CBSE Class 12 Biology Principles of Inheritance and Variation Assignment Set A

Read and download free pdf of CBSE Class 12 Biology Principles of Inheritance and Variation Assignment Set A. Get printable school Assignments for Class 12 Biology. Class 12 students should practise questions and answers given here for Chapter 5 Principles Of Inheritance And Variation Biology in Class 12 which will help them to strengthen their understanding of all important topics. Students should also download free pdf of Printable Worksheets for Class 12 Biology prepared as per the latest books and syllabus issued by NCERT, CBSE, KVS and do problems daily to score better marks in tests and examinations

Assignment for Class 12 Biology Chapter 5 Principles Of Inheritance And Variation

Class 12 Biology students should refer to the following printable assignment in Pdf for Chapter 5 Principles Of Inheritance And Variation in Class 12. This test paper with questions and answers for Class 12 Biology will be very useful for exams and help you to score good marks

Chapter 5 Principles Of Inheritance And Variation Class 12 Biology Assignment


POINTS TO REMEMBER

Allele : Various or slightly different forms of a gene, having same position on chromosomes.

Phenotype : The observable or external characteristics of an organism

Genotype : The genetic constitution of an organism.

Monohybrid cross : A cross between two individuals of species, considering the inheritance of single pair of contrasting character e.g., a cross between pure tall (TT) and Dwarf (tt).

Dihybrid cross : A cross between two individuals of a species, considering the inheritance of two pairs of contrasting traits/characters e.g., a cross between Round and Yellow (RRYY) and wrinkled and green (rryy) pea seeds

Incomplete dominance : When one of the two alleles of a gene is incompletely dominant over the other allele.

Co-dominance : When two alleles of a gene are equally dominant and express themselves even when they are together.

Multiple allelism : When a gene exists in more than two allelic forms e.g., gene for blood group exist in three allelic forms, IA, IB and i.

Aneuploidy : The phenomenon of gain or loss of one or more chromosome(s), that results due to failure of separation of homologous pair of chromosomes during meiosis.

Trisomy : The condition in which a particular chromosome is present in three copies in a diploid cell/ nucleus.

Male heterogamety : When male produces two different types of gametes/ sperms e.g., In human beings X and Y.

QUESTIONS

1. Give any two reasons for the selection of pea plants by Mendel for his experiments.
2. Name any one plant that shows the phenomenon of incomplete dominance during the inheritance of its flower colour.
3. Name the base change and the amino acid change, responsible for sickle cell anaemia.
4. Name the disorder with the following chromosome complement.
(i) 22 pairs of autosomes + X X Y
(ii) 22 pairs of autosomes + 21st chromosome + XY.
5. A haemophilic man marries a normal homozygous woman. What is the probability that their daughter will be haemophilic?
6. A test is performed to know whether the given plant is homozygous dominant or heterozygous. Name the test and phenotypic ratio of this test for a monohybrid cross.
7. Identify the sex of organism as male or female in which the sex chromosome are found as
(i) ZW in bird (ii) XY in Drosophila (iii) ZZ in birds. (iv) XO in grasshopper.
8. Mention two differences between Turner's syndrome and Klinefelter's syndome.
9. The human male never passes on the gene for haemophilia to his son. Why is it so?
10. Mention four reasons why Drosophila was chosen by Morgan for his experiments in genetics.
11. Differentiate between point mutation and frameshift mutations.

 

Important Questions for NCERT Class 12 Biology Principles of Inheritance and Variation
 

Question. In monohybrid cross the allele do not show any blending and that both the characters are recovered as such in F2 generation. This statement is explained on the basis of :
(a) Dominance
(b) Segregation
(c) Independent assortmant
(d) All the above
Answer : B

Question. Recessive traits are seen due to :
(a) Formation of non functional enzyme
(b) Enzyme is not produced
(c) 1 and 2 both
(d) Formation of functional enzyme
Answer : C

Question. Multiple alleles can be found only when :
(a) Population studies are made
(b) Individual study is made
(c) Mutation is absent
(d) Dominance is present
Answer : A

