CBSE Class 6 Mathematics Revision Worksheet Set 06

Choose the correct option in Q. 1, 2 and 3

Question 1. A book of 1,456 pages has 9,95,904 words in it. The number of words in each page is
(a) 584
(b) 684
(c) 675
(d) 595
Answer: (b) 684
Total number of words = 995904
Total number of pages = 1456
Words per page = \(\frac{995904}{1456} = 684\)
In simple words: Divide the total number of words in the book by the total number of pages to find the words on a single page.

Exam Tip: Perform division carefully or check using multiplication (\(1456 \times 684 = 995904\)) to verify your answer.

Question 2. 5050501 - 969696 is
(a) 4080805
(b) 418225
(c) 4080885
(d) 418235
Answer: (c) 4080885
\(5050501 - 969696 = 4080885\)
In simple words: Subtract the second number from the first number by properly aligning the digits according to their place values.

Exam Tip: Always double check borrowing steps in subtraction to avoid calculation errors.

Question 3. 5628 + 39784 is
(a) 45400
(b) 45412
(c) 45410
(d) 45422
Answer: (b) 45412
\(5628 + 39784 = 45412\)
In simple words: Add the two numbers column by column from right to left, carrying over where necessary.

Question 3(i). Add the following: 923584 and 166799
Answer: \(923584 + 166799 = 1090383\)
In simple words: Combine both numbers using standard addition.

Exam Tip: Write the numbers one below the other aligning the place values correctly.

Question 3(ii). Add the following: 3718925 and 4292918
Answer: \(3718925 + 4292918 = 8011843\)
In simple words: Add the two numbers together step by step from the units place.

Exam Tip: Keep track of carryovers carefully when adding digits in large numbers.

Question 3(iii). Add the following: 2296634, 4829963 and 1789508
Answer: \(2296634 + 4829963 + 1789508 = 8916105\)
In simple words: Add all three numbers together by lining up their place values.

Exam Tip: When adding three numbers, you can add the first two and then add the third to the result.

Question 4(1). Add and write the sum in words: 3978412 and 5432106
Answer:
\(3978412 + 5432106 = 9410518\)
Sum in words: Nine million four hundred ten thousand five hundred eighteen (or Ninety-four lakh ten thousand five hundred eighteen in the Indian system).
In simple words: First find the sum of the numbers, then write that final number in word form.

Exam Tip: Mention the number system (Indian or International) clearly when writing large numbers in words.

Question 4(2). Add and write the sum in words: 437819 and 829519
Answer:
\(437819 + 829519 = 1267338\)
Sum in words: Twelve lakh sixty-seven thousand three hundred thirty-eight.
In simple words: Add the given numbers and convert the result into words.

Exam Tip: Check spelling for number names like thousand, hundred, and thirty-eight.

Question 5(i). Find the difference between the given numbers: 5050501 and 969696
Answer:
\(5050501 - 969696 = 4080805\)
In simple words: Subtract the smaller number from the larger number.

Exam Tip: Borrow correctly across zeros when performing subtraction.

Question 5(ii). Find the difference between the given numbers: 578397 and 298098
Answer:
\(578397 - 298098 = 280299\)
In simple words: Find the difference by subtracting the second number from the first.

Exam Tip: Align columns properly to avoid place value mistakes.

Question 6(i). Multiply and express the product in words: 5217 × 325
Answer:
\(5217 \times 325 = 1695525\)
Product in words: Sixteen lakh ninety-five thousand five hundred twenty-five.
In simple words: Multiply the two numbers and write the resulting product in words.

Exam Tip: Lay out multiplication steps clearly by multiplying by units, tens, and hundreds digits separately.

Question 6(ii). Multiply and express the product in words: 2032 × 613
Answer:
\(2032 \times 613 = 1245616\)
Product in words: Twelve lakh forty-five thousand six hundred sixteen.
In simple words: Compute the product of 2032 and 613, then translate the number into words.

Exam Tip: Double-check intermediate multiplication products before adding them together.

Question 6(iii). Multiply and express the product in words: 2586 × 1008
Answer:
\(2586 \times 1008 = 2606688\)
Product in words: Twenty-six lakh six thousand six hundred eighty-eight.
In simple words: Multiply 2586 by 1008 and write the final answer in words.

Exam Tip: Handle zeros in the multiplier carefully during long multiplication.

Question 7(i). Divide and find the quotient and remainder: 16135 by 875
Answer:
Quotient = 18
Remainder = 385
In simple words: Divide 16135 by 875 to get 18 with a leftover of 385.

Exam Tip: Verify division using the relation: Dividend = (Divisor × Quotient) + Remainder.

Question 7(ii). Divide and find the quotient and remainder: 46087 by 356
Answer:
Quotient = 129
Remainder = 163
In simple words: Perform long division of 46087 by 356.

Exam Tip: Ensure each digit brought down in long division is accounted for.

Question 7(iii). Divide and find the quotient and remainder: 55390 by 299
Answer:
Quotient = 185
Remainder = 115
In simple words: Divide 55390 by 299 using long division.

Exam Tip: Round the divisor mentally to estimate the quotient digit for each step.

Question 8. The digits 6 and 9 of the number 36490 are interchanged. Find the difference between the original number and the new number
Answer:
Original number = 36490
New number (after interchanging 6 and 9) = 39460
Difference = \(39460 - 36490 = 2970\)
In simple words: Swap the positions of digits 6 and 9 to form the new number, then find the difference between the two numbers.

Exam Tip: Read place value instructions carefully when swapping digits.

Question 9. A dealer purchased 125 colour television sets. If the cost of each set is Rs. 19820, determine the cost of all sets together?
Answer:
Number of television sets = 125
Cost of each television set = Rs. 19820
Total cost = \(125 \times 19820 = \text{Rs. } 2477500\)
In simple words: Multiply the number of TV sets by the cost of each set to find the total amount.

Exam Tip: Include the currency unit (Rs.) in your final statement.

Question 10. A group housing society constructed 350 flats. If the cost of construction of each flat is Rs. 993570, what is the total cost of construction of each flat?
Answer:
Number of flats = 350
Cost of construction of each flat = Rs. 993570
Total cost of construction = \(350 \times 993570 = \text{Rs. } 347749500\)
In simple words: Multiply the total number of flats by the construction cost of a single flat.

Exam Tip: Take extra care with multiplication involving trailing zeros.