CBSE Class 9 Science Structure of the Atom VBQs

Read and download the CBSE Class 9 Science Structure of the Atom VBQs. Designed for the 2025-26 academic year, these Value Based Questions (VBQs) are important for Class 9 Science students to understand moral reasoning and life skills. Our expert teachers have created these chapter-wise resources to align with the latest CBSE, NCERT, and KVS examination patterns.

VBQ for Class 9 Science Chapter 4 Structure of the Atom

For Class 9 students, Value Based Questions for Chapter 4 Structure of the Atom help to apply textbook concepts to real-world application. These competency-based questions with detailed answers help in scoring high marks in Class 9 while building a strong ethical foundation.

Chapter 4 Structure of the Atom Class 9 Science VBQ Questions with Answers

Question. What are canal rays?
Answer : The positively charged particles moving from anode to cathode in cathode ray tube are known as canal rays or anode rays.

Question. On the basis of Thomson’s model of an atom, explain how the atom is neutral as a whole.
Answer : As per Thomson’s model of an atom, electrons and protons are equal in number hence an atom on the whole is electrically neutral.

Question. Write the distribution of electrons in Carbon and Sodium atoms.
Answer : Carbon (Z=6) = 2, 4.
Sodium (Z=11) = 2, 8, 1.

Question. Name the three subatomic particles of an atom.
Answer : Protons, Electrons and Neutrons.

Question. Draw a sketch of Bohr’s model of an atom with three shells.
Answer :

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Question. What do you think would be the observation if the ∝– particle scattering experiment is carried out using a foil of a metal other than gold?
Answer : In the ∝ – particle scattering experiment, when any other metal foil is used instead of gold, the observation would almost remain the same. But as other metals are not as malleable as gold, so more number of alpha particles will bounce back.

Question. How will you find the valency of chlorine, sulphur and magnesium?
Answer : (i) Chlorine (Z=17) = 2, 8, 7
Clearly Chlorine requires 1 electron to complete its outermost shell, So its valency is -1.
(ii) Sulphur (Z=16) = 2, 8, 6
Clearly Sulphur requires 2 electron to complete its outermost shell, So its valency is -2.
(iii) Magnesium (Z=12) = 2, 8, 2
Clearly Magnesium requires 2 electrons to eject from its outermost shell to be fully vacant, So its valency is +2.

Question. On the basis of Rutherford’s model of an atom, which subatomic particle is present in the nucleus of an atom?
Answer : Protons.

Question. Helium atom has an atomic mass of 4 u and two protons in its nucleus. How many neutrons does it have?
Answer : Number of neutrons = A-P = 4 – 2 = 2.

Question. For the symbol H, D and T, tabulate three subatomic particles found in each of them.
Answer :

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Question. If K and L shells of an atom are full, then what would be the total number of electrons in the atom?
Answer : Total electrons = 2 + 8 = 10.

Question. If an atom contains one electron and one proton, will it carry any charge or not?
Answer : Since a proton is a positively charged particle and an electron is a negatively charged particle, the net charge becomes neutral as both the particles neutralize each other.

Question. If the number of electrons in an atom is 8 and number of protons is also 8, then
(i) What is the atomic number of the atom? and
(ii) What is the charge on the atom?
Answer : (i) Atomic number (Z) of the atom = 8.
(ii) Total charge on the atom is zero as number of protons (positive charge) and electrons (negative charge) are same.

Question. Write the electronic configuration of any one pair of isotopes and isobar.
Answer : (a) Isotopes: Isotopes are atoms of same element, which have different mass number. Example:
Carbon molecule exists as 6C12 and 6C14 but when their electronic configuration is noticed, both have 2, 4.
(b) Isobars: Isobars are atoms of different element ,which have the same mass number but differ in the atomic number. Example: Electronic configuration of 6C14 =2,4. Electronic configuration of 7N14 = 2,5.

