Please refer to CBSE Class 11 Mathematics HOTs Straight Lines. Download HOTS questions and answers for Class 11 Mathematics. Read CBSE Class 11 Mathematics HOTs for Chapter 10 Straight Lines below and download in pdf. High Order Thinking Skills questions come in exams for Mathematics in Class 11 and if prepared properly can help you to score more marks. You can refer to more chapter wise Class 11 Mathematics HOTS Questions with solutions and also get latest topic wise important study material as per NCERT book for Class 11 Mathematics and all other subjects for free on Studiestoday designed as per latest CBSE, NCERT and KVS syllabus and pattern for Class 11
Chapter 10 Straight Lines Class 11 Mathematics HOTS
Class 11 Mathematics students should refer to the following high order thinking skills questions with answers for Chapter 10 Straight Lines in Class 11. These HOTS questions with answers for Class 11 Mathematics will come in exams and help you to score good marks
HOTS Questions Chapter 10 Straight Lines Class 11 Mathematics with Answers
Question. Through the point P(α,β),where αβ > 0 , the straight line x/a + y/b = 1 is drawn so as to form with coordinate axes a triangle of area S. If ab > 0, then least value of S is
(a) 2αβ
(b) (1/2)αβ
(c) ab
(d) None of these
Answer : A
Question. If the straight lines 2x + 3y – 1 = 0, x + 2y – 1 = 0 and ax + by – 1 = 0 form a triangle with origin as orthocentre, then (a, b) is given by
(a) (6, 4)
(b) (– 3, 3)
(c) (– 8, 8)
(d) (0, 7)
Answer : C
Question. The vertices of a triangle are (ab, 1/ab), (bc, 1/bc) and (ca,1/ca) where a, b, c are the roots of the equation x3 – 3x2 + 6x + 1 = 0. The coordinates of its centroid are.
(a) (1, 2)
(b) (2, – 1)
(c) (1, – 1)
(d) (2, 3)
Answer : B
Question. Consider points A (3, 4) and B (7, 13). If P be a point on the line y = x such that PA + PB is minimum, then coordinates of P are
(a) (12/7, 12/7)
(b) (13/7, 13/7)
(c) (31/7, 31/7)
(d) (0, 0)
Answer : C
Question. Let A (–3, 2) and B (–2, 1) be the vertices of a triangle ABC. If the centroid of this triangle lies on the line 3x + 4y + 2 = 0, then the vertex C lies on the line :
(a) 4x + 3y + 5 = 0
(b) 3x + 4y + 3 = 0
(c) 4x + 3y + 3 = 0
(d) 3x + 4y + 5 = 0
Answer : B
Question. The straight line y = x – 2 rotates about a point where it cuts the x-axis and becomes perpendicular to the straight line ax + by + c = 0. Then its equation is
(a) ax + by + 2a = 0
(b) ax – by – 2a = 0
(c) bx + ay – 2b = 0
(d) ay – bx + 2b = 0
Answer : D
Question. The range of values of β such that (0, β) lie on or inside the triangle formed by the lines y + 3x + 2 = 0, 3y – 2x – 5 = 0, 4y + x – 14 = 0 is
(a) 5 < b ≤ 7
(b) 1/1 ≤ β ≤ 1
(c) 5/3 ≤ β ≤ 7/2
(d) None of these
Answer : C
Question. The line x/a + y/b = 1 meets the axis of x and y at A and B respectively and the line y = x at C so that area of the trinagle AOC is twice the area of the triangle BOC, O being the origin, then one of the positions of C is
(a) (a, a)
(b) (2a/3, 2a/3)
(c) (b/3, b/3)
(d) (2b/3, 2b/3)
Answer : D
Question. If three distinct points A, B, C are given in the 2-dimensional coordinate plane such that the ratio of the distance of each one of them from the point (1, 0) to the distance from (– 1, 0) is equal to 1/2, then the circumcentre of the triangle ABC is at the point
(a) (5/3 ,0)
(b) (0, 0)
(c) (1/3 ,0)
(d) (3, 0)
Answer : A
Question. The line parallel to the x- axis and passing through the intersection of the lines ax + 2by + 3b = 0 and bx – 2ay – 3a = 0, where (a, b) ¹ (0, 0) is
(a) below the x - axis at a distance of 3/2 from it
(b) below the x - axis at a distance of 2/3 from it
(c) above the x - axis at a distance of 3/2 from it
(d) above the x - axis at a distance of 2/3 from it
Answer : A
Question. The equation of bisector of that angle between the lines x + y + 1 = 0 and 2x – 3y – 5 = 0 which contains the point (10, – 20) is
(a) x (√13 + 2√2) + y (√13 – 3√2) + (√13 – 5√2) = 0
(b) x (√13 – 2√2) + y (√13 + 3√2) + (√13 + 5√2) = 0
(c) x (√13 + 2√2) + y (√13 + 3√2) + (√13 + 5√2) = 0
(d) None of these
Answer : A
Question. The intercepts on the straight line y = mx by the lines y = 2 and y = 6 is less than 5, then m belongs to
(a) (- 4/3, 4/3)
(b) (4/3, 4/3)
(c) (- ∞, 4/3) ∪ (4/3, ∞)
(d) (- 4/3, ∞)
Answer : C
Question. The base of an equilateral triangle is along the line given by 3x + 4y = 9. If a vertex of the triangle is (1, 2), then the length of a side of the triangle is:
(a) 2√3/15
(b) 4√3/15
(c) 4√3/5
(d) 2√3/5
Answer : B
Question. The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points (a2 + 1, a2 + 1) and (2a, – 2a), a ¹ 0. Then for any a, the orthocentre of this triangle lies on the line:
(a) y – 2ax = 0
(b) y – (a2 + 1)x = 0
(c) y + x = 0
(d) (a – 1)2x – (a + 1)2y = 0
Answer : D
Question. If the point (a, 2) lies between the lines x – y – 1 = 0 and 2 (x – y) + 5 = 0, then the set of values of ‘a’ is
