CBSE Class 12 Chemistry The p Block Elements Assignment Set 01

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LEVEL-1 QUESTIONS
 
1. NH3 has higher boiling point than phosphine. Why?
Ans—Ammonia is a polar molecule it form in-termolecular hydrogen bonding.
 
2. Why BiH3 the strongest reducing agent amongst all the hydrides of group 15 elements
Ans- Less B.E or longer bond length.
 
3. Why H2S is acidic and H2S is neutral ?
Ans-The S---H bond is weaker than O---H bond because the size of S atomis bigger than that of O atom . Hence H2S can dissociate to give H+ Ions in aqueous solution .
 
4. Name two poisonous gases which can be prepared from chlorine gas ?
Ans- Phosgene (COCl2) , tear gas (CCl3NO2)
 
5. Name the halogen which does not exhibit positive oxidation state .
Ans- Flourine being the most electronegative element does not show positive oxidation state .
 
6. Iodine forms I3- but F2 does not form F3- ions .why?
Ans- Due to the presence of vacant D-orbitals , I2 accepts electrons from I-ions to form I3-ions , but because of d-orbitals F2 does not accept electrons from F-ions to form F3 ions.
 
7. Draw the structure of peroxosulphuric acid .
CBSE Class 12 Chemistry The p Block Elements Assignment
 
Important Questions for NCERT Class 12 Chemistry The p Block Elements

Question. Which would quickly absorb oxygen?
(a) Alkaline solution of pyrogallol
(b) Conc. H2SO4
(c) Lime water
(d) Alkaline solution of CuSO4

Answer     A

Question. Oxygen will directly react with each of the following elements except
(a) P
(b) Cl
(c) Na
(d) S 

Answer   B

Question. It is possible to obtain oxygen from air by fractional distillation because
(a) oxygen is in a different group of the periodic table from nitrogen
(b) oxygen is more reactive than nitrogen
(c) oxygen has higher b.pt. than nitrogen
(d) oxygen has a lower density than nitrogen.

Answer     C

Question. The angular shape of ozone molecule (O3) consists of
(a) 1s and 1p bond
(b) 2s and 1p bond
(c) 1s and 2p bonds
(d) 2s and 2p bonds. 

Answer    B

Question. The gases respectively absorbed by alkaline pyrogallol and oil of cinnamon are
(a) O3, CH4
(b) O2, O3
(c) SO2, CH4
(d) N2O, O3

Answer     B

Question. Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by the other?
(a) Is soluble in water.
(b) Is used as a food preservative.
(c) Forms ‘acid-rain’.
(d) Is a reducing agent.

Answer     B

Question. Which of the following oxoacid of sulphur has — O — O — linkage
(a) H2SO3, sulphurous acid
(b) H2SO4, sulphuric acid
(c) H2S2O8, peroxodisulphuric acid
(d) H2S2O7, pyrosulphuric acid 

Answer    C

Question. Identify the correct formula of oleum from the following :
(a) H2S2O7
(b) H2SO3
(c) H2SO4
(d) H2S2O8

Answer    A

Question. In which pair of ions both the species contain S — S bond?
(a) S4O62–, S2O32–
(b) S2O72–, S2O82–
(c) S4O62–, S2O72–
(d) S2O72–, S2O32–

Answer    A

Question. Oleum is
(a) castor oil
(b) oil of vitriol
(c) fuming H2SO4
(d) none of these.

Answer   C

Question. Which of the following statements is not true for halogens?
(a) All form monobasic oxyacids.
(b) All are oxidizing agents.
(c) All but fluorine show positive oxidation states.
(d) Chlorine has the highest electron-gain enthalpy. 

Answer   C

Question. Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?
(a) Br2 > I2 > F2 > Cl2
(b) F2 > Cl2 > Br2 > I2
(c) I2 > Br2 > Cl2 > F2
(d) Cl2 > Br2 > F2 > I2

Answer    D

Question. The variation of the boiling points of the hydrogen halides is in the order HF > HI > HBr > HCl.
What explains the higher boiling point of hydrogen fluoride?
(a) There is strong hydrogen bonding between HF molecules.
(b) The bond energy of HF molecules is greater than in other hydrogen halides.
(c) The effect of nuclear shielding is much reduced in fluorine which polarises the HF molecule.
(d) The electronegativity of fluorine is much higher than for other elements in the group. 

Answer    A

Question. Among the following which is the strongest oxidising agent?
(a) Br2
(b) I2
(c) Cl2
(d) F2 

Answer    D

Question. Which one of the following arrangements does not give the correct picture of the trends indicated against it?
(a) F2 > Cl2 > Br2 > I2 : Bond dissociation energy
(b) F2 > Cl2 > Br2 > I2 : Electronegativity
(c) F2 > Cl2 > Br2 > I2 : Oxidizing power
(d) F2 > Cl2 > Br2 > I2 : Electron gain enthalpy

Answer     A,D

Question. Which one of the following orders is not in accordance with the property stated against it?
(a) F2 > Cl2 > Br2 > I2 : Bond dissociation energy
(b) F2 > Cl2 > Br2 > I2 : Oxidising power
(c) HI > HBr > HCl > HF : Acidic property in water
(d) F2 > Cl2 > Br2 > I2 : Electronegativity 

Answer    A

Question. Which statement is wrong?
(a) Bond energy of F2 > Cl2
(b) Electronegativity of F > Cl
(c) F is more oxidising than Cl
(d) Electron affinity of Cl > F 

Answer    A

Question. Which of the following has the greatest electron affinity?
(a) I
(b) Br
(c) F
(d) Cl 

Answer   D

Question. Which of the following displaces Br2 from an aqueous solution containing bromide ions?
(a) I2
(b) I3–
(c) Cl2
(d) Cl– 

Answer    C

Question. Which of the following species has four lone pairs of electrons?
(a) I
(b) O
(c) Cl–
(d) He

Answer   C
 
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