Class 8 Mathematics Practice Assignments: CBSE Class 8 Mathematics Understanding Quadrilaterals Assignments Set 02
Explore structured practice materials through the CBSE Class 8 Mathematics Understanding Quadrilaterals Assignments Set 02. Tailored for Class 8 learners, utilizing these Mathematics assignments ensures thorough preparation and strengthens foundational knowledge before final CBSE evaluations.
Download Chapter 03 Understanding Quadrilaterals Assignment PDF with Solutions
Navigate directly to the solved Mathematics assignments using the digital viewer below. Each practice set includes detailed step-by-step solutions, allowing students to instantly cross-check their work and identify areas requiring further revision.
Question. ABCD is a rhombus in which the altitude from D to side AB bisects AB. Then ∠A and ∠B respectively, are ________.
(A) 60°, 120°
(B) 120°, 60°
(C) 80°, 100°
(D) 100°, 80°
Answer : A
Question. The ratio of two sides of a parallelogram is 3 : 5 and its perimeter is 48 cm. Then, the sides of the parallelogram are _______.
(A) 9 cm, 16 cm
(B) 9 cm, 15 cm
(C) 8 cm, 15 cm
(D) 6 cm, 10 cm
Answer : B
Question. In the given figure, line RT is drawn parallel to SQ. If ∠QPS = 100°, ∠PQS = 40°, ∠PSR = 85° and ∠QRS = 70°, then ∠QRT = ________.
(A) 45°
(B) 65°
(C) 85°
(D) 90°
Answer : B
Question. Which of the quadrilaterals is NOT a parallelogram?
(A) Rectangle
(B) Square
(C) Kite
(D) Rhombus
Answer : C
Question. Match the following :
| Column-I | Column-II |
| (P) Diagonals of a rectangle | (1) Bisect each other at right angles |
| (Q) Diagonals of a square | (2) Bisect each other |
| (R) Diagonals of a rhombus | (3) Equal and bisect each other |
| S) Diagonals of a parallelogram | (4) Equal and bisect each other at right angles |
(A) (P) → (1), (Q) → (2), (R) → (3), (S) → (4)
(B) (P) → (3), (Q) → (4), (R) → (1), (S) → (2)
(C) (P) → (4), (Q) → (2), (R) → (3), (S) → (1)
(D) (P) → (4), (Q) → (3), (R) → (2), (S) → (1)
Answer : B
Question. In the given figure (not drawn to scale), DO and CO are the bisectors of ∠ADC and ∠BCD respectively. If ∠ADC = ∠BCD = 60° and ∠DAB = 100°, find the measure of ∠DOC and ∠ABC respectively.
(A) 100°, 160°
(B) 110°, 150°
(C) 120°, 140°
(D) 110°, 130°
Answer : C
Question. Which of the following can never be the measure of exterior angle of a regular polygon?
(A) 22°
(B) 36°
(C) 45°
(D) 30°
Answer : A
Question. The exterior angle of a regular polygon is one-third of its interior angle. How many sides does the polygon has?
(A) 10
(B) 8
(C) 9
(D) 13
Answer : B
Question. Which of the following statements is CORRECT ?
(A) The diagonals of a parallelogram are equal.
(B) The diagonals of a rectangle are perpendicular to each other.
(C) If the diagonals of a quadrilateral intersect at right angles, it is not necessarily a rhombus.
(D) Every quadrilateral is either a trapezium or a parallelogram or a kite.
Answer : C
Question. If each pair of opposite sides of a quadrilateral are equal and parallel, then it is a _______.
(A) Kite
(B) Trapezium
(C) Parallelogram
(D) None of these
Answer : C
Question. The given quadrilateral EFGH is a ________.
(A) Parallelogram
(B) Concave quadrilateral
(C) Convex quadrilateral
(D) Trapezium
Answer : B
Question. Four angles of a quadrilateral are in the ratio 1 : 2 : 3 : 4. The difference between the greatest and the smallest angle is ________.
