Class 11 Biology Practice Assignments: CBSE Class 11 Biology Morphology of Flowering Plants Assignments
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Question. Placenta and pericarp are both edible portions in
(a) apple
(b) banana
(c) tomato
(d) potato.
Answer. C
Question. An aggregate fruit is one which develops from
(a) multicarpellary syncarpous gynoecium
(b) multicarpellary apocarpus gynoecium
(c) complete inflorescence
(d) multicarpellary superior ovary.
Answer. B
Question. How many plants in the list given below have composite fruits that develop from an inflorescence?
Walnut, poppy, radish, fig, pineapple, apple, tomato, mulberry.
(a) Four
(b) Five
(c) Two
(d) Three
Answer. D
Question. The coconut water and the edible part of coconut are equivalent to
(a) endosperm
(b) endocarp
(c) mesocarp
(d) embryo.
Answer. A
Question. A drupe develops in
(a) mango
(b) wheat
(c) pea
(d) tomato.
Answer. A
Question. A fruit developed from hypanthodium inflorescence is called
(a) sorosis
(b) syconus
(c) caryopsis
(d) hesperidium.
Answer. B
Question. Cotyledons and testa respectively are edible parts in
(a) walnut and tamarind
(b) french bean and coconut
(c) cashew nut and litchi
(d) groundnut and pomegranate.
Answer. D
Question. The fleshy receptacle of syconus of fig encloses a number of
(a) berries
(b) mericarps
(c) achenes
(d) samaras.
Answer. C
Question. Dry indehiscent single-seeded fruit formed from bicarpellary syncarpous inferior ovary is
(a) berry
(b) cremocarp
(c) caryopsis
(d) cypsela.
Answer. D
Question. The fruit is chambered, developed from inferior ovary and has seeds with succulent testa in
(a) guava
(b) cucumber
(c) pomegranate
(d) orange.
Answer. C
Question. Pineapple (Ananas) fruit develops from
(a) a multilocular monocarpellary flower
(b) a unilocular polycarpellary flower
(c) a multipistillate syncarpous flower
(d) a cluster of compactly borne flowers on a common axis.
Answer. D
Question. In which of the following fruits, the edible part is the aril ?
(a) Litchi
(b) Custard apple
(c) Pomegranate
(d) Orange
Answer. A
Question. Which of the following represents the edible part of the fruit of litchi?
(a) Mesocarp
(b) Endocarp
(c) Pericarp
(d) Juicy aril
Answer. D
Question. Edible part of mango is
(a) endocarp
(b) receptacle
(c) epicarp
(d) mesocarp.
Answer. D
Question. Juicy hair-like structures observed in the lemon fruit develop from
(a) exocarp
(b) mesocarp
(c) endocarp
(d) mesocarp and endocarp.
Answer. C
Question. Geocarpic fruit is
(a) potato
(b) peanut
(c) onion
(d) garlic.
Answer. B
Question. Edible part in mango is
(a) mesocarp
(b) epicarp
(c) endocarp
(d) epidermis.
Answer. A
Question. Edible part of banana is
(a) epicarp
(b) mesocarp and less developed endocarp
(c) endocarp and less developed mesocarp
(d) epicarp and mesocarp.
Answer. C
Question. Geocarpic fruit is
(a) carrot
(b) radish
(c) groundnut
(d) turnip.
Answer. C
Question. Which plant will lose its economic value, if its fruits are produced by induced parthenocarpy?
(a) Orange
(b) Banana
(c) Grape
(d) Pomegranate
Answer. D
Question. Which of the following is a ‘true fruit’?
(a) Banana
(b) Fig
(c) Apple
(d) Pear
Answer. A
Question. Fruit of Mangifera indica is
(a) berry
(b) drupe
(c) capsule
(d) siliqua.
Answer. B
Question. Mango juice is obtained from
(a) epicarp
(b) mesocarp
(c) endocarp
(d) pericarp and thalamus.
Answer. B
Question. Fruit of groundnut is
(a) legume
(b) caryopsis
(c) berry
(d) nut.
