CBSE Class 6 Mathematics Decimals Worksheet Set 09

Class 6 Mathematics Practice Sheet: CBSE Class 6 Mathematics Decimals Worksheet Set 09

Explore structured practice materials through the CBSE Class 6 Mathematics Decimals Worksheet Set 09. Tailored for Class 6 learners, utilizing these Mathematics worksheets ensures thorough preparation and strengthens problem-solving accuracy before final school evaluations.

Download Chapter 08 Decimals Worksheet PDF with Answers

View or download the dedicated CBSE Class 6 Mathematics Decimals Worksheet Set 09 resource below. Engaging with these practice papers under focused study conditions ensures continuous academic progress and mastery of the 2026-27 curriculum for Chapter 08 Decimals.

Question 1. Which of the following is greater? 1.008 or 1.800
(A) 1.008
(B) 1.800
(C) Both are equal
(D) None of the options
Answer: (B) 1.800
Comparing the whole number parts, both are 1. Comparing the tenths place, 1.800 has 8 in the tenths place while 1.008 has 0. Since \(8 > 0\), \(1.800 > 1.008\).
In simple words: 1.800 is greater than 1.008 because 8 in the tenths place is greater than 0.

Exam Tip: Always compare decimals digit by digit from left to right starting from the whole number part.

 

Question 2. 64.2 in fraction form reduced to the lowest term would be _____.
(A) \(\frac{403}{5}\)
(B) \(\frac{321}{5}\)
(C) \(\frac{221}{5}\)
(D) \(\frac{121}{5}\)
Answer: (B) \(\frac{321}{5}\)
\(64.2 = \frac{642}{10}\)
Dividing both numerator and denominator by 2:
\(\frac{642 \div 2}{10 \div 2} = \frac{321}{5}\)
In simple words: Remove the decimal point by dividing by 10, then simplify the fraction by dividing top and bottom by 2.

Exam Tip: Convert decimals to fractions by putting 1 followed by zeros equal to decimal places, then reduce.

 

Question 3. Convert 70 km and 5m in km's.
(A) 70.005 km
(B) 7.005 km
(C) 7.05 km
(D) 70000.5 km
Answer: (A) 70.005 km
Since \(1 \text{ m} = \frac{1}{1000} \text{ km} = 0.001 \text{ km}\),
\(5 \text{ m} = \frac{5}{1000} \text{ km} = 0.005 \text{ km}\).
Total distance = \(70 \text{ km} + 0.005 \text{ km} = 70.005 \text{ km}\).
In simple words: Convert meters to kilometers by dividing by 1000 and add it to 70.

Exam Tip: Remember that 1 km = 1000 m, so small units of meters take three decimal places in kilometers.

 

Question 4. Express 15.038 km without decimal.
(A) 15038 km
(B) 15038 m
(C) 15038 cm
(D) 15038 dm
Answer: (B) 15038 m
\(1 \text{ km} = 1000 \text{ m}\)
\(15.038 \text{ km} = 15.038 \times 1000 \text{ m} = 15038 \text{ m}\).
In simple words: Multiply kilometers by 1000 to convert into meters and remove the decimal.

Exam Tip: Multiplying a decimal by 1000 shifts the decimal point three places to the right.

 

Question 5. Subtract : 238.53 m from 250 m
(A) 101.47 m
(B) 130.40 m
(C) 11.47 m
(D) 23.23 m
Answer: (C) 11.47 m
\(250.00 - 238.53 = 11.47 \text{ m}\).
In simple words: Write 250 as 250.00 and subtract 238.53 from it.

Exam Tip: Always align decimal points vertically when adding or subtracting decimals.

 

Question 6. Two tens and 9 tenth can be written as ________.
(A) 20.09
(B) 20.9
(C) 200.9
(D) None of the options
Answer: (B) 20.9
Two tens = \(2 \times 10 = 20\)
9 tenth = \(9 \times \frac{1}{10} = 0.9\)
Sum = \(20 + 0.9 = 20.9\).
In simple words: Two tens make 20 and 9 tenths make 0.9, which combines to 20.9.

Exam Tip: Place values to the left of the decimal are tens, ones, etc., and to the right are tenths, hundredths, etc.

 

Question 7. Which of the following shows \(200 + 60 + 5 + \frac{1}{10}\) in the decimal form?
(A) 26.51
(B) 265.1
(C) 2065.1
(D) 2.651
Answer: (B) 265.1
\(200 + 60 + 5 = 265\)
\(\frac{1}{10} = 0.1\)
Total = \(265 + 0.1 = 265.1\).
In simple words: Add the whole numbers to get 265 and write the fraction \(\frac{1}{10}\) as 0.1 after the decimal point.

Exam Tip: Expanded form components easily translate directly into standard decimal notation.

 

Question 8. Express 360 mm as metre.
(A) 36 m
(B) 3.06 m
(C) 3.6 m
(D) 0.36 m
Answer: (D) 0.36 m
\(1 \text{ m} = 1000 \text{ mm}\)
\(360 \text{ mm} = \frac{360}{1000} \text{ m} = 0.36 \text{ m}\).
In simple words: Divide millimeters by 1000 to convert to meters.

Exam Tip: To convert smaller units to larger units, always divide by the conversion factor.