(a) (– ∞ , 3) ∪ ( 9/2, ∞)
(b) (3, 9/2)
(c) (– ∞ , 3)
(d) (- 1/2 , 3)
Answer : D
Question. If two vertices of a triangle are (5, –1) and (–2, 3) and its orthocentre is at (0, 0), then the third vertex is
(a) (4, – 7)
(b) (– 4, – 7)
(c) (– 4, 7)
(d) (4, 7)
Answer : B
Question. The bisector of the acute angle formed between the lines 4x - 3y + 7 = 0 and 3x - 4y +14 = 0 has the equation :
(a) x + y + 3 = 0
(b) x - y -3 = 0
(c) x - y + 3 = 0
(d) 3x + y - 7 = 0
Answer : C
Numeric Value Answer
Question. The straight line L ≡ x + y + 1 = 0 and L1 ≡ x + 2y + 3 = 0 are intersecting. m is the slope of the straight line L2 such that L is the bisector of the anlge between L1 and L2. The unit digit of 812m2 + 3 is equal to
Answer : 1
Question. In ΔABC, the vertex A = (1, 2), y = x is the perpendicular bisector of the side AB and x – 2y + 1 = 0 is the equation of the internal angle bisector of L . If the equation of the side BC is ax + by – 5 = 0, then the value of a – b is ..... .
Answer : 4
Question. A straight line through the origin O meets the parallel lines 4x + 2y = 9 and 2x + y + 6 = 0 at points P and Q respectively. If the point O divides the segment PQ in the ratio m/n , then m + n is ________.
Answer : 7
Question. The vertex of an equilateral triangle is (2, –1), and the equation of its base is x + 2y = 1. If the length of its sides is 2 /√K , then value of K is ____.
Answer : 15
Question. If (sin θ, cos θ), θ ∈ [0, 2π] and (1, 4) lie on the same side or on the line √3x – y + 1 = 0, then the maximum value of sin θ will be ______.
Answer : 0
Question. The straight lines (3secq + 5cosec q)x + (7sec θ - 3cosecθ)y +11(secθ - cosecθ) = 0 always pass through a fixed point P for all possible values of q. If the maximum value of the difference of distances of P and B (3, 4) from a point on the line x - y + 3 = 0 is k then k2/10 is equal to .
Answer : 4
Question. If tana, tanb, tanl are the roots of the equation t3 – 12t2 + 15t – 1 = 0; then the centroid of triangle having vertices (tana, cota); (tanβ, cotbb); (tanλ, cotl) is given by G(h, k); then evaluate (h + k)/(k – h).
Answer : 9
Question. Consider a ΔABC whose sides AB, BC, and CA are represented by the straight lines 2x + y = 0, x + py = q, and x – y = 3, respectively. The point P(2, 3) is the orthocenter. The value of (p + q)/10 is ..... .
Answer : 5
CBSE Class 11 Mathematics HOTs Sets |
CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction |
CBSE Class 11 Mathematics HOTs Permutations and Combinations |
CBSE Class 11 Mathematics HOTs Sequences and Series |
CBSE Class 11 Mathematics HOTs Straight Lines |
CBSE Class 11 Mathematics HOTs Conic Sections |
CBSE Class 11 Mathematics HOTs Mathematical Reasoning |
CBSE Class 11 Mathematics HOTs Statistics |
CBSE Class 11 Mathematics HOTs Probability |
HOTS for Chapter 10 Straight Lines Mathematics Class 11
Expert teachers of studiestoday have referred to NCERT book for Class 11 Mathematics to develop the Mathematics Class 11 HOTS. If you download HOTS with answers for the above chapter you will get higher and better marks in Class 11 test and exams in the current year as you will be able to have stronger understanding of all concepts. High Order Thinking Skills questions practice of Mathematics and its study material will help students to have stronger understanding of all concepts and also make them expert on all critical topics. You can easily download and save all HOTS for Class 11 Mathematics also from www.studiestoday.com without paying anything in Pdf format. After solving the questions given in the HOTS which have been developed as per latest course books also refer to the NCERT solutions for Class 11 Mathematics designed by our teachers. We have also provided lot of MCQ questions for Class 11 Mathematics in the HOTS so that you can solve questions relating to all topics given in each chapter. After solving these you should also refer to Class 11 Mathematics MCQ Test for the same chapter
You can download the CBSE HOTS for Class 11 Mathematics Chapter 10 Straight Lines for latest session from StudiesToday.com
Yes, the HOTS issued by CBSE for Class 11 Mathematics Chapter 10 Straight Lines have been made available here for latest academic session
HOTS stands for "Higher Order Thinking Skills" in Chapter 10 Straight Lines Class 11 Mathematics. It refers to questions that require critical thinking, analysis, and application of knowledge
Regular revision of HOTS given on studiestoday for Class 11 subject Mathematics Chapter 10 Straight Lines can help you to score better marks in exams
Yes, HOTS questions are important for Chapter 10 Straight Lines Class 11 Mathematics exams as it helps to assess your ability to think critically, apply concepts, and display understanding of the subject.