Answer. A
Question. The body of the ovule is fused within the funicle at
(a) hilum
(b) micropyle
(c) nucellus
(d) chalaza.
Answer. A
Question. Cotyledon of maize grain is called
(a) coleoptile
(b) scutellum
(c) plumule
(d) coleorhiza.
Answer. B
Question. The wheat grain has an embryo with one large, shield shaped cotyledon known as
(a) scutellum
(b) coleoptile
(c) epiblast
(d) coleorhiza.
Answer. A
Question. Which one of the following statements is correct?
(a) The seed in grasses is not endospermic.
(b) Mango is a parthenocarpic fruit.
(c) A proteinaceous aleurone layer is present in maize grain.
(d) A sterile pistil is called a staminode.
Answer. C
Case Based MCQs
Direction Read the following and answer the questions that follow
Flower morphology consists of a large number of parameters, including the number and shape of petals, number of stamens, petal size and number and arrangement of styles and ovaries. Some of these characters, for example, the size of floral organs, seem to be controlled by several genes, whereas single (five petals) versus double (> 10 petals) was shown to be inherited by a single gene. Wild rose species (with the exception of Rosa sericea and Rosa omeiensis) normally have five petals but a variable number of stamens and styles.
Question. A modified shoot wherein the shoot apical meristem changes into floral meristem is known as
(a) inflorescence
(b) thalamus
(c) peduncle
(d) flower
Answer. D
Question. Individual flowers are attached to inflorescence axis by
(a) peduncle
(b) petiole
(c) pedicel
(d) bract
Answer. C
Question. A flower which can be divided into two exactly equal halves by any vertical plane passing through centre is
(a) zygomorphic
(b) actinomorphic
(c) hypogynous
(d) epigynous
Answer. B
Question. Epipetalous is condition of
(a) placentation
(b) position of ovary
(c) stamens
(d) aestivation of petals
Answer. C
Question. Match the following columns.
Column I Column II
A. Calyx and corolla 1. Bisexual
B. Androecium and 2. Unisexual
gynoecium
C. A flower having either 3. Accessory organs
only stamen or
only carpels
D. When a flower 4. Reproductive organs
has both
androecium
and gynoecium
Codes
A B C D
(a) 3 4 2 1
(b) 4 3 1 2
(c) 1 2 4 3
(d) 2 1 3 4
Answer. A
Identify the given representation of flower with its various parts and answer the questions that follows
Question. Choose the incorrect match for the labels A, B, C and D in the above figure.
(a) A–Androecium
(b) B–Gynoecium
(c) C–Pedicel
(d) D–Calyx
Answer. C
Question. The term ‘polyadelphous’ is related to
(a) gynoecium
(b) androecium
(c) corolla
(d) calyx
Answer. B
Question. Ovary is half-inferior in the flowers of
(a) guava
(b) plum
(c) brinjal
(d) cucumber
Answer. B
Question. The enlarged basal part on which lies the elongated tube of style is
(a) corolla
(b) calyx
(c) ovary
(d) ovule
Answer. C
Question. Trimerous, tetramerous and pentamerous are terms related to
(a) placentation
(b) position of ovary
(c) number of floral appendages
(d) number of stamens
Answer. C
Identify the given floral diagram and answer the questions that follow
Question. The given floral formula is of
(a) Aloe
(b) lupin
(c) chilli
(d) All of these
Answer. A
Question. Which of the following is the correct representation of floral diagram given above?
Answer. A
Question. Plants having the above given floral diagram are
(a) leguminous
(b) dicots
(c) medicinal and perennial
(d) having pinnately compound leaves
Answer. C
Question. The given floral formula is of plants belonging to
(a) dicots
(b) monocots
(c) Both dicots and monocots
(d) monoecious plants
Answer. B
Question. Choose the incorrect match for family in the floral diagram.
