 Mathematics Chapter 5 Arithmetic Progression

Students of Class 10 should use this Mathematics practice paper to check their understanding of Chapter 5 Arithmetic Progression as it includes essential problems and detailed solutions. Regular self-testing with these will help you achieve higher marks in your school tests and final examinations.

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet with Answers

Arithmetic Progression MCQ Questions with Answers Class 10 

Question. If the sides of a right triangle are in A.P., then the ratio of its smallest side to the greatest side is :-
(1) 3 : 4
(2) 3 : 5
(3) 4 : 5
(4) None
Answer : 3
 
Question. Given that n A.M.'s are inserted between two sets of numbers a, 2b and 2a, b, where a, b Î R. If the mth means in the two cases are same then ratio a : b is equal to :-
(1) n : (n - m + 1)
(2) (n - m + 1) : m
(3) (n - m + 1) : n
(4) m : (n - m + 1)
Answer : 4
 
Question. The next term of the sequence 9, 16, 27, 42, .........is :-
(1) 53
(2) 61
(3) 57
(4) None
Answer : 2
 
Question. If a, b, c, d, e, f are A.M.s between 2 and 12, then a + b + c + d + e + f is equal to :-
(1) 14
(2) 84
(3) 42
(4) None
Answer : 3  
 
Question. In an A.P. sum of first p terms is equal to the sum of first q terms. Sum of it's first p + q terms is :-
(1) - (p + q)
(2) p + q
(3) 0
(4) None
Answer : 3 
 
Question. 2, √6 , 4.5 are the following terms of an A.P..
(1) 101st, 207th, 309th
(2) 101st, 201st, 301st
(3) 2nd, 6th, 9th
(4) None of these
Answer : 4
 
Question. The sum of 40 A.M's between two numbers is 120.The sum of 50 A.M's between them is equal to :-
(1) 130
(2) 160
(3) 150
(4) None
Answer : 3
 
Question. In an A.P., sum of first n terms is 2n2 + 3n, it's common difference is :-
(1) 4
(2) 3
(3) 2
(4) 6
Answer : 1 
 
Question. The number of terms common to the arithmetic progressions 3, 7, 11, ......., 407 and 2, 9, 16,....., 709 is :-
(1) 51
(2) 14
(3) 21
(4) 28
Answer : 2
 
Question. If the sum of first n terms of an A.P. is Pn + Qn2 where P and Q are constants, then common difference of A.P. will be :-
(1) P + Q
(2) P - Q
(3) 2P
(4) 2Q
Answer : 4 
 
Question. The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?
(1) 1st
(2) 9th
(3) 12th
(4) None of these
Answer : 3
 
Question. A person pays Rs. 975 in monthly instalments, each monthly instalment being less than the former by Rs. 5. The amount of the first instalment is Rs. 100. In what tune, will the entire amount be paid ?
(1) 12 months
(2) 26 months
(3) 15 months
(4) 18 months
Answer : 3
 
Question. If the nth term of an A.P. is 4n + 1, then the common difference is
(1) 3
(2) 4
(3) 5
(4) 6
Answer : 2
 
Question. 30 trees are planted in a straight line at intervals of 5 m. To water them, the gardener needs to bring water for each tree, separately from a well, which is 10 m from the first tree in line with the trees. How far will he have to walk in order to water all the trees beginnings with the first tree ? Assume that he starts from the well.
(1) 4785 m
(2) 4795 m
(3) 4800 m
(4) None of these
Answer : 2
 
Question. If the sum of first n natural numbers is one-fifth of the sum of their squares, then n is
(1) 5
(2) 6
(3) 7
(4) 8
Answer : 2 
 
Question. Find the sum of all natural numbers not exceeding 1000, which are divisible by 4 but not by 8.
(1) 62500
(2) 62800
(3) 64000
(4) 65600
Answer : 1
 
Question. A club consists of members whose ages are in AP,the common difference being 3 months. If the youngest member of the club is just 7 years old and the sum of the ages of all the members is 250 year, then the number of members in the club are
(1) 15
(2) 20
(3) 25
(4) 30
Answer : 3

Question. In an AP, if d = – 4, n = 7, an = 4, then a is
(a) 6
(b) 7
(c) 20
(d) 28
Answer : D

Question. The nth term of the AP: a, 3a, 5a, ... is
(a) na
(b) (2n – 1)a
(c) (2n + 1)a
(d) 2na
Answer : B

