Access the latest CBSE Class 12 Physics Atoms Worksheet Set A. We have provided free printable Class 12 Physics worksheets in PDF format, specifically designed for Chapter 12 Atoms. These practice sets are prepared by expert teachers following the 2025-26 syllabus and exam patterns issued by CBSE, NCERT, and KVS.
Chapter 12 Atoms Physics Practice Worksheet for Class 12
Students should use these Class 12 Physics chapter-wise worksheets for daily practice to improve their conceptual understanding. This detailed test papers include important questions and solutions for Chapter 12 Atoms, to help you prepare for school tests and final examination. Regular practice of these Class 12 Physics questions will help improve your problem-solving speed and exam accuracy for the 2026 session.
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CBSE Class 12 Physics Atoms Worksheet Set A
Question. The ionization energy of Li++ is equal to
(a) 9hcR
(b) 6hcR
(c) 2hcR
(d) hcR.
Answer: A
Question. The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent
(a) first member of Lyman series, third spectral line of Balmer series and the second spectral line of Paschen series
(b) ionization potential of hydrogen, second spectral line of Balmer series, third spectral line of Paschen series
(c) series limit of Lyman series, third spectral line of Balmer series and second spectral line of Paschen series
(d) series limit of Lyman series, second spectral line of Balmer series and third spectral line of Paschen series
Answer: C
Question. Taking Rydberg’s constant RH = 1.097 × 107m, first and second wavelength of Balmer series in hydrogen spectrum is
(a) 2000 Å, 3000 Å
(b) 1575 Å, 2960 Å
(c) 6529 Å, 4280 Å
(d) 6552 Å, 4863 Å
Answer: D
Question. Hydrogen atom in ground state is excited by a monochromatic radiation of λ = 975 Å. Number of spectral lines in the resulting spectrum emitted will be
(a) 3
(b) 2
(c) 6
(d) 10
Answer: C
Question. The ionisation potential of H-atom is 13.6 V. When it is excited from ground state by monochromatic radiations of 970.6 Å, the number of emission lines will be (according to Bohr’s theory)
(a) 10
(b) 8
(c) 6
(d) 4
Answer: C
Question. Rutherford’s a-particle experiment showed that the atoms have
(a) Proton
(b) Nucleus
(c) Neutron
(d) Electrons
Answer: B
Question. Two H atoms in the ground state collide inelastically. The maximum amount by which their combined kinetic energy is reduced, is
(a) 10.20 eV
(b) 20.40 eV
(c) 13.6 eV
(d) 27.2 eV
Answer: A
Question. The ratio of the longest to shortest wavelengths in Brackett series of hydrogen spectra is
(a) 25/9
(b) 17/6
(c) 9/5
(d) 4/5
Answer: A
Question. In Rutherford scattering experiment, the number of α-particles scattered at 60° is 5 × 106. The number of α-particles scattered at 120° will be
(a) 15 × 106
(b) 3/5 x 106
(c) 5/9 x 106
(d) None of these
Answer: C
Question. The energy of He+ in the ground state is – 54.4 eV, then the energy of Li++ in the first excited state will be
(a) – 30.6 eV
(b) 27.2 eV
(c) – 13.6 eV
(d) – 27.2 eV
Answer: A
Question. The wavelength of radiation is λ0 when an electron jumps from third to second orbit of hydrogen atom. For the electron to jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be
(a) 16/25 λ0
(b) 20/27 λ0
(c) 27/20 λ0
(d) 25/16 λ0
Answer: B
Question. O2 molecule consists of two oxygen atoms. In the molecule, nuclear force between the nuclei of the two atoms
(a) is not important because nuclear forces are short – ranged
(b) is as important as electrostatic force for binding the two atoms
(c) cancels the repulsive electrostatic force between the nuclei
(d) is not important because oxygen nucleus have equal number of neutrons and protons
Answer: A
Question. In the hydrogen atom, an electron makes a transition from n = 2 to n = 1. The magnetic field produced by the circulating electron at the nucleus
(a) decreases 16 times
(b) increases 4 times
(c) decreases 4 times
(d) increases 32 times
Answer: D
Question. One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is n = 12 → n = x. Find the value of x.