Question. Which of the following characters of Drosophila is not suitable for genetical studies ?
(a) They could be grown on simple synthetic medium in laboratory
(b) They complete their life cycle in about 2-weeks
(c) Single mating produces few number of progeny flies.
(d) They have many types of heredilaty variations that can be seen with low power microscope.
(e) Male & Female flies are not easily distinguishable
(a) a, b, c
(b) a, b, c, d, e
(c) d and e
(d) c and e
Answer : D

Question. Incomplete dominance can be seen in :
(a) Flower colour in Mirabilis jalapa
(b) Flower colour in Pisum sativum
(c) Size of starch grains in pea
(d) 1 and 3 both
Answer : D

Question. Which of the following cow breed comes in existance through artifical selection and domestication from ancestral wild cows
(a) Brown swiss
(b) Jamanapari
(c) Murrah
(d) Sahiwal
Answer : D

Question. Which of the following was/were applied first time to problems in biology during Mendel's investigations into inheritance
(a) Statistical analysis
(b) Mathematical logic
(c) Computational devices
(d) Both 1 and 2
Answer : D

Question. A true breeding line is that
(a) Having undergone continuous cross pollination
(b) Having undergone continuous self pollination
(c) Having undergone continuous vegetative propagation
(d) Obtain through tissue culture (Meristem)
Answer : B

Question. Variations are :
(a) Degree by which progeny differs from their parents
(b) Degree by which progeny similar to their parents
(c) Process by which characters are passed on from parent to progeny
(d) True breeding lines
Answer : A

Question. In any dihybrid cross segregation of one pair of characters is independent of other pair of characters, is known as
(a) Law of segregation
(b) Law of purity of gametes
(c) Law of independent assortment
(d) Law of dominance
Answer : C

Question. In dihybrid mendelian cross how many types of genotype and phenotype will be obtain
(a) 4 and 9 respectively
(b) 9 and 4 respectively
(c) 9 & 16 respectively
(d) 4 & 16 respectively
Answer : B

Ques. How many different types of genetically different gametes will be produced by a heterozygous plant having the genotype AABbCc?
(a) Six
(b) Nine

(c) Two
(d) Four 

Answer: D

Ques. The polygenic genes show
(a) different karyotypes
 (b) different genotypes

(c) different phenotypes
(d) none of these. 

Answer: C

Ques. A polygenic inheritance in human beings is
(a) skin colour
(b) phenylketonuria

(c) colour blindness
(d) sickle cell anaemia.

Answer: A

Ques. Match the terms in column I with their description in column II and choose the correct option.
    Column I                   Column II
A. Dominance         (i) Many genes govern a single character
B. Co-dominance    (ii) In a heterozygous organism only one allele expresses itself
C. Pleiotropy          (iii) In a heterozygous organism both alleles express themselves fully
D. Polygenic           (iv) A single gene inheritance influences many characters
       A   B   C   D
(a) (iv) (i) (ii) (iii)
(b) (iv) (iii) (i) (ii)
(c) (ii) (i) (iv) (iii)
(d) (ii) (iii) (iv) (i) 
Answer: D

Ques. A pleiotropic gene
(a) controls a trait only in combination with another gene
(b) controls multiple traits in an individual
(c) is expressed only in primitive plants
(d) is a gene evolved during Pliocene. 
Answer: B

Ques. Which of the following is an example of pleiotropy?
(a) Haemophilia
(b) Thalassemia

(c) Sickle cell anaemia
(d) Colour blindness

Answer: C

Ques. When a single gene influences more than one trait it is called
(a) pseudodominance
(b) pleiotropy

(c) epistasis
(d) none of these. 

