Read and download free pdf of CBSE Class 12 Physics Electromagnetic Induction And Alternating Current Worksheet Set A. Download printable Physics Class 12 Worksheets in pdf format, CBSE Class 12 Physics Chapter 6 Electromagnetic Induction Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Physics Class 12 Assignments and practice them daily to get better marks in tests and exams for Class 12. Free chapter wise worksheets with answers have been designed by Class 12 teachers as per latest examination pattern
Chapter 6 Electromagnetic Induction Physics Worksheet for Class 12
Class 12 Physics students should refer to the following printable worksheet in Pdf in Class 12. This test paper with questions and solutions for Class 12 Physics will be very useful for tests and exams and help you to score better marks
Class 12 Physics Chapter 6 Electromagnetic Induction Worksheet Pdf
ONE MARK QUESTIONS
Question. The power factor of an ac circuit is 0.5. What is the phase difference between current and voltage in this circuit.
Answer : 600
Question. Define quality factor of resonance in series LCR circuit. What is its SI unit?
Answer : Q = ωr /2Δω
Question. An ac source of voltage V= V_0 sinωt is connected to an ideal inductor. Draw graphs of voltage V and current i versus ωt.
Answer :
Question. A bar magnet is moved in the direction indicated by the arrow between two coils PQ and CD. Predict the direction of the induced current in each coil.
Answer : P to Q in coil 1 and C to D in coil 2
TWO MARKS QUESTIONS
Question. Show that magnetic energy required to build up the current I in a coil of self-inductance L is given by 1/2 LI^2.
Answer : Derivation
Question. State the underlying principle of a transformer. How is the large scale transmission of electric energy over long distances done with the use of transformers?
Answer : Mutual induction. Step up transformer
Question. A light bulb is rated 100 W for 220V ac supply of 50Hz. Calculate
(a) the resistance of the bulb
(b) the rms current through the bulb
Answer : R= 484 Ω
Question. State Lenz’s law. A metallic rod held horizontally along east-west direction, is allowed to fall under gravity. Will there be an emf induced at its ends? Justify your answer.
Answer : Statement. Emf is induced.
THREE MARKS QUESTIONS
Question. Derive expression for self inductance of a long air-cored solenoid of length l, cross-sectional area A and having number of turns N.
Answer : derivation
Question. Describe briefly, with the help of a labeled diagram, the working of a step up transformer.
Answer : Brief explanation
Question. (a) Define mutual inductance and write its SI units.
(b) Derive an expression for the mutual inductance of two long coaxial solenoids of same length wound one over other.
Answer : (a) definition and hennery (b) derivation
Question. A wheel of 8 metallic spokes each 50cm long is rotated with a speed of 120 rev/min in a plane normal to the horizontal component of the Earth’s magnetic field. The Earth’s magnetic field at the plane is 0.4 G and the angle of dip is 60⁰. Calculate the emf induced between the axle and the rim of the wheel. How will be the emf is affected if the number of spokes were increased?
Answer : E= 1/2 Bωl^2
B_H=B cosδ
E= 1/2 B cosδ ωl^2=3.14×〖10〗^(-5) volt
Question.) Using phasor diagram for a series LCR circuit connected to an AC source of voltage
v= v_0 sinωτ, derive the relation for the current flowing in the circuit and the phase angle between the voltage across the resistor and the net voltage in the circuit.
Answer : Derivation
The phasor diagram of the RLC Series Circuit when the circuit is acting as an inductive circuit that means (VL>VC) is shown below and if (VL< VC) the circuit will behave as a capacitive circuit.
Steps to draw the Phasor Diagram of the RLC Series Circuit
• Take current I as the reference as shown in the figure above
• The voltage across the inductor L that is VL is drawn leads the current I by a 90-degree angle.
• The voltage across the capacitor c that is Vc is drawn lagging the current I by a 90 degree angle because in capacitive load the current leads the voltage by an angle of 90 degrees.
• The two vectors VL and VC are opposite to each other.
FIVE MARKS QUESTIONS
Question. (a) Draw a schematic sketch of an ac generator describing its basic elements. State briefly its working principle. Show a plot of variation of (i) magnetic flux and (ii) alternating emf versus time generated by a loop of wire rotating in a magnetic field (b) Why is choke coil needed in the use of fluorescent tubes with ac mains?
Answer : Brief explanation.
Principle of AC generator- It works on the principle of electromagnetic induction.
In an A.C. generator, mechanical energy is converted to electrical energy by virtue of electromagnetic induction.
* Rotation of rectangular coil in a magnetic field causes change in flux (Φ = NBACosωt).
Change in flux induces emf in the coil which is given by
ε= -dΦ/dt = NBAωSinωt ε ε= ε0Sinω
* Current induced in the coil I = ε/R = ε0Sinωt/R = I0Sinωt
,In case of choke coil power dissipation is very negligible
Question. (a) An ac source of voltage V= V_0 sinωt is connected to a series combination of L, C and R. Use the phasor diagram to obtain expressions for impedance of the circuit and phase angle between voltage and current. Find the condition when current will be in phase with the voltage. What is the circuit in this condition called?
(b) In a series LR circuit X_L=R and power factor of the circuit is P_1. When capacitor with capacitance C such that X_L=X_C is put in series, the power factor becomesP_2. CalculateP_1/P_2 .
Answer :
Question. (i) What is the function of a transformer. State it principle of working with the help of a diagram. Mention various energy losses in this device.
(ii) The primary coil of an ideal step up transformer has 100 turns and transformation ratio is also 100. The input voltage and power are respectively 220 V and 1100 W. Calculate
(a) Number of turns in secondary
(b) Current in primary
(c ) voltage across secondary
(d) Current in secondary
(e) Power in secondary
Answer : (i) Function: Transformer is used for converting
low alternating voltage at high current into high voltage at low current and vice-versa.
Principle: It works on the principle of mutual induction.
Various Energy loses in transformer are -
(a) Flux losses.
(b) Copper and Iron losses.
( c) Hysteresis Losses
(d) Humming Losses.
Step-Up Transformer:
Converts low voltage A.C. into high voltage A.C. It increase the voltage
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CBSE Class 12 Physics Chapter 6 Electromagnetic Induction Worksheet
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