CBSE Class 10 Mathematics Arithmetic Progressions Worksheet Set D

Read and download free pdf of CBSE Class 10 Mathematics Arithmetic Progressions Worksheet Set D. Download printable Mathematics Class 10 Worksheets in pdf format, CBSE Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 10 Assignments and practice them daily to get better marks in tests and exams for Class 10. Free chapter wise worksheets with answers have been designed by Class 10 teachers as per latest examination pattern

Chapter 5 Arithmetic Progression Mathematics Worksheet for Class 10

Class 10 Mathematics students should refer to the following printable worksheet in Pdf in Class 10. This test paper with questions and solutions for Class 10 Mathematics will be very useful for tests and exams and help you to score better marks

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet Pdf

Question. The sum first n odd natural number is
(a) 2n-1
(b) n2
(c) 2n+1
(d) n2-1
Answer : B

Question. The next term of an AP √7 , √28 , √63 , ………..
(a) √84
(b) √70
(c) √97
(d) √112
Answer : A

Question. For the A.P. 3/2 , 1/2 , -1/2 , -3/2 write common difference
(a) 1
(b) 14
(c) -1
(d) 3/2
Answer : C

Question. What is common difference of an AP . in which a18 – a14 = 32
(a) 8
(b) -8
(c) -4
(d) 4
Answer : A

Question. If 6/5, a , 4 are in AP then value of a is
(a) 13/3
(b) 13/6
(c) 13/5
(d) 13/7
Answer : C

 
Short Answer Type Question
 
Question. Find the sum of first 30 terms of an A.P. whose second term is 2 and seventh term is 22.
Answer : ​​​​Let a be the first term and d be the common difference of the given A.P. Then,
a2 = 2 and a7 = 22
=> a + d = 2 and a + 6d = 22
Solving these two equations, we get
a = – 2 and d = 4.
Sn = n/2
[2a + (n – 1) d]
 S30 = 30/2
[2 × (–2) + (30 – 1) × 4]
=> 15 (–4 + 116) = 15 × 112
= 1680
Hence, the sum of first 30 terms is 1680.
 
Question.  Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3.
Answer : Clearly, the numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258,...., 999.
This is an A.P. with first term a = 252, common difference = 3 and last term = 999. Let there be n terms in this A.P. Then,
=> an = 999
=> a + (n – 1)d = 999
=> 252 + (n – 1) × 3 = 999 => n = 250
 Required sum = Sn = n/2 [a + l]
= 250/2 [252 + 999] = 156375
 
Question. How many terms of the series 54, 51, 48, ....be taken so that their sum is 513 ? Explain the double answer.
Answer : a = 54, d = – 3 and Sn = 513
=> n/2 [2a + (n – 1) d] = 513
 n/2[108 + (n – 1) × – 3] = 513
 => n2 – 37n + 342 = 0
=> (n – 18) (n – 19) = 0   =>n = 18 or 19
Here, the common difference is negative, So,
19th term is a19 = 54 + (19 – 1) × – 3 = 0.
Thus, the sum of 18 terms as well as that of 19 terms is 513.
 
CBSE Class 10 Mathematics Arithmetic Progressions Worksheet Set D

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CBSE Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet

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Worksheet for Mathematics CBSE Class 10 Chapter 5 Arithmetic Progression

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