Read and download the CBSE Class 10 Science Carbon And Its Compounds Worksheet Set E in PDF format. We have provided exhaustive and printable Class 10 Science worksheets for Chapter 4 Carbon and Its Compounds, designed by expert teachers. These resources align with the 2025-26 syllabus and examination patterns issued by NCERT, CBSE, and KVS, helping students master all important chapter topics.
Chapter-wise Worksheet for Class 10 Science Chapter 4 Carbon and Its Compounds
Students of Class 10 should use this Science practice paper to check their understanding of Chapter 4 Carbon and Its Compounds as it includes essential problems and detailed solutions. Regular self-testing with these will help you achieve higher marks in your school tests and final examinations.
Class 10 Science Chapter 4 Carbon and Its Compounds Worksheet with Answers
Question. Which of the following statements is incorrect regarding a homologous series?
(i) Compounds in a homologous series can have the same or different functional group.
(ii) Compounds in a homologous series have very less similarity in chemical properties.
(iii) Difference between the two successive compounds in a homologous series differ by a CH2 group.
(iv) Successive members in a homologous series differ in molecular mass by 14 units
(a) i and ii
(b) ii and iii
(c) iii and iv
(d) i and iv
Answer: a
Question: Name the metal that is not present in carbon family
a) Si
b) Ge
c) Sb
d) Sn
Answer: c
Question: Which of the following is unsaturated molecule?
a) C3H8
b) C2H2
c) C5H12
d) C4H10
Answer: b
Question: Which of the statement regarding homologous series is wrong?
a) only alkanes have homologous series
b) consecutive members of a homologous series differ by an atomic mass of 14u
c) A given homologous series can be expressed by a general formula
d) Homologues of a given series show gradation in physical properties.
Answer: a
Question: 3rd homologue of alkyne series is—
a) Propyne
b) Propene
c) Butyne
d) Butane
Answer: c
Question: Which among the following is an unsaturated molecule that has the molecular formula of a cycloalkane?
a) C3H6
b) C8H18
c) C5H12
d) C3H4
Answer: a
Question: Which of the following aliphatic compounds is a saturated molecule?
a) C6H12
b) C2H2
c) C5H10
d) C4H10
Answer: d
Assertion Reason Type Questions
Question. Assertion(A): Carbon compounds can form chain, branched and ring structures.
Reason (R): Carbon exhibits the property of catenation.
Answer: a
Question. Assertion (A): Covalent compounds are generally poor conductor of electricity.
Reason (R): They consist of molecules and not ions which can transfer charge.
Answer: a
Question. Assertion (A): Graphite is a good conductor of electricity.
Reason (R): It has one free valence electron.
Answer: a
Case Study Based
1. Read the following and answer any four questions from (i) to (v)
The compounds which have the same molecular formula but differ from each other in physical or chemical properties are called isomers and the phenomenon is called isomerism. When the isomerism is due to difference in the arrangement of atoms within the molecule, without any reference to space, the phenomenon is called structural isomerism. In other words. Structural isomers are compounds that have the same molecular formula but different structural formulas, i.e., they are different in the order in which different atoms are linked. In these compounds, carbon atoms can be linked together in the form of straight chains, branched chains or even rings.
Question: Which of the following sets of compounds have same molecular formula?
a) Butane and iso-butane
b) Cyclohexane and hexene
c) Propanal and propanone
d) All of these
Answer: d
Question: In order to form branching, an organic compound must have a minimum of
a) four carbon atoms
b) three carbon atoms
c) five carbon atoms
d) any number of carbon atoms
Answer: a
Question: Which of the following is an isomeric pair?
a) Ethane and propane
b) Ethane and ethene
c) Propane and butane
d) Butane and 2-methylpropane
Answer: d
Question: Among the following the one having longest chain is
a) neo-pentane
b) iso-pentane
c) 2-methylpentane
d) 2,2-dimethylbutane
Answer: c
Question: The number of isomers of pentane is
a) 2
b) 3
c) 4
d) 5
Answer: b
Short Answer Type Questions
Question. In the electron dot structure of hydrogen molecules, each individual atom is not satisfying the octet. Justify.
Answer. For hydrogen atom as there is only a K shell,it can occupy a maximum of two electrons
Question. Define homologous series of organic compounds. List its two characteristics. Write the name and formula of the first member of the series of alkenes.
Answer. The series of organic compounds having same functional group and similar chemical properties is called homologous series. Each member differs from successive member by —CH2— group. The difference in molecular weight between two successive members is 14 u. Characteristics:
(i) It has same general formula, from which, all members can be derived.
(ii) They have similar chemical properties. C2H4, CH2 = CH2, Ethene is first member of alkene series.
Question. Allotropes of carbon has same chemical properties. Give reason.
Answer. Chemical properties of an element depends on valence electrons. Allotropes have same number of valence electrons, hence same chemical properties.
Question. A hydrocarbon molecule contains 3 carbon atoms. What would be its molecular formula in case it is (i) an alkane (ii) an alkene (iii) an alkyne?
Answer. (i) General formula of alkanes = CnH2n+2; if n = 3, formula will be C3H8
(ii) General formula of alkanes = CnH2n; So, if n = 3, formula will be C3H6
(iii) General formula of alkanes = CnH2n-2. So, if n = 3, formula will be C3H4
Question. Carbon cannot make ionic compounds. Why?
Answer. Due to small size and high effective nuclear charge, carbon cannot lose electrons to form C4+ ion and as carbon with 6 protons cannot afford four more electrons in its L shell, it cannot form C4- ions, As carbon cannot form an anion or cation, it cannot make ionic bonds.
Question. Atom of an element contains 5 electrons in the valence shell. This element exists as diatomic molecules, and is a major component of air.
(a) Identify the element.
(b) Show the bond formation between two atoms of this element.
(c) What is the nature of bond formed between the 2 atoms.
Answer. (a) Nitrogen

Question. Draw the electron dot structure of ethyne and also draw its structural formula.
Answer.

