CBSE Class 11 Mathematics HOTs Straight Lines

Check out CBSE Class 11 Mathematics HOTs Straight Lines right here. Get complete High Order Thinking Skills (HOTS) questions and answers for Class 11 Mathematics Chapter 09 Straight Lines. Created for the 2026-27 exam session, these analytical practice problems help learners master core ideas while following guidelines from CBSE, NCERT, and KVS.

High Order Thinking Skills: Class 11 Mathematics Chapter 09 Straight Lines

Check out these Class 11 Mathematics HOTS Questions to test your advanced knowledge of Mathematics. The detailed answers below will help you practice smarter and build high-level accuracy for your Class 11 tests.

Download HOTS: Chapter 09 Straight Lines (Class 11 Mathematics)

Question. Through the point P(α,β),where αβ > 0 , the straight line x/a + y/b = 1 is drawn so as to form with coordinate axes a triangle of area S. If ab > 0, then least value of S is
(a) 2αβ
(b) (1/2)αβ
(c) ab
(d) None of these
Answer : A

Question. If the straight lines 2x + 3y – 1 = 0, x + 2y – 1 = 0 and ax + by – 1 = 0 form a triangle with origin as orthocentre, then (a, b) is given by
(a) (6, 4)
(b) (– 3, 3)
(c) (– 8, 8)
(d) (0, 7)
Answer : C

Question. The vertices of a triangle are (ab, 1/ab), (bc, 1/bc) and (ca,1/ca) where a, b, c are the roots of the equation x3 – 3x2 + 6x + 1 = 0. The coordinates of its centroid are.
(a) (1, 2)
(b) (2, – 1)
(c) (1, – 1)
(d) (2, 3)
Answer : B

Question. Consider points A (3, 4) and B (7, 13). If P be a point on the line y = x such that PA + PB is minimum, then coordinates of P are
(a) (12/7, 12/7)
(b) (13/7, 13/7)
(c) (31/7, 31/7)
(d) (0, 0)
Answer : C

Question. Let A (–3, 2) and B (–2, 1) be the vertices of a triangle ABC. If the centroid of this triangle lies on the line 3x + 4y + 2 = 0, then the vertex C lies on the line :
(a) 4x + 3y + 5 = 0
(b) 3x + 4y + 3 = 0
(c) 4x + 3y + 3 = 0
(d) 3x + 4y + 5 = 0
Answer : B

Question. The straight line y = x – 2 rotates about a point where it cuts the x-axis and becomes perpendicular to the straight line ax + by + c = 0. Then its equation is
(a) ax + by + 2a = 0
(b) ax – by – 2a = 0
(c) bx + ay – 2b = 0
(d) ay – bx + 2b = 0
Answer : D

Question. The range of values of β such that (0, β) lie on or inside the triangle formed by the lines y + 3x + 2 = 0, 3y – 2x – 5 = 0, 4y + x – 14 = 0 is
(a) 5 < b ≤ 7
(b) 1/1 ≤ β ≤ 1
(c) 5/3 ≤ β ≤ 7/2
(d) None of these
Answer : C

Question. The line x/a + y/b = 1 meets the axis of x and y at A and B respectively and the line y = x at C so that area of the trinagle AOC is twice the area of the triangle BOC, O being the origin, then one of the positions of C is
(a) (a, a)
(b) (2a/3, 2a/3) 
(c) (b/3, b/3) 
(d) (2b/3, 2b/3) 
Answer : D

Question. If three distinct points A, B, C are given in the 2-dimensional coordinate plane such that the ratio of the distance of each one of them from the point (1, 0) to the distance from (– 1, 0) is equal to 1/2, then the circumcentre of the triangle ABC is at the point
(a) (5/3 ,0)
(b) (0, 0)
(c) (1/3 ,0)
(d) (3, 0)
Answer : A

Question. The line parallel to the x- axis and passing through the intersection of the lines ax + 2by + 3b = 0 and bx – 2ay – 3a = 0, where (a, b) ¹ (0, 0) is
(a) below the x - axis at a distance of 3/2 from it
(b) below the x - axis at a distance of 2/3 from it
(c) above the x - axis at a distance of 3/2 from it
(d) above the x - axis at a distance of 2/3 from it
Answer : A

Question. The equation of bisector of that angle between the lines x + y + 1 = 0 and 2x – 3y – 5 = 0 which contains the point (10, – 20) is
(a) x (√13 + 2√2) + y (√13 – 3√2) + (√13 – 5√2) = 0
(b) x (√13 – 2√2) + y (√13 + 3√2) + (√13 + 5√2) = 0
(c) x (√13 + 2√2) + y (√13 + 3√2) + (√13 + 5√2) = 0
(d) None of these
Answer : A

Question. The intercepts on the straight line y = mx by the lines y = 2 and y = 6 is less than 5, then m belongs to
(a) (- 4/3, 4/3)
(b) (4/3, 4/3)
(c) (- ∞, 4/3) ∪ (4/3, ∞)
(d) (- 4/3, ∞)
Answer : C

Question. The base of an equilateral triangle is along the line given by 3x + 4y = 9. If a vertex of the triangle is (1, 2), then the length of a side of the triangle is:
(a) 2√3/15
(b) 4√3/15
(c) 4√3/5
(d) 2√3/5
Answer : B