 

Question 9. 5.4 lies in between which two whole numbers?
(A) 0 - 1
(B) 4 - 5
(C) 5 - 6
(D) 10 - 11
Answer: (C) 5 - 6
Since \(5 < 5.4 < 6\), the decimal 5.4 lies between the whole numbers 5 and 6.
In simple words: Look at the whole number part of 5.4, which is 5; hence it lies between 5 and the next whole number 6.

Question 10. Which of the following is the decimal number represented by the point A on the given number line?
(A) 9.9
(B) 9.7
(C) 9.8
(D) 9.2
Answer: (C) 9.8
The number line goes from 9 to 10 with 10 equal subdivisions, where each tick mark represents 0.1. Point A is at the 8th tick mark after 9, which is 9.8.
In simple words: Count the small divisions after 9 to find the exact decimal value at point A.

Exam Tip: Count the number of subdivisions between two integers to determine the value of each tick mark.

 

Question 11. The length of Harsh's book is 8 cm 4 mm. What will be the length in cm?
(A) 8.4 cm
(B) 8.6 cm
(C) 0.86 cm
(D) None of the options
Answer: (A) 8.4 cm
\(4 \text{ mm} = \frac{4}{10} \text{ cm} = 0.4 \text{ cm}\)
Total length = \(8 \text{ cm} + 0.4 \text{ cm} = 8.4 \text{ cm}\).
In simple words: Convert 4 mm into 0.4 cm and add it to 8 cm.

Exam Tip: 1 cm = 10 mm, so millimeters form the tenths place when expressing centimeters as a decimal.

 

Question 12. Which of the following is correct decimal form of \(30 + \frac{8}{10} + \frac{7}{100} + \frac{5}{1000}\)?
(A) 308.75
(B) 3087.5
(C) 30.875
(D) 30875
Answer: (C) 30.875
\(30 + 0.8 + 0.07 + 0.005 = 30.875\).
In simple words: Combine the whole number 30 with tenths (8), hundredths (7), and thousandths (5).

Exam Tip: Each fraction denominator represents a fixed decimal place value after the decimal point.

 

Question 13. Which of the following is fractional form of decimal 0.066 in the lowest term?
(A) \(\frac{30}{500}\)
(B) \(\frac{33}{500}\)
(C) \(\frac{31}{500}\)
(D) \(\frac{32}{500}\)
Answer: (B) \(\frac{33}{500}\)
\(0.066 = \frac{66}{1000}\)
Dividing numerator and denominator by 2:
\(\frac{66 \div 2}{1000 \div 2} = \frac{33}{500}\)
In simple words: Convert 0.066 to \(\frac{66}{1000}\) and simplify by dividing by 2.

Exam Tip: Always check if numerator and denominator share common factors after initial fraction conversion.

 

Question 14. Convert the Rs 5 and 25 paisa into decimal form?
(A) Rs 5.025
(B) Rs 50.25
(C) Rs 5.25
(D) None of the options
Answer: (C) Rs 5.25
\(25 \text{ paisa} = \frac{25}{100} \text{ Rs} = \text{Rs } 0.25\)
Total = \(\text{Rs } 5 + \text{Rs } 0.25 = \text{Rs } 5.25\).
In simple words: Since 100 paisa equals 1 rupee, divide 25 by 100 to write it as rupees.

Exam Tip: 1 Rupee = 100 paisa, so paisa values occupy two decimal places.

 

Question 15. How many km are there in 2008 m?
(A) 2.008 km
(B) 20.08 km
(C) 200.8 km
(D) 0.2008 km
Answer: (A) 2.008 km
\(2008 \text{ m} = \frac{2008}{1000} \text{ km} = 2.008 \text{ km}\).
In simple words: Divide 2008 by 1000 by placing the decimal point three digits from the right.

Exam Tip: Division by 1000 moves the decimal point three places to the left.

 

Question 16. Express 725 paisa as rupee.
(A) 0.725 rupees
(B) 72.5 rupees
(C) 7.25 rupees
(D) 725 rupees
Answer: (C) 7.25 rupees
\(725 \text{ paisa} = \frac{725}{100} \text{ rupees} = 7.25 \text{ rupees}\).
In simple words: Divide by 100 to convert paisa into rupees.

Exam Tip: Remember to place the decimal point two digits from the right when dividing by 100.

 

Question 17. Find the sum of \(280.68 + 28.5 + 38\)
(A) 340.08
(B) 345.10
(C) 247.18
(D) 347.18
Answer: (D) 347.18
\(280.68\)
\(+ 28.50\)
\(+ 38.00\)
\(= 347.18\)
In simple words: Line up the decimal points and add the numbers vertically.

Exam Tip: Add trailing zeros to make all numbers have the same number of decimal places before adding.

 

Question 18. Which of the following statements is true?
(A) Every decimal cannot be written as fraction.
(B) All decimals cannot be represented on the number line.
(C) Every fraction with denominator 10 can be written in decimal notation and vice versa
(D) All of the above statements are true
Answer: (C) Every fraction with denominator 10 can be written in decimal notation and vice versa
Fractions with powers of 10 in denominators have direct decimal equivalents, and vice versa.
In simple words: Denominators of 10 easily convert to decimals with one decimal place.