(a) 8
(b) 6
(c) 7
(c) 5
Answer: B
Question. The wavelength Kα of X-rays for two metals ‘A’ and ‘B’ are 4/1875R and 1/675R respectively, where ‘R’ is Rydberg constant. Find the number of elements lying between A and B according to their atomic numbers
(a) 3
(b) 1
(c) 4
(d) 5
Answer: C
Question. In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is
(a) 9/4
(b) 27/5
(c) 5/27
(d) 4/9
Answer: D
Question. A hydrogen atom emits a photon corresponding to an electron transition from n = 5 to n = 1. The recoil speed of hydrogen atom is almost
(a) 10–4 ms–1
(b) 2 × 10–2 ms–1
(c) 4 ms–1
(d) 8 × 102 ms–1
Answer: C
Question. A hydrogen atom in its ground state absorbs 10.2 eV of energy. The orbital angular momentum is increased by
(a) 1.05 × 10–34 J-s
(b) 3.16 × 10–34 J-s
(c) 2.11 × 10–34 J-s
(d) 4.22 × 10–34 J-s
Answer: A
Question. Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. The spectral lines emitted by hydrogen atom according to Bohr’s theory will be
(a) one
(b) two
(c) three
(d) four
Answer: C
Question. The energy of electron in the nth orbit of hydrogen atom is expressed as En = -13.6/n2(eV) . The shortest and longest wavelength of Lyman series will be
(a) 910 Å, 1213 Å
(b) 5463 Å, 7858 Å
(c) 1315 Å, 1530 Å
(d) None of these
Answer: A
Question. The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He+ ion in the first excited state will be
(a) –13.6 eV
(b) – 27.2 eV
(c) – 54.4 eV
(d) – 6.8 eV
Answer: A
Question. A hydrogen atom is in ground state. Then to get six lines in emission spectrum, wavelength of incident radiation should be
(a) 800 Å
(b) 825 Å
(c) 975 Å
(d) 1025 Å
Answer: C
Question. Electrons in a certain energy level n = n1, can emit 3 spectral lines. When they are in another energy level, n = n2. They can emit 6 spectral lines. The orbital speed of the electrons in the two orbits are in the ratio of
(a) 4 : 3
(b) 3 : 4
(c) 2 : 1
(d) 1 : 2
Answer: A
Question. Which of the following statements are true regarding Bohr’s model of hydrogen atom?
(I) Orbiting speed of electron decreases as it shifts to discrete orbits away from the nucleus
(II) Radii of allowed orbits of electron are proportional to the principal quantum number
(III) Frequency with which electrons orbit around the nucleus in discrete orbits is inversely proportional to the cube of principal quantum number
(IV) Binding force with which the electron is bound to the nucleus increases as it shifts to outer orbits Select correct answer using the codes given below.
Codes :
(a) I and II
(b) II and IV
(c) I, II and III
(d) II, III and IV
Answer: A
Question. Consider the spectral line resulting from the transition n = 2→n = 1 in the atoms and ions given below. The shortest wavelength is produced by
(a) hydrogen atom
(b) deuterium atom
(c) singly ionized Helium
(d) doubly ionised Lithium
Answer: D
Question. If the atom 100Fm257 follows the Bohr model and the radius of 100Fm257 is n times the Bohr radius, then find n.
(a) 100
(b) 200
(c) 4
(d) 1/4
Answer: D
Question. Which of the following transitions in hydrogen atoms emit photons of highest frequency?
(a) n = 1 to n = 2
(b) n = 2 to n = 6
(c) n = 6 to n = 2
(d) n = 2 to n = 1
Answer: D
Question. For the ground state, the electron in the H – atom has an angular momentum = h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true,
(a) because Bohr model gives in correct values of angular momentum
(b) because only one of these would have a minimum energy
(c) angular momentum must be in the direction of spin of electron
(d) because electrons go around only in horizontal orbits
Answer: A
Question. When an a-particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on m as :
(a) 1/m
(b) 1/√m
(c) 1/m2
(d) m
Answer: A
Question. Doubly ionised helium atom and hydrogen ions are accelerated, from rest, through the same potential difference.
The ratio of final velocities of helium and hydrogen is
(a) 1 : √2
(b) √2 : 1
(c) 1 : 2
(d) 2 : 1
Answer: A
Question. An alpha nucleus of energy 1/2 mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
(a) 1/Ze
(b) v2
(c) 1/m
(d) 1/v4
Answer: C
Question. Taking the Bohr radius as a0 = 53 pm, the radius of Li++ ion in its ground state, on the basis of Bohr's model, will be about
(a) 53 pm
(b) 27 pm
(c) 18 pm
(d) 13 pm
Answer: C
Question. Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 × 109 constant, Z = 2 and h (Plank's Constant) = 6.6 × 10–34 J s]
(a) 1.46 × 106 m/s
(b) 0.73 × 106 m/s
(c) 3.0 × 108 m/s
(d) 2.92 × 106 m/s
Answer: A
Question. Two particles of masses m1, m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy e. If final velocities of particles be v1 and v2 then we must have
Answer: B
Question. The binding energy of a H – atom, considering an electron moving around a fixed nuclei (proton), is
B = -me4/8n2ε02h2(m = electron mass)
If one decides to work in a frame of reference where the electron is at rest, the proton would be moving around it.