(a) Fruit – Capsule
(b) Seed – Endospermic
(c) Androecium – Epipetalous
(d) Gynoecium – Inferior ovary
Answer. D
Direction Read the following and answer the questions that follow
Floral formula is a symbolic and numerical representation of various floral parts of a plant family. It helps to ascertain the symmetry, sexuality and the arrangement of various floral parts like calyx, corolla, androecium and gynoecium. It also helps to describe the families of flowering plants in a sequential, brief and scientific language. While writing the floral formula, the bract are represented first, followed by bracteate, symmetry, sex of flower, calyx, corolla, androecium and gynoecium. The number of parts of each structure is indicated in numerals after their relevant symbol.
Question. The number of ‘K’ and ‘C’ in family–Solanaceae is
(a) 5 and 6, respectively
(b) 5 each
(c) 6 each
(d) 3 and 6, respectively
Answer. B
Question. The symbol G(3) represents
(a) tricarpellary gynoecium
(b) inferior ovary
(c) apocarpous ovary
(d) All of the above
Answer. A
Question. Petunia belongs to the family
(a) Liliaceae
(b) Fabaceae
(c) Solanaceae
(d) Orchidaceae
Answer. C
Question. To represent bracteate and actinomorphic condition, which symbol is used?
(a) Brs
(b) Brl%
(c) Brl
(d) Brr
Answer. D
Question. Study and identify the correct conclusions with respect to the floral diagram given below.
I. The calyx has 5 gamosepalous sepals.
II. Corolla has 5 gamopetalous petals.
III. Flowers possess radial symmetry.
IV. Androecium has 5 polyandrous stamens.
Codes
(a) I and II
(b) III and IV
(c) I, II, III and IV
(d) I, II and IV
Answer. C
Very Short Answer Questions (1 mark each)
Question 1. Which part of opuntia is modified to form spines ?
Answer: Leaves are modified into spines in Opuntia to reduce transpiration and provide protection against herbivores.
In simple words: Leaves become sharp spines to save water and protect the plant.
Exam Tip: Remember that leaf modifications in xerophytes primarily serve to conserve water.
Question 2. Name one plant in which leaf is pinnately compound.
Answer: Neem (or Rose, Acacia) is a plant with a pinnately compound leaf where leaflets are arranged on a common axis called the rachis.
In simple words: Neem has leaves divided into many small leaflets along a central stalk.
Exam Tip: Keep common examples like Neem and Rose handy for compound leaf questions.
Question 3. In mangroves, pneumatophores are the modified adventitious roots. How are these roots helpful to the plant ?
Answer: Pneumatophores grow vertically upwards out of the water-logged soil and help the plant get oxygen for respiration.
In simple words: They act like breathing roots in muddy, oxygen-poor soil.
Exam Tip: Link pneumatophores directly with gaseous exchange in halophytes.
Question 4. Which part of mango fruit is edible ?
Answer: The mesocarp (fleshy middle layer) of the fruit is edible in mango.
In simple words: The juicy, pulpy part we eat is the mesocarp.
Exam Tip: Be precise about fruit layers: epicarp (skin), mesocarp (fleshy edible part), and endocarp (hard stone).
Question 5. Why do various plants have different type of phyllotaxy ?
Answer: Different types of phyllotaxy ensure that each leaf receives maximum sunlight for photosynthesis without shading other leaves.
In simple words: It helps every leaf get enough sunlight.
Exam Tip: Mention light capture as the primary adaptive significance of phyllotaxy.
Question 6. State the main function of leaf tendril.
Answer: Leaf tendrils help weak-stemmed plants climb up supports.
In simple words: They coil around objects to support climbing plants.
Exam Tip: Distinguish between stem tendrils and leaf tendrils based on their origin.
Question 7. Which plant family represent the following floral formula: \(\oplus \widehat{P}_{3+3} A_{3+3} \underline{G}_{(3)}\)
Answer: Liliaceae family.
In simple words: This formula belongs to the lily family.
Question 8. The endosperm is formed as a result of double fertilisation (triple fusion). What is its function ?
Answer: The primary function of the endosperm is to store food and provide nourishment to the developing embryo.
In simple words: It acts as a food store for the growing baby plant.
Exam Tip: Mention triple fusion and its triploid nature (\(3n\)) for complete credit.
Question 9. Which type of venation do you observe in dicot leaf ?
Answer: Reticulate venation, where veinlets form a network.