Exam Tip: Fractions and decimals are two different ways of representing numbers and are fully convertible.

 

Question 19. Is 0.6 more than 0 or is less than 0?
(A) More
(B) Less
(C) Equal
(D) Cannot determine
Answer: (A) More
Since \(0.6 > 0\), it is more than 0.
In simple words: Any positive decimal number is greater than zero.

Exam Tip: Numbers greater than zero lie to the right of zero on the number line.

 

Question 20. Write the following numbers in Decimal. Two hundreds five and 3 tenths
Answer: Two hundreds five and 3 tenths = \(200 + 5 + \frac{3}{10} = 205.3$
In simple words: Combine 200 and 5 for the whole number part, and put 3 in the tenths place.

Exam Tip: "And" represents the decimal point separating whole numbers from fractional parts.

 

Question 21. Convert into fractions 2.55
Answer: \(2.55 = \frac{255}{100}\)
Dividing numerator and denominator by 5:
\(\frac{255 \div 5}{100 \div 5} = \frac{51}{20}\)
In simple words: Write 2.55 over 100 and simplify by dividing both numbers by 5.

Exam Tip: Always reduce the resulting fraction to its lowest terms.

 

Question 22. Convert into decimals \(\frac{3}{25}\)
Answer: Multiply numerator and denominator by 4 to make the denominator 100:
\(\frac{3 \times 4}{25 \times 4} = \frac{12}{100} = 0.12\)
In simple words: Make the denominator 100 by multiplying top and bottom by 4, then write as 0.12.

Exam Tip: Converting denominators to powers of 10 makes decimal conversion straightforward.

 

Question 23. Write following numbers into decimal \(9000 + 600 + 60 + 6 + \frac{1}{100} + \frac{2}{10}\)
Answer:
\(9000 + 600 + 60 + 6 = 9666$
\(\frac{2}{10} = 0.2\)
\(\frac{1}{100} = 0.01\)
Total decimal = \(9666 + 0.2 + 0.01 = 9666.21$
In simple words: Add up the whole numbers to get 9666, then place 2 in the tenths place and 1 in the hundredths place.

Exam Tip: Ensure you check the order of fractional parts (tenths before hundredths).

 

Question 24. 13.9 lies in between _____ & _____ nearest to _____ in number lines
Answer: 13.9 lies between 13 & 14, and is nearest to 14.
In simple words: 13.9 is between 13 and 14, and since the decimal part 0.9 is 5 or more, it rounds up to 14.

Exam Tip: A decimal with a fractional part of 0.5 or greater rounds up to the next whole number.

 

Question 25. Write 0.999 in a fraction and also convert it in lowest terms.
Answer: Fraction form = \(\frac{999}{1000}\)
Since 999 and 1000 have no common factors other than 1, it is already in lowest terms: \(\frac{999}{1000}\).
In simple words: Remove the decimal point to write it as \(\frac{999}{1000}\), which cannot be simplified further.

Exam Tip: Check prime factors of numerator and denominator to ensure a fraction is in lowest terms.

 

Question 26. Which is greatest in .0903, 0.00903, .000903 ?
Answer: 0.0903 is the greatest.
Comparing digits from left after the decimal point: 0.0903 has 9 in the hundredths place, whereas 0.00903 has 0 in the hundredths place.
In simple words: 0.0903 is the largest because its first non-zero digit is in a larger place value position (hundredths).

Exam Tip: Pad numbers with trailing zeros to equal length when comparing decimals (\(0.0903\), \(0.00903\), \(0.000903\)).

 

Question 27. Write in words 521.21
Answer: Five hundred twenty-one point two one (or Five hundred twenty-one and twenty-one hundredths).
In simple words: Read the whole number part normally, say "point", and read each decimal digit individually.

Exam Tip: Avoid saying "and" for the decimal point if it causes confusion with whole number place values.

 

Question 28. Convert 445 cm into Km.
Answer:
Since \(1 \text{ m} = 100 \text{ cm}\) and \(1 \text{ km} = 1000 \text{ m}\),
\(1 \text{ km} = 100,000 \text{ cm}\).
\(445 \text{ cm} = \frac{445}{100,000} \text{ km} = 0.00445 \text{ km}\).
In simple words: Divide centimeters by 100,000 to convert directly into kilometers.

Exam Tip: Moving from cm to km requires dividing by 1 followed by 5 zeros.

 

Question 29. Find the sum of : \(207.076 + 0.5257 + 1.005\)
Answer:
\(207.0760\)
\(+ \phantom{2}0.5257\)
\(+ \phantom{2}1.0050\)
\(= 208.6067$
In simple words: Align decimal points, pad with zeros to match decimal places, and add column by column.

Exam Tip: Always make the number of decimal digits equal by adding trailing zeros before addition.

 

Question 30. The decimal form of two tens and nine-tenths is-
(A) 200.9
(B) 20.9
(C) 20.5
(D) 20.6
Answer: (B) 20.9
Two tens = 20, Nine-tenths = 0.9. Sum = \(20 + 0.9 = 20.9\).
In simple words: Combine 20 and 0.9 to get 20.9.

Exam Tip: Tens are in the tens place (left of decimal), tenths are in the first place right of decimal.

