CBSE Class 11 Chemistry Chemical Bonding and Molecular Structure MCQs Set D

Question. The percentage of p-character in the orbitals forming P—P bonds in P₄ is 
(a) 25
(b) 33
(c) 50
(d) 75
Answer: d

Question. The total number of lone pairs of electrons in melamine is
(a) 4
(b) 7 
(c) 6
(d) 9
Answer: c

Question. What type of hydridisation takes place in the N atom of NH₃ ? 
(a) sp₂
(b) sp₃
(c) dsp₂
(d) sp
Answer: b

Question. In TeCI₄ , the central atom tellurium involves 
(a) sp³ hybridisation
(b) sp³d hybridisation
(c) sp³d² hybridisation
(d) dsp² hybridisation
Answer: b

Question. In BrF₃ molecule, the lone pairs occupy equatorial positions to minimise 
(a) lone pair-bond pair repulsion only
(b) bond pair-bond pair repulsion only
(c) lone pair-lone pair repulsion and lone pair-bond pair repulsion
(d) lone pair-lone pair repulsion only
Answer: c

Question. In a homonuclear molecule which of the following set of orbitals is degenerate? 
(a) σ2s and σ1s
(b) n2P_x and n2p_y
(c) n2P_x and σ2p_z
(d) σ2p_z and n2P_x
Answer: b

Question. Which species has the highest bond order ?
(a) O₂
(b) O^2–₂
(c) N₂
(d) Both O₂ and O^2–₂
Answer: c

Question. In methane the bond angle is 
(a) 180°
(b) 90°
(c) 109°
(d) 120°
Answer: c

Question. In I-butene number of σ-bonds is
(a) 8
(b) 10
(c) 11
(d) 12
Answer: c

Question. Which of the following set of properties belong to PCl₅ ?
(a) sp³, tetrahedral, 4 valence shell pairs of electrons
(b) sp³d, trigonal bipyramidal, 5 valence shell pairs of electrons
(c) sp³d², octahedral, 6 valence she! II pairs of electrons
(d) sp³d, square planar, 4 valence shell pairs of electrons
Answer: b

Question. The shape of XeF₄ molecule and hybridisation of xenon in it are 
(a) tetrahedral and sp³
(b) square planar and dsp²
(c) square planar and sp³d²
(d) octahedral and sp₃d₂
Answer: c

Question. The relationship between the dissociation energy of N₂ and N⁺₂ is 
(a) dissociation energy of N₂ = dissociation energy of N⁺₂
(b) dissociation energy of N₂ can either be lower or higher than the dissociation energy of N⁺₂
(c) dissociation energy of N⁺₂ > dissociation energy of N⁺₂
(d) dissociation energy of N; > dissociation energy of N₂
Answer: c

Question. The species having bond order different from that in CO is
(a) NO^–
(b) NO⁺
(c) CN^–
(d) N₂
Answer: a

Question. The bond angle is smallest in
(a) H₂O
(b) H₂S
(c) BeCI₂
(d) N₂O
Answer: b

Question. Two type F XF angles are present in which of the following molecules? (X = S, Xe, C) 
(a) SF₄
(b) XeF₄
(c) SF₆
(d) CF₄
Answer: a

Question. Number of lone pair(s) in XeOF₄ is/are
(a) 0
(b) 1
(c) 2
(d) 3
Answer: b

Question. Which of the following groups all do not have sp³d hybridisation? 
(a) ClF₃ , IF₃, XeF₃⁺
(b) ICI₂, ClF₂, I₃
(c) CIF₃, BrF₃, IF₃
(d) PCl₃, AsCI₃, PF₅
Answer: d

Question. How many electron pairs are present in valence shell of oxygen in water molecule ? 
(a) 4
(b) 1
(c) 2
(d) 3
Answer: a

Question. Among the following, the pair in which the two species are not isostructural, is 
(a) SiF₄ and SF₄
(b) IO^–₃ and XeO₃
(c) BH^–₄ and NH⁺₄
(d) PF^–₆ and SF₆
Answer: a

Question. Which one of the following compounds has sp² hybridisation?
(a) CO₂
(b) SO₂
(c) N₂O
(d) CO
Answer: b

Question. In a regular octahedral molecule, MX ₆ the number of X — M — X bonds at 180° is
(a) three
(b) two
(c) six
(d) four
Answer: a

