CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set D

Read and download the CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set D in PDF format. We have provided exhaustive and printable Class 10 Mathematics worksheets for Chapter 5 Arithmetic Progression, designed by expert teachers. These resources align with the 2025-26 syllabus and examination patterns issued by NCERT, CBSE, and KVS, helping students master all important chapter topics.

Chapter-wise Worksheet for Class 10 Mathematics Chapter 5 Arithmetic Progression

Students of Class 10 should use this Mathematics practice paper to check their understanding of Chapter 5 Arithmetic Progression as it includes essential problems and detailed solutions. Regular self-testing with these will help you achieve higher marks in your school tests and final examinations.

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet with Answers

 

ARITHMETIC PROGRESSIONS

 

Very Short Answer type Questions

Question. Find the sum of the first 22 terms of the AP : 8, 3, –2, . . .
Answer : – 979

Question. If the 3rd and the 9th terms of an AP are 4 and – 8 respectively, which term of this AP is zero?
Answer : 
5th term

Question. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms.
Answer : n2

Question. How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78?
Answer : 
4 or 13

Question. In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students?
Answer : 
234

Question. For what value of n, are the nth terms of two APs: 63, 65, 67, . . . and 3, 10, 17, . . . equal?
Answer : 
13

 

Short Answer type Questions

Question. lf 2x, x + 10, 3x + 2 are in A.P., find the value of x.
Answer : 
lf 2x, x + 10, 3x + 2 are in A.P.,we have to find the value of x.
Since, 2x, x + 10, 3x + 2 are in A.P.therefore 2 (x + 10) = 2x + 3x + 2
2x + 20 = 5x + 2
3x = 18 x = 6

Question. Find 7th term from the end of the AP : 7, 10 , 13,....,184. 
Answer : 
Given, AP is 7, 10 , 13,....,184.
we have to find 7th term from the end reversing the AP , 184,.....,13,10,7.
now, = common difference = 7-10 = -3
7th term from the beginning of AP =a+(7-1)d=a+6d
=184+(6 ×(-3))
= 184 - 18 = 166

Question. Find the 11th term from the end of the AP 10,7,4,....,-62. 
Answer : We have
a = 10, d = (7-10) = -3, l = -62 and n = 11.
11th term from the end = [l - (n -1) d]
= {-62 - (11 -1)× (-3)}
= (-62 + 30) = -32.
Hence, the 11th term from the end of the given AP is -32. 
 
Question. Divide 24 in three parts such that they are in AP and their product is 440. 
Answer : Let the required numbers in A.P.are (a - d), a and (a + d).
Sum of these numbers = (a - d) + a + (a + d) = 3a
Product of these numbers = (a - d)× a × (a + d)=a(a2 - d2)
But given, sum = 24 and product = 440
∴ 3a = 24
a = 8
and a(a2 - d2) = 8(64 - d2) = 440 [ a = 8]
Or, 64 - d2 = 55
Or, d2 = 64 - 55
=> d2 = 9
=> d = ± 3
When a = 8 and d = 3
The required numbers are (5, 8, 11).
When a = 8 and d = -3
The required numbers are ( 11, 8, 5 ).
 
Question. Determine an A.P. whose third term is 9 and when fifth term is subtracted from 8th term, we get 6. 
Answer : Let the first term be a and the common difference be d.
an = a + (n - 1)d
Here given, a3 =9
or, a + 2d = 9 ....(i)
a8 - a5 = 6
or, (a + 7d) - (a + 4d) = 6
a + 7d - a - 4d = 6
or, 3d = 6
or, d = 2 ....(ii)
Substituting this value of d from (ii) in (i), we get
or, a + 2(2) = 9
or, a + 4 = 9
or a = 9 - 4
or, a = 5
a = 5 and d = 2
So, A.P. is 5,7,9,11,....
 
Question. If 9th term of an A.P. is zero, prove that its 29th term is double the 19th term. 
Answer : We have,
a9 = 0
a + (9 - 1)d = 0
a + 8d = 0
a = -8d
To prove: a29 = 2a19
Proof: LHS = a29
= a + (29 - 1)d
= a + 28d
= -8d + 28d = 20d
RHS = 2a19
= 2 a + (19 - 1)d]
= 2[ -8d + 18d]
= 2 10d
= 20d
LHS = RHS
Hence, 29th term is double the 19th term.
 
Question. Find the first four terms of an A.P. whose first term is - 2 and common difference is - 2. 
Answer : given a1= -2, common difference d= -2
a1 = -2 ,
a2 = a1 + d = -2 + (-2) = -4
a3 = a2 + d = -4 + ( -2) = -6
a4 = a3 + d = =-6 + (-2) = -8
First four terms are - 2, - 4, - 6, - 8
 
Question. If the sum of n terms of an A.P. is 2n2 + 5n, then find the 4th term.
Answer : Let the sum of n terms of A.P. = Sn.
Given, Sn = 2n2 + 5n
Now, nth term of A.P, = Sn - Sn-1
or, an = (2n2 + 5n) - [2(n - 1)2 + 5 (n - 1)]
an= (2n2 + 5n) - [2(n2 -2n + 1) + 5 (n - 1)]
an = 2n2 + 5n - [2n2 - 4n + 2 + 5n - 5]
an = 2n2 + 5n - [2n2+ n - 3]
an = 2n2 + 5n - 2n2 - n + 3
an = 4n + 3
4th term a4=4×4+3
=16+3=19
 
Question. In the following AP's find the missing terms: 2, __, 26. 
Answer : 2, __, 26
We know that the difference between consecutive terms is equal in any A.P.
Let the missing term be x .
x - 2 = 26 - x ⇒ 2x = 28 ⇒ x = 14
Therefore, missing term is 14.
 