Answer: B

Ques. Select the incorrect statement.
(a) Human males have one of their sex-chromosome much shorter than other.
(b) Male fruit fly is heterogametic.
(c) In male grasshoppers, 50% of sperms have no sex-chromosome.
(d) In domesticated fowls, sex of progeny depends on the type of sperm rather than egg.
Answer: D

Ques. Which of the following pairs is wrongly matched?
(a) Starch synthesis in pea : Multiple alleles
(b) ABO blood grouping : Co-dominance
(c) XO type sex determination: Grasshopper
(d) T.H. Morgan : Linkage 
Answer: A

Ques. Which one of the following conditions of the zygotic cell would lead to the birth of a normal human female child?
(a) Two X chromosomes
(b) Only one Y chromosome
(c) Only one X chromosome
(d) One X and one Y chromosome 
Answer: A

Ques. In Drosophila, the sex is determined by
(a) the ratio of number of X-chromosome to the sets of autosomes
(b) X and Y chromosomes
(c) the ratio of pairs of X-chromosomes to the pairs of autosomes
(d) whether the egg is fertilized or develops parthenogenetically. 
Answer: C

Ques. Number of Barr bodies in XXXX female is
(a) 1
(b) 2

(c) 3
(d) 4. 

Answer: C

Ques. Male XX and female XY sometime occur due to
(a) deletion
(b) transfer of segments in X and Y chromosome
(c) aneuploidy
(d) hormonal imbalance. 
Answer: B

Ques. Probability of four sons to a couple is
(a) 1/4
(b) 1/8

(c) 1/16
(d) 1/32. 

Answer: C

Ques. Genetic identity of a human male is determined by
(a) sex-chromosome
(b) cell organelles

(c) autosome
(d) nucleolus. 

Answer: A

Ques. When an animal has both the characters of male and female, it is called
(a) super female
(b) super male

(c) intersex
(d) gynandromorph.

Answer: D

Ques. Mr. Kapoor has Bb autosomal gene pair and d allele sex-linked. What shall be proportion of Bd in sperms?
(a) Zero
(b) 1/2

(c) 1/4
(d) 1/8 

Answer: C

Ques. Sex is determined in human beings
(a) by ovum
(b) at time of fertilisation
(c) 40 days after fertilisation
(d) seventh to eight week when genitals differentiate in fetus.
Answer: B

Ques. A normal green male maize is crossed with albino female. The progeny is albino because
(a) trait for a albinism is dominant
(b) the albinos have biochemical to destroy plastids derived from green male
(c) plastids are inherited from female parent
(d) green plastids of male must have mutated.
Answer: C

Ques. A family of five daughter only is expecting sixth issue. The chance of its being a son is
(a) zero
(b) 25%

(c) 50%
(d) 100%. 

Answer: C

Ques. One of the parents of a cross has a mutation in its mitochondria. In that cross, that parent is taken as a male. During segregation of F2 progenies that mutation is found in
(a) one-third of the progenies
(b) none of the progenies
(c) all the progenies
(d) fifty percent of the progenies. 
Answer: B

Ques. The most striking example of point mutation is found in a disease called
(a) Down’s syndrome
(b) sickle cell anaemia

(c) thalassaemia
(d) night blindness.

Answer: B

Ques. Select the correct match.
(a) Haemophilia – Y linked
(b) Phenylketonuria – Autosomal dominant trait
(c) Sickle cell anaemia – Autosomal recessive trait,chromosome -11
(d) Thalassemia – X linked
Answer: B


Very Short Answer Questions Class 12 Biology Chapter 5 Principles of Inheritance and Variation

Question. Give an example of a chromosomal disorder caused due to non-disjunction of autosomes.
Answer. Down’s Syndrome.

Question. Name a human genetic disorder due to the following:
(i) An additional X-chromosome in a male
(ii) Deletion of one X-chromosome in a female
Answer. (i) Klinefelter’s Syndrome (ii) Turner’s Syndrome

Question. State what does aneuploidy lead to. 
Answer. Aneuploidy leads to individuals with abnormal number of chromosomes. Some disorder due to aneuploidy are Down’s Syndrome, Turner’s Syndrome, Klinefelter’s Syndrome.

Question. Name the type of cross that would help to find the genotype of a pea plant bearing violet flowers. 
Answer. Test cross.

Question. A garden pea plant produced axial white flowers. Another of the same species produced terminal violet flowers. Identify the dominant traits.
Answer. Axial, violet flower.