By similar arguments, the binding energy would be
B = -me4/8n2ε02h2(m = proton mass)
This last expression is not correct, because
(a) n would not be integral
(b) Bohr – quantisation applies only two electron
(c) the frame in which the electron is at rest is not inertial
(d) the motion of the proton would not be in circular orbits, even approximately.
Answer: C
Question. If in hydrogen atom, radius of nth Bohr orbit is rn, frequency of revolution of electron in nth orbit is fn, choose the correct option.
Answer: D
Directions for : Each question contains STATEMENT-1 and STATEMENT-2. Choose the correct answer from the following.
(a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement -1
(b) Statement-1 is True, Statement -2 is True; Statement-2 is NOT a correct explanation for Statement - 1
(c) Statement-1 is True, Statement- 2 is False
(d) Statement-1 is False, Statement -2 is True
Question. Statement-1 : Bohr had to postulate that the electrons in stationary orbits around the nucleus do not radiate.
Statement-2 : According to classical physics all moving electrons radiate.
Answer: B
Question. Statement 1 : In Lyman series, the ratio of minimum and maximum wavelength is 3/4 .
Statement 2 : Lyman series constitute spectral lines corresponding to transition from higher energy to ground state of hydrogen atom.
Answer: B
Question. Statement-1 : Balmer series lies in the visible region of electromagnetic spectrum.
Statement-2 : 1/λ = R[1/22 - 1/n2] , where n = 3, 4, 5.
Answer: A
Question. Statement-1 : The force of repulsion between atomic nucleus and α-particle varies with distance according to inverse square law.
Statement-2 : Rutherford did a-particle scattering experiment.
Answer: B
Question. In Geiger-Marsden experiment, detection of scattered a-particles at a particular angle is done by
(a) counting flashes produced by a-particles on a ZnS coated screen
(b) counting spots produced on a photographic film
(c) using a galvanometer detector
(d) using a Geiger-counter
Answer : A
Question. Atoms consists of a positively charged nucleus is a consequence from the following observation of Geiger-Marsden experiment that
(a) most of a-particles do not pass straight through the gold foil
(b) very few a-particles scattered through an angle more than 90°
(c) very large number of a-particles are deflected by large angles
(d) None of the above
Answer : B
Question. If the orbital radius of the electron in a hydrogen atom is 4.7×10-11 m. Compute the kinetic energy of the electron
in hydrogen atom.
(a) 15.3 eV
(b) - 15.3 eV
(c) 13.6 eV
(d) -13.6 eV
Answer : A
Question. The orbital radius of an electron in H-atom is increased by factor of 2, then the total energy of the electron will be
(a) decreased by 4
(b) increased by 2
(c) decreased by 2
(d) remain same
Answer : C
Question. An emission line spectrum is observed when
(a) a gas is excited by heating or by passing a electric discharge through it
(b) a gas is excited by applying pressure
(c) a gas under low pressure condition is excited by heating or by passing a electric discharge through it
(d) a gas under high pressure condition is excited by heating or by passing a electric discharge through it
Answer : C
Question. An electron of a hydrogen like atom is in excited state. If total energy of the electron is - 4.6 eV, then de-Broglie
wavelength of the electron is
(a) 6.27 nm
(b) 2.48 mm
(c) 0.57 nm
(d) 8 nm
Answer : C
Question. When white light is passed through an unexcited gas, then transmitted light consists of
(a) few bright lines in dark background
(b) few dark lines in bright background
(c) alternate dark and bright lines
(d) alternate dark and bright bands
Answer : B
Question. The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is
(a) 2
(b) 1
(c) 4
(d) 0.5
Answer : C
Question. Rutherford’s atomic model could account for
I. concept of stationary orbits.
II. the positively charged central core of an atom.
III. origin of spectra.
IV. stability of atoms.
Choose the correct option from the codes given below.