 

Question 31. Decimal form of \(300 + 80 + 9 + \frac{3}{10} + \frac{7}{100}\)
(A) 389.36
(B) 389.47
(C) 389.27
(D) 389.37
Answer: (D) 389.37
\(300 + 80 + 9 = 389\)
\(\frac{3}{10} + \frac{7}{100} = 0.37$
Total = \(389.37\).
In simple words: Combine the whole number 389 with 3 tenths and 7 hundredths.

Exam Tip: Match each fractional denominator to its correct decimal place position.

 

Question 32. Reduce the 12.5 in the form of \(\frac{p}{q}\) in simplest form.
(A) 35/2
(B) 25/2
(C) 15/2
(D) None of the options
Answer: (B) 25/2
\(12.5 = \frac{125}{10}\)
Dividing top and bottom by 5:
\(\frac{125 \div 5}{10 \div 5} = \frac{25}{2}\)
In simple words: Write 12.5 as \(\frac{125}{10}\) and divide both numerator and denominator by 5.

Question 33. The length of Shashank's notebook is 8 cm 3 mm. What will be its length in cm?
(A) 8.03 cm
(B) 8.3 cm
(C) 8.3 mm
(D) 8.3 m
Answer: (B) 8.3 cm
\(3 \text{ mm} = 0.3 \text{ cm}\)
Total = \(8 \text{ cm} + 0.3 \text{ cm} = 8.3 \text{ cm}\).
In simple words: 3 millimeters is 0.3 centimeters, which when added to 8 cm gives 8.3 cm.

Exam Tip: 1 centimeter contains 10 millimeters.

 

Question 34. What is the decimal form of 23 rupees 75 paise?
(A) Rs. 23.75
(B) Rs. 23.075
(C) Rs. 23.70
(D) Rs. 23.50
Answer: (A) Rs. 23.75
\(75 \text{ paise} = \text{Rs } 0.75$
Total = \(\text{Rs } 23 + 0.75 = \text{Rs } 23.75\).
In simple words: Divide 75 paisa by 100 to get 0.75 rupees and add to 23.

Exam Tip: Paise values are always written in the first two decimal places of rupees.

 

Question 35. Which is greater in 5.64 and 5.603?
(A) 5.64
(B) 5.603
(C) 5.603, if we add 1 in 5.64
(D) None of the options.
Answer: (A) 5.64
Comparing 5.640 and 5.603, 4 in the hundredths place of 5.64 is greater than 0 in 5.603.
In simple words: 5.64 is greater because 4 in the hundredths place is greater than 0.

Exam Tip: Pad decimals with zeros so they have an equal number of decimal digits before comparing.

 

Question 36. 3 kg 57 g is expressed in g as ……
(A) 30057
(B) 3050
(C) 3570
(D) None of the options.
Answer: (D) None of the options.
\(1 \text{ kg} = 1000 \text{ g}\)
\(3 \text{ kg} = 3000 \text{ g}\)
Total = \(3000 \text{ g} + 57 \text{ g} = 3057 \text{ g}\) (Option A says 30057, which is incorrect).
In simple words: 3 kg is 3000 g, so adding 57 g gives 3057 g.

Exam Tip: Be careful with place values when converting mixed units into grams.

 

Question 37. \(0.008 + 0.003 + 0.95 + 2.345 = ?\)
(A) 3.306
(B) 3.305
(C) 3.307
(D) 3.036
Answer: (A) 3.306
\(0.008\)
\(+ 0.003\)
\(+ 0.950\)
\(+ 2.345\)
\(= 3.306$
In simple words: Line up all decimal points and add the numbers vertically.

Exam Tip: Ensure all numbers have the same number of decimal digits by adding trailing zeros.

 

Question 38. The value of \((3 \text{ km} + 5 \text{ m} + 37 \text{ cm} + 53 \text{ mm})\) in m is ……
(A) 3005.413
(B) 3005.423
(C) 3005.433
(D) 3005.443
Answer: (C) 3005.433
\(3 \text{ km} = 3000 \text{ m}\)
\(5 \text{ m} = 5 \text{ m}\)
\(37 \text{ cm} = 0.37 \text{ m}\)
\(53 \text{ mm} = 0.053 \text{ m}\)
Total = \(3000 + 5 + 0.37 + 0.053 = 3005.423\) Wait, let us recalculate carefully:
\(0.37 + 0.053 = 0.423\).
Total = \(3005.423 \text{ m}\).
Correct option is (B).
In simple words: Convert all units into meters and add them together.

Exam Tip: Check your addition of decimal parts carefully.

 

Question 39. Subtract: Rs 17.35 from Rs 23.75
(A) Rs 6.40
(B) Rs 6.30
(C) Rs 6.20
(D) Rs 6.50
Answer: (A) Rs 6.40
\(23.75 - 17.35 = 6.40\)
In simple words: Subtract 17.35 from 23.75 to get 6.40 rupees.

Exam Tip: Subtract the smaller decimal amount from the larger one column by column.

 

Question 40. The value of \((10.5 - 9.487)\) is-
(A) 1.103
(B) 1.012
(C) 1.013
(D) 1.001
Answer: (C) 1.013
\(10.500\)
\(- \phantom{1}9.487\)
\(= \phantom{1}1.013$
In simple words: Pad 10.5 with zeros to make it 10.500 and subtract 9.487.

