CBSE Class 10 Arithmetic Progression Printable Worksheet Set B

Read and download free pdf of CBSE Class 10 Arithmetic Progression Printable Worksheet Set B. Download printable Mathematics Class 10 Worksheets in pdf format, CBSE Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 10 Assignments and practice them daily to get better marks in tests and exams for Class 10. Free chapter wise worksheets with answers have been designed by Class 10 teachers as per latest examination pattern

Chapter 5 Arithmetic Progression Mathematics Worksheet for Class 10

Class 10 Mathematics students should refer to the following printable worksheet in Pdf in Class 10. This test paper with questions and solutions for Class 10 Mathematics will be very useful for tests and exams and help you to score better marks

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet Pdf

Very Short Answer Type Questions

Question. How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?
Answer : 
12

Question. Find the sum of the odd numbers between 0 and 50.
Answer : 
625

Question. For what value of k: 2k, k + 10 and 3k + 2 are in AP?
Answer : 
k+10 = 2π‘˜+3π‘˜+2/2 = k+10 = 5π‘˜+2/2 Also by cross multiplying we get 2(k+10) = 5k+2
2k+20 = 5k+2, 18 = 3k, k = 6

Question. Find the common difference of the AP 1/𝑝, 1βˆ’π‘/𝑝 , 1βˆ’2𝑝/𝑝,…
Answer : 
d = a2-a1 = 1βˆ’π‘/𝑝 - 1/𝑝 = 1βˆ’π‘βˆ’1/𝑝 = βˆ’π‘/𝑝 = -1

Question. Write first four terms of the AP,when first term is 1.25 and common difference is -0.25.
Answer :
 a, a+d, a+2d, a+3d = 1.25, 1 ,0.75, 0.50

Question. Find the missing terms in the given AP 2, --------, 26 ------------ SHORT ANSWER 
Answer : 
a = a1+a3/2 , a = 2+26/2 = 14, d = a2 - a1 = 12, a4 = a3+d = 26+12 = 38

Question. If the nth term of an AP is 2n+1, then find the sum of its first three terms.
Answer : 
an = 2n+1, a1 = 2x1+1=3 , a= 2x3+1 = 7, S= 3/2(3+7) = 15

Question. Find the sum of all natural numbers from 1 to 100.
Answer : 
𝑛(𝑛+!)/2 = 100(100+!)/2 = 5050

Question. Find the 9th term from the end (towards the first term) of the AP 5, 9, 13, …, 185.
Answer : 
nth term from the end = l- (n-1)d, where l is the last term.
9th term from the end = 185-(9-1)4, 185-32 = 153

Question. Find the common difference of an AP in which a18 – a14 = 32
Answer : 
a18 – a14 = 32.,a+17d-(a+13d) = 32, 4d = 32,d = 32Γ·4 = 8

Question. The first, second and last terms of an AP are respectively 4, 7 and 31. How many terms are there in the given AP?
Answer : 
a1 = 4 , a2 = 7 , an = 31 ,d = a2- a1 = 7-4 = 3
31 = 4+(n-1)3,(n-1)3 = 27,n-1 = 9,n = 10

Question. In an AP,if the common difference is -4 and the seventh term is 4,then find thefirst term.
Answer : 
a7 = 4,d = -4, a+6d = 4, a+6x-4 = 4, a-24 = 4,a = 28.

Question. Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.
(i) – 1.2, – 3.2, – 5.2, – 7.2, . . . (ii) 3, 3 + √2 , 3 + 2 √2 , 3 + 3√2 , . . .
(iii) 0.2, 0.22, 0.222, 0.2222, . . . (iv) 12, 32, 52, 72, . . .
Answer : 
(i) Yes. d = – 2; – 9.2, –11.2, – 13.2,
(ii) Yes. d = √2 ; 3 + 4 √2 , 3 + 5 √2 , 3 + 6 √2 ,
(iii) No
(iv) No

Question. Subba Rao started work in 1995 at an annual salary of β‚Ή 5000 and received an increment of β‚Ή 200 each year. In which year did his income reach β‚Ή 7000?
Answer : 
11th year

Question. How many multiples of 4 lie between 10 and 250?
Answer : 
60

Question. A sum of β‚Ή 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is β‚Ή 20 less than its preceding prize, find the value of each of the prizes. 
Answer : 
Values of the prizes (in Rs) are 160, 140, 120, 100, 80, 60, 40.

Question. Which term of the sequence –1, 3, 7, 11, ..... ,is 95 ?
Answer : Clearly, the given sequence is an A.P.
We have,
a = first term = –1 and,
d = Common difference = 4.
Let 95 be the nth term of the given A.P. then, an = 95
= a + (n – 1) d = 95
= – 1 + (n – 1) Γ— 4 = 95
= – 1 + 4n – 4 = 95
= 4n – 5 = 95
= 4n = 100
= n = 25
Thus, 95 is 25th term of the given sequence.
 
Question. Which term of the sequence 4, 9 , 14, 19, ......is 124 ?
Answer : Clearly, the given sequence is an A.P. with first term a = 4 and common difference d = 5.
Let 124 be the nth term of the given sequence.
Then, an = 124
a + (n – 1) d = 124
=4 + (n – 1) Γ— 5 = 124
= n = 25
Hence, 25th term of the given sequence is 124.
 
Question. The 10th term of an A.P. is 52 and 16th term is 82. Find the 32nd term and the general term
Answer : Let a be the first term and d be the common difference of the given A.P. Let the A.P. be a1, a2, a3, ..... an, ......
It is given that a10 = 52 and a16 = 82
= a + (10 – 1) d = 52 and a + (16 – 1) d = 82
= a + 9d = 52                          ....(i)
and, a + 15d = 82                    ....(ii)
Subtracting equation (ii) from equation (i),we get
–6d = – 30 
d = 5
Putting d = 5 in equation (i), we get
a + 45 = 52 
a = 7
∴ a32 = a + (32 – 1) d = 7 + 31 Γ— 5 = 162
and, an = a + (n – 1) d = 7 (n – 1) Γ— 5 = 5n + 2.
Hence a32 = 162 and an = 5n + 2.
 
 

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 1

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 2

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 3

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 4

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 5

CBSE Class 10 Arithmetic Progression Printable Worksheet Set B 6

Please click on below link to download CBSE Class 10 Arithmetic Progression Printable Worksheet Set B

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