(a) Only I
(b) Only II
(c) I, III and IV
(d) I, II, III and IV
Answer : B
Question. It is found experimentally that 13.6 eV energy is required to separate a hydrogen atom into a proton and an electron.
Then, the velocity of the electron in a hydrogen atom is
(a) 1015 m/s
(b) 2.2×106 m/s
(c) 4.2×108 m/s
(d) 3×108 m/s
Answer : B
Question. The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom to the velocity of light in air is
(a) e2/2πhc
(b) 2eπ/hc
(c) e3/2πhck
(d) 2πe2k/hc
Answer : D
Question. The speed of an electron in ground state energy level is 2.6×106ms-1, then its speed in third excited state will be
(a) 5.6×106ms-1
(b) 6.5×105 ms-1
(c) 5.5×105 ms-1
(d) 4.3×106 ms-1
Answer : B
Question. The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is
(a) 2 : - 1
(b) 1 : - 1
(c) 1 : 1
(d) 1 : - 2
Answer : B
Question. The total energy of an electron in an atom in an orbit is -3.4 eV. Its kinetic and potential energies are, respectively
(a) -3.4 eV, -6.8 eV
(b) 3.4 eV, -6.8 eV
(c) 3.4 eV, 3.4 eV
(d) - 3.4 eV, -3.4 eV
Answer : B
Question. If radius of first Bohr orbit is r,then the radius of second Bohr’s orbit will be
(a) 2r
(b) 8 r
(c) 4r
(d) 2 2r
Answer : C
Question. A 12.75 eV electron beam is used to bombard gaseous hydrogen at room temperature, then wavelengths emitted
are in
(a) either Paschen, Lyman or Balmer series
(b) either Brackett, Pfund or Lyman series
(c) either Paschen, Brackett or Balmer series
(d) either Lyman, Balmer or Brackett series
Answer : A
Question. The Bohr model for the spectra of a H-atom
(a) will not be applicable to hydrogen in the molecular form
(b) is applicable for multi-electron atom
(c) explain continuous as well as discrete spectral lines
(d) Both (a) and (b)
Answer : A
Very Short Answer
Q1) What is the full form of LASER?
Q2) Who is credited for the discovery of the nucleus?
Q3) Who discovered empirical formula?
Q4) What is impact parameter?
Q5) What is nucleus?
Short Answer
Q6) Define about electron orbits?
Q7) What are atoms?
Q8) What do you understand by Franck-Hertz experiment?
Q9) How atomic hydrogen emits a line spectrum?
Q10) What do you understand by the alpha-particle trajectory?
Long Answer
Q11) State the difference between kinetic energy and potential energy?
Q12) Write short note on energy levels?
Q13) What are the limitations of the Bohr’s model?
Q14) Explain Rutherford’s Nuclear Model of Atom?
Q15) Explain the Bohr model of the hydrogen atom?
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Important Practice Resources for Class 12 Physics
Chapter 12 Atoms CBSE Class 12 Physics Worksheet
Students can use the Chapter 12 Atoms practice sheet provided above to prepare for their upcoming school tests. This solved questions and answers follow the latest CBSE syllabus for Class 12 Physics. You can easily download the PDF format and solve these questions every day to improve your marks. Our expert teachers have made these from the most important topics that are always asked in your exams to help you get more marks in exams.
NCERT Based Questions and Solutions for Chapter 12 Atoms
Our expert team has used the official NCERT book for Class 12 Physics to create this practice material for students. After solving the questions our teachers have also suggested to study the NCERT solutions which will help you to understand the best way to solve problems in Physics. You can get all this study material for free on studiestoday.com.
Extra Practice for Physics
To get the best results in Class 12, students should try the Physics MCQ Test for this chapter. We have also provided printable assignments for Class 12 Physics on our website. Regular practice will help you feel more confident and get higher marks in CBSE examinations.
You can download the teacher-verified PDF for CBSE Class 12 Physics Atoms Worksheet Set A from StudiesToday.com. These practice sheets for Class 12 Physics are designed as per the latest CBSE academic session.
Yes, our CBSE Class 12 Physics Atoms Worksheet Set A includes a variety of questions like Case-based studies, Assertion-Reasoning, and MCQs as per the 50% competency-based weightage in the latest curriculum for Class 12.
Yes, we have provided detailed solutions for CBSE Class 12 Physics Atoms Worksheet Set A to help Class 12 and follow the official CBSE marking scheme.
Daily practice with these Physics worksheets helps in identifying understanding gaps. It also improves question solving speed and ensures that Class 12 students get more marks in CBSE exams.
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