Question. The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points (a2 + 1, a2 + 1) and (2a, – 2a), a ¹ 0. Then for any a, the orthocentre of this triangle lies on the line:
(a) y – 2ax = 0
(b) y – (a2 + 1)x = 0
(c) y + x = 0
(d) (a – 1)2x – (a + 1)2y = 0
Answer : D

Question. If the point (a, 2) lies between the lines x – y – 1 = 0 and 2 (x – y) + 5 = 0, then the set of values of ‘a’ is
(a) (– ∞ , 3) ∪ ( 9/2, ∞)
(b) (3, 9/2)
(c) (– ∞ , 3)
(d) (- 1/2 , 3)
Answer : D

Question. If two vertices of a triangle are (5, –1) and (–2, 3) and its orthocentre is at (0, 0), then the third vertex is
(a) (4, – 7)
(b) (– 4, – 7)
(c) (– 4, 7)
(d) (4, 7)
Answer : B

Question. The bisector of the acute angle formed between the lines 4x - 3y + 7 = 0 and 3x - 4y +14 = 0 has the equation :
(a) x + y + 3 = 0
(b) x - y -3 = 0
(c) x - y + 3 = 0
(d) 3x + y - 7 = 0
Answer : C

Numeric Value Answer

Question. The straight line L ≡ x + y + 1 = 0 and L1 ≡ x + 2y + 3 = 0 are intersecting. m is the slope of the straight line L2 such that L is the bisector of the anlge between L1 and L2. The unit digit of 812m2 + 3 is equal to
Answer : 1

Question. In ΔABC, the vertex A = (1, 2), y = x is the perpendicular bisector of the side AB and x – 2y + 1 = 0 is the equation of the internal angle bisector of L . If the equation of the side BC is ax + by – 5 = 0, then the value of a – b is ..... .
Answer : 4

Question. A straight line through the origin O meets the parallel lines 4x + 2y = 9 and 2x + y + 6 = 0 at points P and Q respectively. If the point O divides the segment PQ in the ratio m/n , then m + n is ________.
Answer : 7

Question. The vertex of an equilateral triangle is (2, –1), and the equation of its base is x + 2y = 1. If the length of its sides is 2 /√K , then value of K is ____.
Answer : 15

Question. If (sin θ, cos θ), θ ∈ [0, 2π] and (1, 4) lie on the same side or on the line √3x – y + 1 = 0, then the maximum value of sin θ will be ______.
Answer : 0

Question. The straight lines (3secq + 5cosec q)x + (7sec θ - 3cosecθ)y +11(secθ - cosecθ) = 0 always pass through a fixed point P for all possible values of q. If the maximum value of the difference of distances of P and B (3, 4) from a point on the line x - y + 3 = 0 is k then k2/10 is equal to .
Answer : 4

Question. If tana, tanb, tanl are the roots of the equation t3 – 12t2 + 15t – 1 = 0; then the centroid of triangle having vertices (tana, cota); (tanβcotbb); (tanλ, cotl) is given by G(h, k); then evaluate (h + k)/(k – h).
Answer : 9

Question. Consider a ΔABC whose sides AB, BC, and CA are represented by the straight lines 2x + y = 0, x + py = q, and x – y = 3, respectively. The point P(2, 3) is the orthocenter. The value of (p + q)/10 is ..... .
Answer : 5

Download Class 11 Mathematics Chapter 09 Straight Lines HOTS Practice Questions

High Order Thinking Skills: Chapter 09 Straight Lines Overview

Download high-level analytical questions for Chapter 09 Straight Lines. Designed in alignment with the latest CBSE syllabus for Class 11 Mathematics, these problem sets test deep conceptual understanding and prepare students for complex exam questions.

Step-by-Step Answers for Chapter 09 Straight Lines

Pair these practice sets with our comprehensive NCERT solutions for Class 11 Mathematics to clear up doubts. Checking your working against our detailed explanations guarantees absolute mastery over this chapter.

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FAQs

Where can I download the latest PDF for CBSE Class 11 Mathematics HOTs Straight Lines?

You can download the teacher-verified PDF for CBSE Class 11 Mathematics HOTs Straight Lines from StudiesToday.com. These questions have been prepared for Class 11 Mathematics to help students learn high-level application and analytical skills required for the 2026-27 exams.

Why are HOTS questions important for the 2026 CBSE exam pattern?

In the 2026 pattern, 50% of the marks are for competency-based questions. Our CBSE Class 11 Mathematics HOTs Straight Lines are to apply basic theory to real-world to help Class 11 students to solve case studies and assertion-reasoning questions in Mathematics.

How do CBSE Class 11 Mathematics HOTs Straight Lines differ from regular textbook questions?

Unlike direct questions that test memory, CBSE Class 11 Mathematics HOTs Straight Lines require out-of-the-box thinking as Class 11 Mathematics HOTS questions focus on understanding data and identifying logical errors.

What is the best way to solve Mathematics HOTS for Class 11?

After reading all conceots in Mathematics, practice CBSE Class 11 Mathematics HOTs Straight Lines by breaking down the problem into smaller logical steps.

Are solutions provided for Class 11 Mathematics HOTS questions?

Yes, we provide detailed, step-by-step solutions for CBSE Class 11 Mathematics HOTs Straight Lines. These solutions highlight the analytical reasoning and logical steps to help students prepare as per CBSE marking scheme.