CBSE Class 10 Mathematics Polynomials MCQs Set E

Refer to CBSE Class 10 Mathematics Polynomials MCQs Set E provided below available for download in Pdf. The MCQ Questions for Class 10 Mathematics with answers are aligned as per the latest syllabus and exam pattern suggested by CBSE, NCERT and KVS. Chapter 2 Polynomials Class 10 MCQ are an important part of exams for Class 10 Mathematics and if practiced properly can help you to improve your understanding and get higher marks. Refer to more Chapter-wise MCQs for CBSE Class 10 Mathematics and also download more latest study material for all subjects

MCQ for Class 10 Mathematics Chapter 2 Polynomials

Class 10 Mathematics students should refer to the following multiple-choice questions with answers for Chapter 2 Polynomials in Class 10.

Chapter 2 Polynomials MCQ Questions Class 10 Mathematics with Answers

Question. If α,β are the zeros of the polynomial x2 − px + q, then α22 +β22 is equal to −
(a) p4/q2 +2 −4p2/q
(b) p4/q2 −2 +4p2/q
(c) p4/q2+2q−4p2/q
(d) None of the options

Answer: A

Question. If a,b are the zeros of the polynomial x2 − px + 36 and α2 + β2 = 9, then p =
(a) ± 6
(b) ± 3
(c) ± 8
(d) ± 9

Answer: D

Question. If α,β are the roots of ax2 + bx + c and a + k, b + k are the roots of px2 + qx + r, then k =
(a) −1/2[a/b−p/q]
(b) [a/b−p/q]
(c) 1/2[b/a−q/p]
(d) (ab − pq)

Answer: C

Question. The condition that x3 − ax2 + bx − c = 0 may have two of the roots equal to each other but of opposite signs is :
(a) ab = c
(b) 2/3,a
(c) a2b = c
(d) None of the options

Answer: A

Question. If the sum of zeros of the polynomial p(x) = kx− 5x2 − 11x − 3 is 2, then k is equal to
(a) k = − 5/ 2
(b) k = 2/ 5
(c) k = 10
(d) k = 5/ 2

Answer: D

Question. If y = f(x) = mx + c; then f(y) in terms of x is
(a) mx + m + c
(b) m + mc + c
(c) m2x + mc + c
(d) m2x + m2c

Answer: C

Question. If a, b and g are the zeros of the polynomial f(x) = x3 + px2 − pqrx + r, then 1/αβ + 1/βγ +1/γα =
(a) r/p
(b) p/ r
(c) − p/ r
(d) − r/ p

Answer: B

Question. The coefficient of x in x2 + px + q was taken as 17 in place of 13 and it's zeros were found to be − 2 and − 15. The zeros of the original polynomial are
(a) 3, 7
(b) − 3, 7
(c) − 3, − 7
(d) −3, − 10

Answer: D

Question. If a, b and g are the zeros of the polynomial 2x3 − 6x2 − 4x + 30, then the value of (ab + bg + ga) is
(a) − 2
(b) 2
(c) 5
(d) − 30

Answer: A

Question. If ax3 + 9x2 + 4x − 1 is divided by (x + 2), the remainder is −6; then the value of 'a' is
(a) −3
(b) −2
(c) 0
(d) 33 8

Answer: D

Question. The graph of y = – 3x2 + 2x– 1 cuts the x-axis at :
(a) 1/ 3 and 0
(b) 1/ 3 and 1/ 3
(c) do not cut
(d) none of the options

Answer: C

Question. The two zeroes of f(x) = x4– 6x3 – 26x2 + 138x – 35 are 2 ± √3 , the other two zeroes are :
(a) 7 and –5
(b) –7 and 5
(c) –7 and – 5
(d) none of the options

Answer: A

Question. The quadratic polynomial, sum of whose zeroes is 8 and their product is 12, is given by
(a) x2 – 8x + 12
(b) x2 + 8x – 12
(c) x2 – 5x + 7
(d) x2 + 5x – 7

Answer: A

Question. A quadratic polynomial whose product and sum of zeroes are −13/ 5 and 3/5 , respectively.
(a) k(x2 + 12x + 5)
(b) k[x2 – (8x) + (–9))
(c) k [x2 − (1/2 x) + ( −7/5)]
(d) k [x2 − (3/5 x) + (−13/5)] 

Answer: D

Question. If the L.C.M. of two polynomials p(x) and q(x) is (x + 3)(x − 2)2(x − 6) and their H.C.F. is (x − 2).If p(x) = (x + 3)(x − 2)2, then q(x) =________
(a) (x + 3)((x − 2) 
(b) x2 − 3x − 18
(c) x2 − 8x + 12
(d) none of the options

Answer: C

Question. If α,β,γ are the zeros of the polynomial x3 + 4x + 1, then (α + β)−1 + (β + γ)−1 + (γ + α)−1 =
(a) 2
(b) 3
(c) 4
(d) 5

Answer: C

Question. f(x) = 3x5 + 11x4 + 90x− 19x + 53 is divided by x + 5 then the remainder is ______.
(a) 100 
(b) −100
(c) −102
(d) 102

Answer: C

Question. If f(x) = 4x3 − 6x2 + 5x − 1 and α,β and γ are its zeros, then αβγ =
(a) 3/ 2
(b) 5/ 4
(c) −3/2
(d) 1/ 4

Answer: D

Question. Find the remainder obtained when x2007 is divisible by x2 − 1.
(a) x2
(b) x
(c) x + 1
(d) −x

Answer: B

Question. If a polynomial 2x− 9x2 + 15x + p, when divided by (x − 2), leaves −p as remainder, then p is equal to
(a) −16
(b) −5
(c) 20
(d) 10

