School Assignments for Class 4 Mathematics: The Junk Seller
Access comprehensive school assignments for The Junk Seller using the CBSE Class 4 Mathematics The Junk Seller Assignment Set 01. Designed to align with the 2026-27 CBSE academic guidelines, these practice sets help Class 4 Mathematics students reinforce core concepts and improve their problem-solving accuracy.
Practice Class 4 Mathematics Assignments: The Junk Seller
View or download the dedicated CBSE Class 4 Mathematics The Junk Seller Assignment Set 01 resource below. Engaging with these assignments under focused study conditions ensures continuous academic progress and mastery of the 2026-27 curriculum.
Q.1- A tea seller earns Rs.20 per day. Find out how much he will earn in:
a) A week
b) 10 days
c) A month
d) A year
Answer:
Earnings per day = Rs. 20
a) A week (7 days):
Total earning = \(20 \times 7 = \text{Rs. } 140\)
b) 10 days:
Total earning = \(20 \times 10 = \text{Rs. } 200\)
c) A month (taking 30 days):
Total earning = \(20 \times 30 = \text{Rs. } 600\)
d) A year (365 days):
Total earning = \(20 \times 365 = \text{Rs. } 7300\)
In simple words: Multiply the daily earning by the number of days to find the total amount.
Exam Tip: Remember standard conversions: 1 week = 7 days, 1 month = 30 days (unless specified), and 1 year = 365 days.
Q.2- Shanti took a loan of Rs.3000 from a bank for one year and returned Rs.3800 after one year. What is the interest paid by her?
Answer:
Total amount returned = Rs. 3800
Principal amount taken as loan = Rs. 3000
Interest paid = Total amount returned - Principal amount
Interest = \(3800 - 3000 = \text{Rs. } 800\)
In simple words: Interest is the extra money paid over the borrowed amount, found by subtracting the original loan from the total returned amount.
Exam Tip: Interest = Total Money Paid Back - Money Borrowed.
Q.3- Ratan took a loan of Rs.300 from a bank for 7 months and paid Rs.48 every month. Aman took a loan of Rs.300 from a person named Chunnilal and paid Rs.350 after 7 months.
Find out:
a) How much amount will be paid by Ratan?
b) Find out the interest paid by Ratan?
c) Who has paid more (Ratan/Aman)?
Answer:
a) Monthly payment by Ratan = Rs. 48
Number of months = 7
Total amount paid by Ratan = \(48 \times 7 = \text{Rs. } 336\)
b) Principal amount taken by Ratan = Rs. 300
Interest paid by Ratan = Total amount paid - Principal amount
Interest = \(336 - 300 = \text{Rs. } 36\)
c) Total amount paid by Aman = Rs. 350
Total amount paid by Ratan = Rs. 336
Comparing both amounts, \(350 > 336\), so Aman has paid more.
In simple words: Multiply Ratan's monthly installment by 7 to get his total payment, then compare it directly with Aman's total payment of Rs. 350.
Exam Tip: Read carefully whether the payment is given as a monthly installment or as a lump sum total at the end.
Q.4- Look at Kirans rate list and answer the following questions:
| Kind of junk | Price per kg |
|---|---|
| Waste paper | Rs. 4 |
| Newspaper | Rs. 5 |
| Brass | Rs. 180 |
| Plastic | Rs. 10 |
| Iron | Rs. 12 |
a) How much will Kiran pay for 42 kg newspaper?
b) How much Kiran has to pay for 22 kg plastic?
c) Find out the cost of 2 kg Brass?
Answer:
a) Rate of newspaper per kg = Rs. 5
Quantity = 42 kg
Total cost = \(42 \times 5 = \text{Rs. } 210\)
b) Rate of plastic per kg = Rs. 10
Quantity = 22 kg
Total cost = \(22 \times 10 = \text{Rs. } 220\)
c) Rate of brass per kg = Rs. 180
Quantity = 2 kg
Total cost = \(180 \times 2 = \text{Rs. } 360\)
In simple words: Multiply the given weight of each item by its respective rate from the table.
Exam Tip: Always pick the correct rate for each material from the given rate list table before multiplying.
Q.5- Solve it using Lattice multiplication.
a) 23×13
b) 36×21
Answer:
a) For \(23 \times 13\):
Set up a \(2 \times 2\) grid with digits 2, 3 on top and 1, 3 on the side. Multiply each digit and add along the diagonals.
Diagonal sums: Unit digit = 9, Tens digit = \(6 + 3 = 9\), Hundreds digit = 2.
Result = 299
b) For \(36 \times 21\):
Set up a \(2 \times 2\) grid with digits 3, 6 on top and 2, 1 on the side. Multiply each digit and add along the diagonals.
Diagonal sums: Unit digit = 6, Tens digit = \(3 + 12 = 15\) (write 5, carry 1), Hundreds digit = \(6 + 1 = 7\).
Result = 756
In simple words: Draw a box divided into cells with diagonal lines, multiply individual digits, and sum the numbers along the diagonals to get the product.
Exam Tip: Pay careful attention to diagonal carry-overs in lattice multiplication grids.
Q.6- What cost more and by how much?
Burger Rs.60.50
Pizza Rs.75.45
Answer:
Cost of Pizza = Rs. 75.45
Cost of Burger = Rs. 60.50
Since \(75.45 > 60.50\), Pizza costs more.
Difference in cost = \(75.45 - 60.50 = \text{Rs. } 14.95\)
In simple words: Compare the two prices and subtract the smaller price from the larger price to find the difference.
Exam Tip: Align the decimal points properly when subtracting amounts of money.
Free study material for Mathematics
CBSE Class 4 Mathematics Assignments for The Junk Seller
Download Assignment: The Junk Seller (Class 4 Mathematics)
Access structured practice assignments for The Junk Seller designed in alignment with the latest CBSE curriculum for Class 4 Mathematics. These printable sets cover objective and descriptive problem types to support thorough revision.
Maximize Exam Scores with Chapter Practice Sets
- Syllabus Compliance: Sets reflect current CBSE evaluation criteria and official marking frameworks.
- Multi-Format Practice: Includes varied problem types designed to deepen comprehension across all sub-topics.
- Time Management: Routine practice optimizes pacing to finish school examinations comfortably within schedule.
Steps to Complete The Junk Seller Assignments Successfully
- Concept Foundation: Review the NCERT book for Class 4 Mathematics thoroughly before diving into assignment tasks.
- Self-Evaluation: Solve exercises independently before inspecting professional answer guides.
- Progress Monitoring: Note down complex formulas or concepts, clearing them up using available online practice aids.
FAQs
You can download free PDF assignments for Class 4 Mathematics The Junk Seller from StudiesToday.com. These practice sheets have been updated for the 2026-27 session covering all concepts from latest NCERT textbook.
Yes, our teachers have given solutions for all questions in the Class 4 Mathematics The Junk Seller assignments. This will help you to understand step-by-step methodology to get full marks in school tests and exams.
Yes. These assignments are designed as per the latest CBSE syllabus for 2026. We have included huge variety of question formats such as MCQs, Case-study based questions and important diagram-based problems found in The Junk Seller.
Practicing topicw wise assignments will help Class 4 students understand every sub-topic of The Junk Seller. Daily practice will improve speed, accuracy and answering competency-based questions.
Yes, all printable assignments for Class 4 Mathematics The Junk Seller are available for free download in mobile-friendly PDF format.