CBSE Class 12 Physics Electro Magnetic Waves chapter notes and important questions

Advanced Study Material for Class 12 Physics: Chapter 08 Electromagnetic Waves

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ELECTRO MAGNETIC WAVES

Class 12 Physics: Electromagnetic Waves (Chapter Notes and Important Questions)

Chapter 5: Electromagnetic Waves – Gist

  1. Conduction current and displacement current together have the property of continuity.
  2. Conduction current and displacement current are precisely the same.
  3. Conduction current arises due to the flow of electrons in a conductor. Displacement current arises due to an electric flux changing with time.
  4. The displacement current is \[ I_D=\varepsilon_0\frac{d\phi_E}{dt} \]
  5. Maxwell's equations:
    Gauss's law in electrostatics: \( \displaystyle\oint\vec E\cdot d\vec S=\frac{q}{\varepsilon_0} \)
    Gauss's law in magnetism: \( \displaystyle\oint\vec B\cdot d\vec S=0 \)
    Faraday–Lenz law of electromagnetic induction: \( \displaystyle\oint\vec E\cdot d\vec l=-\frac{d\phi_B}{dt} \)
    Ampere–Maxwell law: \( \displaystyle\oint\vec B\cdot d\vec l=\mu_0 I+\mu_0\varepsilon_0\frac{d\phi_E}{dt} \)
  6. Electromagnetic wave: the wave in which there are sinusoidal variations of the electric and magnetic fields at right angles to each other as well as at right angles to the direction of wave propagation.
  7. Velocity of EM waves in free space: \[ c=\frac{1}{\sqrt{\mu_0\varepsilon_0}}=3\times10^8\ \text{m/s} \]
  8. The scientists associated with the study of EM waves are Hertz, Jagdish Chandra Bose and Marconi.
  9. An EM wave is a transverse wave, because of which it undergoes the polarization effect.
  10. Electric vectors are only responsible for the optical effects of EM waves.
  11. The amplitudes of the electric and magnetic fields are related by \( \dfrac{E}{B}=c \).
  12. An oscillating or accelerating charged particle produces EM waves.
  13. The orderly arrangement of electromagnetic radiation according to its frequency or wavelength is the electromagnetic spectrum.
  14. A hint to memorise the electromagnetic spectrum in decreasing order of frequency: G X U V I M R (gamma rays, X-rays, ultraviolet, visible, infrared, microwaves, radio waves).
  15. EM waves also carry energy, momentum and information.

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Electromagnetic spectrum: its production, detection and uses in general

TypeWavelength range / frequency rangeProductionDetectionUses
Radio> 0.1 m
\(10^9\) to \(10^5\) Hz
Rapid acceleration/deceleration of electrons in aerialsReceiver's aerialsRadio, TV communication
Microwave0.1 mm
\(10^{11}\) to \(10^{9}\) Hz
Klystron valve or magnetron valvePoint contact diodesRadar, TV communication
Infrared1 mm to 700 nm
\(10^{11}\) to \(10^{14}\) Hz
Vibration of atoms or moleculesThermopiles, bolometer, infrared photographic filmGreenhouse effect, looking through haze, fog and mist, aerial mapping
Light700 nm to 400 nm
\(4\times10^{14}\) to \(8\times10^{14}\) Hz
Electrons in an atom during transitionEye, photocell, photographic filmPhotography, illumination; emitted and reflected by the objects
Ultraviolet400 nm to 1 nm
\(5\times10^{14}\) to \(8\times10^{14}\)
Inner shell electrons in an atom moving from one energy level to a lower energy levelPhotocell and photographic filmPreservation of food items, detection of invisible writing, finger prints in a forensic laboratory, determination of the structure of molecules and atoms
X-rays1 nm to \(10^{-3}\) nm
\(10^{16}\) to \(10^{21}\) Hz
X-ray tube or inner shell electronsPhotographic film, Geiger tube, ionization chamberStudy of crystal structure and atoms, fracture of bones
Gamma rays< \(10^{-3}\) nm
\(10^{18}\) to \(10^{22}\) Hz
Radioactive decay of the nucleusPhotographic film, Geiger tube, ionization chamberNuclear reactions and the structure of atoms and nuclei; to destroy cancer cells

Questions

Write the SI unit of displacement current. (1 mark)

Answer: Ampere (A).

