CBSE Class 10 Mathematics Arithmetic Progressions Worksheet Set E

Read and download free pdf of CBSE Class 10 Mathematics Arithmetic Progressions Worksheet Set E. Download printable Mathematics Class 10 Worksheets in pdf format, CBSE Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 10 Assignments and practice them daily to get better marks in tests and exams for Class 10. Free chapter wise worksheets with answers have been designed by Class 10 teachers as per latest examination pattern

Chapter 5 Arithmetic Progression Mathematics Worksheet for Class 10

Class 10 Mathematics students should refer to the following printable worksheet in Pdf in Class 10. This test paper with questions and solutions for Class 10 Mathematics will be very useful for tests and exams and help you to score better marks

Class 10 Mathematics Chapter 5 Arithmetic Progression Worksheet Pdf

Question. In an A.P. if a = 5, an = 81 and Sn = 860, then n is
(a) 10
(b) 15
(c) 20
(d) 25

Answer: C

Question. What is the value of k if (k + 2), (4k – 6) and (3k – 2) are three consecutive terms of an A.P.?
(a) k = –3
(b) k = 2
(c) k = –2
(d) k = 3

Answer: D

Question. The first term of an A.P. is 5 and its 100th term is –292. The 50th term of this A.P. will be
(a) 142
(b) –142
(c) 130
(d) –140

Answer: B

Question. If a, b, c are in A.P., then the value of (a + 2b – c) (2b + c – a) (c + a – b) will be
(a) 4abc
(b) 2abc
(c) abc
(d) None of these

Answer: A

Question. Sum of n terms of the series √2 + √8 + √18 + √32 +.... is
(a) n(n+1)/2
(b) 2n( (n + 1)
(c) (n+1)/√2
(d) 1

Answer: C

Question. If eight times the 8th term of an A.P. is equal to 12 times the 12th term of the A.P. then its 20th term will be
(a) –1
(b) 1
(c) 0
(d) 2

Answer: C

Question. The 10th term of an AP is 20 and the 19th term is 101.
Then, the third term is
(a) – 43
(b) – 61
(c) – 52
(d) 1

Answer: A

Question. Given that the sum of the first ‘n’ terms of an arithmetic progression is 2n2 + 3n, find the 12th term.
(a) 72
(b) 36
(c) √625
(d) 56

Answer: A

Question. The common difference of the A.P. 1/p, 1-p/p, 1-2p/p ........ is
(a) 1
(b)
1/p
(c) –1
(d) − (1/p)

Answer: C

Question. The nth term of the A.P. a, 3a, 5a, ......., is
(a) na
(b) (2n – 1)a
(c) (2n + 1)a
(d) 2na

Answer: B

Question. If the sum of the series 2 + 5 + 8 + 11 ........... is 60100, then the number of terms are
(a) 100
(b) 200
(c) 150
(d) 250

Answer: B

Question. What is the common difference of four terms in A.P. such that the ratio of the product of the first and fourth term to that of the second and third term is 2 : 3 and the sum of all four terms is 20 ?
(a) 3
(b) 1
(c) 4
(d) 2

Answer: D

Question. There are 60 terms in an A.P. of which the first term is 8 and the last term is 185. The 31st term is
(a) 56
(b) 94
(c) 85
(d) 98

Answer: D

Question. There are four arithmetic means between 2 and –18. The means are
(a) –4, –7, –10, –13
(b) 1, –4, –7, –10
(c) –2, –5, –9, –13
(d) –2, –6, –10, –14

Answer: D

Question. If the first, second and the last terms of an A.P. are a, b, c respectively, then the sum is
(a) (a + b) (a + c − 2b)/2(b − a)
(b) (b + c) (a + b − 2c)/2(b − a)
(c) (a + c) (b + c − 2a)/2(b − a)
(d) None of these

Answer: C

Question. The sum of 11 terms of an A.P. whose middle term is 30, is
(a) 320
(b) 330
(c) 340
(d) 350

Answer: B

Question. If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least, then the numbers are
(a) 5, 10, 15, 20
(b) 4, 10, 16, 22
(c) 3, 7, 11, 15
(d) None of these

Answer: A

Question. Let Tr be the rth term of an A.P. for r = 1, 2, 3, .... If for some positive integers m, n we have, Tm = 1/n and Tn = 1/m, then Tmn equals
(a) 1/mn
(b) m/1 + n/1
(c) 1
(d) 0