Question. With the help of Table 4.1, find out the mass number of oxygen and sulphur atom.
Answer : Mass number (A) of Oxygen = No. of protons + No. of neutrons = 8+8 = 16.
Mass number (A) of Sulphur = No. of protons + No. of neutrons = 16+16 = 32.

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Exercise Question-Answers

Question. Compare the properties of electrons, protons and neutrons.
Answer :

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Question. Describe Bohr’s model of the atom.
Answer : (i) All the positive charge and nearly all the mass (P+N) is concentrated in the center of the atom, known as nucleus.
(ii) Negatively charged electrons revolve around the nucleus in some discrete orbits.
(iii) Electrons do not radiate energy when they are in their orbits.
(iv) The distinct orbits are named as K, L, M, N orbits. Numbers used to denote them are n=1, 2, 3, 4

Question. What are the limitations of Rutherford’s model of the atom?
Answer : (i) It failed to explain the stability of an atom.
(ii) It doesn't explain the spectrum of hydrogen and other atoms.

Question. Compare all the proposed models of an atom given in this chapter.
Answer :

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Question. Summarize the rules for writing of distribution of electrons in various shells for the first eighteen elements.
Answer : Electrons in nth shell are 2n2. So for first 18 elements electron distribution is: 2, 8, 8.

Question. Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and (iv) Isobars.
Give any two uses of isotopes.
Answer : (i) Atomic Number (Z)- Total number of protons present in an atom. For example Carbon has 6 protons in its nucleus, So its atomic number is 6.
(ii) Mass Number (A)- Sum of protons and neutrons present in an atom. For example Carbon has 6 protons and 6 neutrons in its nucleus, So its mass number is 12.
(iii) Isotopes: Isotopes are atoms of same element, which have different mass number. Example: Isotopes of Carbon are 6C12 and 6C14.
(iv) Isobars: Isobars are atoms of different element, which have same mass number but differ in the atomic number. Example: 6C14 and 7N14 .
Uses of isotopes: (i) The isotope of Iodine atom is used to treat Goitre and iodine deficient disease.
(ii) In the treatment of cancer, an isotope of cobalt is used.
(iii) Fuel for nuclear reactors is derived from the isotopes of the Uranium atom.

Question. Define valency by taking examples of silicon and oxygen.
Answer : The definite combining capacity of the atoms of each element, where electrons are lost, gained or
shared to make the octet of electrons present in the outermost shell is defined as valency.
For Silicon (Z = 14) = 2, 8, 4
Thus, the valency of silicon is 4 as these electrons can be shared with others to complete octet.
For Oxygen (Z = 8) = 2, 6
Clearly Oxygen requires 2 electrons to complete its outermost shell, So its valency is -2.

Question. What are the limitations of J.J.Thomson’s model of the atom?
Answer : (i) It could not explain the result of scattering experiment performed by Rutherford.
(ii) It did not have any experiment support.

Question. Na+ has completely filled K and L shells. Explain.
Answer : Electronic configuration of Sodium-Na (Z=11) is = 2, 8, 1
Electronic configuration of Sodium ion-Na+ is = 2, 8
Clearly Na+ has completely filled K (2) and L (8) shells.

Question. If bromine atom is available in the form of, say, two isotopes 35Br79 (49.7%) and 35Br81 (50.3%), calculate the average atomic mass of Bromine atom.
Answer : Average atomic mass of bromine atom is = 79 X 49.7/100 + 81 X 59.3/100 = 3926.3/100 + 4074.3/100
= 8000.6/100 = 80.006 u

Question. Composition of the nuclei of two atomic species X and Y are given as under
       X             Y
Protons =      6        6
Neutrons =    6        8
Give the mass numbers of X and Y. What is the relation between the two species?
Answer : Mass number of X: Protons + neutrons = 6+6 = 12
Mass number of Y: Protons + neutrons = 6+8 = 14
They are isotopes of the same element.