If \(\vec E\) and \(\vec B\) represent the electric and magnetic field vectors of the electromagnetic wave, then what is the direction of propagation of the electromagnetic wave? (1 mark)

Answer: \( \vec E\times\vec B \)

Can the velocity of light in vacuum be changed? (1 mark)

Answer: No, it is not possible; it is a universal constant, \(c=3\times10^8\) m/s.

Calculate the wavelength of the e.m. waves emitted by an oscillator antenna system, if \(L=0.253\ \mu\text{H}\) and \(C=25\ \text{pF}\).

The frequency is \( \nu=\dfrac{1}{2\pi\sqrt{LC}}=\dfrac{1}{2\pi\sqrt{0.253\times10^{-6}\times25\times10^{-12}}}\approx6.3\times10^{7}\ \text{Hz} \), so the wavelength is

\[ \lambda=\frac{c}{\nu}=2\pi c\sqrt{LC}\approx\frac{3\times10^8}{6.33\times10^7}\approx4.7\ \text{m} \]

(The source gives only the formula for the frequency; the numerical value is worked out here.)

The magnetic component of a polarized wave of light is \( B_x=(4\times10^{-6}\ \text{T})\sin\left[(1.57\times10^{7}\ \text{m}^{-1})\,y+(4.5\times10^{11}\ \text{s}^{-1})\,t\right] \). (a) Find the direction of propagation of light. (b) Find the frequency. (c) Find the wavelength and write the expression for the electric field. (3 marks)

         useful-resources-physics-cbse-class-12-physics-electro-5 

(a) The phase is \(ky+\omega t\), so the wave travels along the y-axis, in the \(-y\) direction.

(b) \( f=\dfrac{\omega}{2\pi}=\dfrac{4.5\times10^{11}}{2\pi}\approx7.2\times10^{10}\ \text{Hz} \)

(c) \( \lambda=\dfrac{2\pi}{k}=\dfrac{2\pi}{1.57\times10^{7}}=4\times10^{-7}\ \text{m} \). The amplitude of the electric field is \( E_0=cB_0=3\times10^8\times4\times10^{-6}=1.2\times10^3\ \text{V/m} \), perpendicular to both \(B\) (x) and the direction of propagation (y), i.e. along z:

\[ E_z=-(1.2\times10^{3}\ \text{V/m})\sin\left[(1.57\times10^{7})y+(4.5\times10^{11})t\right] \]

Note: the given \(\omega\) and \(k\) correspond to a phase speed \(\omega/k\approx2.9\times10^4\) m/s, not \(c\); the data are used as printed.

Which physical quantity is the same for X-rays of wavelength \(10^{-10}\) m, red light of wavelength 6800 Å and radio waves of wavelength 500 m? (1 mark)

Answer: The velocity (speed) in vacuum, \(3\times10^8\) m/s.

The amplitude \(B_0\) of a harmonic electromagnetic wave in vacuum is 510 nT. What is the amplitude of the electric field part of the wave? (1 mark)

Answer: \( E_0=cB_0=3\times10^8\times510\times10^{-9}=153\ \text{N/C} \)

Suppose \(E_0=120\) N/C and its frequency \( \nu=50\) Hz. Find \(B_0\), \(\omega\), \(k\) and \(\lambda\), and write the expressions for \(\vec E\) and \(\vec B\). (2 marks)

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\( B_0=E_0/c=400\ \text{nT} \); \( \omega=3.14\times10^8 \) rad/s; \( k=1.05 \) rad/m; \( \lambda=6 \) m.

\[ E_y=120\sin\left[1.05x-3.14\times10^8t\right]\hat j\ \text{N C}^{-1} \]

\[ B_z=400\sin\left[1.05x-3.14\times10^8t\right]\hat k\ \text{nT} \]

Note: the source question says 50 Hz, but its answer (and the standard NCERT problem) uses 50 MHz.

The charging current for a capacitor is 0.25 A. What is the displacement current across its plates? (1 mark)

Answer: 0.25 A (the displacement current equals the conduction (charging) current).

A variable frequency a.c. source is connected to a capacitor. Will the displacement current increase or decrease with increasing frequency? (1 mark)

Answer: It increases (the current \( I=\omega CV \) is proportional to the frequency).

An e.m. wave travels in a medium at a speed of \(2\times10^8\) m/s. The relative permeability of the medium is 1.0. Calculate the relative permittivity.

