Read and download the CBSE Class 12 Mathematics Application of Derivatives VBQs Set B. Designed for the 2025-26 academic year, these Value Based Questions (VBQs) are important for Class 12 Mathematics students to understand moral reasoning and life skills. Our expert teachers have created these chapter-wise resources to align with the latest CBSE, NCERT, and KVS examination patterns.
VBQ for Class 12 Mathematics Chapter 6 Application of Derivatives
For Class 12 students, Value Based Questions for Chapter 6 Application of Derivatives help to apply textbook concepts to real-world application. These competency-based questions with detailed answers help in scoring high marks in Class 12 while building a strong ethical foundation.
Chapter 6 Application of Derivatives Class 12 Mathematics VBQ Questions with Answers
Fill in the blanks.
Question. The slope of the tangent to the curve \( y = x^3 - x \) at the point \( (2, 6) \) is _____________ .
Answer: 11
Question. The maximum value of \( f(x) = x + \frac{1}{x}, x < 0 \) is _____________ .
Answer: -2
Question. The rate of change of the area of a circle with respect to its radius r, when r = 3 cm, is _____________ .
Answer: \( 6\pi \text{ cm}^2\text{/cm} \)
Question. If \( f(x) = \frac{1}{4x^2 + 2x + 1} \), then its maximum value is _____________ .
Answer: \( \frac{4}{3} \)
Very Short Answer Questions:
Question. If the rate of change of volume of a sphere is equal to the rate of change of its radius, find the radius of the sphere.
Answer: \( \frac{1}{2\sqrt{\pi}} \text{ units} \)
Question. Find the interval in which the function f given by \( f(x) = 7 - 4x - x^2 \) is strictly increasing.
Answer: \( (-\infty, -2) \)
Question. At what points on the curve \( x^2 + y^2 - 2x - 4y + 1 = 0 \), the tangents are parallel to y-axis?
Answer: \( (-1, 2) \text{ and } (3, 2) \)
Question. It is given that at \( x = 1 \) the function \( x^4 - 62x^2 + ax + 9 \) attains the maximum value on the interval \( [0, 2] \). Find the value of a.
Answer: \( a = 120 \)
Question. Find the least value of \( \lambda \) such that the function \( (x^2 + \lambda x + 1) \) is increasing on \( [1, 2] \).
Answer: \( \lambda = -2 \)
Short Answer Questions–I:
Question. The contentment obtained after eating x-units of a new dish at a trial function is given by the function \( C(x) = x^3 + 6x^2 + 5x + 3 \). If the marginal contentment is defined as rate of change of \( C(x) \) with respect to the number of units consumed at an instant, then find the marginal contentment when three units of dish are consumed.
Answer: 68 units
Question. Prove that the function \( f(x) = \tan x - 4x \) is strictly decreasing on \( \left( -\frac{\pi}{3}, \frac{\pi}{3} \right) \).
Answer: \( f'(x) = \sec^2 x - 4 \). For \( x \in \left( -\frac{\pi}{3}, \frac{\pi}{3} \right) \), \( 1 \le \sec x < 2 \), so \( 1 \le \sec^2 x < 4 \), hence \( f'(x) < 0 \). Function is strictly decreasing.
Question. Find the value of a for which the function \( f(x) = \sin x - ax + b \) increasing on R.
Answer: \( (-\infty, -1) \)
Question. Show that the function \( f(x) = 4x^3 - 18x^2 + 27x - 7 \) is always increasing on \( \mathbb{R} \).
Answer: \( f'(x) = 12x^2 - 36x + 27 = 3(4x^2 - 12x + 9) = 3(2x - 3)^2 \ge 0 \). Hence always increasing.
Question. Prove that \( f(x) = \sin x + \sqrt{3} \cos x \) has maximum value at \( x = \frac{\pi}{6} \).