Question. Why, in a test cross, did Mendel cross a tall pea plant with a dwarf pea plant only?
Answer. To determine the genotype of the tall plant, whether it is homozygous dominant or heterozygous, as dwarfness is a recessive trait which is expressed only in homozygous condition and he was sure of genotype of dwarf plant.

Question. Name the event, during cell division cycle that results in the gain or loss of chromosome.s
Answer. Failure of segregation of chromosomes.

Question. If the frequency of a parental form is higher than 25% in a dihybrid test cross, what does that indicate about the two genes involved? 
Answer. It shows that the two genes are linked. 

Question. Write the types of sex determination mechanisms the following crosses show. Give an example of each type.
(i) Female XX with Male XO
(ii) Female ZW with Male ZZ 
Answer. (i) Male heterogamety, Grasshopper
(ii) Female heterogamety, Birds

Question. A haemophilic man marries a normal homozygous woman. What is the probability that their daughter will be haemophilic? 
Answer. 0% because only one X chromosome will carry the haemophilia gene. So, she will be a carrier.

Question. How many chromosomes do drones of honeybee possess? Name the type of cell division involved in the production of sperms by them. 
Answer. Drones possess 16 chromosomes. Mitosis is involved in the production of sperms.

Question. A male honeybee has 16 chromosomes whereas its female has 32 chromosomes. Give one reason. 
Answer. Male honeybee develops from unfertilised female gamete (Parthenogenesis) and thus has 16 chromosomes whereas female develops by fertilisation and thus has 32 chromosomes.

Question. State a difference between a gene and an allele. 
Answer. Gene contains information that is required to express a particular trait whereas alleles are alternating forms of a gene and are the code for a pair of contrasting traits for e.g., for plant height has two alleles – for tallness and dwarfness.

Question. Name the respective pattern of inheritance where F1 phenotype
(a) does not resemble either of the two parents and is in between the two.
(b) resembles only one of the two parents. 
Answer. (a) Incomplete dominance (b) Dominance

Question. Give an example of a human disorder that is caused due to a single gene mutation.
Answer. Sickle-cell anaemia.

Question. The egg of an animal contains 10 chromosomes, of which one is X-chromosome. How many autosomes would there be in the karyotype of this animal? 
Answer. There will be 9 pairs of autosomes in the karyotype of this animal.

Question. State the chromosomal defect in individuals with Turner’s syndrome. 
Answer. Monosomy of sex chromosome in females (XO condition).

Question. Name the stage of cell division where segregation of an independent pair of chromosomes occurs. 
Answer. Anaphase-I of Meiosis-I.

Question. How many type of gametes are produced by the individual with genotype AABBCCDD and AaBbCcDd? 
Answer. One type of gamete by individual (AABBCCDD) ABCD and sixteen (= 24 = 16) type of gametes by individual AaBbCcDd. 

 

Short Answer Questions Class 12 Biology Chapter 5 Principles of Inheritance and Variation

Question. What are the characteristic features of a true-breeding line? 
Answer. A true-breeding line for a trait is one that has undergone continuous self-pollination, showing a stability in the inheritance of the trait for several generations.

Question. In order to obtain the F1 generation, Mendel pollinated a true-breeding, say, tall plant with a true-breeding dwarf plant. But for getting the F2 generation, he simply self-pollinated the tall F1 plants. Why? 
Answer. All the F1 offsprings of the cross are heterozygous so allowing self-pollination is sufficient to raise F2 offspring. Also he intended to understand the inheritance of the selected trait over generations.

Question. In snapdragon, a cross between true-breeding red flowered (RR) plants and true-breeding white flowered (rr) plants showed a progeny of plants with all pink flowers.
(a) The appearance of pink flowers is not known as blending. Why?
(b) What is this phenomenon known as? 
Answer. (a) R (dominant allele red colour) is not completely dominant over r (recessive allele white colour). r maintains its originality and reappears in F2 generation. Therefore, it is not blending.
(b) Incomplete dominance.

