CBSE Class 9 Mathematics Surface Areas And Volumes Notes Set 01

CBSE Class 9 Concepts for Surface Areas and Volumes. Learning the important concepts is very important for every student to get better marks in examinations. The concepts should be clear which will help in faster learning. The attached concepts made as per NCERT and CBSE pattern will help the student to understand the chapter and score better marks in the examinations. 

Chapter 13

Surface Areas and Volumes

Chapter Notes

Top Definitions

1. A Cube is a special type of cuboids in which length = breadth = height. Also called an edge of a cube.

2. A sphere is a perfectly round geometrical object in three-dimensional space, such as the shape of a round ball.

3. A cylinder is a solid or a hollow object that has a circular base and a circular top of the same size.

4. A hemisphere is half of a sphere.

5. If a right circular is cut off by a plane parallel to its base, then the portion of the cone between the plane and the base of the cone is called a frustum of the cone.

Top Concepts

1. The total surface area of the solid formed by the combination of solids is the sum of the curved surface area of each of the individual parts.

2. A solid is melted and converted to another, volume of both the solids remains the same, assuming there is no wastage in the conversions. The surface area of the two solids may or may not be the same.

3. A frustum can be obtained by cutting a cone by a plane, parallel to the base of the cone.

4. The solids having the same curved surface do not necessarily occupy the same volume.

Top Formulae

1. Cuboids:

Lateral surface area Or Area of four walls = 2(ℓ + b) h

Total surface area = 2(ℓb + bh + hℓ)

Volume = ℓ x b x h

Diagonal of a cuboids = √l² + b² + h²

2. Cube Lateral surface area Or Area of four walls = 4 x (edge)² Total surface area = 6 x (edge)² Volume = (edge)³ Diagonal of a cube = 3 x edge.

3. Right circular cylinder: Area of each end or Base area = pr² Area of curved surface or lateral surface area = perimeter of the base x height = 2p r h
Total surface area (including both ends) = 2 prh + 2pr² = 2pr (h + r) Volume = (Area of the base0 x height = pr²h

4. Right circular hollow cylinder: Area of curved surface

= (External surface) + (Internal surface)

= (2pRh + 2prh) = 2 (pR² - pr²)

= [2ph(R+ r) + 2p (R² - r²)]

= [2p(R + r) (h + R – r)]

Volume of the material

= (External volume) – (Internal volume)

= (pR²h - pr²h) = ph (R² - r²)

5. Right circular cone:

Slant height (ℓ) = √h² + r²

Area of curved surface = prℓ = pr √h² + r²

Total surface area = Area of curved surface + Area of base = prℓ + pr² = pr (ℓ + r) Volume = 1/3pr²

6. Sphere:

Surface area = 4 pr²

Volume = 4/3pr³ 

7. Spherical shell:

Surface area (outer) = 4pR²

Volume of material =4/3 pr³ - 4/3 pr³= 4/3p (R³ - r³)

8. Hemisphere:

Area of curved surface = 2 pr²

Total surface Area = Area of curved surface + Area of base

                           = 2 pr² + pr²

                           = 3pr²

Volume = 2/3(pr³⁾

9. Frustum of a cone:

Total surface area = p[R² + r² + ℓ (R + r)]

Volume of the material =1/3ph (R² + r² + Rr)

Please click the link below to download pdf file for CBSE Class 9 Concepts for Surface Areas and Volumes.