Answer: \( f'(x) = \cos x - \sqrt{3} \sin x \). Setting \( f'(x) = 0 \Rightarrow \tan x = \frac{1}{\sqrt{3}} \Rightarrow x = \frac{\pi}{6} \). \( f''(x) = -\sin x - \sqrt{3} \cos x < 0 \) at \( x = \frac{\pi}{6} \).
Question. Show that the function f defined by \( f(x) = (x - 1) e^x + 1 \) is an increasing function for all \( x > 0 \).
Answer: \( f'(x) = (x-1)e^x + e^x(1) = xe^x \). For \( x > 0 \), \( xe^x > 0 \). Hence increasing.
Short Answer Questions–II:
Question. Find the equations of the tangent and the normal to the curve \( y = \frac{x-7}{(x-2)(x-3)} \) at the point where it cuts the x-axis.
Answer: \( x - 20y - 7 = 0 \) and \( 20x + y - 140 = 0 \) respectively
Question. A ladder 13 m long is leaning against a vertical wall. The bottom of the ladder is dragged away from the wall along the ground at the rate of 2 cm/sec. How fast is the height on the wall decreasing when the foot of the ladder is 5 m away from the wall?
Answer: \( \frac{5}{6} \text{ cm/sec} \)
Question. Find the intervals in which the function \( f(x) = 3x^4 - 4x^3 - 12x^2 + 5 \) is (a) strictly increasing (b) strictly decreasing.
Answer: (a) \( (-1, 0) \cup (2, \infty) \) (b) \( (-\infty, -1) \cup (0, 2) \)
Question. Find the point on the curve \( 9y^2 = x^3 \), where the normal to the curve makes equal intercepts on the axes.
Answer: \( \left( 4, \frac{8}{3} \right) \) and \( \left( 4, -\frac{8}{3} \right) \)
Question. Find the equations of the normals to the curve \( y = x^3 + 2x + 6 \) which are parallel to the line \( x + 14y + 4 = 0 \).
Answer: \( x + 14y - 254 = 0 \) and \( x + 14y + 86 = 0 \)
Question. Prove that the semi-vertical angle of the right circular cone of given volume and least curved surface area is \( \cot^{-1} \sqrt{2} \).
Answer: [Result proved following optimization of surface area with respect to volume]
Question. Find all the points of local maxima and local minima of the function \( f(x) = -\frac{3}{4}x^4 - 8x^3 - \frac{45}{2}x^2 + 105 \).
Answer: Local maxima at 0, -5; and local minima at -3
Question. Using differentials, find the approximate value of \( \sqrt{0.082} \).
Answer: 0.2867
Long Answer Questions:
Question. Find the dimensions of the rectangle of perimeter 36 cm which will sweep out a volume as large as possible, when revolved about one of its side. Also, find the maximum volume.
Answer: Length = 12 cm, breadth = 6 cm and maximum volume = \( \frac{216}{\pi} \text{ cm}^3 \)
Question. Find the angle of intersection of the curve \( y^2 = 4ax \) and \( x^2 = 4by \).
Answer: 90°
Question. The volume of a sphere is increasing at the rate of 3 cubic centimeter per second. Find the rate of increase of its surface area, when the radius is 2 cm.
Answer: \( 3 \text{ cm}^2\text{/sec.} \)
Question. Find the local maxima and local minima, of the function \( f(x) = \sin x - \cos x, 0 < x < 2\pi \), Also find the local maximum and local minimum values.
Answer: Local maximum value = \( \sqrt{2} \), local minimum value = \( -\sqrt{2} \)
Question. Find the value of p for which the curves \( x^2 = 9p(9 - y) \) and \( x^2 = p(y + 1) \) cut each other at right angles.
Answer: \( p = 0, 4 \)
Question. Find the point on the curve \( y = \frac{x}{1 + x^2} \), where the tangent to the curve has the greatest slope.
Answer: (0, 0)
Question. Find the absolute maximum and absolute minimum values of the function f given by \( f(x) = \cos^2 x + \sin x, x \in [0, \pi] \).