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\[ v=\frac{c}{\sqrt{\mu_r\varepsilon_r}}\ \Rightarrow\ \varepsilon_r=\left(\frac cv\right)^2\frac1{\mu_r}=\left(\frac{3\times10^8}{2\times10^8}\right)^2=2.25 \]

How does a charge q oscillating at a certain frequency produce an electromagnetic wave? (1 mark)

Answer: An oscillating charge produces an oscillating electric field, which produces an oscillating magnetic field, which in turn produces an oscillating electric field, and so on; the fields propagate as an electromagnetic wave.

How would you establish an instantaneous displacement current of 1 A in the space between the parallel plates of a 1 \(\mu\)F capacitor? (1 mark)

Answer: By changing the voltage across the capacitor at the rate \( \dfrac{dV}{dt}=\dfrac{I}{C}=\dfrac{1}{10^{-6}}=10^6\ \text{V/s} \).

Name the Maxwell equation, among the four, which shows that a magnetic monopole does not exist. (1 mark)

Answer: Gauss's law for magnetism, \( \oint\vec B\cdot d\vec S=0 \).

Write the unit of \( \mu_0\varepsilon_0 \). (1 mark)

Answer: Since \( \mu_0\varepsilon_0=1/c^2 \), its unit is \( (\text{m/s})^{-2} \).

Give a reason for the decrease or increase in the velocity of light when it moves from air to glass or from glass to air respectively. (1 mark)

Answer: The velocity of light in a medium is \( v=\dfrac{1}{\sqrt{\mu\varepsilon}} \); it depends on the permittivity \(\varepsilon\) and permeability \(\mu\) of the medium. Glass has larger \(\varepsilon\) and \(\mu\) than air, so the velocity decreases in glass and increases again when the light comes back to air.

A parallel plate capacitor made of circular plates each of radius 10 cm has a capacitance of 200 pF. The capacitor is connected to a 200 V a.c. supply with an angular frequency of 200 rad/s. (a) What is the rms value of the conduction current? (b) Is the conduction current equal to the displacement current? (c) Find the peak value of the displacement current. (d) Determine the amplitude of the magnetic field at a point 2 cm from the axis between the plates.

(a) \( I_{rms}=\omega C V_{rms}=200\times200\times10^{-12}\times200=8\ \mu\text{A} \)

(b) Yes, \( I_c=I_d \).

(c) \( I_0=\sqrt2\,I_{rms}=11.3\ \mu\text{A} \)

(d) \[ B=\frac{\mu_0}{2\pi}\frac{r\,I_0}{R^2}=\frac{2\times10^{-7}\times0.02\times11.3\times10^{-6}}{(0.1)^2}\approx4.525\times10^{-12}\ \text{T} \]

Electromagnetic waves with wavelengths (i) \(\lambda_1\) are used to treat muscular strain, (ii) \(\lambda_2\) are used by an FM radio station for broadcasting, (iii) \(\lambda_3\) are produced by bombarding a metal target by high speed electrons, (iv) \(\lambda_4\) are absorbed by the ozone layer of the atmosphere. Identify and name the part of the electromagnetic spectrum to which these radiations belong. Arrange these wavelengths in decreasing order of magnitude. (3 marks)

\( \lambda_1 \): infrared radiation; \( \lambda_2 \): VHF/radio waves; \( \lambda_3 \): X-rays; \( \lambda_4 \): ultraviolet (UV).

\[ \lambda_2>\lambda_1>\lambda_4>\lambda_3 \]

(a) Which of the following, if any, can act as a source of electromagnetic waves? (i) A charge moving with constant velocity. (ii) A charge moving in a circular orbit. (iii) A charge at rest. Give reasons. (b) Identify the part of the electromagnetic spectrum to which waves of frequency (i) \(10^{20}\) Hz and (ii) \(10^{9}\) Hz belong. (3 marks)

(a) (i) It cannot produce e.m. waves, because there is no acceleration.
(ii) It is an accelerated motion, so it can produce e.m. waves.
(iii) It cannot produce e.m. waves, because there is no acceleration.

(b) (i) Gamma rays. (ii) Microwaves.

Ans : useful-resources-physics-cbse-class-12-physics-electro-3

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BX=(4×10-6T) Sin [(1.57×107m-1)y+(4.5×1011t)]

(c) and wavelength write the expressions for electric field.

Ans :

Ans : Gauss’s theorem of Magnetism

15. Write the unit of µ0ε0 ?

Ans : The velocity of light depends on ε & μ of the medium.

Free CBSE Study Guides: Class 12 Physics Chapter 08 Electromagnetic Waves

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