Exam Tip: Always add trailing zeros to match decimal places before subtracting.

 

Question 41. 9.2 lies between two whole numbers…..
(A) 9-10
(B) 8-9
(C) 10-11
(D) 11-12
Answer: (A) 9-10
Since \(9 < 9.2 < 10\), 9.2 lies between 9 and 10.
In simple words: 9.2 is greater than 9 and less than 10.

Exam Tip: Look at the whole number part to find the lower integer bound.

 

Question 42. Convert 3 hours 45 minutes into hours and write in decimal form.
(A) 3.50
(B) 3.75
(C) 3.25
(D) 3.60
Answer: (B) 3.75
\(45 \text{ minutes} = \frac{45}{60} \text{ hours} = \frac{3}{4} \text{ hours} = 0.75 \text{ hours}\).
Total = \(3 + 0.75 = 3.75 \text{ hours}\).
In simple words: Convert 45 minutes into a fraction of an hour (\(\frac{3}{4}\) or 0.75) and add to 3 hours.

Exam Tip: Remember that 15 min = 0.25 hr, 30 min = 0.50 hr, and 45 min = 0.75 hr.

 

Question 43. Every decimal can be written as a fraction. Select suitable answer from the following options-
(A) Yes
(B) No
(C) May be.
(D) None of the options.
Answer: (A) Yes
Terminating decimals can always be expressed as fractions with powers of 10 in the denominator.
In simple words: Every terminating decimal can be converted into a fraction.

Exam Tip: Terminating decimals convert easily into fractions by using powers of 10.

 

Question 44. Express 7.5 in as fraction of lowest terms.
(A) \(\frac{15}{2}\)
(B) \(\frac{35}{3}\)
(C) \(\frac{25}{2}\)
(D) \(\frac{45}{2}\)
Answer: (A) \(\frac{15}{2}\)
\(7.5 = \frac{75}{10} = \frac{15}{2}\) (dividing by 5).
In simple words: Write 7.5 as \(\frac{75}{10}\) and simplify by dividing numerator and denominator by 5.

Exam Tip: Always divide both numbers by their highest common divisor.

 

Question 45. On the given number line, point A represents which decimal?
(A) 6.2
(B) 6.5
(C) 6.7
(D) 6.3
Answer: (D) 6.3
Counting the subdivisions from 6, point A is at the 3rd tick mark, representing 6.3.
In simple words: Count 3 small steps after 6 to find 6.3.

Exam Tip: Identify the scale of subdivisions on the number line before counting.

 

Question 46. \(6.25 \div 2.5 = ?\)
(A) 3.5
(B) 2.5
(C) 4.5
(D) 5.5
Answer: (B) 2.5
\(\frac{6.25}{2.5} = \frac{625}{250} = \frac{25}{10} = 2.5\)
In simple words: Multiply both numbers by 100 to remove decimals, then divide 625 by 250.

Exam Tip: Shift the decimal point in both divisor and dividend by the same number of places to simplify division.

 

Question 47. Express three hundred six and seven-hundredths as decimal.
(A) 306.8
(B) 306.5
(C) 306.07
(D) None of the options.
Answer: (C) 306.07
Three hundred six = 306, Seven-hundredths = \(\frac{7}{100} = 0.07\). Combined = \(306.07\).
In simple words: Write 306 for the whole number and 0.07 for seven-hundredths.

Exam Tip: Hundredths require a zero in the tenths place if no tenths are given.

 

Question 48. Is 2.5 more than 2 or is less than 2?
(A) More.
(B) Less.
(C) Equal.
(D) None of the options.
Answer: (A) More.
Since \(2.5 > 2\), it is more than 2.
In simple words: 2.5 has an extra 0.5, making it greater than 2.

Exam Tip: Numbers with positive decimal tails are always greater than their whole number bases.

 

Question 49. Ruchi's mother gave her Rs. 15.50 and her father gave her Rs. 20.60. The total amount given to Ruchi by her parents is-
(A) Rs. 36.11
(B) Rs. 36.10
(C) Rs. 36.20
(D) Rs. 36.50
Answer: (B) Rs. 36.10
\(15.50\)
\(+ 20.60\)
\(= 36.10$
In simple words: Add mother's amount and father's amount together.

Exam Tip: Align decimal points carefully when adding money amounts.

 

Question 50. Amit purchased 5 kg 400 g rice, 3 kg 30 g sugar and 11 kg 750 g flour. Find the total weight of his purchases.
(A) 20 kg 180 g
(B) 19 kg 180 g
(C) 18 kg 180 g
(D) 21 kg 180 g
Answer: (A) 20 kg 180 g
\(5.400 \text{ kg} + 3.030 \text{ kg} + 11.750 \text{ kg} = 20.180 \text{ kg} = 20 \text{ kg } 180 \text{ g}\).
In simple words: Convert all weights into kilograms in decimal form and add them up.

Exam Tip: 30 g must be written as 0.030 kg, not 0.300 kg.

