Class 10 NCERT Solutions Heredity and Evolution

Class 10 NCERT Solutions Heredity and Evolution with answers available in Pdf for free download. The NCERT Solutions for Class 10 Science with answers have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Standard 10 by CBSE, NCERT and KVS. Solutions to questions given in NCERT book for Class 10 Science are an important part of exams for Grade 10 Science and if practiced properly can help you to get higher marks. Refer to more Chapter-wise Solutions for NCERT Class 10 Science and also download more latest study material for all subjects

Heredity and Evolution Class 10 NCERT Solutions

Class 10 Science students should refer to the following NCERT questions with answers for Heredity and Evolution in standard 10. These NCERT Solutions with answers for Grade 10 Science will come in exams and help you to score good marks

Heredity and Evolution NCERT Solutions Class 10

Class 10 NCERT Solutions Heredity and Evolution- NCERT Solutions prepared for CBSE students by the best teachers in Delhi.

Class X Chapter 9 – Heredity and Evolution Science

Question 1: If a trait A exists in 10% of a population of an asexually reproducing species and a trait B exists in 60% of the same population, which trait is likely to have arisen earlier?

Answer: In asexual reproduction, the reproducing cells produce a copy of their DNA through some chemical reactions. However, this copying of DNA is not accurate and therefore, the newly formed DNA has some variations.

It can be easily observed in the above figure that in asexual reproduction, very few variations are allowed. Therefore, if a trait is present in only 10% of the population, it is more likely that the trait has arisen recently. Hence, it can be concluded that trait B that exists in 60% of the same population has arisen earlier than trait A.

Question 2: How does the creation of variations in a species promote survival?

Answer: Sometimes for a species, the environmental conditions change so drastically that their survival becomes difficult. For example, if the temperature of water increases suddenly, most of the bacteria living in that water would die. Only few variants resistant to heat would be able to survive. If these variants were not there, then the entire species of bacteria would have been destroyed. Thus, these variants help in the survival of th species.However, not all variations are useful. Therefore, these are not necessarily beneficial for the individual organisms.

Class X Chapter 9 – Heredity and Evolution Science

Question 1: How do Mendel’s experiments show that traits may be dominant or recessive?

Answer: Mendel selected true breeding tall (TT) and dwarf (tt) pea plants. Then, he crossed these two plants. The seeds formed after fertilization were grown and these plants that were formed represent the first filial or F1 generation. All the F1 plants obtained were tall. Cross-pollination of tall and short plant Then, Mendel self-pollinated the F1 plants and observed that all plants obtained in the F2

generation were not tall. Instead, one-fourth of the F2 plants were short. Self-pollination of F1 plants From this experiment, Mendel concluded that the F1 tall plants were not true breeding. They were carrying traits of both short height and tall height. They appeared tall only because the tall trait is dominant over the dwarf trait.

Question 2: How do Mendel’s experiments show that traits are inheritedindependently?

Answer: Mendel crossed pea plants having round green seeds (RRyy) with pea plants having wrinkled yellow seeds (rrYY).

An example of dihybrid crosses Since the F1 plants are formed after crossing pea plants having green round seeds and pea plants having yellow wrinkled seeds, F1 generation will have both these characters in them. However, as we know that yellow seed colour and round seeds are dominant characters, therefore, the F1 plants will have yellow round seeds. Then this F1 progeny was self-pollinated and the F2 progeny was found to have yellow round seeds, green round seeds, yellow wrinkled seeds, and green wrinkled seeds in the ratio of 9:3:3:1. In the above cross, more than two factors are involved, and these are independently inherited.

Question 3: A man with blood group A marries a woman with blood group O and their daughter has blood group O. Is this information enough to tell you which of the traits - blood group A or O - is dominant? Why or why not?

Answer: No. This information is not sufficient to determine which of the traits - blood group A or O - is dominant. This is because we do not know about the blood group of all the progeny.

Blood group A can be genotypically AA or AO. Hence, the information is incomplete to draw any such conclusion.

Question 4: How is the sex of the child determined in human beings?

Answer: In human beings, the females have two X chromosomes and the males have one X and one Y chromosome. Therefore, the females are XX and the males are XY. The gametes, as we know, receive half of the chromosomes. The male gametes have 22 autosomes and either X or Y sex chromosome. Type of male gametes: 22+X OR 22+ Y. However, since the females have XX sex chromosomes, their gametes can only have X sex chromosome.

Sex determination in humans :Thus, the mother provides only X chromosomes. The sex of the baby is determined by the type of male gamete (X or Y) that fuses with the X chromosome of the female.

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Chapter 5 Periodic Classification of Elements
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Chapter 6 Life Processes
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Chapter 7 Control and Coordination
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Chapter 8 How do Organisms Reproduce?
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Chapter 9 Heredity and Evolution
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Chapter 11 The Human Eye and Colourful World
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Chapter 12 Electricity
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Chapter 13 Magnetic Effects of Electric Current
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Chapter 14 Sources of Energy
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Chapter 15 Our Environment
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