Answer: Absolute maximum value = \( \frac{5}{4} \) at \( x = \frac{\pi}{6} \) and \( \frac{5\pi}{6} \), absolute minimum value = 1 at \( x = 0, \frac{\pi}{2} \) and \( \pi \)
Question. Find the equation of tangents to the curve \( y = \cos (x + y), -2\pi \le x \le 2\pi \), that are parallel to the line \( x + 2y = 0 \).
Answer: \( x + 2y = 0 \)
Question. Determine the intervals in which the function \( f(x) = x^4 - 8x^3 + 22x^2 - 24x + 21 \) is strictly increasing or strictly decreasing.
Answer: \( (1, 2) \cup (3, \infty) \); \( (-\infty, 1) \cup (2, 3) \)
Question. Find the equation of the normal at a point on the curve \( x^2 = 4y \) which passes through the point (1, 2). Also find the equation of the corresponding tangent.
Answer: \( x + y - 3 = 0 \); \( x - y - 1 = 0 \)
Question. A manufacturer can sell x items at a price of Rs left( 5 - \frac{x}{100} \right) \) each. The cost price of x items is Rs left( \frac{x}{5} + 500 \right) \). Find the number of items he should sell to earn maximum profit.
Answer: 240 items
Question. A wire of length 34 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a rectangle whose length is twice its breadth. What should be the lengths of the two pieces, so that the combined area of the square and the rectangle is minimum?
Answer: 16 m, 18 m
Question. If \( y = x^4 - 10 \) and x changes from 2 to 1.99, then what is the change in y?
(a) 0.32
(b) 0.032
(c) 5.68
(d) 5.698
Answer: (a)
Question. The maximum slope of curve \( y = -x^3 + 3x^2 + 9x - 27 \) is
(a) 0
(b) 12
(c) 16
(d) 32
Answer: (b)
Question. The maximum value of \( \frac{\log x}{x} \) in \( [2, \infty) \) is
(a) 0
(b) 1
(c) \( \frac{1}{e} \)
(d) e
Answer: (c)
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Important Practice Resources for Class 12 Mathematics
VBQs for Chapter 6 Application of Derivatives Class 12 Mathematics
Students can now access the Value-Based Questions (VBQs) for Chapter 6 Application of Derivatives as per the latest CBSE syllabus. These questions have been designed to help Class 12 students understand the moral and practical lessons of the chapter. You should practicing these solved answers to improve improve your analytical skills and get more marks in your Mathematics school exams.
Expert-Approved Chapter 6 Application of Derivatives Value-Based Questions & Answers
Our teachers have followed the NCERT book for Class 12 Mathematics to create these important solved questions. After solving the exercises given above, you should also refer to our NCERT solutions for Class 12 Mathematics and read the answers prepared by our teachers.
Improve your Mathematics Scores
Daily practice of these Class 12 Mathematics value-based problems will make your concepts better and to help you further we have provided more study materials for Chapter 6 Application of Derivatives on studiestoday.com. By learning these ethical and value driven topics you will easily get better marks and also also understand the real-life application of Mathematics.
The latest collection of Value Based Questions for Class 12 Mathematics Chapter Chapter 6 Application of Derivatives is available for free on StudiesToday.com. These questions are as per 2026 academic session to help students develop analytical and ethical reasoning skills.
Yes, all our Mathematics VBQs for Chapter Chapter 6 Application of Derivatives come with detailed model answers which help students to integrate factual knowledge with value-based insights to get high marks.
VBQs are important as they test student's ability to relate Mathematics concepts to real-life situations. For Chapter Chapter 6 Application of Derivatives these questions are as per the latest competency-based education goals.
In the current CBSE pattern for Class 12 Mathematics, Chapter 6 Application of Derivatives Value Based or Case-Based questions typically carry 3 to 5 marks.
Yes, you can download Class 12 Mathematics Chapter Chapter 6 Application of Derivatives VBQs in a mobile-friendly PDF format for free.