 

Question 51. Renu bought 3 m 20 cm cloth for shirt and 2 m 5 cm cloth for her trousers. Find the total length of the cloth bought by her?
(A) 4 m 28 cm
(B) 3 m 25 cm
(C) 5 m 34 cm
(D) 5 m 25 cm
Answer: (D) 5 m 25 cm
\(3.20 \text{ m} + 2.05 \text{ m} = 5.25 \text{ m} = 5 \text{ m } 25 \text{ cm}\).
In simple words: Add 3 m 20 cm and 2 m 5 cm directly.

Question 52. Rani had Rs 18.50. She bought one ice-cream for Rs 11.75. How much money does she have now?
(A) Rs 16.75
(B) Rs 26.75
(C) Rs 6.75
(D) Rs 66.59
Answer: (C) Rs 6.75
\(18.50 - 11.75 = 6.75$
In simple words: Subtract the cost of the ice-cream from the total money Rani had.

Exam Tip: Use borrowing correctly when subtracting decimals in money problems.

 

Question 53. Shanti had 25 m 5 cm long cloth. She cuts 8 m 25 cm length of cloth from this for making a curtain. How much cloth is left with her?
(A) 16 m 80 cm
(B) 16 m 70 cm
(C) 16 m 60 cm
(D) 16 cm 80 cm
Answer: (A) 16 m 80 cm
\(25.05 \text{ m} - 8.25 \text{ m} = 16.80 \text{ m} = 16 \text{ m } 80 \text{ cm}\).
In simple words: Subtract 8 m 25 cm from 25 m 5 cm.

Exam Tip: 5 cm is 0.05 m, so 25 m 5 cm is written as 25.05 m.

 

Question 54. Rinki had Rs. 17.25. She bought one ice-cream for Rs. 9.75. How much money does she has now?
(A) Rs. 7.75
(B) Rs. 7.50
(C) Rs. 7.25
(D) Rs. 8.00
Answer: (B) Rs. 7.50
\(17.25 - 9.75 = 7.50$
In simple words: Subtract 9.75 from 17.25 to get 7.50 rupees.

Exam Tip: Always align decimal points before performing subtraction.

 

Question 55. Write into words
a) 123.321
b) 1.0093

Answer:
a) One hundred twenty-three point three two one
b) One point zero zero nine three
In simple words: Read whole numbers normally, say "point", and name each decimal digit separately.

Exam Tip: Never read decimal digits as tens or hundreds; read each digit individually.

 

Question 56. Write ascending and descending order. (Using sample set: 4.25, 4.025, 4.52, 4.2)
Answer:
Ascending order: 4.025, 4.2, 4.25, 4.52
Descending order: 4.52, 4.25, 4.2, 4.025
In simple words: Ascending means smallest to largest; descending means largest to smallest.

Exam Tip: Compare digits from left to right after padding decimals to equal lengths.

 

Question 57. Write the following in decimals
a) Eighteen thousand six and seven thousandths
b) Sixty five hundred and point three five two

Answer:
a) \(18006.007$
b) \(6500.352$
In simple words: Write the whole number part first, put a decimal point, and then write the fractional digits in their correct place values.

Exam Tip: Thousandths place is the third position after the decimal point.

 

Question 58. Write in a fraction in lowest terms
a) 0.444
b) 0.101

Answer:
a) \(0.444 = \frac{444}{1000} = \frac{111}{250}\)
b) \(0.101 = \frac{101}{1000}\) (already in lowest terms)
In simple words: Remove the decimal and put over 1000, then simplify if possible.

Exam Tip: Check for common divisors like 2, 5, or 10 to simplify fractions.

 

Question 59. Length of a stick is 12cm and 5mm. What will be its length in meters?
Answer:
\(12 \text{ cm} = 0.12 \text{ m}\)
\(5 \text{ mm} = 0.005 \text{ m}\)
Total = \(0.12 + 0.005 = 0.125 \text{ m}\).
In simple words: Convert cm and mm into meters by dividing by 100 and 1000 respectively.

Exam Tip: 1 meter = 100 cm = 1000 mm.

 

Question 60. Convert into fractions
a) 13.8
b) 13.08
c) 13.008
d) 1.38

Answer:
a) \(13.8 = \frac{138}{10} = \frac{69}{5}\)
b) \(13.08 = \frac{1308}{100} = \frac{327}{25}\)
c) \(13.008 = \frac{13008}{1000} = \frac{1625}{125} ...\) Wait, \(\frac{13008 \div 8}{1000 \div 8} = \frac{1625}{125}\) no, \(\frac{1626}{125}\)
d) \(1.38 = \frac{138}{100} = \frac{69}{50}\)
In simple words: Write numbers as fractions over powers of 10 and reduce to lowest terms.

Exam Tip: The number of decimal places determines the number of zeros in the denominator.

 

Question 61. Write following numbers in decimals.
a) \(200 + 60 + 5 + \frac{1}{10}\)
b) \(1000 + \frac{1}{100} + \frac{6}{10}\)

Answer:
a) \(265.1$
b) \(1000.61$
In simple words: Combine whole numbers and fractional place values into decimal form.

Exam Tip: Missing place values like tenths or hundredths must be represented by 0.

 

Question 62. Convert into decimals
a) \(\frac{3}{2}\)
b) \(\frac{1}{5}\)
c) \(\frac{25}{4}\)
d) \(\frac{2}{5}\)

Answer:
a) \(\frac{3}{2} = 1.5$
b) \(\frac{1}{5} = \frac{2}{10} = 0.2$
c) \(\frac{25}{4} = \frac{625}{100} = 6.25$
d) \(\frac{2}{5} = \frac{4}{10} = 0.4$
In simple words: Make denominators powers of 10 or perform long division.

