Read and download free pdf of CBSE Class 10 Physics Electricity Worksheet Set B. Students and teachers of Class 10 Science can get free printable Worksheets for Class 10 Science Chapter 12 Electricity in PDF format prepared as per the latest syllabus and examination pattern in your schools. Class 10 students should practice questions and answers given here for Science in Class 10 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 10 Science Worksheets prepared by teachers as per the latest Science books and syllabus issued this academic year and solve important problems with solutions on daily basis to get more score in school exams and tests
Worksheet for Class 10 Science Chapter 12 Electricity
Class 10 Science students should download to the following Chapter 12 Electricity Class 10 worksheet in PDF. This test paper with questions and answers for Class 10 will be very useful for exams and help you to score good marks
Class 10 Science Worksheet for Chapter 12 Electricity
Question: The unit of potential difference is:
a) Volt
b) Ohm
c) Ampere
d) Faraday
Answer: a
Question: The instrument used for measuring electric current is:
a) Ammeter
b) Galvanometer
c) Voltmeter
d) Potentiometer
Answer: a
Question: Copper is not preferred to make fuse wire because it:
a) is a good conductor of electricity
b) has a low melting point
c) has a high melting point
d) is not easily available
Answer: b
Question: While a cell is being charged, ______ energy is converted into ______ energy.
a) mechanical, electrical
b) electrical, chemical
c) heat, electrical
d) chemical, heat
Answer: b
Question: Which of the given statements is true regarding ammeter and voltmeter?
a) Ammeter is connected in series with the required device, Voltmeter in parallel
b) Both ammeter and voltmeter are connected in series with the required device
c) The voltmeter is connected in series with the device, Ammeter in parallel
d) They can be connected in any way
Answer: a
Question: The obstruction offered by the material of a conductor to the passage of electric current is known as:
a) Resistance
b) Conductance
c) Inductance
d) None of these
Answer: a
Question: The unit of resistivity is:
a) V A
b) V A
c) V m / A
d) VA / m
Answer: c
Question: Identify the correct circuit diagram:
a) i
b) ii
c) iii
d) iv
Answer: d
Assertion-Reason Type Questions
Following questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below:
(a) Both A and R are true and R is the correct explanation of A.
(b) Both A and R are true but R is not the correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.
Question: Assertion (A) : Longer wires have greater resistance and the smaller wires have lesser resistance.
Reason (R) : Resistance is inversely proportional to the length of the wire.-
Answer: c
Question: Assertion (A) : Tungsten metal is used for making filaments of incandescent lamps.
Reason (R) : The melting point of tungsten is very low.
Answer: c
Question: Assertion (A) : Alloys are commonly used in electrical heating devices, like electrical iron, toasters etc.
Reason (R) : Alloys do not oxidise (burn) readily at high temperatures.
Answer: a
Question: Assertion (A) : Bending a wire does not affect electrical resistance.
Reason (R) : Resistance of a wire is proportional to resistivity of material.
Answer: b
Case Study Based Questions
Electrical resistivities of some substances, at 20°C are given below in the table.
Study the table and answer the given questions.
Question: Which is a better conductor of electric current?
a) Silver
b) Copper
c) Tungsten
d) Mercury
Answer: a
Question: Which element will be used for electrical transmission lines?
a) Iron
b) Copper
c) Tungsten
d) Mercury
Answer: b
Question: Nichrome is used in the heating elements of electric heating devices because:
a) It has high resistivity
b) It does not oxidise readily at high temperature
c) Both of the above
d) None of the above
Answer: c
Question: Series arrangement is not used for domestic circuits because:
a) Current drawn is less
b) Current drawn is more
c) Neither of the above
d) Both of the above
Answer: a
Short Answer Type Questions
Question: Write the factors on which heat produced in a resistor depends
Answer. heat produced in a resistor is directly proportional to
- Square of current (I2)
- Resistance of the resistor (R) and
- Time for which the current flows through the resistor.(t)
H = I2Rt joules
By Ohm’s law, we get H = VIt joules = V2t/R joules
Question: Two students perform experiments on series and parallel combinations of two given resistors R1 and R2 and plot the following V-I graphs
Answer. Which of the graphs is (are) correctly labelled in terms of the words ‘Series and parallel’? justify your answer. In case of series combination, the effective resistance = R1 + R2 is more, hence slope of V – I graph will be more. It is otherwise in case of I – V graph. So, series and parallel are correctly marked in graph (ii).
