CBSE Class 9 Maths Areas of Parallelogram and Triangle MCQs Set B with answers available in Pdf for free download. The MCQ Questions for Class 9 Mathematics with answers have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Standard 9 by CBSE, NCERT and KVS. Multiple Choice Questions are an important part of Term 1 and Term 2 exams for Grade 9 Mathematics and if practiced properly can help you to get higher marks. Refer to more Chapter-wise MCQs for NCERT Class 9 Mathematics and also download more latest study material for all subjects

## Areas of Parallelogram and Triangle Class 9 MCQ

Class 9 Mathematics students should refer to the following multiple-choice questions with answers for Areas of Parallelogram and Triangle in standard 9. These MCQ questions with answers for Grade 9 Mathematics will come in exams and help you to score good marks

### Class 9 Areas of Parallelogram and Triangle MCQ Questions with Answers

**1. D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC, then ar (DEF)**

(a) ar(ABC) (b) 1/2ar(ABC) (c) 1/3 ar(ABC) (d) 1/4 ar(ABC)

**2. D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC, then ar (BDEF)**

(a) ar(ABC) (b) 1/2ar(ABC) (c) 1/3ar(ABC) (d) 1/4ar(ABC)

**3. In a triangle ABC, E is the mid-point of median AD, then ar (BED) =**

(a) ar(ABC) (b) 1/2ar(ABC) (c) 1/3ar(ABC) (d) 1/4ar(ABC)

**4. In ΔABC, E is any point on median AD then ar (ABE) =**

(a) ar(ACE) (b) 1/2ar(ACE) (c) 1/3ar(ACE) (d) 1/4ar(ACE)

**5. ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O then ar(ABC) =**

(a) ar(ABD) (b) 1/2ar(ABD) (c) 1/3ar(ABD) (d) 1/4ar(ABD)

**6. In Fig. ABCD is a quadrilateral and BE || AC and also BE meets DC produced at E then the area of ΔADE is ______ to the area of the quadrilateral ABCD.**

(a) half (b) one third (c) one fourth (d) equal

**7. In the above sided Fig, P is a point in the interior of a parallelogram ABCD then ar (APB) + ar(PCD) =**

(a) ar(ABCD) (b) 1/2ar(ABCD) (c) 1/3ar(ABCD) (d) 1/4ar(ABCD)

**8. In Fig, PQRS and ABRS are parallelograms and X is any point on side BR then ar (AX S) =**

(a) ar(PQRS) (b) 1/2ar(PQRS) (c) 1/3ar(PQRS) (d) 1/4ar(PQRS)

**9. In Fig, PQRS and ABRS are parallelograms and X is any point on side BR then ar (ABRS) =**

(a) ar(PQRS) (b) 1/2ar(PQRS) (c) 1/3ar(PQRS) (d) 1/4ar(PQRS)

**10. P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD then ar (APB) =**

(a) ar(BQC) (b) 1/2ar(BQC) (c) 1/3ar(BQC) (d) 1/4ar(BQC)

**11. In the below figure, ABCD is trapezium in which AB || DC and its diagonals AC and BD intersect at O then ar(AOD) =**

(a) ar(BOC) (b) 1/2ar(BOC) (c) 1/3ar(BOC) (d) 1/4ar(BOC)

**12. In the adjoining figure, ABCD is a quadrilateral in which diagonal BC = 14 cm. If AL BD and CM BD such that AL = 8cm and CM = 6 cm, then the area of quadrilateral is**

(a) 90 cm^{2} (b) 95 cm^{2} (c) 98 cm^{2} (d) none of these

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