Question 63. Write the following numbers in decimals.
a) Two ones and five tenth
b) Three hundreds and three tenth

Answer:
a) \(2.5$
b) \(300.3$
In simple words: Write whole numbers and place the tenths digit after the decimal point.

Exam Tip: Tenths occupy the first place immediately to the right of the decimal point.

 

Question 64. Ritu's school is at a distance of 6 km 530 m from her home. She traveled 1 km 70 m by foot and rest by bus. How much distance did she covered by bus?
(A) 8.460 km
(B) 7.500 km
(C) 5.460 km
(D) 6.490 km
Answer: (C) 5.460 km
Total distance = \(6.530 \text{ km}\)
Distance by foot = \(1.070 \text{ km}\)
Distance by bus = \(6.530 - 1.070 = 5.460 \text{ km}\).
In simple words: Subtract the distance traveled on foot from the total distance to find the bus distance.

Exam Tip: Convert all distances into kilometers with three decimal places before subtracting.

 

Question 65. Match the following from the code given below :
Column I: (A) Rs 4.68, (B) 5.46 km, (C) 840 gm, (D) cm
Column II: (i) 5460 m, (ii) 0.01 m, (iii) 468 paisa, (iv) 0.84 kg

(A) A-(iii); B-(i); C-(iv); D-(ii)
(B) A-(i); B-(ii); C-(iii); D-(iv)
(C) A-(iv); B-(iii); C-(ii); D-(i)
(D) A-(i); B-(iii); C-(ii); D-(iv)
Answer: (A) A-(iii); B-(i); C-(iv); D-(ii)
Rs 4.68 = 468 paisa (A-iii); 5.46 km = 5460 m (B-i); 840 gm = 0.84 kg (C-iv); 1 cm = 0.01 m (D-ii).
In simple words: Match each measurement in Column I with its correct equivalent in Column II.

Exam Tip: Verify each conversion factor independently to ensure correct matching.

 

Question 66. Find the sum of : \(27.076 + 0.557 + 0.004\)
Answer:
\(27.076\)
\(+ \phantom{2}0.557\)
\(+ \phantom{2}0.004\)
\(= 27.637$
In simple words: Align decimal points and add column by column.

Exam Tip: Always double-check column additions and carry-overs.

 

Question 67. Convert 42 ml into litres.
Answer:
Since \(1 \text{ litre} = 1000 \text{ ml}\),
\(42 \text{ ml} = \frac{42}{1000} \text{ litres} = 0.042 \text{ litres}\).
In simple words: Divide milliliters by 1000 to convert into liters.

Exam Tip: Shifting the decimal point three places to the left converts ml to liters.

 

Question 68. Convert 42 cm into Km.
Answer:
\(1 \text{ km} = 100,000 \text{ cm}\)
\(42 \text{ cm} = \frac{42}{100,000} \text{ km} = 0.00042 \text{ km}\).
In simple words: Divide centimeters by 100,000 to convert to kilometers.

Exam Tip: Count zeros carefully when converting cm directly to km.

 

Question 69. Represent the shaded figure in Decimal and Fractional numbers.
Answer:
Assuming a standard 10x10 grid with 45 shaded squares:
Fractional form = \(\frac{45}{100} = \frac{9}{20}\)
Decimal form = \(0.45$
In simple words: Count the shaded parts out of the total 100 parts to get the fraction and decimal.

Exam Tip: Grid representations of decimals are usually based on 10 or 100 total squares.

 

Question 70. Find the solution of: \((1280.69 + 1024.25) - (13.5 + 2121.32)\)
Answer:
First bracket sum: \(1280.69 + 1024.25 = 2304.94$
Second bracket sum: \(13.50 + 2121.32 = 2134.82$
Difference: \(2304.94 - 2134.82 = 170.12$
In simple words: Add the first two numbers, add the second two numbers, and subtract the second sum from the first.

Exam Tip: Follow BODMAS order of operations by solving inside parentheses first.

 

Question 71. Write in decimals
a) 3 km and 50 cm
b) Two thousand rupees and fifty five paise
c) Eight hundred rupees and Seventy five paise.

Answer:
a) \(3.050 \text{ km}\)
b) \(\text{Rs } 2000.55$
c) \(\text{Rs } 800.75$
In simple words: Convert smaller units into decimals of the larger unit.

Exam Tip: 50 cm is 0.050 km when converted through meters.

 

Question 72. Write the following as decimals
a) \(50 + 8 + \frac{5}{10} + \frac{3}{1000}\)
b) \(46 + \frac{3}{10} + \frac{8}{1000}\)
c) \(9000 + 30 + 6 + \frac{5}{10} + \frac{6}{100} + \frac{7}{1000}\)

Answer:
a) \(58.503$
b) \(46.308$
c) \(9036.567$
In simple words: Combine whole numbers and place missing decimal places with zeros.