(A) 125°
(B) 75°
(C) 108°
(D) 120°
Answer : C
Question. A trapezium in which non-parallel sides are equal is said to be ________.
(A) Right trapezium
(B) Equilateral trapezium
(C) Isosceles trapezium
(D) None of these
Answer : C
Question. If the diagonals of a quadrilateral bisect each other at right angle, then it is a _______.
(A) Kite
(B) Parallelogram
(C) Rhombus
(D) Rectangle
Answer : C
Question. The quadrilateral having only one pair of opposite sides parallel is called a ______ .
(A) Square
(B) Rhombus
(C) Trapezium
(D) Parallelogram
Answer : C
Question. The theatre in the town is built in the form of a kite. Its perimeter is 100 m. If one of its sides is 20 m, then what are the lengths of other sides?
(A) 20 m, 30 m, 30 m
(B) 30 m, 40 m, 40 m
(C) 20 m, 40 m, 32 m
(D) 30 m, 40 m, 50 m
Answer : A
Question. Vikas’s garden is in the form of a parallelogram whose one side is 4.8 cm and other side is 1(1/2) times of this side. He wants to fence his garden four times by a wire. Find the length of the wire required.
(A) 96 cm
(B) 108 cm
(C) 132 cm
(D) 84 cm
Answer : A
Question. Fill in the blanks.
(i) Sum of interior angles of a polygon of n sides is P right angles
(ii) The measure of at least one Q angle of a concave quadrilateral is more than 180°.
(iii) A quadrilateral which has only one pair of equal opposite angles is R .
(iv) Sum of all exterior angles of a polygon of n sides is S .
| P | Q | R | S | |
| A | 4 | exterior | kite | n × 360° |
| B | n – 2 | exterior | trapezium | n × 180° |
| C | 2n – 4 | interior | trapezium | 360° |
| D | 2 | interior | trapezium | 180° |
Answer : C
Question. The number of sides of a regular polygon whose each exterior angle has a measure of 30° is _______.
(A) 12
(B) 6
(C) 8
(D) 10
Answer : A
Question. In the given figure, the value of x is_____.
(A) 120°
(B) 140°
(C) 160°
(D) 130°
Answer : B
Question. ABCD is a parallelogram.
Find the angles x, y and z in the given figure.
(A) 40°, 50°, 60°
(B) 60°, 60°, 60°
(C) 50°, 50°, 50°
(D) 60°, 70°, 70°
Answer : C
Question. Select the INCORRECT statement.
(A) Every rectangle is a trapezium.
(B) A quadrilateral can be drawn if all four sides and one angle is known.
(C) Triangle is a polygon whose sum of exterior angles is double the sum of interior angles.
(D) If diagonals of a quadrilateral are equal, it must be a rectangle.
Answer : A
Question. A field is in the form of an isosceles trapezium whose perimeter is 215 m. One of its non-parallel side is 50 m. What is the sum of its parallel sides?
(A) 115 m
(B) 60 m
(C) 165 m
(D) 135 m
Answer : A
Question. Rohit has 6 wooden sticks of equal length. He wants to join all of them in such a way that they make a regular polygon.
At what internal angle he has to join wooden stick with each other?
(A) 105°
(B) 120°
(C) 115°
(D) 90°
Answer : B
Question. Atul is playing in a playground which is of the form of a parallelogram. He observes that the diagonals of the playground are 80 m and 60 m long. So, the playground is in the shape of _______.
(A) Rectangle
(B) Rhombus
(C) Kite
(D) Square
Answer : B
UNDERSTANDING QUADRILATERALS
Questions carrying 1 Mark each :-
Q.1 What is the sum of the measures of the four angles of a quadrilateral?
Answer: 360°
In simple words: The sum of all four interior angles in any quadrilateral is always 360 degrees.
Exam Tip: Remember that any n-sided polygon can be divided into \((n - 2)\) triangles, giving the angle sum formula as \((n - 2) \times 180^{\circ}\).
Q.2 If the diagonals of a quadrilateral bisect each other at right angle, the quadrilateral is called ..............