Question. For what value of K, the number x, 2x + k, 3x + 6,are three consecutive terms of A.P
Answer: 
k=3

Question. How many numbers of two digits are divisible by 8?
Answer: n = 11

Question. Write next term of A.P ∫8, ∫18, ∫32….
Answer: 5√2, 6√2, 7√2

Question. In the given A.P, find the missing terms 0,_,-8,-12,_.
Answer: 
0,-4,-8,-12,-16

Question. Find the middle term of A.P 1,8,15,…,505
Answer: middle term = 73

Question. Find the 10th term from the end of A.P 3, 8, 13, 18…253
Answer: 209

Question. Find first three terms of an A.P whose nth term is -5 + 2x
Answer: –3, -1, 1

Question. Which term of the sequence 4,9,14…is 124?
Answer: n = 25

Question. What is the common difference of an A.P in which a23 – a18 = 45
Answer: d = 9

Question. Find the sum of all odd integers between 1 and 100 which are not multiples of 4
Answer: 2500

Questions of 2 Mark

Question. Determine the A.P whose zero term is 16 and when 5th term is subtracted from 7th ,we get 12
Answer: 4,10,16,22

Question. Which term of A.P 121,117,113….is the first negative term?
Answer: 32nd term

Question. For what values of n, nth term of the series 3, 10, 17…and 63,65,67…are equal?
Answer: n = 13

Question. Solve the equation – 2 + 5 + 8… + x = 155
Answer: 29

Question. If the 10th term of an A.P is 47 and first term is 2, find the sum of the first 15 terms
Answer: 
255

Question. How many multiples of 4 lie between 10 and 250?
Answer: 60

Question. How many terms of A.P 18, 16, 14…Should be taken so that their sum is zero?
Answer: 19

Question. If seven times the seventh term of an A.P is equal to 11 times the eleventh term, show that 18th term of an A.P is zero.
Answer: 
a + 17d = 0
T18 = 0

Question. If the sum of n terms of an A.P is n2 + 2x, find the A.P and the 20th term.
Answer: 3,5,7,9
T20 = 41

 

More question- 

1. S17 − S16 = ?

(a) S1

(b) T1

(c) T17

(d) 2d

2. T10 of an AP = 31 & T20 = 71 then T30 = ?

(a) 171

(b) 222

(c) 112

(d) 111

3. No. of terms of the sequence −12, −9, −6, −3, …….. must be added to make the sum 54 are _____

(a) 33

(b) −46

(d) 10

(d) 12

4. If ‘n’ times the ‘n’th term an AP is equal to m times its ‘m’th term, then (m + n)th term is _____

(a) 0

(b) 1

(c) −1

(d) 2

5. The sum of three numbers in an AP is (−3), and their product is 8. Then numbers are

(a) −4, −1, 2

(b) −4, −1, −2

(c) 4, 1, 2

(d) 2, 1, −4

6. The sum of four numbers is 20 and sum of whose squares is 120. This nos. are _____

(a) 2, 4, −6, −8

(b) 2, 4, 6, 8

(c) 8, 6, 2, −1

(d) 8, 6, −2, 1

7. The nth term of a pattern of numbers is 2n + 1. The common difference of this AP is ________.

(a) 2

(b) −2

(c) 3

(d) −3

8. Which term of the AP 3, 8, 13, 18………… is 78 ?

(a) t15

(b) t16

(c) t17

(d) t18

9. Which term of the sequence 114, 109, 104, ………….. is the first negative term ?

(a) t23

(b) t24

(c) t25

(d) None of these

10. The sum of first 18 terms of an AP whose nth term is 3 − 2n is

(a) −288

(b) 250

(c) −278

(d) −260

11. If 2x, x + 10, 3x + 2 are in AP, then the value of x is

(a) 6

(b) 5

(c) 4

(d) 3

12. The 9th term of an AP is 499 and 499th term is 9. The term which is equal to zero is

(a) t508

(b) t805

(c) t504

(d) t501

13. If in an AP a = 1, tn = 20 and Sn = 399 then n is

(a) 19

(b) 21

(c) 38

(d) 42

14. Two APs have the same common difference. The first term of one of these −1 and that of the other is −8. Then the difference between their 4th term is

(a) −1

(b) −8

(c) 7

(d) −9

15. Sum of n terms of the series ..........321882++++ is

(a) ()21+nn

(b) ()312+nn

(c) ()21+nn

(d) None of these

16. The sum of first 50 odd natural numbers is

(a) 2500

(b) 2400

(c) 2600

(d) 2300

17. If nnnnbaba++++11 is the AM between a and b, then the value of n is

(a) 1

(b) −1

(c) 0

(d) None of these

18. If an AP a = −2.5, d = 0.5, an = 7.5 then n is

(a) 20

(b) 21

(c) 3.6

(d) −3.6

 

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CBSE Mathematics Class 10 Chapter 5 Arithmetic Progression Worksheet

Students can use the practice questions and answers provided above for Chapter 5 Arithmetic Progression to prepare for their upcoming school tests. This resource is designed by expert teachers as per the latest 2026 syllabus released by CBSE for Class 10. We suggest that Class 10 students solve these questions daily for a strong foundation in Mathematics.

Chapter 5 Arithmetic Progression Solutions & NCERT Alignment

Our expert teachers have referred to the latest NCERT book for Class 10 Mathematics to create these exercises. After solving the questions you should compare your answers with our detailed solutions as they have been designed by expert teachers. You will understand the correct way to write answers for the CBSE exams. You can also see above MCQ questions for Mathematics to cover every important topic in the chapter.

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