Question. The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes 8X16 and 8X18 in the sample?
Answer : Average atomic mass = 16.2 u.
Let the percentage of isotope 8X16 is = y %
Then, the percentage of isotope 8X18 is = (100- y) %
So 18 X (y/100) + 16 X (100-y/100) = 16.2
18y + 1600 - 16y / 100 = 16.2
18y + 1600 - 16y = 1620
2y = 1620 - 1600 = 20
y = 20/2 = 10

Question. . If Z=3, what would be the valency of the element? Also, name the element.
Answer : Atom with atomic number 3 is Lithium (Li).
For Lithium (Z=3) = 2, 1
So valency is +1.

For the following statements, write T for true and F for false.

(a) J.J. Thomson proposed that the nucleus of an atom contains only nucleons.
Answer : (F)

(b) A neutron is formed by an electron and a proton combining together. Therefore it is neutral.
Answer :(F)

(c) The mass of an electron is about 1/1837 times that of proton.
Answer :(T)

(d) An isotope of iodine is used for making tincture iodine, which is used as a medicine.
Answer :(F)

Put a tick (✓) against correct choice and cross (x) against wrong choice in questions

Question. Rutherford’s alpha – particle scattering experiment was responsible for the discovery of
(a) Atomic nucleus
(b) Electron
(c) Proton
(d) Neutron

Answer : A

Question. Which one of the following is a correct electronic configuration of Sodium?
(a) 2, 8
(b) 8, 2, 1
(c) 2, 1, 8
(d) 2, 8, 1

Answer : D

Question. Isotopes of an element have
(a) The same physical properties
(b) Different chemical properties
(c) Different number of neutrons
(d) Different atomic numbers.

Answer : C

Question. Number of valence electrons in Cl- ion are:
(a) 16
(b) 8 
(c) 17
(d) 18

Answer : B

VBQs for Chapter 4 Structure of the Atom Class 9 Science

Students can now access the Value-Based Questions (VBQs) for Chapter 4 Structure of the Atom as per the latest CBSE syllabus. These questions have been designed to help Class 9 students understand the moral and practical lessons of the chapter. You should practicing these solved answers to improve improve your analytical skills and get more marks in your Science school exams.

Expert-Approved Chapter 4 Structure of the Atom Value-Based Questions & Answers

Our teachers have followed the NCERT book for Class 9 Science to create these important solved questions. After solving the exercises given above, you should also refer to our NCERT solutions for Class 9 Science and read the answers prepared by our teachers.

Improve your Science Scores

Daily practice of these Class 9 Science value-based problems will make your concepts better and to help you further we have provided more study materials for Chapter 4 Structure of the Atom on studiestoday.com. By learning these ethical and value driven topics you will easily get better marks and also also understand the real-life application of Science.

Where can I find 2025-26 CBSE Value Based Questions (VBQs) for Class 9 Science Chapter Chapter 4 Structure of the Atom?

The latest collection of Value Based Questions for Class 9 Science Chapter Chapter 4 Structure of the Atom is available for free on StudiesToday.com. These questions are as per 2026 academic session to help students develop analytical and ethical reasoning skills.

Are answers provided for Class 9 Science Chapter Chapter 4 Structure of the Atom VBQs?

Yes, all our Science VBQs for Chapter Chapter 4 Structure of the Atom come with detailed model answers which help students to integrate factual knowledge with value-based insights to get high marks.

What is the importance of solving VBQs for Class 9 Chapter Chapter 4 Structure of the Atom Science?

VBQs are important as they test student's ability to relate Science concepts to real-life situations. For Chapter Chapter 4 Structure of the Atom these questions are as per the latest competency-based education goals.

How many marks are usually allocated to VBQs in the CBSE Science paper?

In the current CBSE pattern for Class 9 Science, Chapter 4 Structure of the Atom Value Based or Case-Based questions typically carry 3 to 5 marks.

Can I download Science Chapter Chapter 4 Structure of the Atom VBQs in PDF for free?

Yes, you can download Class 9 Science Chapter Chapter 4 Structure of the Atom VBQs in a mobile-friendly PDF format for free.