CBSE Class 11 Chemistry The P Block Elements Notes Set A

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Revision Notes for Class 11 Chemistry Chapter 11 The p-Block Elements

Class 11 Chemistry students should refer to the following concepts and notes for Chapter 11 The p-Block Elements in Class 11. These exam notes for Class 11 Chemistry will be very useful for upcoming class tests and examinations and help you to score good marks

Chapter 11 The p-Block Elements Notes Class 11 Chemistry

 Subject: Chemistry

Class: XI

Chapter: The p-Block Elements

Top concepts

1. Elements in which the last electron enters the p-subshell of their outermost energy level are called p-block elements. The elements belonging to groups 13 to 18 constitute p-block elements.

2. General electronic configuration for elements belonging to p-block is ns2np1-6

3. General characteristics of p-block elements

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 2. Metallic and non-metallic character: Elements which show characteristics of both metals and non-metals and are called metalloids. Common metalloids in p-block elements are Si, Ge, As, Sb, Te, Po, At.

3. Differences in behaviour of first element of each group:

(a)Covalence upto four: First member of each group belongs to second period elements and have only four valence orbitals i.e., one 2s and three 2p orbitals. They do not have vacant d-orbitals in their valence shell. Therefore each member has maximum covalence of four (using one 2s and three 2p orbitals).Next members belonging to third or higher periods have vacant d-orbitals. For example elements of third period of p-block with the electronic configuration 3s2 3px has vacant 3d-orbitals lying between 3p and 4s energy levels. Therefore, they can easily expand their octets and can show covalence above four. For example:

(i) Boron forms only BF-4(coordination number of B is four) whereas aluminium forms AlF3(coordination number of Al is six). 

(ii) Carbon can form only tetrahalides (CX4, X = F, Cl, Br, I) whereas other members can form hexahalides, SF6,  SiCl2-6 etc. 

(iii) Nitrogen forms only NF3 while phosphorous forms pentahalides like PCl5, PF5 etc. 

(iv) Fluorine does not form FCl3 (F has more than octet) while chlorine forms (Cl has extended octet) 3 ClF

(b)Reactivity: Elements of second period do not have d – orbitals and are less reactive as compared to elements of third period which have d – orbitals .For example tetrahalides of carbon are not hydrolysed by water whereas tetrahalides of other elements of group 14 are readily hydrolysed (for e.g. Si)

(c)Tendency to form multiple bonds: Because of combined effect of smaller size and availability of p – orbitals, the first member of each group shows greater tendency to form pπ – pπ multiple bonds either with itself (such as C = C, C ≡ C, N ≡ N, O = O) or with other members of the second period of elements (such as C = O, C ≡ N, N = O, etc.). Heavier elements of the group do not have strong tendency to form this type of pπ- pπ bonding. The heavier elements do form π - bonding but they but they involve d – orbitals and form dπ – pπ or dπ – dπ bonding.

5. Group 13 Elements: The Boron family

1. Electronic Configurations: Elements of group 13 have the general outer electronic configuration of ns²np1

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CBSE Class 11 Chemistry Notes - The p-Block Elements 1

CBSE Class 11 Chemistry Notes - The p-Block Elements 2

 

4. Structure of diborane (B 2 H 6 ):

 

The electron diffraction studies have shown bridged structure for diborane as shown below
CBSE Class 11 Chemistry Notes - The p-Block Elements 3
 
Four hydrogen atoms (2 on the left and 2 on the right) are known as terminal hydrogens. These are different than the other two hydrogen atoms, which are known as bridged hydrogens. The two boron atoms and the four terminal H-atoms lie in the same plane while the two bridging H-atoms are in a plane perpendicular to the rest of the molecule. There are two types of bonds n the molecule:

 

(i) The four terminal hydrogens are bonded by normal covalent bonds formed by sharing of one electron each from B and H atoms

 

(ii) The bridged hydrogens are bonded by three centre electron pair bond,which involve one electron pair only (i.e. two electrons) but binds three atoms i.e. two B atoms and one H atom.

 

Boron atom undergoes sp³ hybridisation involving 2s and all the three 2p orbitals including one empty orbital. The four sp³ hybrid orbitals adopt tetrahedral arrangement. Two hybrid orbitals of each B atom overlap with 1s orbital of two H atoms. Of the hybrid orbitals left on each B atom, one contains an unpaired electron while the other is vacant. The hybrid orbital containing an unpaired electron of one B atom and the vacant hybrid orbital of the second B atom overlaps simultaneously with 1s orbitals of H atom to form B–H–B bridge bond. B–H–B bond is called three centre electron pair bond.

 

5. Group 14 Elements: Carbon Family

 

1. Electronic Configuration: Elements of group 14 have the general outerconfiguration of ns²np2
CBSE Class 11 Chemistry Notes - The p-Block Elements 4
CBSE Class 11 Chemistry Notes - The p-Block Elements 5
 
(3)Allotropes of Carbon: Allotrope forms or allotropes are the different forms of the same elements having different physical properties but similar chemical properties.
1. Crystalline form: Diamond and graphite are two crystalline forms of carbon having well defined structure
2. Amorphous form: Coal, wood charcoal, animal charcoal, lamp black, coke, etc. are many amorphous forms of carbon such as
 
(5)Structure of different allotropes of carbon:
(a) Diamond: Diamond has a network structure consisting of a very large number of carbon atoms bonded to each other. Each carbon atom is sp³ hybridized and is bonded to four other carbon atoms by single covalent bonds. There is a three – dimensional network of strong covalent bonds in diamond. This makes diamond an extremely hard crystal with very high melting point (about 3843 K).
 

CBSE Class 11 Chemistry Notes - The p-Block Elements 6

 

Since all the valence electrons of carbon are strongly held in carbon – carbon bonds, diamond is a poor conductor of electricity.

 

(b)Graphite: In graphite, each carbon atom undergoes sp² hybridisation and is covalently bonded to three other carbon atoms by single bonds. The fourth electron on each carbon atom forms Π bonds. In this way, graphite consists of hexagonal rings in two dimensions. The C–C covalent distance in rings is 141.5 pm indicating strong bonding. These arrays of ring form layers. The layers are separated by a distance of 340 pm. The large distance between these layers indicates that only weak van der Waals’ forces hold these layers together. The weak van der Waals’ forces which hold these layers together are responsible for soft nature of graphite.

 

Because of the weak Van der Waals’ forces between layers, one layer can move over the other layer and this account for the slippery nature of graphite. Therefore, graphite is used as lubricant. The electrons forming  Π bonds in the rings of graphite are delocalized and are relatively free to move under the influence of electric field. Therefore, graphite is a good conductor of electricity.


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