CBSE Class 10 Arithmetic Progression Printable Worksheet Set A

Read and download free pdf of CBSE Class 10 Arithmetic Progression Printable Worksheet Set A. Download printable Mathematics Class 10 Worksheets in pdf format, CBSE Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 10 Assignments and practice them daily to get better marks in tests and exams for Class 10. Free chapter wise worksheets with answers have been designed by Class 10 teachers as per latest examination pattern

Chapter 5 Arithmetic Progression Mathematics Worksheet for Class 10

Class 10 Mathematics students should refer to the following printable worksheet in Pdf in Class 10. This test paper with questions and solutions for Class 10 Mathematics will be very useful for tests and exams and help you to score better marks

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet Pdf

 

 

 

VERY SHORT ANSWER QUESTIONS(1 MARK)

Question. If the sum of first m terms of an AP is am2 + bm, find the common difference.
Answer : 
Sm= am2 + bm, S1= a+b= a1, S= 4a+2b= a1+ a2
a2 = S2- S1= 4a+2b- (a+b) = 3a +b , d= a2-a1= 3a+b-(a+b)= 2a

Question. Three numbers are in AP and their sum is 24. Find the middle term.
Answer : 
Let the three numbers of the AP be a-d, a, a+d. So a-d +a+a+d= 24 ⟹ 3a=24,a=24/3=8. Hence the middle term =8.

Question. Find the sum of first 8 multiples of 3.
Answer : 
First 8 multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24 These numbers are in A.P.
where a = 3, d = 3 and n = 8 , an=24, Sn= 𝑛/2(a 1+ an), S8= 8/2(3+ 24)= 4x27=108

Question. Find the sum: 34+ 32+30+……+10
Answer : 
Given, 34 + 32 + 30 + … + 10, first term, a = 34, d = a2−a1 = 32−34 = −2, Let 10 be the nth term of this A.P., an= a +(n−1)d, 10 = 34+(n−1)(−2), −24 = (n −1)(−2), 12 = n −1, n = 13, Sn = n/2 (a +l) , l = 10, Sn = n/2 (34 + 10) = 13/2 x44= 286

Question. Find the number of terms of an AP 5, 9,13, …, 185.
Answer : 
a1=5, d=9-5=4, an=185, 185 = 5 + (n - 1)4, 185 = 5 + 4n -4,185 = 1 + 4n, 185 - 1 = 4n, 184 = 4n, n= 184/4 = 46

Question. Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5
Answer : 
Since, the number is divisible by both 2 and 5, means it must be divisible by 10.AP = 110, 120, 130,..., 990, a = 110, d = 10, nth term of the AP = 990
a+(n-1)d=990, 110+(n-1)10=990, (n-1)10=990-110,(n-1)= 880/10, n-1=88, n=88+1, n=89

Question. The fourth term of an AP is 11 and the eleventh term is 25. Determine the first term and common difference.
Answer : 
a + 3d = 11….(1) a + 10d = 25…..(2)
Subtracting equation (1) from equation (2 )
a + 10d – (a + 3d) = 25 – 11, 7d = 14, d = 2,
Putting value of d=2 in the equation 2,
a + 10x2 = 25, a + 20 = 25, a = 25 – 20, a = 5

Question. In an AP a = 15, d = -3, an = 0, then find the value of n.
Answer : 
First term (a) =15,Common difference (d) = -3,
Last term(an) = 0, 0 = 15 + (n - 1)-3 -15 = -3n + 3, -15 - 3 = -3n, -18 = -3n, n=6

Question. If the nth term of a progression be a linear expression in n, then prove that this progression is an AP.
Answer : Let the nth term of a given progression be given by
Tn = an + b, where a and b are constants.
Then, Tn–1 = a(n – 1) + b = [(an + b) – a]
(Tn – Tn–1) = (an + b) – [(an + b) – a] = a,
which is a constant.
Hence, the given progression is an AP.
 
Question. Write the first three terms in each of the sequences defined by the following -
(i) an = 3n + 2    (ii) an = n2 + 1
Answer : (i) We have,
an = 3n + 2
Putting n = 1, 2 and 3, we get
a1 = 3 × 1 + 2 = 3 + 2 = 5,
a2 = 3 × 2 + 2 = 6 + 2 = 8,
a3 = 3 × 3 + 2 = 9 + 2 = 11
Thus, the required first three terms of the sequence defined by an = 3n + 2 are 5, 8, and 11.
(ii) We have,
an = n2 + 1
Putting n = 1, 2, and 3 we get
a1 = 12 + 1 = 1 + 1 = 2
a2 = 22 + 1 = 4 + 1 = 5
a3 = 32 + 1 = 9 + 1 = 10
Thus, the first three terms of the sequence
defined by an = n2 + 1 are 2, 5 and 10.
 
Question. The nth term of a sequence is 3n – 2. Is the sequence an A.P. ? If so, find its 10th term.
Answer : We have an = 3n – 2
Clearly an is a linear expression in n. So, the given sequence is an A.P. with common difference 3.
Putting n = 10, we get
a10 = 3 × 10 – 2 = 28
 
Question. Find the 12th, 24th and nth term of the A.P. given by 9, 13, 17, 21, 25, .........
Answer : We have,
a = First term = 9 and,
d = Common difference = 4
[ 13 – 9 = 4, 17 – 13 = 4, 21 – 7 = 4 etc.]
We know that the nth term of an A.P. with first term a and common difference d is given by
an = a + (n – 1) d
Therefore,
a12 = a + (12 – 1) d
= a + 11d = 9 + 11 × 4 = 53
a24 = a + (24 – 1) d
= a + 23 d = 9 + 23 × 4 = 101
and, an = a + (n – 1) d
= 9 + (n – 1) × 4 = 4n + 5
a12 = 53, a24 = 101 and an = 4n + 5
Sequences
Arithmetic Progression
A sequence of terms is said to be in arithmetic progression (A.P) when the difference between any term and its preceeding term is a fixed constant. This constant is called the common difference (c.d) of the A.P.
If a is first term and d is the common difference of the A.P., then its nth term tn is given by tn = a + ( n – 1)d.
 
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A
 
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-
 
Geometric Progression (G.P.)
 
A sequence is said to be in G.P. when its first term is non-zero and each term is r times the preceeding term,where r is a non-zero constant. The fixed number r is known as the common ratio of the G.P.
 
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-1
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-2
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-3
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-4
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-5
CBSE Class 10 Arithmetic Progression Printable Worksheet Set A-6
 
 
 
 
 
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