Answer: C

Question. If the sum of the first 2n terms of 2, 5, 8, ....... is equal to the sum of the first n terms of 57, 59, 61......., then n is equal to
(a) 10
(b) 12
(c) 11
(d) 13

Answer: C

Question. The number of terms of the series 5, 7, 9, .... that must be taken in order to have the sum 1020 is
(a) 20
(b) 30
(c) 40
(d) 50

Answer: B

Question. If the nth term of an A.P. is 4n + 1, then the common difference is :
(a) 3
(b) 4
(c) 5
(d) 6

Answer: B

Question. If a, b, c, d, e, f are in A.P., then e – c is equal to:
(a) 2(c – a)
(b) 2(d – c)
(c) 2(f – d)
(d) (d – c)

Answer: B

Question. The number of common terms of the two sequences 17, 21, 25, ....., 417 and 16, 21, 26, ........, 466 is
(a) 19
(b) 20
(c) 21
(d) 91

Answer: B

Question. The number of two digit numbers which are divisible by 3 is
(a) 33
(b) 31
(c) 30
(d) 29

Answer: C

Question. If the nth term of an A.P. is given by an = 5n – 3, then the sum of first 10 terms is
(a) 225
(b) 245
(c) 255
(d) 270

Answer: B

Question. If S1, S2, S3, ......., Sr are the sum of first n terms of r arithmetic progressions respectively. Whose first terms are 1, 2, 3, ......... and whose common differences are 1, 3, 5, ........ respectively, then the value of S1 + S2 + S3...... Sr is
(a) (nr-1(nr+1)/2 
(b) (nr+1)nr/2
(c) n(nr-1)/nr
(d) n(nr+1)/2 

Answer: B

Question. First term of an arithmetic progression is 2. If the sum of its first five terms is equal to one-fourth of the sum of the next five terms, then the sum of its first 30 terms is
(a) 2670
(b) 2610
(c) –2520
(d) –2550

Answer: D

Question. The odd natural numbers have been divided in groups as (1, 3) ; (5,7, 9, 11) ; (13, 15, 17, 19, 21, 23), .....
Then the sum of numbers in the 10th group is
(a) 4000
(b) 4003
(c) 4007
(d) 4008

Answer: A

Question. Suppose the sum of the first m terms of an arithmetic progression is n and the sum of its first n terms is m, where m ≠ n. Then, the sum of the first (m + n) terms of the arithmetic progression is
(a) 1 – mn
(b) mn – 5
(c) – (m + n)
(d) m + n

Answer: C

Question. Which of the following represents an A.P. ?
(a) 0.2, 0.4, 0.6, ....
(b) 29, 58, 116....
(c) 15, 45, 135, 405...
(d) 3, 3.5, 4.5, 8.5 ....

Answer: A

Question. If tn = 6n + 5, then tn+1 =
(a) 6(n + 1) + 17
(b) 6(n – 1) + 11
(c) 6n + 11
(d) 6n – 11

Answer: C

Question. Sn = 54 + 51 + 48 + ........ n terms = 513. Least value of n is
(a) 18
(b) 19
(c) 15
(d) None of these

Answer: A

Question. If the nth term of an A.P. be (2n – 1), then the sum of its first n terms will be
(a) n2 – 1
(b) (n – 1)2
(c) (n – 1)2 – (2n – 1)
(d) n2

Answer: D

Question. If b+c−a/a , c+a−b/b , a+b−c/c are in A.P., then which of the following is in A.P.?
(a) a, b, c
(b) a2, b2, c2
(c) 1/a , 1/b , 1/c
(d) a3, b3, c3

Answer: B

ARITHMETIC PROGRESSIONS
 
Q.- If the term of m terms of an A.P. is the same as the sum of its n terms, show that the sum of its (m + n) terms is zero.
 
Sol. Let a be the first term and d be the common difference of the given A.P. Then,
Sm = Sn
m/2[2a + (m – 1) d] =  n/2[2a + (n – 1) d]
=> 2a(m – n) + {m (m – 1) – n (n – 1)} d = 0
=> 2a (m – n) + {(m2 – n2) – (m – n)} d = 0
=> (m – n) [2a + (m + n – 1) d] = 0
=>2a + (m + n – 1) d = 0
=> 2a + (m + n – 1) d = 0 [ m – n ≠ 0] ....(i)
Now, Sm+n = m + n/2 {2a + (m + n – 1) d}
Sm+n = m + n/2× 0 = 0 [Using equation (i)]
 
Q.- Four numbers are in A.P. If their sum is 20 and the sum of their square is 120, then find the middle terms.
 