In simple words: Dicot leaves have a net-like web of veins.
Question 10. In pea flower, the aestivation in corolla is known as vexillary. Give reason.
Answer: In vexillary aestivation, there are five petals: the largest posterior petal (standard) overlaps two lateral petals (wings), which in turn overlap the two smallest anterior petals (keel).
In simple words: The petals overlap in a specific overlapping pattern characteristic of legumes.
Exam Tip: Use the terms standard (banner), wings, and keel when describing vexillary aestivation.
Question 11. What is the name given to the cotyledon in case of Monocots
Answer: Scutellum.
In simple words: The single cotyledon in monocots is called the scutellum.
Question 12. Flower is a modified shoot. Justify.
Answer: A flower is considered a modified shoot because the shoot apical meristem changes to a floral meristem, internodes do not elongate, the axis gets condensed, and different floral appendages (sepals, petals, stamens, and carpels) arise at successive nodes instead of leaves.
In simple words: The stem stops growing long and packs its leaves closely together to form floral parts.
Question 13. Name the type of root for the following :
(a) Roots performing the function of photosynthesis.
(b) Roots come above the surface of the soil to absorb air.
(c) The pillar like roots developed from lateral branches for providing mechanical support.
(d) Roots coming out of the lower nodes of the stem and provide the support to the plant.
Answer:
(a) Assimilatory roots
(b) Respiratory roots (Pneumatophores)
(c) Prop roots
(d) Stilt roots
In simple words: Different roots perform special jobs like breathing, climbing support, and extra mechanical strength.
Question 14. Fill up the blank spaces (a), (b), (c) and (d) in the table given below :
| Type of flower | Position of calyx, corolla and androecium in respect of the ovary on thalamus | Type of ovary |
|---|---|---|
| Hypogynous | (a) Floral parts are situated below the ovary | Superior |
| Perigynous | On the rim of the thalamus almost at the same level of ovary. | (b) Half inferior |
| (c) Epigynous | (d) Floral parts are situated above the ovary | Inferior |
Answer:
(a) Floral parts are situated below the ovary.
(b) Half inferior.
(c) Epigynous.
(d) Floral parts are situated above the ovary.
In simple words: The terms describe how floral parts are placed relative to the ovary.
Exam Tip: Practice drawing diagrams of hypogynous, perigynous, and epigynous flowers.
Question 15. Provide the scientific terms for the following :
(i) The leaf without a petiole (stalk).
(ii) The flat and expanded portion of a leaf.
(iii) Orderly arrangement of leaves on the node.
(iv) Lateral appendages on either side of the leaf.
Answer:
(i) Sessile
(ii) Lamina (Leaf blade)
(iii) Phyllotaxy
(iv) Stipules
In simple words: These are standard botanical terms for leaf structures.
Exam Tip: Learn exact morphological terminology for full marks in definitions.
Short Answer Questions - I (3 marks each)
Question 16. Observe the given figure showing various types of placentation. Identify the type of plancentation. Give one example of each.
Answer:
(a) Marginal placentation - Example: Pea
(b) Parietal placentation - Example: Mustard / Argemone
(c) Axile placentation - Example: China rose / Tomato / Lemon
In simple words: Placentation is how ovules are attached inside the ovary.
Exam Tip: Distinguish axile (multilocular with central axis) from free central (unilocular without septa).
Question 17. 'Potato is a stem and sweet potato is a root.' Justify the statement on the basis of external features.
Answer: Potato is a modified underground stem (tuber) because it possesses nodes (eyes) containing buds subtended by leaf scars, and can sprout new shoots. Sweet potato is a modified adventitious root (tuberous root) because it lacks nodes, internodes, and true buds.
In simple words: Potato has buds and eyes like a stem, while sweet potato has none, acting like a swollen root.
Exam Tip: The presence of nodes and buds is the definitive proof of a stem.
Question 18. Define aestivation. Which type of aestivation is found in China rose, Calotropis Gulmohar and pea.
Answer: Aestivation is defined as the mode of arrangement of sepals or petals in a floral bud with respect to other members of the same whorl.