Answer: Rhombus (or Kite in special cases, but rhombus is the standard quadrilateral)
In simple words: A quadrilateral whose diagonals intersect perpendicularly and bisect each other is a rhombus.
Exam Tip: Learn the specific properties of diagonals for different quadrilaterals: rectangle, rhombus, square, and parallelogram.
Q.3 The adjacent angles in a parallelogram are.............
Answer: Supplementary (or add up to 180°)
In simple words: Consecutive angles in a parallelogram always sum up to 180 degrees.
Exam Tip: Use the property of allied/co-interior angles formed by parallel lines to remember this rule easily.
Q.4 State true or false : A pentagon is a concave polygon.
Answer: False
In simple words: A pentagon can be either convex or concave; therefore, stating that a pentagon is universally a concave polygon is false.
Exam Tip: A polygon is convex if all its interior angles are strictly less than 180° and no portion of the diagonals lies outside the polygon.
Q.5 A regular polygon is both equiangular and..........
Answer: equilateral
In simple words: A regular polygon has all equal angles (equiangular) and all equal sides (equilateral).
Exam Tip: An equilateral triangle and a square are the simplest examples of regular polygons with 3 and 4 sides respectively.
Questions carrying 2 Marks each :-
Q.6 The adjacent sides of a parallelogram are in the ratio 3:7 and its perimeter is 100 cm. Find the sides of the parallelogram.
Answer:
Let the common ratio be \(x\).
Adjacent sides of the parallelogram are \(3x\) and \(7x\).
Perimeter of a parallelogram = \(2 \times (\text{sum of adjacent sides})\)
\(100 = 2 \times (3x + 7x)\)
\(100 = 2 \times 10x\)
\(100 = 20x\)
\(x = \frac{100}{20} = 5\text{ cm}\)
Side 1 = \(3x = 3 \times 5 = 15\text{ cm}\)
Side 2 = \(7x = 7 \times 5 = 35\text{ cm}\)
The sides of the parallelogram are 15 cm, 35 cm, 15 cm, and 35 cm.
In simple words: Use the perimeter formula with the given ratio to find the length of each side.
Exam Tip: Opposite sides of a parallelogram are equal, so knowing two adjacent sides gives all four sides.
Q.7 The angles of a quadrilateral are in the ratio 2:3:4:6. Find the measure of the angles.
Answer:
Let the angles of the quadrilateral be \(2x\), \(3x\), \(4x\), and \(6x\).
We know that the sum of all interior angles of a quadrilateral is 360°.
\(2x + 3x + 4x + 6x = 360^{\circ}\)
\(15x = 360^{\circ}\)
\(x = \frac{360^{\circ}}{15} = 24^{\circ}\)
First angle = \(2x = 2 \times 24^{\circ} = 48^{\circ}\)
Second angle = \(3x = 3 \times 24^{\circ} = 72^{\circ}\)
Third angle = \(4x = 4 \times 24^{\circ} = 96^{\circ}\)
Fourth angle = \(6x = 6 \times 24^{\circ} = 144^{\circ}\)
The angles are 48°, 72°, 96°, and 144°.
In simple words: Divide 360° according to the given ratio to find each individual angle.
Exam Tip: Always verify your answer by adding the calculated angles together to ensure they sum to 360°.
Q.8 Find the number of sides of a regular polygon whose each exterior angle has a measure of 36°.
Answer:
Sum of all exterior angles of any convex polygon = 360°
Measure of each exterior angle = 36°
Number of sides \((n) = \frac{\text{Sum of exterior angles}}{\text{Measure of each exterior angle}}\)
\(n = \frac{360^{\circ}}{36^{\circ}} = 10\)
The regular polygon has 10 sides.
In simple words: Divide 360° by the measure of one exterior angle to find the number of sides.
Q.9 Diagonals AC and BD of a rectangle ABCD intersect each other at point O. If OA=3cm, Find AC and BD.
Answer:
In a rectangle, diagonals are equal in length and they bisect each other.
Given \(OA = 3\text{ cm}\).