Question. The first term of an AP is p and the common difference is q, then its 10th term is
(a) q + 9p
(b) p – 9q
(c) p + 9q
(d) 2p + 9p
Answer : C

Question. If 4/5, a, 2 are three consecutive terms of an AP, then the value of a is
(a) 5/2
(b) 2/7
(c) 5/7
(d) 7/5
Answer : A
 

Answer the following:

Question. Write first four terms of the AP, whose first term and the common difference are given as follows: a = 10, d = 10
Answer : 10, 20, 30, 40

(2) Find the 10th term of the AP: 2, 7, 12, ...
Answer : 47

Question. In the given AP, find the missing terms: ......., 13, ......., 3.
Answer : 18, 8

Question. Find the 6th term from the end of the AP: 17, 14, 11, ..., –40.
Answer : –25

Question. Which term of the AP: 21, 18, 15, ... is zero?
Answer : 

Question. Write the next term of the AP: √8, √18, √32 , ...........
Answer : √50 or 5√2

Question. Find a, b, and c such that the numbers a, 7, b, 23, c are in AP.
Answer : a = –1, b = 15, c = 31

Question. Find the 9th term from the end (towards the first term) of the AP: 5, 9, 13, ..., 185.
Answer : Reversing the given AP, we get
185, 181, 174, ..., 9, 5
Ninth term a9 = a + (9 – 1)d
= 185 + 8 × (– 4)
= 185 – 32
= 153

Question. For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an AP? 
Answer : Given that k + 9, 2k – 1 and 2k + 7 are in AP
Then,
(2k – 1) – (k + 9) = (2k + 7) – (2k – 1)

k – 10 = 8
k = 18

Question. For what value of k will the consecutive terms 2k + 1, 3k + 3 and 5k – 1 form an AP? 
Answer : Given that 2k + 1, 3k + 3 and 5k – 1 are in AP.
So, (3k + 3) – (2k + 1) = (5k – 1) – (3k + 3)

k + 2 = 2k – 4
2k – k = 2 + 4
⇒ k = 6

Question. Find the eleventh term from the last term of the AP: 27, 23, 19, ..., –65. 
Answer : a11 = –25

Question. If the first three terms of an AP are b, c and 2b, then find the ratio of b and c. 
Answer : b, c and 2b are in AP
⇒ c = 3b/2
∴ b : c = 2 : 3

Question. Find the value of x so that –6, x, 8 are in AP.
Answer : 1

Question. Find the 11th term of the AP: –27, –22, –17, –12, ... .
Answer : 23

Question. The nth term of an AP is (7 – 4n), then what is its common difference?
Answer : an = 7 – 4n
⇒ a1 = 7 – 4 × 1 = 3
⇒ a2 = 7 – 4 × 2 = 7 – 8 = –1
a3 = 7 – 4 × 3 = 7 – 12 = –5
Now, a2 – a1 = –1 – 3 = –4
a3 – a2 = –5 – (–1)
= –5 + 1 = –4
So, the common difference of AP is –4.

Question. Find the common difference of the AP whose first term is 12 and fifth term is 0.
Answer : A5 = a1 + 4d = 0
12 + 4d = 0
d = –3

 

Assertion Reasoning Questions Arithmetic Progression

Directions:
(a) If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
(b) If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
(c) If Assertion is correct but Reason is incorrect.
(d) If Assertion is incorrect but Reason is correct.

Question. Assertion : If Sn is the sum of the first n terms of an A.P., then its nth term an is given by an = Sn – Sn – 1 .
Reason : The 10th term of the A.P. 5, 8, 11, 14, ………………. is 35.
Answer : C

Question. Assertion: arithmetic mean between 5 and 90 is 47.5
Reason: arithmetic mean between two given number a,b is (a+b)/2
Answer : A

Question. Assertion: the value of n, if a = 10, d = 5, an = 95.
Reason: the formula of general term an is an= a+(n-1)d.
Answer : A

Question. Assertion: The constant difference between any two terms of an AP is commonly known as common difference
Reason: the common difference of 2,4,6,8 this A.P. sequence is 2
Answer : A

Question. Assertion : Let the positive numbers a, b, c be in A.P., then 1/bc, 1/ac, 1/ab are also in A.P.
Reason : If each term of an A.P. is divided by abc, then the resulting sequence is also in A.P.
Answer : A

 

CASE STUDY QUESTIONS

Q1. Your elder brother wants to buy a car and plans to take loan from a bank for his car. He repays his total loan of Rs 1,18,000 by paying every month starting with the first instalment of Rs 1000. If he increases the instalment by Rs 100 every month , answer the following:

""CBSE-Class-10-Mathematics-Arithmetic-Progression-2

Question. Find the amount paid by him in 30th installment.
Answer : 3900

Question. Find the amount paid by him in the 30 installments.
Answer : 73500

Question. If total instalments are 40 then amount paid in the last installment?
Answer : 490

 

Q2. In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?