- China rose: Twisted aestivation
- Calotropis: Valvate aestivation
- Gulmohar: Imbricate aestivation
- Pea: Vexillary aestivation
In simple words: Aestivation is how floral petals or sepals overlap inside the bud.
Exam Tip: Memorize the four main types of aestivation with their textbook examples.
Question 19. Explain the different types of phyllotaxy. Give one example of each type.
Answer:
1. Alternate phyllotaxy: A single leaf arises at each node in an alternate manner. Example: China rose, Mustard.
2. Opposite phyllotaxy: A pair of leaves arise at each node and lie opposite to each other. Example: Calotropis, Guava.
3. Whorled phyllotaxy: More than two leaves arise at a node and form a whorl. Example: Alstonia, Nerium.
In simple words: Phyllotaxy tells us how leaves are arranged along the stem.
Exam Tip: Use clear diagrams or bullet points for differences in leaf arrangements.
Question 20. Differentiate between :
(a) Actinomorphic flower and Zygomorphic flower
(b) Apocarpous ovary and Syncarpous ovary
(c) Racemose inflorescence and Cymose inflorescence
Answer:
(a) Actinomorphic flower can be divided into two equal radial halves in any radial plane passing through the centre (e.g., Mustard). Zygomorphic flower can be divided into two similar halves only in one particular vertical plane (e.g., Pea).
(b) Apocarpous ovary has multiple free carpels (e.g., Nelumbo). Syncarpous ovary has fused carpels (e.g., Tomato).
(c) Racemose inflorescence has unlimited main axis growth with flowers borne in acropetal succession. Cymose inflorescence has limited main axis growth terminating in a flower with basipetal succession.
In simple words: These are structural differences in flower symmetry, ovary carpel fusion, and flower cluster growth patterns.
Exam Tip: Contrast acropetal (younger flowers at top) with basipetal (younger flowers at base) succession.
Question 21. In the given structure of a Monocotyledonous seed label the parts a, b, c, d, e. Give the function of part 'a'
Answer:
(a) Endosperm
(b) Plumule
(c) Coleoptile
(d) Coleorhiza
(e) Scutellum
Function of (a) Endosperm: Stores food and provides nourishment to the developing embryo during seed germination.
In simple words: Parts of a monocot seed include the food-storing endosperm and protective sheaths.
Exam Tip: Learn coleoptile (protects plumule) and coleorhiza (protects radicle) carefully.
Long Answer Questions (5 marks each)
Question 22. Describe various stem modifications associated with food storage, climbing and protection.
Answer:
1. Food Storage: Underground stems like rhizomes (ginger), tubers (potato), bulbs (onion), and corms (colocasia) store food and help tide over unfavorable conditions.
2. Climbing: Stem tendrils develop from axillary buds and help weak stems climb, such as in cucumbers, grapevines, and watermelons.
3. Protection: Axillary buds of stems get modified into woody, straight, and pointed thorns to protect plants from grazing animals, as seen in Bougainvillea and Citrus.
In simple words: Stems can change their form to store food, help the plant climb, or protect against animals.
Exam Tip: Give precise examples for each modification to secure full marks.
Question 23. Give the distinguishing morphological features of gynoecium of family Fabaceae, Solanaceae and Liliaceae. Draw floral diagrams of Fabaceae and Solanaceae.
Answer:
- Family Fabaceae: Ovary superior, monocarpellary, unilocular with many ovules along the marginal suture, single style.
- Family Solanaceae: Ovary superior, bicarpellary, syncarpous, bilocular, ovary swollen with many ovules on axile placentation.
- Family Liliaceae: Ovary superior, tricarpellary, syncarpous, trilocular with many ovules on axile placentation.
In simple words: Each family has a distinct carpel number, chamber count, and placenta layout in the ovary.
Exam Tip: Practice drawing standard floral diagrams and writing floral formulas for these three families.
Free study material for Biology
Chapter Assignment & Practice Material for Class 11 Biology Chapter 05 Morphology Of Flowering Plants
Revision Assignment: Chapter 05 Morphology Of Flowering Plants (CBSE)
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