Answer: B

Question. The zeroes of the quadratic equation 4s2 – 4s + 1 are
(a) 1/2 , 1/4
(b) 1/2 , 1/2
(c) 1/4 , 1/14
(d) 1/3 , 1/4

Answer: B

Question. A quadratic polynomial whose zeroes are 1 and –3 is
(a) x2 + 3x – 2
(b) x2 + 5x – 5
(c) x2 + 2x – 3
(d) none of the options

Answer: C

Question. The value of ax2 + bx + c when x = 0 is 6. The remainder when dividing by x + 1 is 6. The remainderwhen dividing by x + 2 is 8. Then the sum of a, b and c is
(a) 0
(b) −1
(c) 10
(d) None of the options

Answer: A

Question. If the G.C.D. of the polynomials x3 − 3x2 + px + 24 and x2 −7x + q is (x − 2), then the value of (p + q) is:
(a) 0
(b) 20
(c) −20
(d) 40

Answer: A

Question. If (x − 1), (x + 1) and (x − 2) are factors of x4 + (p − 3)x3 − (3p − 5)x2 + (2p − 9) x + 6 then the value of p is
(a) 1
(b) 2
(c) 3
(d) 4

Answer: D

Question. If f (−3/4)=0; then for f(x), which of the following is a factor?
(a) 3x − 4
(b) 4x + 3
(c) −3x + 4
(d) 4x − 3

Answer: B

Question. The zeroes of f (x) = 4 √3x2 +5x − 2 √3 are :
(a) 2/√3 and −√3/4
(b) −/√32 and −√3/4 
(c) −2/√3 and √3/4
(d) none of the options

Answer: D

Question. The solution of x2 + 6x + 9 = 0 is
(a) –1
(b) 3
(c) –3
(d) 1

Answer: C

Question. The remainder of x4 + x− x2 + 2x + 3 when divided by x − 3 is
(a) 105
(b) 108
(c) 10
(d) None of the options

Answer: B

Question. The remainder when x1999 is divided by x2 − 1 is
(a) − x
(b) 3x
(c) x
(d) Noneo f the options

Answer: C

Question. If a,b and c are not all equal and a and b be the zeros of the polynomial ax2 + bx + c, then value of (1 + a + a2) (1 + b + b2) is :
(a) 0
(b) positive
(c) negative
(d) non-negative

Answer: D

Question. f(x) = 16x2 + 51x + 35 then one of the factors of f(x) is
(a) x − 1
(b) x + 3
(c) x − 3
(d) x + 1

Answer: D

Question. For the expression f(x) = x3 + ax2 + bx + c, if f(a) = f(b) = 0 and f(d) = f(0). The values of a, b & c are
(a) a = − 9, b = 20, c = − 12
(b) a = 9, b = 20, c = 12
(c) a = − 1, b = 2, c = − 3
(d) none of the options

Answer: A

Question. If x2 − ax + b = 0 and x2 − px + q = 0 have a root in common and the second equation has equal roots, then
(a) b + q = 2ap
(b) b + q = ap /2
(c) b + q = ap
(d) none of the options

Answer: B

Question. If a, b are the zeroes of the polynomial 2x2 – 5x + 7, then a polynomial whose zeroes are 2α + 3β, 3α + 2β is
(a) k(x2 − 3/5 x + 21)
(b) k (x2 − 25/2 x + 41)
(c) k (x2 +9/2 x − 45 )
(d) none of the options

Answer: B

Question. The remainder when f (x) = – 3x2 + x4 + 4x + 5 is divided by –x2 + 2 is
(a) 6
(b) 8
(c) 12
(d) none of the options

Answer: D

Question. The zeroes of y = x2 + 7x + 12 are :
(a) 4 and – 3
(b) –4 and –3
(c) –4 and 3
(d) 4 and 3

Answer: B

Question. If the zeroes of f(x) = x3 – 3x2 + x + 1 are a – b, a, a + b, then value of a and b is :
(a) a =1, b = −√ 2
(b) a =1, b = −√2
(c) a =1, b =√2
(d) none of the options

Answer: B

Assertion and Reason:
(a) If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
(b) If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
(c) If Assertion is correct but Reason is incorrect.
(d) If Assertion is incorrect but Reason is correct.

Question. Assertion : x3 + x has only one real zero.
Reason : A polynomial of nth degree must have n real zeroes.

Answer: C

Question. Assertion : Degree of a zero polynomial is not defined.
Reason: Degree of a non-zero constant polynomial is ‘0’.

Answer: B

Question. Assertion : Zeroes of f(x) = x2 – 4x – 5 are 5, – 1.
Reason : The polynomial whose zeroes are 2 + √3, 2 –√3 is x2 – 4x + 7.

Answer: C

Question. Assertion : x2 + 4x – 5 has two zeroes.
Reason : A quadratic polynomial can have at the most two zeroes.

Answer: D

Question. Assertion : If one zero of polynomial p(x) = (k 2 + 4) x2 + 13x + 4k is reciprocal of other, then k = 2.
Reason : If (x – α) is a factor of p(x), then p(α) = 0 i.e. α is a zero of p(x).

Answer: B

One word Question :

Question. Find the common zero of x2 –1, x4 –1 and (x –1)2 ?
Answer: x + 1

Question. Write a polynomial whose sum and product of zeroes are 2 and –9 respectively.
Answer: x2 – 2x – 9

Question. What should be added to the polynomial p(x) = x2 – 5x + 4, so that 2 is a zero of p(x)?
Answer: 2

Question. If α and β are the zeroes of the polynomial x2 – 5x + 6, find the value of 1/α +1/β .
Answer: 5/ 6

Chapter 09 Some Applications of Trigonometry
CBSE Class 10 Mathematics Application of Trigonometry MCQs

MCQs for Chapter 2 Polynomials Mathematics Class 10

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