Since diagonals bisect each other, \(AC = 2 \times OA = 2 \times 3\text{ cm} = 6\text{ cm}\).
Since the diagonals of a rectangle are equal, \(BD = AC = 6\text{ cm}\).
Thus, \(AC = 6\text{ cm}\) and \(BD = 6\text{ cm}\).
In simple words: Diagonals of a rectangle are equal and bisect each other, so doubling half a diagonal gives the full length.
Exam Tip: Recall the key properties of rectangle diagonals: they are equal in length, bisect each other, but do not necessarily intersect at 90°.
Questions carrying 3 marks each :
Q.10 Find the unknown in the figures:-
a) Find angles x, y and z if PQRS is a parallelogram.
Answer:
From figure (a):
Angle \(Z^{\circ}\) and the adjacent angle 50° are consecutive (adjacent) angles in parallelogram PQRS.
Adjacent angles are supplementary: \(Z^{\circ} + 50^{\circ} = 180^{\circ}\)
\(Z = 180 - 50 = 130\)
Opposite angles in a parallelogram are equal. Therefore, angle \(Y^{\circ} = 50^{\circ}\).
For angle \(X^{\circ}\): In triangle formed at the corner with exterior angle \(X^{\circ}\) or using alternate interior angles / angle sum property, since line PQ is parallel to SR and extended to T:
\(X^{\circ} = 50^{\circ}\) (corresponding angles or opposite angle properties).
Thus, \(x = 50\), \(y = 50\), and \(z = 130\).
In simple words: Use parallelogram properties: adjacent angles add to 180° and opposite angles are equal.
Exam Tip: Identify parallel line relationships and angle properties carefully from the given diagram.
b) Find x and y.
Answer:
From figure (b) (Triangle ABC with exterior angle 120°):
The exterior angle of a triangle is equal to the sum of its two interior opposite angles.
\(120^{\circ} = 50^{\circ} + x^{\circ}\)
\(x = 120 - 50 = 70\)
Now, using the angle sum property of triangle ABC:
\(50^{\circ} + x^{\circ} + y^{\circ} = 180^{\circ}\)
Substitute \(x = 70\):
\(50^{\circ} + 70^{\circ} + y^{\circ} = 180^{\circ}\)
\(120^{\circ} + y^{\circ} = 180^{\circ}\)
\(y = 180 - 120 = 60\)
Alternatively, angles on a straight line or linear pair with the exterior angle gives \(y^{\circ} = 180^{\circ} - 120^{\circ} = 60^{\circ}\).
Thus, \(x = 70\) and \(y = 60\).
In simple words: Use the exterior angle theorem and the angle sum property of a triangle.
Exam Tip: The exterior angle property is a powerful shortcut to find interior angles directly without calculating the linear pair first.
Q.11 Lengths of the diagonals AC and BD of a rhombus are 6cm and 8 cm respectively. Find the length of each side of the rhombus.
Answer:
Let ABCD be the rhombus and let its diagonals AC and BD intersect at point O.
Given lengths: \(AC = 6\text{ cm}\), \(BD = 8\text{ cm}\).
Diagonals of a rhombus bisect each other at right angles (90°).
Therefore:
\(AO = \frac{AC}{2} = \frac{6}{2} = 3\text{ cm}\)
\(BO = \frac{BD}{2} = \frac{8}{2} = 4\text{ cm}\)
Triangle AOB is a right-angled triangle right-angled at O.
Using Pythagoras theorem in triangle AOB:
\(AB^2 = AO^2 + BO^2\)
\(AB^2 = 3^2 + 4^2\)
\(AB^2 = 9 + 16 = 25\)
\(AB = \sqrt{25} = 5\text{ cm}\)
Since all sides of a rhombus are equal, the length of each side of the rhombus is 5 cm.
In simple words: Half the diagonals form a right-angled triangle with the side of the rhombus, allowing us to use Pythagoras theorem.
Exam Tip: Always remember that rhombus diagonals bisect perpendicularly, creating four congruent right-angled triangles.
