CBSE Class 12 Chemistry Amines Worksheet Set A

Read and download free pdf of CBSE Class 12 Chemistry Amines Worksheet Set A. Download printable Chemistry Class 12 Worksheets in pdf format, CBSE Class 12 Chemistry Unit 13 Amines Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Chemistry Class 12 Assignments and practice them daily to get better marks in tests and exams for Class 12. Free chapter wise worksheets with answers have been designed by Class 12 teachers as per latest examination pattern

Unit 13 Amines Chemistry Worksheet for Class 12

Class 12 Chemistry students should refer to the following printable worksheet in Pdf in Class 12. This test paper with questions and solutions for Class 12 Chemistry will be very useful for tests and exams and help you to score better marks

Class 12 Chemistry Unit 13 Amines Worksheet Pdf

Question. Which of the following reactions is appropriate for converting acetamide to methanamine?
(a) Hoffmann hypobromamide reaction
(b) Stephen’s reaction
(c) Gabriel phthalimide synthesis
(d) Carbylamine reaction 
Answer. A

Question. Method by which aniline cannot be prepared is
(a) degradation of benzamide with bromine in alkaline solution
(b) reduction of nitrobenzene with H2/Pd in ethanol
(c) potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
(d) hydrolysis of phenylisocyanide with acidic solution. 
Answer. C

Question. The electrolytic reduction of nitrobenzene in strongly acidic medium produces
(a) azobenzene
(b) aniline
(c) p-aminophenol
(d) azoxybenzene.
Answer. C

Question. Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?
(a) NaOH-Br2
(b) Sodalime
(c) Hot conc.H2SO4
(d) PCl5
Answer. A

Question. Which one of the following on reduction with lithium aluminium hydride yields a secondary amine?
(a) Methyl isocyanide
(b) Acetamide
(c) Methyl cyanide
(d) Nitroethane
Answer. A

Question. Electrolytic reduction of nitrobenzene in weakly acidic medium gives
(a) N-phenylhydroxylamine
(b) nitrosobenzene
(c) aniline
(d) p-hydroxyaniline. 
Answer. C

Question. Intermediates formed during reaction of RCONH2 with Br2 and KOH are
(a) RCONHBr and RNCO
(b) RNHCOBr and RNCO
(c) RNH – Br and RCONHBr
(d) RCONBr2
Answer. A

Question. Amides may be converted into amines by a reaction named after
(a) Hoffmann
(b) Claisen
(c) Perkin
(d) Kekule. 
Answer. A

Question. Indicate which nitrogen compound amongst the following would undergo Hoffmann reaction (i.e., reaction with Br2 and strong KOH) to furnish the primary amine (R–NH2)?
(a) RCONHCH
(b) RCOONH4
(c) RCONH2
(d) R – CO – NHOH
 Answer. C

Question. The correct order of the basic strength of methyl substituted amines in aqueous solution is
(a) CH3NH2 > (CH3)2NH > (CH3)3N
(b) (CH3)2NH > CH3NH2 > (CH3)3N
(c) (CH3)3N > CH3NH2 > (CH3)2NH
(d) (CH3)3N > (CH3)2NH > CH3NH2
Answer. B

Question. Nitration of aniline in strong acidic medium also gives m-nitroaniline because
(a) inspite of substituents nitro group always goes to only m-position
(b) in electrophilic substitution reactions amino group is meta directive
(c) in absence of substituents nitro group always goes to m-position
(d) in acidic (strong) medium aniline is present as anilinium ion.
Answer. D

Question. The correct statement regarding the basicity of arylamines is
(a) arylamines are generally more basic than alkylamines because of aryl group
(b) arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridised
(c) arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring p-electron system
(d) arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring p-electron system.
Answer. C

Question. On hydrolysis of a “compound”, two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens’ reagent and Fehling’s solution. The “compound” is
(a) CH3CH2CH2NC
(b) CH3CH2CH2CN
(c) CH3CH2CH2ON≡ O
(d) CH3CH2CH2CON(CH3)
Answer. A

Question. Which of the following statements about primary amines is false?
(a) Alkyl amines are stronger bases than aryl amines.
(b) Alkyl amines react with nitrous acid to produce alcohols.
(c) Aryl amines react with nitrous acid to produce phenols.
(d) Alkyl amines are stronger bases than ammonia. 
Answer. C

Question. Which of the following is more basic than aniline?
(a) Benzylamine
(b) Diphenylamine
(c) Triphenylamine
(d) p-Nitroaniline 
Answer. A

Question. Phenyl isocyanides are prepared by which of the following reaction?
(a) Reimer–Tiemann reaction
(b) Carbylamine reaction
(c) Rosenmund’s reaction
(d) Wurtz reaction
Answer. B

Question. The compound obtained by heating a mixture of ethylamine and chloroform with ethanolic potassium hydroxide (KOH) is
(a) an amide
(b) an amide and nitro compound
(c) an ethyl isocyanide
(d) an alkyl halide.
Answer. C

Question. The action of nitrous acid on an aliphatic primary amine gives
(a) secondary amine
(b) nitro alkane
(c) alcohol
(d) alkyl nitrite. 
Answer. C

