NEET Physics Time Period Frequency Simple Pendulum and Spring Pendulum MCQs Set B

Question. A simple harmonic motion has an amplitude A and time period T. The time required by it to travel from x = A to x = A/2 is
(a) T/6
(b) T/4
(c) T/3
(d) T/2

Answer: A

Question. If the maximum velocity and acceleration of a particle executing SHM are equal in magnitude, the time period will be
(a) 6.28 sec
(b) 3.14 sec
(c) 12.56 sec
(d) 1.57 sec

Answer: A

Question. A simple pendulum oscillates in air with time period T and amplitude A. As the time passes
(a) T remains same and A decreases
(b) None of these
(c) T decreases and A is constant
(d) T and A both decrease

Answer: A

Question. Which of the following will change the time period as they are taken to moon?
(a) A simple pendulum
(b) A physical pendulum
(c) A spring-mass system
(d) A torsional pendulum

Answer: A

Question. For an oscillating simple pendulum, the tension in the string is
(a) maximum at mean position
(b) constant throughout the motion
(c) cannot be predicted
(d) maximum at extreme position

Answer: A

Question.  A simple pendulum is set into vibrations. The bob of the pendulum comes to rest after some time due to
(a) Air friction
(b) Moment of inertia
(c) Weight of the bob
(d) Combination of all the above

Answer: A

Question. The ratio of energies of oscillations of two exactly identical pendulums oscillating with amplitudes 5 cm and 10 cm is
(a) 1 : 4
(b) 2 : 1
(c) 1 : 2
(d) 4 : 1

Answer: A

Question. A child swinging on swing in sitting position stands up. The time period of the swing will
(a) decrease
(b) increase
(c) remain same
(d) increase if the child is tall and decrease if the child is short.

Answer: A

Question.  Select the correct statement(s) from the following
I. Motion of a satellite and a planet is periodic as well as SHM.
II. Mass suspended by a spring executes SHM.
III. Motion of a simple pendulum is always SHM.
(a) II only
(b) I and II
(c) I only
(d) I, II and III

Answer: A

Question.  A pendulum is undergoing S.H.M. The velocity of the bob in the mean position is v. If now its amplitude is doubled, keeping the length same, its velocity in the mean position will be
(a) 2 v
(b) v
(c) v/2
(d) 4 v

Answer: A

Question.  Choose the correct statement
(a) The graph between length of the pendulum and time period is a parabola.
(b) In a simple pendulum time period varies linearly with the length of the pendulum
(c) Time shown by a spring watch varies with acceleration due to gravity g.
(d) Time period of a simple pendulum depends on amplitude.

Answer: A

Question.  A particle executing simple harmonic motion covers a distance equal to half of its amplitude in one second. Then the time period of the simple harmonic motion is
(a) 12 s
(b) 8 s
(c) 6 s
(d) 4 s

Answer: A

Question. The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The period of oscillation is
(a) 0.01 s
(b) 10 s
(c) 0.1 s
(d) 100 s

Answer: A

Question.  Two pendulums of lengths 1.44 m and 1 m start to swing together. The number of vibrations after which they will again start swinging together is
(a) 5
(b) 2
(c) 3
(d) 4

Answer: A

Question. When two springs A and B with force constants k_A and k_B are stretched by the same force, then the respective ratio of the work done on them is
(a) k_B : k_A
(b) k_A : k_B
(c) k_Ak_B : 1
(d) None of these

Answer: A

Question.  The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is
(a) 10%
(b) 42%
(c) 21%
(d) 11%

Answer: A

Question.  The height of liquid column in a U tube is 0.3 m. If the liquid in one of the limbs is depressed and then released, then the time period of the liquid column will be
(a) 1.1 sec
(b) 2 sec
(c) 19 sec
(d) 0.11 sec

Answer: A

Question.  A wall clock uses a vertical spring-mass system to measure the time. Each time the mass reaches an extreme position, the clock advances by a second. The clock gives correct time at the equator. If the clock is taken to the poles it will
(a) give correct time
(b) run slow
(c) stop working
(d) run fast

Answer: A