Question. The paramagnetic behaviour of B₂ is due to the presence of
(a) two unpaired electrons in n_b MO 
(b) two unpaired electrons in n* MO
(c) two unpaired electrons in σ* MO
(d) two unpaired electrons in σ_b MO
Answer: a

Question. The d-orbital involved in sp³ d-hybridisation is
(a) d_{x2- y2}
(b) d_xy 
(c) d_z2
(d) d_zx
Answer: c

Question. Which of the following is planar? 
(a) XeF₂
(b) XeO₃F
(c) XeO₂F₂
(d) XeF₄
Answer: a

Question. As per molecular orbital theory, which can’t exist in stable state? 
(a) H₂
(b) H⁺₂
(c) H^–₂
(d) He₂
Answer: d

Question. Which of the following is diamagnetic?
(a) H₂
(b) H^–₂
(c) H⁺₂
(d) He⁺₂
Answer: b

Question. When O₂ is converted into H⁺₂
(a) both paramagnetic character and bond order increase
(b) bond order decreases
(c) paramagnetic character increases
(d) paramagnetic character decreases and the bond order increases
Answer: d

Question. In which pair of species, both species do have the similar geometry? 
(a) CO₂ , SO₂
(b) NH₃ , BH₃
(c) CO^2-₃ , SO^2-₃
(d) SO^2-₄ , CO^–₄
Answer: d

Question. The number of valence shell bonding electrons to be distributed in the Lewis electron dot model for HNNN is
(a) 6
(b) 10
(c) 11
(d) 16
Answer: b

Question. Which of the following is not correct with respect to bond length of the species ? 
(a) C₂ > C^2–₂
(b) B⁺₂ > B₂
(C) O₂ > O^–₂
(d) Nl⁺₂ > N₂
Answer: c

Question. Stability of the species Li₂ , Li₂^– and Li₂⁺ increases in the order of 
(a) Li2 < Li! < Li2
(c) Li2 < Li2 < Li!
(b) Li2 < Li! < Li2
(d) Li2 < Li2 < Li!
Answer: b

Question. The bond order in the superoxide ion (O^–₂) is 
(a) 2.5
(b) 2
(c) 1.5
(d) 1
Answer: c

Question. Oxygen molecules contains 
(a) no unpaired electron
(b) one unpaired electron
(c) two unpaired electrons
(d) three unpaired electrons
(e) four unpaired electrons
Answer: c

Question. In which of the following pairs the two species are not isostructural? 
(a) CO^2-₃and NO_3^–
(b) PCl⁴₄and SiCl₄
(c) PF₃ and BrF₅
(d) AlF^3-₆ and SF₆
Answer: c

Question. The bond order in NO is 2.5 while that in NO⁺ is 3. Which of the following statements is tme for these two species ?
(a) Bond length in NO^– is greater than in NO 
(b) Bond length in NO is greater than in NO⁺
(c) Bond length in NO^– is equal to in NO
(d) Bond length is unpredictable
Answer: b

Question. Given are O₂ , o;, o~+ and o~-, respectively. Find the correct increasing bond order 
(a) O₂ < O₂^2– < O²⁺₂ < O⁺₂
(b) O²⁺₂ < O₂< O⁺₂ < O²⁺₂
(c) O₂^2– < O₂ < O⁺₂ < O^2-₂
(d) O⁺₂ < O₂^2– < O₂ < O²⁺₂
Answer: b

Question. SF₂, SF₄ and SF₆ have the hybridisations at sulphur atom respectively, as 
(a) sp², sp³, sp²d²
(b) sp³, sp³, sp³d²
(c) sp³, sp³d, sp³d²
(d) sp³,, spd², d²sp³,
Answer: c

Question. In pyrophosphoric acid, H₄P₂O₇ , number of σ and dn — pn bonds are respectively
( a) 8 and 2
(b) 6 and 2
(c) 12 and O
(d) 12 and 2 
Answer: d

Question. According of VSEPR theory the repulsion between different pair (lone or bond) of electrons obey the order Codes
(a) lp – bp > Ip – Ip > bp – bp
(b) Ip – bp > bp – bp > Ip – Ip
(c) Ip – Ip > Ip – bp > bp – bp
(d) bp – bp > Ip – Ip > Ip – bp
Answer: c

Question. In which of the following compound sp² hybridisation is absent ? 
(a) CH₂ = CH—CH= CH₂
(b) CH = C—CH₂—CH₃
(c) CH₂ —CH=CH₂
(d) CH₂ = CH—CH₂—CH₃
Answer: b