Question 73. a) add \(0.008 + 7.5 + 20.05\)
b) Subtract 103.5m from 150m

Answer:
a) \(0.008\)
\(\phantom{0}7.500\)
\(+ 20.050\)
\(= 27.558$
b) \(150.0 - 103.5 = 46.5 \text{ m}\).
In simple words: Align decimal points for addition and subtraction.

Exam Tip: Pad numbers with trailing zeros to make decimal lengths equal.

 

Question 74. Write the following decimals as fractions. Reduce the fractions to lowest terms
a) 0.8
b) 1.5
c) 2.25

Answer:
a) \(0.8 = \frac{8}{10} = \frac{4}{5}\)
b) \(1.5 = \frac{15}{10} = \frac{3}{2}\)
c) \(2.25 = \frac{225}{100} = \frac{9}{4}\)
In simple words: Convert decimals to fractions over 10 or 100 and simplify.

Exam Tip: Divide numerator and denominator by their greatest common factor.

 

Question 75. Narendra travelled 25km 165m by bus, 8km 8m by car and 800m on foot in order to reach his school. How far is his school from his home.
Answer:
Distance by bus = \(25.165 \text{ km}\)
Distance by car = \(8.008 \text{ km}\)
Distance on foot = \(0.800 \text{ km}\)
Total distance = \(25.165 + 8.008 + 0.800 = 33.973 \text{ km}\).
In simple words: Convert all travel distances into kilometers in decimal form and add them together.

Exam Tip: 8 m is written as 0.008 km, and 800 m is written as 0.800 km.

 

Question 76. Represent the following on number line \(A = 0.2\), \(B = 1.5\), \(C = 1.8\)
Answer:
Construct a number line from 0 to 2 with subdivisions of 0.1.
- Point A is placed at the 2nd tick mark after 0 (representing 0.2).
- Point B is placed at the 5th tick mark after 1 (representing 1.5).
- Point C is placed at the 8th tick mark after 1 (representing 1.8).
In simple words: Draw a number line and mark points A, B, and C at their respective decimal values.

Exam Tip: Ensure tick marks are spaced equally to represent tenths accurately.

 

Question 77. Ramesh bought vegetables from the market weighing 15 Kg in all. Out of this 10.250 Kg. are onion and 3.500 Kg. are tomatoes and the rest are potatoes. Find the weight of potatoes.
Answer:
Total weight = \(15.000 \text{ kg}\)
Weight of onions and tomatoes = \(10.250 + 3.500 = 13.750 \text{ kg}\)
Weight of potatoes = \(15.000 - 13.750 = 1.250 \text{ kg}\).
In simple words: Add onion and tomato weights, then subtract from the total weight to find potatoes.

Exam Tip: Subtract the combined weight of known vegetables from the total weight.

 

Question 78. Radha purchased 1g 200mg lemon, 800g 150mg lady finger and 3 kg 250g oranges and rest was coriander and the weight of the bag was 100g. If Radha carried total 6 kg weight. Find the weight of the coriander.
Answer:
Convert all weights into grams:
Lemon = \(1.200 \text{ g}\) (or assuming 1 kg 200 mg = 1000.200 g, or 1 kg 200 g = 1200 g. Let us assume standard 1 kg 200 g = 1200 g)
Lady finger = \(800.150 \text{ g}\) or \(950 \text{ g}\)
Let us convert everything to kg:
Lemon = \(1.200 \text{ kg}\)
Lady finger = \(0.800 + 0.150 = 0.950 \text{ kg}\)
Oranges = \(3.250 \text{ kg}\)
Bag weight = \(0.100 \text{ kg}\)
Total known weight = \(1.200 + 0.950 + 3.250 + 0.100 = 5.500 \text{ kg}\)
Weight of coriander = \(6.000 - 5.500 = 0.500 \text{ kg} = 500 \text{ g}\).
In simple words: Add up all item weights and the bag weight, then subtract from 6 kg to get coriander weight.

Question 79. a) In a grocery store, Bharati bought a tin of biscuits for rs15.95, a bag of rice for Rs22.29 and a box of sweets for Rs 1.65. How much did Bharati pay altogether.
(b) Subtract 10.19 from 49.81.

Answer:
a) \(15.95\)
\(+ 22.29\)
\(+ \phantom{2}1.65\)
\(= 39.89\)
Total paid = \(\text{Rs } 39.89$
b) \(49.81 - 10.19 = 39.62$
In simple words: Add all item prices for part a, and subtract 10.19 from 49.81 for part b.

Exam Tip: Align decimal points carefully in both addition and subtraction steps.

 

Question 80. a) After winning Rs 2150 in a Drawing competition, Haneef bought his father a T-Shirt for Rs 75.89 and his mother a saree for Rs 186.99. How much money does Haneef have left?
b) Add \(0.08 + 4.07 + 0.378\).

Answer:
a) Total spent = \(75.89 + 186.99 = \text{Rs } 262.88$
Money left = \(2150.00 - 262.88 = \text{Rs } 1887.12$
b) \(0.080\)
\(+ 4.070\)
\(+ 0.378\)
\(= 4.528$
In simple words: Add the total spent and subtract from 2150 for part a; add all decimals with trailing zeros for part b.

Exam Tip: Always add trailing zeros to make decimal lengths equal when performing addition.

 

Free CBSE Practice Worksheets: Class 6 Mathematics Chapter 08 Decimals

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