Question. The phenotypic and genotypic ratio in F2 generation are same in a certain kind of inheritance.
Name an organism in which it occurs and mention the kind of inheritance involved. 
Answer. This kind of inheritance occurs in Mirabilis jalapa (4 O’clock plant) and the type of inheritance is called incomplete dominance.

Question. In a particular plant species, majority of the plants bear purple flowers. Very few plants bear white flowers. No intermediate colours are observed. If you are given a plant bearing purple flowers, how would you ascertain that it is a pure breed for that trait? Explain.
Answer. By test cross. Cross, purple flower plant with a (homozygous) recessive plant with white flowers, if all the flowers of the progeny are purple, the plant is homozygous dominant, i.e. pure breed.

Question. In snapdragon (Antirrhinum majus), a cross between varieties with red and white flowers produces all pink progeny. Explain how it is a case of incomplete dominance and not of blending inheritance.
Answer. In incomplete dominance, the genes of an allelomorphic pair are not expressed as dominant and recessive, but express themselves partially when present together in a hybrid and is an intermediate between the two genes. As a result an intermediate character is obtained. e.g., Two types of flowers occur in Mirabilis jalapa (4 o’ clock plant) and Antirrhinum majus (snapdragon/ dog flower). The red flower colour is due to gene RR, white flower colour is due to gene rr but pink flower colour appears in case of genotype Rr.It is not a case of blending inheritance because the parental characters reappear in the F2 generation without any modification. 

Question. What is a test cross? How can it decipher the heterozygosity of a plant? 
Answer. A cross to analyse whether genotype of dominant individual is homozygous or heterozygous is called test cross.
On crossing with a recessive parent, if 50% of progeny have dominant trait and 50% have recessive trait then the plant is said to he heterozygous.

Question. How does a test cross help to determine the genotype of an individual? 
Answer. In a test cross the individual of unknown genotype is crossed with the recessive parent. If all progenies are dominant, then the genotype exhibits homozygosity and if the progenies have a dominant to recessive ratio 1 : 1, then the genotype exhibits heterozygosity.

Question. With the help of one example, explain the phenomena of co-dominance and multiple allelism in human population. 
Answer. ABO blood group in human being is an example of multiple allelism and co-dominance. There are three alleles for the gene I, i.e., IA, IB, and i, thus, exhibiting multiple allelism. When IA and IB are present together the blood group is AB. Both A and B blood groups are expressed. This is called co-dominance.

Question. Explain pleiotropy with the help of an example.
Answer. Pleiotropy is the phenomenon in which a single gene exhibits multiple phenotypic expression.
The pleiotropic gene affects the metabolic pathways, resulting in different phenotypes. For example, phenylketonuria is caused by mutation in the gene coding the enzyme phenylalanine hydroxylase. It also leads to mental retardation & reduction in hair & skin pigmentation.

Question. Who proposed chromosomal theory of inheritance? Point out any two similarities in the behaviour of chromosomes and genes.
Answer. It was proposed by Sutton and Boveri.
Similarities:
(i) Both genes and chromosomes occur in pairs in a diploid cell (2n).
(ii) Both of them separate out during gametogenesis to enter into different gametes.
(iii) Paired condition is again restored by fusion of gametes. 

Question. In a dihybrid cross white eyed, yellow bodied female Drosophila crossed with red eyed, brown bodied male Drosophila produced in F2 generation, 1.3 per cent recombinants and 98.7 per cent progeny with parental type combinations. This observation of Morgan deviated from Mendelian F2 phenotypic dihybrid ratio. Explain, giving reasons, Morgan’s observations.
Answer. Morgan saw that when the two genes in a dihybrid cross were situated on the same chromosome, the proportion of parental gene combinations were much higher than the non-parental type. Morgan attributed this due to physical association or linkage of two genes and coined the term linkage to describe this physical association of genes on a chromosome and the term recombination to describe the generation of non-parental gene combinations. %of recombinants depends on distance between genes. More is the distance more is % of recombinants and vice versa

Question. Linkage and crossing-over of genes are alternatives of each other. Justify with the help of an example. 
Answer. In Drosophila a yellow bodied white eyed female was crossed with brown bodied red eyed male.
The F1 progeny produced, when intercrossed, it was observed that the F2 phenotypic ratio of
Drosophila deviated significantly from Mendel’s 9 : 3 : 3 : 1. The genes for eye colour and body colour are closely located on the ‘X’ chromosome, showing linkage and therefore, these are inherited together. Recombinants were formed due to crossing over but at low percentage.

