BITSAT Mathematics Application Of Integrals MCQs

BITSAT Mathematics Application Of Integrals MCQs with answers available in Pdf for free download. The MCQ Questions for BITSAT Mathematics with answers have been prepared as per the latest BITSAT Mathematics syllabus, books and examination pattern. Multiple Choice Questions form important part of competitive exams and BITSAT exam and if practiced properly can help you to get higher rank. Refer to more topic wise BITSAT Mathematics Questions and also download more latest study material for all subjects and do free BITSAT Mathematics Mock Test

MCQ for BITSAT Mathematics Application Of Integrals

BITSAT Mathematics students should refer to the following multiple-choice questions with answers for Application Of Integrals in BITSAT. These MCQ questions with answers for BITSAT Mathematics will come in exams and help you to score good marks

Application Of Integrals MCQ Questions with Answers

 

Question: The area under the curve y = | cos x – sin x |,BITSAT Mathematics Application of Integralsand above x-axis is :

  • a) 2 √2
  • b) 2 √2 - 2
  • c) 2 √2 + 2
  • d) 0

Answer: 2 √2 - 2

 

Question: The area of the region R =BITSAT Mathematics Application of Integrals 2BITSAT Mathematics Application of Integrals 3 is

  • a)

    BITSAT Mathematics Application of Integrals 4

  • b)

    BITSAT Mathematics Application of Integrals 5

  • c)

    BITSAT Mathematics Application of Integrals 6

  • d)

    BITSAT Mathematics Application of Integrals 7

Answer:

BITSAT Mathematics Application of Integrals 6

 

Question: The area bounded by the x-axis, the curve y = f(x) and the lines x =1, x =b, is equal to BITSAT Mathematics Application of Integrals 8for all b > 1, then f(x) is

  • a)

    BITSAT Mathematics Application of Integrals 9

  • b)

    BITSAT Mathematics Application of Integrals 10

  • c)

    BITSAT Mathematics Application of Integrals 11

  • d)

    BITSAT Mathematics Application of Integrals 12

Answer:

BITSAT Mathematics Application of Integrals 12

 

Question: Area intercepted by the curves y = cos x, x €[0, π] and y = cos 2x, x Î[0,π] , is

  • a)

    BITSAT Mathematics Application of Integrals 13

  • b)

    BITSAT Mathematics Application of Integrals 14

  • c)

    BITSAT Mathematics Application of Integrals 15

  • d)

    BITSAT Mathematics Application of Integrals 16

Answer:

BITSAT Mathematics Application of Integrals 16

 

Question: The area bounded by the curve y = sinx, x-axis and the ordinates x = 0 and x = π/2 is

  • a) π
  • b) π/2
  • c) 1
  • d) 2

Answer: 1 

Question: What is the area bounded by y = tan x , y = 0 and BITSAT Mathematics Application of Integrals 17

  • a) ln 2 sq. units
  • b)

    BITSAT Mathematics Application of Integrals 18

  • c) 2 (ln 2) sq. units
  • d) None of these

Answer: 

BITSAT Mathematics Application of Integrals 18

 

Question: The area of the region bounded by the curve y = x | x |, x-axis and the ordinates x = 1, x = -1is given by :

  • a) zero
  • b)

    BITSAT Mathematics Application of Integrals 19

  • c)

    BITSAT Mathematics Application of Integrals 20

  • d) 1

Answer:

BITSAT Mathematics Application of Integrals 20

 

Question: Area of the triangle formed by the line x + y = 3 and angle bisectors of the pair of straight lines x2 – y2 + 2y =1 is

  • a) 2 sq. units
  • b) 4 sq. units
  • c) 6 sq. units
  • d) 8 sq. units

Answer: 2 sq. units


Question: The area between the parabola y = x2 and the line y = x is:

  • a)

    BITSAT Mathematics Application of Integrals 21

  • b)

    BITSAT Mathematics Application of Integrals 22

  • c)

    BITSAT Mathematics Application of Integrals 23

  • d)

    None of these

Answer:

BITSAT Mathematics Application of Integrals 21

 

Question: The area between the curve y = 1 – |x| and the x – axis is equal to

  • a) 1 sq. unit
  • b)

    BITSAT Mathematics Application of Integrals 24

  • c)

    BITSAT Mathematics Application of Integrals 25

  • d) 2 sq. units

Answer: 1 sq. unit

 

Question: The area of the figure bounded by y = ex, y = ex and x = 1 is

  • a) 2(e – 1)
  • b) 

    BITSAT Mathematics Application of Integrals 26

  • c)

    BITSAT Mathematics Application of Integrals 27

  • d)

    BITSAT Mathematics Application of Integrals 28

Answer:

BITSAT Mathematics Application of Integrals 26

 

Question:  The area of the region bounded by y = | x – 1 | and y = 1 is

  • a) 2
  • b) 1
  • c) 1/2
  • d) 1/4

Answer: 1

 

Question: The area bounded by the x-axis, the curve y = f(x) and the lines x =1, x =b, is equal to BITSAT Mathematics Application of Integrals 8for all b > 1, then f(x) is

  • a)

    BITSAT Mathematics Application of Integrals 9

  • b)

    BITSAT Mathematics Application of Integrals 10

  • c)

    BITSAT Mathematics Application of Integrals 11

  • d)

    BITSAT Mathematics Application of Integrals 12

Answer:

BITSAT Mathematics Application of Integrals 12

 

Question: The area of the region R =BITSAT Mathematics Application of Integrals 2BITSAT Mathematics Application of Integrals 3 is

  • a)

    BITSAT Mathematics Application of Integrals 4

  • b)

    BITSAT Mathematics Application of Integrals 5

  • c)

    BITSAT Mathematics Application of Integrals 6

  • d)

    BITSAT Mathematics Application of Integrals 7

Answer:

BITSAT Mathematics Application of Integrals 6

 

Question: The area under the curve y = | cos x – sin x |,BITSAT Mathematics Application of Integralsand above x-axis is :

  • a) 2 √2
  • b) 2 √2 - 2
  • c) 2 √2 + 2
  • d) 0

Answer:  2 √2 - 2

 

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