""CBSE-Class-10-Mathematics-Arithmetic-Progression-3

Question. Find terms of AP formed in above situation
Answer : 10, 16 , 22……..

Question. What is the total distance the competitor has to run?
Answer : Total distance 370

Question. Find distance cover after 4 potato drop In the bucket?
Answer : 152 m

 

Very Short Answer Type Questions

Question. Check whether – 150 is a term of the AP : 11, 8, 5, 2 . . .
Answer : 
No

Question. A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?
Answer : 
Rs 27750

Question. Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.
Answer : 
178

Question. Find the 20th term from the last term of the AP : 3, 8, 13, . . ., 253
Answer : 
20th term from the last term is 158

Question. In a flower bed, there are 23 rose plants in the first row, 21 in the second, 19 in the third, and so on.
There are 5 rose plants in the last row. How many rows are there in the flower bed?
Answer : 
10 rows

Question. For the AP : 1/3, 5/3, 9/3, 13/3,....... write the first term a and the common difference d.
Answer : 
a = 1/3, d= 4/3

Question. The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Answer : 
1

Question. 200 logs are stacked in following manner . 20 logs in the bottom row , 19 in the next row 18 in the row next to it and so on . how many rows are the 200 logs placed and how many logs are in the top row ?
Answer : total rows 16 and 5 logs placed in top row

Question. Ramkali saves Rs 5 in the first week, of a year and increased her weekly savings by Rs 1.75. If in the nth week her weekly savings became Rs 20.75, find n.
Answer : 10

Question. The digits of a positive number of three digits are in A.P. and their sum is 15. The number obtained by reversing the digits is 594 less than the original number. Find the number.
Answer : 852

Question. The sum of the third and seventh terms of an A.P. is 40 and the sum of its sixth and 14th terms is 70. Find the sum of the first ten terms of the A.P.
Answer : 215

Question. If sum of first n terms of an AP is 4n – n2 What is the first term What is the sum first two terms ?
Find 10th term , 3rd term and nth term .
Answer : S1 = 3 S2 = 4 a10= -15 a3 = -1 and nth term = 5-2n

Please click the link below to download CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set B

CBSE Mathematics Class 10 Chapter 5 Arithmetic Progression Worksheet

Students can use the practice questions and answers provided above for Chapter 5 Arithmetic Progression to prepare for their upcoming school tests. This resource is designed by expert teachers as per the latest 2026 syllabus released by CBSE for Class 10. We suggest that Class 10 students solve these questions daily for a strong foundation in Mathematics.

Chapter 5 Arithmetic Progression Solutions & NCERT Alignment

Our expert teachers have referred to the latest NCERT book for Class 10 Mathematics to create these exercises. After solving the questions you should compare your answers with our detailed solutions as they have been designed by expert teachers. You will understand the correct way to write answers for the CBSE exams. You can also see above MCQ questions for Mathematics to cover every important topic in the chapter.

Class 10 Exam Preparation Strategy

Regular practice of this Class 10 Mathematics study material helps you to be familiar with the most regularly asked exam topics. If you find any topic in Chapter 5 Arithmetic Progression difficult then you can refer to our NCERT solutions for Class 10 Mathematics. All revision sheets and printable assignments on studiestoday.com are free and updated to help students get better scores in their school examinations.

Where can I download the 2025-26 CBSE printable worksheets for Class 10 Mathematics Chapter Chapter 5 Arithmetic Progression?

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Are these Chapter Chapter 5 Arithmetic Progression Mathematics worksheets based on the new competency-based education (CBE) model?

Yes, Class 10 Mathematics worksheets for Chapter Chapter 5 Arithmetic Progression focus on activity-based learning and also competency-style questions. This helps students to apply theoretical knowledge to practical scenarios.

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What is the benefit of solving chapter-wise worksheets for Mathematics Class 10 Chapter Chapter 5 Arithmetic Progression?

For Chapter Chapter 5 Arithmetic Progression, regular practice with our worksheets will improve question-handling speed and help students understand all technical terms and diagrams.