Question: Define the following terms:
(a) one ampere (b) 1 volt.
Answer. Ampere: The SI unit of electric current is ampere (A). One ampere is the electric current when one coulomb of charge flows through a conductor in one second.
Volt: The SI unit of potential difference is volt (V). One volt is the potential difference between two points in an electric circuit when one joule of work is done to move a charge of one coulomb from one point to the other.
Question: A bulb is rated at 5.0 V, 100 mA. Calculate its (a) power and (b) resistance.
Answer. Rating of bulb, V = 5 0. Volt, I = 100 mA = 100 x10-3A = 0.1A
a. Power of bulb = V x l, P = 5 .0 x 0 .1 = 0.5W
b. V = IR, R =V/l = 5/.1 =50 Ω
Long Answer Type Questions
Question: Distinguish between resistances in series and resistances in parallel.
Answer. Resistances in series:
1. If a number of resistances are connected in such a way that the same current flows through each resistance, then the arrangement is called resistances in series.
2. The current across each resistance is same.
3. The equivalent resistance in series combination is greater than the individual resistances.
4. This combination decreases the current in the circuit.
Resistances in parallel:
1. If a number of resistances are connected between two common points in such a way that the potential differences across each of them is the same, then the arrangement is called resistances in parallel.
2. The voltage across each resistance is same.
3. The equivalent resistance in parallel combination is smaller than each of the individual resistances.
4. This combination increases the current in the circuit.
Question: What is the better way of connecting lights and other electrical appliances in domestic wiring? Why?
Answer.
The better way of connecting lights and other electrical appliances in domestic wiring is parallel connection because of the following advantages:
- In parallel circuit, if one appliance stops working due to some defect, then all other appliances keep working normally.
- In parallel circuit, each electrical appliance has its own switch due to which it can be turned on or off, without affecting other appliances.
- In parallel circuit, each electrical appliance gets the same voltage (220V) as that of the power supply line.
- In parallel circuit, the overall resistance of the domestic circuit is reduced due to which the current from the power supply is high.
Question: In the given circuit, A, B, C and D are four lamps connected with a battery of 60 V.
Analyse the circuit to answer the following questions.
(i) What kind of combination are the lamps arranged in (series or parallel)?
(ii) Explain with reference to your above answer, what are the advantages (any two) of this combination of lamps?
(iii) Explain with proper calculations which lamp glows the brightest?
(iv) Find out the total resistance of the circuit R
Answer. (i) The lamps are in parallel.
(ii) Advantages: If one lamp is faulty, it will not affect the working of the other lamps. They will also be using the full potential of the battery as they are connected in parallel.
(ii) The lamp with the highest power will glow the brightest.
P=VI In this case, all the bulbs have the same voltage. But lamp C has the highest current.
Hence, for Lamp C, power P = 5 × 60 Watt = 300 W. (the maximum).
(iii) The total current in the circuit = 3+4+5+3 A = 15A
Voltage = 60V
R = V/I = 60/15 = 4 Ω
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Worksheet for CBSE Science Class 10 Chapter 12 Electricity
We hope students liked the above worksheet for Chapter 12 Electricity designed as per the latest syllabus for Class 10 Science released by CBSE. Students of Class 10 should download in Pdf format and practice the questions and solutions given in the above worksheet for Class 10 Science on a daily basis. All the latest worksheets with answers have been developed for Science by referring to the most important and regularly asked topics that the students should learn and practice to get better scores in their class tests and examinations. Expert teachers of studiestoday have referred to the NCERT book for Class 10 Science to develop the Science Class 10 worksheet. After solving the questions given in the worksheet which have been developed as per the latest course books also refer to the NCERT solutions for Class 10 Science designed by our teachers. We have also provided a lot of MCQ questions for Class 10 Science in the worksheet so that you can solve questions relating to all topics given in each chapter.
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