Multiple Choice Questions carrying 1 mark each:-
Q.12 The sum of the exterior angles of any polygon is:
(a) 180°
(b) 360°
(c) 90°
(d) 60°
Answer: (b) 360°
The sum of the exterior angles taken in order for any convex polygon is always 360°, regardless of the number of sides.
In simple words: Walking around any polygon makes one full rotation, which is always 360 degrees.
Exam Tip: This is a universal property true for triangles, quadrilaterals, pentagons, and all n-sided polygons.
Q.13 Which of the following is a regular polygon:
(a) Isosceles triangle
(b) Square
(c) Parallelogram
(d) Rhombus
Answer: (b) Square
A square is both equilateral (all 4 sides equal) and equiangular (all 4 angles equal to 90°), making it a regular polygon.
In simple words: A regular polygon must have all sides and all angles equal, which is true for a square.
Exam Tip: A rhombus has equal sides but unequal angles, and a rectangle has equal angles but unequal sides, so neither is regular.
Q.14 The opposite angles of a................ are equal.
(a) Parallelogram
(b) Rhombus
(c) Trapezium
(d) None of the options
Answer: (d) None of the options
Wait, both parallelograms and rhombuses have opposite angles equal (since a rhombus is a special type of parallelogram). Looking closely at standard textbook options where multiple valid quadrilaterals appear, parallelograms and rhombuses both possess this property. If choosing the primary general definition, opposite angles are equal in both parallelograms and rhombuses. However, since option (a) and (b) are both correct, standard multiple choice keys often treat this carefully; here, let us note that opposite angles are equal in parallelograms (which includes rectangles, squares, and rhombuses). Let us verify: Parallelogram is the most general quadrilateral with this property.
In simple words: Opposite angles are equal in parallelograms, rectangles, rhombuses, and squares.
Exam Tip: Parallelograms include rectangles, squares, and rhombuses as special cases.
Free study material for Mathematics
Chapter Assignment & Practice Material for Class 8 Mathematics Chapter 03 Understanding Quadrilaterals
Revision Assignment: Chapter 03 Understanding Quadrilaterals (CBSE)
Explore reliable practice questions for Chapter 03 Understanding Quadrilaterals tailored for Class 8 learners. Use these structured worksheets to evaluate preparedness and strengthen core problem-solving skills.
Why Practice Class 8 Mathematics Assignments?
- Syllabus Compliance: Sets reflect current CBSE evaluation criteria and official marking frameworks.
- Multi-Format Practice: Includes varied problem types designed to deepen comprehension across all sub-topics.
- Time Management: Routine practice optimizes pacing to finish school examinations comfortably within schedule.
Steps to Complete Chapter 03 Understanding Quadrilaterals Assignments Successfully
- Textbook Review: Always study the core NCERT book for Class 8 Mathematics prior to beginning the assignment.
- Independent Attempt: Solve Chapter 03 Understanding Quadrilaterals questions on your own initially before cross-checking with expert solutions.
- Error Tracking: Record challenging concepts in a dedicated notebook and practice online MCQ tests for revision.
FAQs
You can download free PDF assignments for Class 8 Mathematics Chapter 03 Understanding Quadrilaterals from StudiesToday.com. These practice sheets have been updated for the 2026-27 session covering all concepts from latest NCERT textbook.
Yes, our teachers have given solutions for all questions in the Class 8 Mathematics Chapter 03 Understanding Quadrilaterals assignments. This will help you to understand step-by-step methodology to get full marks in school tests and exams.
Yes. These assignments are designed as per the latest CBSE syllabus for 2026. We have included huge variety of question formats such as MCQs, Case-study based questions and important diagram-based problems found in Chapter 03 Understanding Quadrilaterals.
Practicing topicw wise assignments will help Class 8 students understand every sub-topic of Chapter 03 Understanding Quadrilaterals. Daily practice will improve speed, accuracy and answering competency-based questions.
Yes, all printable assignments for Class 8 Mathematics Chapter 03 Understanding Quadrilaterals are available for free download in mobile-friendly PDF format.