Question. An element X found in nature in solid form has 4 electrons in valence shell of its atom. Its allotrope Y has properties that allows it to be used as a dry lubricant, as also as a part of pencil lead.
(a) Identify the element.
(b) What is this allotrope Y?
(c) Write any 1 other use of this allotrope other than those mentioned here.
(d) Predict the ability of this allotrope to conduct electricity. Give reason.
(e) Name two other allotropes of this element other than Y.
Answer. (a) Carbon
(b) Graphite
(c) Used for making electrodes in dry cells.
(d) It is a good conductor of electricity.
Reason: In graphite, each carbon atom is covalently bonded with three other carbon atoms. So, only 3 valence electrons are used in bond formation and the 4th valence electron is free to move. Due to the presence of these free electrons (1 per carbon atom), graphite is a good conductor of electricity.
(e) Diamond, Buckminsterfullerene.
Question. A hydrocarbon molecule has 4 carbon atoms. What would be its molecular formula in case it is (i) an alkane (ii) an alkene (iii) an alkyne?
Answer. (i) General formula of alkanes = CnH2n+2; if 2n+2 = 10, n = 4; so, formula will be C4H10
(ii) General formula of alkanes = CnH2n; So, if 2n = 8, n = 4; so, formula will be C4H8
(iii) General formula of alkanes = CnH2n-2. So, if 2n-2 = 6, n = 4; so, formula will be C4H6
Question. How many non-bonded electrons are there in?
a) Ammonia b) Methane c) Nitrogen
Answer. a) two electrons(1 pair) b) 0 c) 4(two pairs)
Question. Write the general IUPAC names of alcohol, carboxylic acid, aldehyde and ketone.
Answer.

Question. a) How can you prove that butene and propane are not in a given homologous Series?
a) Name the first four homologues of alkene series?
b) How many covalent bonds are there in propene?
Answer. a) Propane has the formula C3H8 and butene is C4H8. C3H8 is of the form CnH2n+2 and belongs to alkane homologous series and C4H8 has the general formula CnH2n+2 which shows that it is an alkene. Hence those molecules are not in the same homologous series. Mention their chemical formulab) Ethene(C2H4),Propene(C3H6), Butene(C4H8),Pentene(C5H10) 7 single covalent bond and one double bond
Question. How many saturated hydrocarbons can be made using three carbon atoms? and hydrogen atoms? Name them.
Answer. Two.
Propane and cyclopropane.
Question. Draw the electron dot structure of O2 and N2 molecules
Answer.

Question. Two elements A and B have the property C by which they can combine with more atoms of their same type. Element A is a component of the gas D that is a respiratory byproduct, while element B is the second most abundant element in the crust.
(a) Identify the elements A and B.
(b)What is the property C?
(c) Identify the gas D.
(d) Among A and B, which one shows the property C to a greater extent? Why?
Answer.
(a) A is Carbon; B is Silicon.
(b) Catenation.
(c) Carbon dioxide.
(d) A (Carbon) shows greater extent of catenation than B (Silicon)Reason: Carbon atoms are smaller than that of silicon. So, carbon- carbon bonds are much stronger than silicon- silicon bonds.
Important Practice Resources for Class 10 Science
CBSE Science Class 10 Chapter 4 Carbon and Its Compounds Worksheet
Students can use the practice questions and answers provided above for Chapter 4 Carbon and Its Compounds to prepare for their upcoming school tests. This resource is designed by expert teachers as per the latest 2026 syllabus released by CBSE for Class 10. We suggest that Class 10 students solve these questions daily for a strong foundation in Science.
Chapter 4 Carbon and Its Compounds Solutions & NCERT Alignment
Our expert teachers have referred to the latest NCERT book for Class 10 Science to create these exercises. After solving the questions you should compare your answers with our detailed solutions as they have been designed by expert teachers. You will understand the correct way to write answers for the CBSE exams. You can also see above MCQ questions for Science to cover every important topic in the chapter.
Class 10 Exam Preparation Strategy
Regular practice of this Class 10 Science study material helps you to be familiar with the most regularly asked exam topics. If you find any topic in Chapter 4 Carbon and Its Compounds difficult then you can refer to our NCERT solutions for Class 10 Science. All revision sheets and printable assignments on studiestoday.com are free and updated to help students get better scores in their school examinations.
You can download the latest chapter-wise printable worksheets for Class 10 Science Chapter Chapter 4 Carbon and Its Compounds for free from StudiesToday.com. These have been made as per the latest CBSE curriculum for this academic year.
Yes, Class 10 Science worksheets for Chapter Chapter 4 Carbon and Its Compounds focus on activity-based learning and also competency-style questions. This helps students to apply theoretical knowledge to practical scenarios.
Yes, we have provided solved worksheets for Class 10 Science Chapter Chapter 4 Carbon and Its Compounds to help students verify their answers instantly.
Yes, our Class 10 Science test sheets are mobile-friendly PDFs and can be printed by teachers for classroom.
For Chapter Chapter 4 Carbon and Its Compounds, regular practice with our worksheets will improve question-handling speed and help students understand all technical terms and diagrams.