Sol. Let the numbers are a – 3d, a – d, a + d, a + 3d
given a – 3d + a – d + a + d + a + 3d = 20
=> 4a = 20
=>a = 5
and (a – 3d)2 + (a – d)2 + (a + d)2 + (a + 3d)2= 120
4a2 + 20 d2 = 120
4 × 52 + 20 d2 = 120
d2 = 1 
=>d = ±1
Hence numbers are 2, 4, 6, 8
 
Q.-  If the nth term of an AP is (2n + 1) then find the sum of its first three terms.
 
Sol. an = 2n + 1
a1 = 2(1) + 1 = 3
a2 = 2(2) + 1 = 5
a3 = 2(3) + 1 = 7
  a1 + a2 + a3 = 3 + 5 + 7 = 15
 
SECTION A: 
 
1. For the given AP write the first term and the common difference. -5,-1,3,7,........ 
→ -5, 4
 
2. Write the first 4 terms of the AP if a =-1.25 and d = -0.25 
→ -125,-1.5 ,-1.75,-2
 
3. √3,√12,√27√48.....form an AP? Justify your answer 
→yes
 
4. Given l = 28, S9 =144, FIND a. 
→ 4
 
SECTION B: 
 
4. Find the 16th term of the AP: 2, 7, 12, . . . 
→ 47
 
5. Check whether 202 is a term of the list of numbers 5, 11, 17, 23, 
→ No
 
6. How many three-digit numbers are divisible by 3? 
→ 300
 
7. Which term of the AP: 6,13, 20, ---------, 216 is the middle term? 
→ 16
 
SECTION C: 
 
8. Prove that Sn – Sn-1 = an
 
9. An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.  
→ 64
 
10. Given a = 5, d = 3, an = 50, find n and Sn. 
→ 16,440
 
11. The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference 
→ 16, 8/3
 
SECTION D: 
 
12. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. 
→ n2
 
13. The ratio of the 11th term to 18th term is 2:3. Find the ratio of the 5th term to the 21st term and also the ratio of the sum of first five terms to the sum of first 21 terms 
→ 1:3
5:49
 
14. Raghav buys a shop for Rs 120000. He pays half the amount in cash and agrees to pay the balance in 12 annual instalments of Rs 5000 each. If the rate of interest is 12% per annum and he pays with the instalment the interest due on the unpaid amount, find the total cost of the shop. (CBSE 2012) 
→ 166800
 
15. A small terrace at a football ground comprises of 15 steps each of which is 50m long and built of solid concrete. Each step has a rise of ¼m and a tread of ½m. Calculate the total volume of concrete required to build the terrace. (CBSE 2011) 
→ 750cm3
 
16 Show that the sum of an AP whose first term is a and the second term is b and the last term c is equal to (a+c)(b+c - 2a) ÷ 2(b - a) EXEMPLE

 

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Chapter 5 Arithmetic Progression CBSE Class 10 Mathematics Worksheet

The above practice worksheet for Chapter 5 Arithmetic Progression has been designed as per the current syllabus for Class 10 Mathematics released by CBSE. Students studying in Class 10 can easily download in Pdf format and practice the questions and answers given in the above practice worksheet for Class 10 Mathematics on a daily basis. All the latest practice worksheets with solutions have been developed for Mathematics by referring to the most important and regularly asked topics that the students should learn and practice to get better scores in their examinations. Studiestoday is the best portal for Printable Worksheets for Class 10 Mathematics students to get all the latest study material free of cost. Teachers of studiestoday have referred to the NCERT book for Class 10 Mathematics to develop the Mathematics Class 10 worksheet. After solving the questions given in the practice sheet which have been developed as per the latest course books also refer to the NCERT solutions for Class 10 Mathematics designed by our teachers. After solving these you should also refer to Class 10 Mathematics MCQ Test for the same chapter. We have also provided a lot of other Worksheets for Class 10 Mathematics which you can use to further make yourself better in Mathematics.

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