Question. How does the gene ‘I’ control ABO blood groups in humans? Write the effect the gene has on the structure of red blood cells. 
Answer. Gene ‘I’ has three different alleles IA, IB, i
(a) IA produces A type of sugar polymer on surface of RBC which results in A group
(b) IB produces B type of sugar polymer on surface of RBC which results in B group
(c) i produces no sugar which result in O blood group
The sugar polymers protrude from the surface of plasma membrane of RBCs which are characteristics of each blood group. 

Question. Human blood group is a good example of multiple allelism and co-dominance. Justify.
Answer. Multiple allelism: Generally in an individual or population, only two alleles of a trait govern the character, but in case of ABO blood group, three alleles IA, IB and i are found to govern blood group in human population. This is multiple allelism.
Co-dominance: Allele IA and IB when present in an individual, both being dominant express their own types of sugars or traits. Thus, exhibiting co-dominance.

Question. Give an example of a gene responsible for multiple phenotypic expressions. What are such genes called? State the cause that is responsible for such an effect. 
Answer. Gene causing phenylketonuria causes multiple phenotypic expressions. Such genes are called pleiotropic genes. This effect of multiple phenotypic expressions is caused because pleiotropic gene affects metabolic pathways, resulting in different phenotypes.

Question. Differentiate between male and female heterogamety. 
Answer. Differences between male heterogamety and female heterogamety

Male heterogamety Female heterogamety
Male produces two types of gametes (while female produces only one type of gamete) Female produces two types of gametes (while male produces only one type of gamete)
XY and XO type are two types of male
heterogamety
ZW type is a type of heterogamety
Example, male grasshopper produce gametes of two types––X and O. Example, female birds produce gametes of two types––Z and W.

Question. Explain mechanism of sex determination in birds. 
Answer. In birds, females are heterogemetic and males are homogametic. Females have one Z sex chromosome and one W sex chromosome. Males have a pair of Z sex chromosome. If Z sperm fertilises Z ovum, a male offspring is produced, and if Z sperm fertilises W ovum a female offspring is produced.

Question.Explain the mechanism of sex determination in insects like Drosophila and grasshopper.
Answer. In grasshopper, the mechanism of sex determination is of the XO type. In females, the eggs bear a pair of X chromosomes along with the autosomes. Males contain only 1 X chromosome with autosomes. On the other hand, there are two types of sperms formed in males–one having a X chromosome and other without X chromosome. Hence, grasshopper shows male heterogamety.

Question. Differentiate between “ZZ” and “XY” type of sex-determination mechanisms.
Answer. ZZ type is seen in birds. The males are homogametic (ZZ) and females are heterogametic (ZY).
Sex is determined by the type of egg getting fertilised.
XY type is seen in human beings The males are heterogametic (XY) and females homogametic (XX). Sex is determined by the type of sperm fertilising the ovum.

Question. Why is pedigree analysis done in the study of human genetics? State the conclusions that can be drawn from it. 
Answer. Pedigree analysis is done because control crosses are not possible in case of humans beings.
This can be useful for analysis of traits, in several generations of a family, to trace pattern of inheritance to check whether the trait is dominant or recessive or sex-linked or not.

 

Chapter 02 Sexual Reproduction In Flowering Plants
CBSE Class 12 Biology Sexual Reproduction in Flowering Plants Set A

More Study Material

CBSE Class 12 Biology Chapter 5 Principles Of Inheritance And Variation Assignment

We hope you liked the above assignment for Chapter 5 Principles Of Inheritance And Variation which has been designed as per the latest syllabus for Class 12 Biology released by CBSE. Students of Class 12 should download and practice the above Assignments for Class 12 Biology regularly. We have provided all types of questions like MCQs, short answer questions, objective questions and long answer questions in the Class 12 Biology practice sheet in Pdf. All questions have been designed for Biology by looking into the pattern of problems asked in previous year examinations. 

