JEE Physics Atoms MCQs Set 02

Question. The energy of hydrogen atom in its ground state is –13.6 eV, the energy of the level corresponding to n = 7 is
(a) –0.28 eV
(b) –0.85 eV
(c) –5.40 eV
(d) –0.544 eV

Answer: A

Question. Which series of hydrogen atom lie in infrared region?
(a) Brackett, Paschen and Pfund
(b) Lyman
(c) Balmer
(d) All of these

Answer: A

Question. Total energy of an electron in the hydrogen atom in the ground state is –13.6 eV. The potential energy of this electron is
(a) –27.2 eV
(b) –13.6 eV
(c) 0
(d) 13.6 eV

Answer: A

Question. If potential energy of an electron in a hydrogen atom in first excited state is taken to be zero, kinetic energy (in eV) of an electron in ground state will be
(a) 13.6 eV
(b) 10.2 eV
(c) 3.4 eV
(d) 5.1 eV

Answer: A

Question. Maximum wavelength in balmer series of hydrogen spectrum is
(a) 6561 Å
(b) 8201 Å
(c) 3645 Å
(d) 912 Å

Answer: A

Question. In Rutherford’s experiment, number of particles scattered at 90º angle are x per second. Number particles scattered per second at angle 60º is
(a) 4 x
(b) 16 x
(c) x
(d) 8 x

Answer: A

Question. Compton effect supports that
(a) Photons have momentum
(b) X-rays can easily penetrate matter
(c) X-rays have high frequency compared to visible light
(d) X-rays are transverse waves

Answer: A

Question. Hydrogen atoms are excited from ground state to the principal quantum number 5. Number of spectral lines observed will be
(a) 10
(b) 8
(c) 4
(d) 5

Answer: A

Question. When a hydrogen atom is raised from the ground state to an excited state
(a) The P.E. increases and K.E. decreases
(b) Both K.E. and P.E, decrease
(c) The P.E. decreases and K.E. increases
(d) Both K.E. and P.E. increase

Answer: A

Question. The energy of a hydrogen atom in its ground state is – 13.6 eV. The energy of the level corresponding to the quantum number n = 2 in the hydrogen atom is
(a) – 3.4 eV
(b) 0.54 eV
(c) – 2.72 eV
(d) – 0.85 eV

Answer: A

Question. When hydrogen atom is in its first excited level, its radius is ……………. of the Bohr radius.
(a) 4 times
(b) Same
(c) Half
(d) Twice

Answer: A

Question. Maximum frequency of emission is obtained for the transition
(a) n = 2 to n = 1
(b) n = 6 to n = 2
(c) n = 1 to n = 2
(d) n = 2 to n = 6

Answer: A

Question. When an electron do transition from n = 4 to n = 2, then emitted line in spectrum will be
(a) Second line of Balmer series
(b) Second line of Paschen series
(c) First line of Lyman series
(d) First line of Paschen series

Answer: A

Question. The Bohr model of atoms
(a) Assumes that the angular momentum of electrons is quantized
(b) Uses Einstein’s photo-electric equation
(c) Predicts continuous emission spectra for atoms
(d) Predicts the same emission spectra for all types of atom

Answer: A

Question. Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be
(a) Three
(b) Four
(c) Two
(d) One

Answer: A

Question. In which of the following systems will the radius of the first orbit (n = 1) be minimum?
(a) Doubly ionized lithium
(b) Singly Ionized helium
(c) Hydrogen atom
(d) Deuterium atom

Answer: A

Question. The total energy of electron in the ground state of hydrogen atom is –13.6 eV. The kinetic energy of an electron in the first excited state is
(a) 3.4 eV
(b) 1.7 eV
(c) 13.6 eV
(d) 6.8 eV

Answer: A

Question. The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between
(a) n = 4 to n = 3 states
(b) n = 3 to n = 2 states
(c) n = 2 to n = 1 state
(d) n = 3 to n = 1 state

Answer: A

Question. The energy of a hydrogen atom in the ground state is –13.6 eV. The energy of a He+ ion in the first excited state will be
(a) –13.6 eV
(b) –27.2 eV
(c) –54.4 eV
(d) –6.8 eV

Answer: A

Question. The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
(a) 2
(b) 3
(c) 4
(d) 1

Answer: A

Question. Out of the following which one is not a possible energy for a photon to be emitted by hydrogen atom according to Bohr's atomic model?
(a) 11.1 eV
(b) 1.9 eV
(c) 0.65 eV
(d) 13.6 eV

Answer: A

Question. The ground state energy of hydrogen atom is –13.6 eV. When its electron is in the first excited state, its excitation energy is
(a) 10.2 eV
(b) 6.8 eV
(c) 3.4 eV
(d) 0

Answer: A

Question. The ratio of wavelengths of the 1st line of Balmer series and that of the 1st line of Paschen series is
(a) 7 : 20
(b) 4 : 7
(c) 7 : 4
(d) 20 : 7

Answer: A

Question. The absorption transition between the first and the fourth energy states of hydrogen atom are 3. The emission transition between these states will be
(a) 6
(b) 5
(c) 4
(d) 3

Answer: A