Question. Which one of the following order is wrong, with respect to the property indicated?
(a) Benzoic acid > phenol > cyclohexanol (acid strength)
(b) Aniline > cyclohexylamine > benzamide (basic strength)
(c) Formic acid > acetic acid > propanoic acid (acid strength)
(d) Fluoroacetic acid > chloroacetic acid > bromoacetic acid (acid strength) 
Answer. B

Question. For carbylamine reaction, we need hot alcoholic KOH and
(a) any primary amine and chloroform
(b) chloroform and silver powder
(c) a primary amine and an alkyl halide
(d) a monoalkylamine and trichloromethane.
Answer. A

Question. Which of the following will be most stable diazonium salt RN2+?
(a) CH3N2+X –
(b) C6H5N2+
(c) CH3CH2N2+X –
(d) C6H5CH2N2+X –
Answer. B

Question. Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tetrafluoroborate which is subsequently heated to dry. The final product is
(a) p-bromoaniline
(b) p-bromofluorobenzene
(c) 1, 3, 5-tribromobenzene
(d) 2, 4, 6-tribromofluorobenzene 
Answer. D

Question. Nitrobenzene on reaction with conc. HNO3/H2SO4 at 80–100°C forms which one of the following products?
(a) 1, 4-Dinitrobenzene
(b) 1, 2, 4-Trinitrobenzene
(c) 1, 2-Dinitrobenzene
(d) 1, 3-Dinitrobenzene
Answer. D

Question. Which product is formed, when acetonitrile is hydrolysed partially with cold concentrated HCl?
(a) Methyl cyanide
(b) Acetic anhydride
(c) Acetic acid
(d) Acetamide7=].
Answer. D

QUESTION BANK
 
1. Write the IUPAC names of the following.(one mark each )
 
i. (CH3)2CHNH2
 
ii. C6H5NHCH3
 
iii. (CH3CH2)2NCH3
 
iv. (CH3)3CNH2
 
v. m-BrC6H4NH2
 
vi. C6H5NHCOCH3
 
vii. NH2-CH2CH2-CH2-CH=CH2
 
2. Complete the following reaction equations (one mark each )
 
i. C6H5N2Cl + H3PO2+ H2O→
 
ii. C6H5NH2 + Br2 (aq) →
 
iii. C6H5N2Cl + CH3COCl →
 
iv. C6H5NH2 + HNO2
 
v. RNH2 + CHCl3+ KOH→
 
3. How will you bring about the following conversions? (one mark each)
 
i. Benzene to Aniline
 
ii. Aniline to benzonitrile
 
iii. Ethanoic acid to ethanamine
 
iv. p-Toluidine to 2-Bromo-4-methylaniline.
 
v. Methylbromide to ethanamine
 
vi. Ethylamine to methylamine
 
vii. Benzene to sulphanilic acid
 
viii. Hexanenitrile to 1-aminopentane.
 
4. Giving an example of each describe the following reactions : (each carries one mark)
 
i. Hoffman bromamide reaction
 
ii. Gabriel phthalimide synthesis
 
iii. Gatterman reaction
 
iv. Coupling reaction
 
v. Hoffman’s ammonolysis
 
5. Give one chemical test to distinguish between the following pairs of compounds : (one mark each)
 
i. Methylamine and dimethylamine
 
ii. Secondary and tertiary amines
 
iii. Ethylamine and aniline
 
iv. Aniline and benzylamine
 
v. Methylamine and methanol
 
vi. Methylamine and N, N-Dimethylamine
 
vii. Ethanol and ethanamine
 
6. Explain why : (one mark each)
 
i. The C–N–C bond angle in trimethyl amine is 108°
 
ii. The quaternary ammonium salts having four different alkyl groups are optically active
 
iii. Alkylamines are more basic than ammonia
 
iv. Aniline cannot be prepared by Gabriel phthalimide synthesis
 
v. Garbrielphthalimide synthesis is preferably used for synthesising primary amines.
 
vi. Ethylamine is soluble in water but aniline is not
 
vii. Aniline is soluble in dilute HCl.
 
viii. Amines have lower boiling point than alcohols of comparable molecular masses.
 
ix. 1° Amines have higher boiling points than 2° amines which in turn are higher boiling than 3° amines.
 
x. The pKb value of benzeneamine is 9.33 while that of ammonia is 4.75.
 
xi. Aniline does not undergo Friedel Crafts reaction.
 
xii. Aniline readily forms 2, 4, 6-tribronoaniline on reaction with bromine water.
 
xiii. Sulphanillicacid is soluble in water.
 
xiv. Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
 
7. Arrange the following substances
 
NH3, C2H5NH2, C6H5NH2, (C2H5)2NH
 
i. In an increasing order of basic strength
 
ii. In a decreasing order of basic strength in gas phase
 
8. Primary, secondary and tertiary amines can be distinguished by using Hinsberg’s reagent.
 
i. What is Hinsberg’s reagent?
 
ii. How will you distinguish primary, secondary and tertiary amines using this reagent.?

 

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