BITSAT Mathematics Permutations and Combinations MCQs

Practice BITSAT Mathematics Permutations and Combinations MCQs provided below. The MCQ Questions for Full Syllabus Permutations and Combinations Mathematics with answers and follow the latest BITSAT/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for BITSAT Full Syllabus Mathematics and also download more latest study material for all subjects

MCQ for Full Syllabus Mathematics Permutations and Combinations

Full Syllabus Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Permutations and Combinations

Permutations and Combinations MCQ Questions Full Syllabus Mathematics with Answers

 

Question: How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions ?

  • a) 16
  • b) 36
  • c) 60
  • d) 180

Answer: 60

 

Question: Statement 1 : A five digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5 with repetition. The total number formed are 216. Statement 2 : If sum of digits of any number is divisible by 3 then the number must be divisible by 3.

  • a) Statement-1 is true, Statement-2 is true and is a correct explanation for Statement -1
  • b) Statement -1 is true, Statement -2 is true and is NOT a correct explanation for Statement - 1
  • c) Statement - 1 is true, Statement- 2 is false
  • d) Statement -1 is false, Statement -2 is true

Answer: Statement -1 is false, Statement -2 is true


Question: If

 BITSAT Mathematics Permutations 1

 then a – n is equal to

  • a) 0
  • b) 1
  • c) 2
  • d) None of these

Answer: 0 

Question: The number of values of r satisfying the equation BITSAT Mathematics Permutations 2is

  • a) 1
  • b) 2
  • c) 3
  • d) 4

Answer: 2

 

Question: All the words that can be formed using alphabets A, H, L, U and R are written as in a dictionary (no alphabet is repeated). Rank of the word RAHUL is

  • a) 71
  • b) 72
  • c) 73
  • d) 74

Answer: 74

 

Question: The total number of 4-digit numbers in which the digits are in descending order, is

  • a) 10C4 × 4!
  • b) 10C4
  • c)

    BITSAT Mathematics Permutations 3

  • d) None of these

Answer:   10C4

 

Question: The number of all three elements subsets of the set {a1, a2, a3 . . . an} which contain a3 is

  • a) nC3
  • b) n – 1C3
  • c) n – 1C2
  • d) None of these

Answer: n – 1C2

 

Question: In how many ways can a committee of 5 made out 6 men and 4 women containing atleast one woman?

  • a) 246
  • b) 222
  • c) 186
  • d) None of these

Answer: 246

 

Question: In how many ways can 5 boys and 5 girls be seated at a round table so that no two girls may be together ?

  • a) 4!
  • b) 5!
  • c) 4! + 5!
  • d) 4! × 5!

Answer: 4! × 5!

 

Question: A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?

  • a) 64
  • b) 129
  • c) 84
  • d) None of these

Answer: 64

 

Question: In how many ways can 5 prizes be distributed among 4 boys when every boy can take one or more prizes ?

  • a) 1024
  • b) 625
  • c) 120
  • d) 600

Answer: 1024

 

Question: The number of positive integral solution of abc= 30 is

  • a) 30
  • b) 27
  • c) 8
  • d) None of these

Answer: 27

 

Question: If 20Cr = 20Cr–10 then 18Cr is equal to

  • a) 4896
  • b) 816
  • c) 1632
  • d) None of these

Answer: 816

 

Question: In a polygon no three diagonals are concurrent. If the total number of points of intersection of diagonals interior to the polygon be 70 then the number of diagonals of the polygon is

  • a) 20
  • b) 28
  • c) 8
  • d) None of these

Answer: 20

 

Question: With 17 consonants and 5 vowels the number of words of four letters that can be formed having two different vowels in the middle and one consonant, repeated or different at each end is

  • a) 5780
  • b) 2890
  • c) 5440
  • d) 2720

Answer: 5780

 

Question: The letters of the word TOUGH are written in all possible orders and these words are written out as in a dictionary, then the rank of the word TOUGH is

  • a) 120
  • b) 88
  • c) 89
  • d) 90

Answer: 89

 

Question: If 2n +1Pn–1 : 2n – 1Pn = 3 : 5 then the value of n is equal to

  • a) 4
  • b) 3
  • c) 2
  • d) 1

Answer: 4

 

Question: 3 integers are chosen at random from the set of first 20 natural numbers. The chance that their product is a multiple of 3, is –

  • a) 194/285
  • b) 1/57
  • c) 13/19
  • d) 3/4

Answer: 194/285

 

Question: If the total number of m elements subsets of the set A = {a1, a2, a3, ...., an} is l times the number of 3 elements subsets containing a4, then n is

  • a) (m – 1) λ
  • b) mλ
  • c) (m + 1) λ
  • d) 0

Answer: 

 

Question: The number of arrangements of the letters of the word BANANA is which the two ‘N’s do not appear adjacently is

  • a) 40
  • b) 60
  • c) 80
  • d) 100

Answer: 40

 

MCQs for Permutations and Combinations Mathematics Full Syllabus

Students can use these MCQs for Permutations and Combinations to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Full Syllabus Mathematics released by BITSAT. Our expert teachers suggest that you should practice daily and solving these objective questions of Permutations and Combinations to understand the important concepts and better marks in your school tests.

Permutations and Combinations NCERT Based Objective Questions

Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Full Syllabus. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Permutations and Combinations, you should also refer to our NCERT solutions for Full Syllabus Mathematics created by our team.

Online Practice and Revision for Permutations and Combinations Mathematics

To prepare for your exams you should also take the Full Syllabus Mathematics MCQ Test for this chapter on our website. This will help you improve your speed and accuracy and its also free for you. Regular revision of these Mathematics topics will make you an expert in all important chapters of your course.

Where can I access latest BITSAT Mathematics Permutations and Combinations MCQs?

You can get most exhaustive BITSAT Mathematics Permutations and Combinations MCQs for free on StudiesToday.com. These MCQs for Full Syllabus Mathematics are updated for the 2025-26 academic session as per BITSAT examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Full Syllabus material?

Yes, our BITSAT Mathematics Permutations and Combinations MCQs include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the BITSAT paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in Full Syllabus exams?

By solving our BITSAT Mathematics Permutations and Combinations MCQs, Full Syllabus students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for BITSAT Mathematics Permutations and Combinations MCQs?

Yes, Mathematics MCQs for Full Syllabus have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused BITSAT exams.

Can I practice these Mathematics Full Syllabus MCQs online?

Yes, you can also access online interactive tests for BITSAT Mathematics Permutations and Combinations MCQs on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.