Assignment for Biology CBSE Class 12 Chapter 5 Principles Of Inheritance And Variation

Our team of expert teachers have referred to NCERT book for Class 12 Biology to design the Biology Class 12 Assignments. If you practice at least one test paper daily, you will get higher marks in Class 12 exams this year. Daily practice of Biology course notes and related study material will help you to clear all your doubts and have stronger understanding of all concepts. You can download all Revision notes for Class 12 Biology also from www.studiestoday.com absolutely free of cost.

Chapter 5 Principles Of Inheritance And Variation Assignment Biology CBSE Class 12

All questions and their answers for the assignment given above for Class 12 Biology have been developed as per the latest curriculum and books issued for the current academic year. The students of Class 12 can rest assured that the best teachers have designed the questions of Biology so that you are able to revise the entire syllabus if you do the assignments. Lot of MCQ questions for Class 12 Biology have also been given in the worksheets and assignments for regular use. All study material for Class 12 Biology students have been given on studiestoday.

Chapter 5 Principles Of Inheritance And Variation Assignment CBSE Class 12 Biology

Regular assignment practice helps to get a more comprehensive understanding of Chapter 5 Principles Of Inheritance And Variation concepts. Assignments play a crucial role in understanding Chapter 5 Principles Of Inheritance And Variation in CBSE Class 12. Students can download all the assignments of the same chapter in Class 12 Biology in Pdf format. You can print them or read them online on your computer or mobile.

CBSE Biology Class 12 Chapter 5 Principles Of Inheritance And Variation Assignment

CBSE Class 12 Biology latest books have been used for coming up with the latest questions and solutions for the above assignment. If you have revised all concepts relating to Chapter 5 Principles Of Inheritance And Variation then you should attempt all questions given in the test sheets above. We have also provided lot of Worksheets for Class 12 Biology which you can use to further make your self stronger in Biology

Where can I download in PDF assignments for CBSE Class 12 Biology Chapter 5 Principles Of Inheritance And Variation

You can download free Pdf assignments for CBSE Class 12 Biology Chapter 5 Principles Of Inheritance And Variation from StudiesToday.com

The assignments for Chapter 5 Principles Of Inheritance And Variation Class 12 Biology for have been made based on which syllabus

The Chapter 5 Principles Of Inheritance And Variation Class 12 Biology Assignments have been designed based on latest CBSE syllabus for Class 12 Biology issued for the current academic year

Can I download and print these printable assignments for Biology Chapter 5 Principles Of Inheritance And Variation Class 12

Yes, These printable assignments for Chapter 5 Principles Of Inheritance And Variation Class 12 Biology are free to download and print

How many topics are covered in Chapter 5 Principles Of Inheritance And Variation Biology assignments for Class 12

All topics given in Chapter 5 Principles Of Inheritance And Variation Biology Class 12 Book for the current academic year have been covered in the given assignment

Is there any charge for this assignment for Chapter 5 Principles Of Inheritance And Variation Biology Class 12

No, all Printable Assignments for Chapter 5 Principles Of Inheritance And Variation Class 12 Biology have been given for free and can be downloaded in Pdf format

How can I download the printable test assignments for Chapter 5 Principles Of Inheritance And Variation Biology Class 12

Just click on the View or Download button below, then another window with the Pdf will be visible, just click on the Pdf icon to download the free assignments for Chapter 5 Principles Of Inheritance And Variation Class 12 Biology

Are these assignments available for all chapters in Class 12 Biology

Yes, apart from Biology you can download free assignments for all subjects in Class 12

Can I download solved assignments for Chapter 5 Principles Of Inheritance And Variation CBSE Class 12 Biology

Our team of expert teachers at studiestoday.com have provided all answers for the practice questions which have been given in Class 12 Biology Chapter 5 Principles Of Inheritance And Variation assignments