Refer to CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction. We have provided exhaustive High Order Thinking Skills (HOTS) questions and answers for Class 11 Mathematics Chapter 04 Principle of Mathematical Induction. Designed for the 2026-27 exam session, these expert-curated analytical questions help students master important concepts and stay aligned with the latest CBSE, NCERT, and KVS curriculum.
Chapter 04 Principle of Mathematical Induction Class 11 Mathematics HOTS with Solutions
Practicing Class 11 Mathematics HOTS Questions is important for scoring high in Mathematics. Use the detailed answers provided below to improve your problem-solving speed and Class 11 exam readiness.
HOTS Questions and Answers for Class 11 Mathematics Chapter 04 Principle of Mathematical Induction
Question. If P(n) = 2 + 4 + 6 + .....+ 2n, n∈ N , then P(k) =k(k +1) + 2
⇒ P(k +1) = (k +1)(k + 2) + 2 for all k ∈ N . So we can conclude that P(n) = n(n +1) + 2 for
(a) all n ∈ N
(b) n > 1
(c) n > 2
(d) nothing can be said
Answer : D
Question. For a positive integer n,
Let a(n) = 1 + 1/2 + 1/3 + 1/4 + ....... + 1/(2n) -1 Then
(a) a(100) ≤ 100
(b) a(100) > 100
(c) a(200) ≤ 100
(d) a(200) < 100
Answer : A
Question. If n ∈ N , then the result
1/n + 1/n+1 + 1/n+2 + ...... + 1/2n-1
= 1- 1/2 + 1/3 - 1/4 + ...... + 1/2n-1 holds for
(a) all n ∈ N
(b) for even values of n
(c) for odd values of n
(d) not true for any n
Answer : A
Question. For all n ≥ 1, find
1/1.2 + 1/2.3 + 1/3.4 + ...... + 1/n(n+1)
(a) n/n+1
(b) 1/n+1
(c) 1/n(n +1)
(d) None of these
Answer : A
Question. For all natural numbers n, find
(1+3/1) (1+5/4) (1+7/9) (1+2n+1/n2)
(a) (n + 1)2
(b) (n – 1)2
(c) n(n + 1)
(d) None of these
Answer : A
Question. 2n > n2 when n ∈ N such that
(a) n > 2
(b) n > 3
(c) n < 5
(d) n ≥ 5
Answer : D
Question. The greatest positive integer, which divides n(n +1)(n + 2)(n + 3) for all n∈ N , is
(a) 2
(b) 6
(c) 24
(d) 120
Answer : C
Question. For any n∈ N , the value of the expression
Answer : A
Question. If 49n + 16n + λ is divisible by 64 for all n ∈ N, then the least negative value of λ is
(a) –2
(b) –1
(c) –3
(d) – 4
Answer : B
Question. By mathematical induction,
1/1 • 2 • 3 + 1/2 • 3 • 4 +..... 1 + 1/n(n+1)(n+2) is equal to
(a) n(n+1)/4(n+2) (n+3)
(b) n(n+3)4(n+1)(n+2)
(c) n(n+2)/4(n+1)(n+3)
(d) None of these
Answer : B
Question. If n is a positive integer, then 2 . 42n+1 + 33n+1 is divisible by :
(a) 2
(b) 7
(c) 11
(d) 27
Answer : C
Question. If 4n/n+1 < (2n)!/(n!)2, then P(n) is true for
(a) n ≥ 1
(b) n > 0
(c) n < 0
(d) n ≥ 2
Answer : D
Question. If P(n) : 3n < n!, n ∈ N, then P(n) is true
(a) for n ≥ 6
(b) for n ≥ 7
(c) for n ≥ 3
(d) for all n
Answer : B
Question. If p is a prime number, then n p – n is divisible by p when n is a
(a) Natural number greater than 1
(b) Irrational number
(c) Complex number
(d) Odd number
Answer : A
Question. When 2301 is divided by 5, the least positive remainder is
(a) 4
(b) 8
(c) 2
(d) 6
Answer : C
Question. By the principle of induction ∀ n ∈ N, 32n when divided by 8, leaves remainder
(a) 2
(b) 3
(c) 7
(d) 1
Answer : D
Question. For all n ∈ N, 3.52n + 1 + 23n + 1 is divisible by
(a) 19
(b) 17
(c) 23
(d) 25
Answer : B
Question. For every natural number n, n(n2–1) is divisible by
(a) 4
(b) 6
(c) 10
(d) None of these
Answer : B
Question. For all n ∈ N, 1 + 1/1+2 + 1/1+2+3 + ..... + 1/1+2+3+ ..... +n is equal to
(a) 3n/n+1
(b) n/n+1
(c) 2n/n–1
(d) 2n/n+1
Answer : D
Question. For all n ∈ N, 1.3 + 2.32 + 3.33 + ..... + n.3n is equal to
(a) (2n+1) 3n+1+3/4
(b) (2n –1) 3n+1+3/4
(c) (2n+1)3n+3/4
(d) (2n–1)3n+1+1/4
Answer : B
Numeric Value Answer
Question. The remainder when 599 is divided by 13, is ___________.
Answer : 8
Question. For all n ∈ N, 41n – 14n is a multiple of ___________.
Answer : 27
Question. If n ∈ N, then 11n + 2 + 122n+1 is divisible by ___________.
Answer : 133
Question. For every natural number n, 32n + 2 – 8n – 9 is divisible by ___________.
Answer : 16
Question. If m, n are any two odd positive integers with n < m, then the largest positive integer which divides all the numbers of the type m2 – n2 is
___________.
Answer : 8
Free study material for Mathematics
HOTS for Chapter 04 Principle of Mathematical Induction Mathematics Class 11
Students can now practice Higher Order Thinking Skills (HOTS) questions for Chapter 04 Principle of Mathematical Induction to prepare for their upcoming school exams. This study material follows the latest syllabus for Class 11 Mathematics released by CBSE. These solved questions will help you to understand about each topic and also answer difficult questions in your Mathematics test.
NCERT Based Analytical Questions for Chapter 04 Principle of Mathematical Induction
Our expert teachers have created these Mathematics HOTS by referring to the official NCERT book for Class 11. These solved exercises are great for students who want to become experts in all important topics of the chapter. After attempting these challenging questions should also check their work with our teacher prepared solutions. For a complete understanding, you can also refer to our NCERT solutions for Class 11 Mathematics available on our website.
Master Mathematics for Better Marks
Regular practice of Class 11 HOTS will give you a stronger understanding of all concepts and also help you get more marks in your exams. We have also provided a variety of MCQ questions within these sets to help you easily cover all parts of the chapter. After solving these you should try our online Mathematics MCQ Test to check your speed. All the study resources on studiestoday.com are free and updated for the current academic year.
FAQs
You can download the teacher-verified PDF for CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction from StudiesToday.com. These questions have been prepared for Class 11 Mathematics to help students learn high-level application and analytical skills required for the 2026-27 exams.
In the 2026 pattern, 50% of the marks are for competency-based questions. Our CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction are to apply basic theory to real-world to help Class 11 students to solve case studies and assertion-reasoning questions in Mathematics.
Unlike direct questions that test memory, CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction require out-of-the-box thinking as Class 11 Mathematics HOTS questions focus on understanding data and identifying logical errors.
After reading all conceots in Mathematics, practice CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction by breaking down the problem into smaller logical steps.
Yes, we provide detailed, step-by-step solutions for CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction. These solutions highlight the analytical reasoning and logical steps to help students prepare as per CBSE marking scheme.