CBSE Class 4 Mathematics Trip to Bhopal Assignment

Q.1. Fill in the blanks

Question 1. 3840 + 1 = ________
Answer: 3841
In simple words: Adding 1 gives the next number (successor) of 3840.

Exam Tip: Adding 1 to any number increases its units digit by 1.

Question 2. 26 + 32 + 44 = _____ + 26 + ______
Answer: 44, 32 (or 32, 44)
In simple words: Changing the order of numbers in addition does not change the sum (Commutative Property).

Exam Tip: Look at both sides of the equals sign to find the missing numbers by comparing which ones are already written.

Question 3. 695 - ______ + 0
Answer: 695 (assuming the expression means 695 - 695 + 0 = 0, or if it equals 695 then the blank is 0)
In simple words: Any number minus itself is 0, and adding 0 keeps the value the same.

Exam Tip: Check standard arithmetic properties for subtraction and zero.

Question 4. 9869 + 1 = _______
Answer: 9870
In simple words: Adding 1 to 9869 gives the next number, which is 9870.

Exam Tip: When the units digit is 9, adding 1 carries over to the tens place.

Question 5. 100 less than 5965 = ________
Answer: 5865
In simple words: Subtract 100 from 5965 by decreasing the hundreds digit by 1.

Exam Tip: "Less than" means subtraction.

Question 6. 10 more than 2986 = _________
Answer: 2996
In simple words: Add 10 to 2986 by increasing the tens digit by 1.

Exam Tip: "More than" means addition.

Question 7. 327 + 401 + 9 + 13 = ________
Answer: 750
In simple words: Group numbers that add up easily: \((327 + 13) + (401 + 9) = 340 + 410 = 750\).

Question 8. A book costs Rs. 22 so the cost of 10 books will be Rs. _________
Answer: 220
In simple words: Multiply the cost of 1 book by 10: \(22 \times 10 = 220\).
Exam Tip: To multiply by 10, simply attach a zero to the right of the number.

Question 9. Greatest 5 digit number is ________
Answer: 99,999
In simple words: The largest single digit is 9, so write it 5 times.

Exam Tip: The greatest N-digit number consists of N nines.

Question 10. Smallest 4 digit number is ________
Answer: 1,000
In simple words: It is the number that comes right after the greatest 3-digit number (999).

Exam Tip: The smallest N-digit number is 1 followed by N-1 zeros.

Question Q.2. A school is going to Bhopal for a trip. The students of different classes will be going. One bus can carry 50 children so find out how many buses are needed for 200 children?
Answer:
Total number of children = 200
Number of children 1 bus can carry = 50
Number of buses needed = \(200 \div 50 = 4\) buses
In simple words: Divide the total children by the capacity of one bus to find how many buses are required.

Exam Tip: Cancel out the trailing zeros in division: \(20 \div 5 = 4\).

Question Q.3. If cost of 100 litre diesel is Rs. 3500 then find out the cost of 5 litre diesel and 10 litre diesel.
Answer:
Cost of 100 litres of diesel = Rs. 3500
Cost of 1 litre of diesel = \(3500 \div 100 = \text{Rs. } 35\)
Cost of 5 litres of diesel = \(5 \times 35 = \text{Rs. } 175\)
Cost of 10 litres of diesel = \(10 \times 35 = \text{Rs. } 350\)
In simple words: First find the cost of 1 litre by dividing, then multiply by 5 and 10.

Exam Tip: Always find the unit value (cost of 1 item) first in unitary method problems.

Question Q.4. How many people can sit in 8 buses if 1 bus can carry 35 people?
Answer:
Number of people 1 bus can carry = 35
Total number of buses = 8
Total people who can sit = \(35 \times 8 = 280\) people
In simple words: Multiply the capacity of one bus by the total number of buses.

Exam Tip: Perform multiplication carefully: \(35 \times 8 = (30 \times 8) + (5 \times 8) = 240 + 40 = 280\).

Question Q.5. What numbers can you make using the digits 4, 6 and 9?
Answer:
Using digits 4, 6, and 9 (assuming repetition is not allowed for 3-digit numbers):
469, 496, 649, 694, 946, 964
In simple words: Arrange the given digits in all possible combinations without repeating any digit in a single number.

Exam Tip: Fix the first digit one by one to avoid missing any combination.

Question Q.6. I gave 3 balloons each to 5 of my friends and 5 balloons are left with me. How many balloons did I have?
Answer:
Number of friends = 5
Balloons given to each friend = 3
Total balloons given away = \(5 \times 3 = 15\)
Balloons left with me = 5
Total balloons I had initially = \(15 + 5 = 20\) balloons
In simple words: Multiply the number of friends by the balloons given to each, then add the remaining balloons.

Exam Tip: Break word problems into smaller steps: calculation of distributed items + addition of leftovers.

Question Q.7. A bus can carry 65 passengers. So 15 buses can carry how many passengers?
Answer:
Passengers in 1 bus = 65
Number of buses = 15
Total passengers = \(65 \times 15 = 975\) passengers
In simple words: Multiply 65 by 15 to get the total capacity.

Exam Tip: \(65 \times 15 = 65 \times (10 + 5) = 650 + 325 = 975\).

Question Q.8. Subtract and check your answer by addition
1. 69,758 - 42,631
Answer:
Subtraction:
\(69,758 - 42,631 = 27,127\)
Check by addition:
\(27,127 + 42,631 = 69,758\)
In simple words: Subtract the numbers normally, then add the result to the smaller number to get the original large number.

Exam Tip: To verify subtraction, always add the difference to the subtrahend; it must equal the minuend.

Question Q.8 (Part 2). 10,000 - 9,549
Answer:
Subtraction:
\(10,000 - 9,549 = 451\)
Check by addition:
\(451 + 9,549 = 10,000\)
In simple words: Borrow across zeros carefully, then add the answer back to check.

Exam Tip: When subtracting from powers of 10, use regrouping across adjacent zero digits.

Question Q.9. Subtract 9,403 from 10,000.
Answer:
\(10,000 - 9,403 = 597\)
In simple words: Take away 9,403 from 10,000 using proper borrowing steps.

Question Q.10. There are 210 children went for a trip. For lunch oranges, biscuits and bananas are also distributed. Each child is to be given 1 orange, 1 banana and 5 biscuits. 30 children do not take bananas. Find out how many oranges, biscuits and bananas are distributed? Also find out total number of things distributed in all?
Answer:
Total children = 210
- Oranges distributed: Each child gets 1 orange. Total oranges = \(210 \times 1 = 210\)
- Biscuits distributed: Each child gets 5 biscuits. Total biscuits = \(210 \times 5 = 1,050\)
- Bananas distributed: 30 children do not take bananas, so children who take bananas = \(210 - 30 = 180\). Total bananas = \(180 \times 1 = 180\)
- Total number of things distributed in all = \(210 + 1,050 + 180 = 1,440\)
In simple words: Multiply each item by the number of children who take it, and subtract the children who refused bananas before calculating total bananas.
Exam Tip: Read conditions carefully regarding exceptions (like children refusing bananas) before multiplying.