CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction

Please refer to CBSE Class 11 Mathematics HOTs Principle of Mathematical Induction. Download HOTS questions and answers for Class 11 Mathematics. Read CBSE Class 11 Mathematics HOTs for Chapter 04 Principle of Mathematical Induction below and download in pdf. High Order Thinking Skills questions come in exams for Mathematics in Class 11 and if prepared properly can help you to score more marks. You can refer to more chapter wise Class 11 Mathematics HOTS Questions with solutions and also get latest topic wise important study material as per NCERT book for Class 11 Mathematics and all other subjects for free on Studiestoday designed as per latest CBSE, NCERT and KVS syllabus and pattern for Class 11

Chapter 04 Principle of Mathematical Induction Class 11 Mathematics HOTS

Class 11 Mathematics students should refer to the following high order thinking skills questions with answers for Chapter 04 Principle of Mathematical Induction in Class 11. These HOTS questions with answers for Class 11 Mathematics will come in exams and help you to score good marks

HOTS Questions Chapter 04 Principle of Mathematical Induction Class 11 Mathematics with Answers

Question. If P(n) = 2 + 4 + 6 + .....+ 2n, n∈ N , then P(k) =k(k +1) + 2
⇒ P(k +1) = (k +1)(k + 2) + 2 for all k ∈ N . So we can conclude that P(n) = n(n +1) + 2 for
(a) all n ∈ N
(b) n > 1
(c) n > 2
(d) nothing can be said
Answer : D

Question. For a positive integer n, 
Let a(n) = 1 + 1/2 + 1/3 + 1/4 + .......  + 1/(2n) -1 Then
(a) a(100) ≤ 100
(b) a(100) > 100
(c) a(200) ≤ 100
(d) a(200) < 100
Answer : A

Question. If n ∈ N , then the result
1/n + 1/n+1 + 1/n+2 + ...... + 1/2n-1 

= 1- 1/2 + 1/3 - 1/4 + ...... + 1/2n-1 holds for
(a) all n ∈ N
(b) for even values of n
(c) for odd values of n
(d) not true for any n
Answer : A

Question. For all n ≥ 1, find 
1/1.2 + 1/2.3 + 1/3.4 + ...... + 1/n(n+1)

(a) n/n+1
(b) 1/n+1
(c) 1/n(n +1)
(d) None of these
Answer : A

Question. For all natural numbers n, find
(1+3/1) (1+5/4) (1+7/9) (1+2n+1/n2)

(a) (n + 1)2
(b) (n – 1)2
(c) n(n + 1)
(d) None of these
Answer : A

Question. 2n > n2 when n ∈ N such that
(a) n > 2
(b) n > 3
(c) n < 5
(d) n ≥ 5
Answer : D

 

Question. The greatest positive integer, which divides n(n +1)(n + 2)(n + 3) for all n∈ N , is
(a) 2
(b) 6
(c) 24
(d) 120
Answer : C

Question. For any n∈ N , the value of the expression

""CBSE-Class-11-Mathematics-HOTs-Principle-of-Mathematical-Induction

Answer : A

 

Question. If 49n + 16n + λ is divisible by 64 for all n ∈ N, then the least negative value of λ is
(a) –2
(b) –1
(c) –3
(d) – 4
Answer : B

Question. By mathematical induction,
1/1 • 2 • 3 + 1/2 • 3 • 4 +..... 1 + 1/n(n+1)(n+2) is equal to
(a) n(n+1)/4(n+2) (n+3)
(b) n(n+3)4(n+1)(n+2)
(c) n(n+2)/4(n+1)(n+3)
(d) None of these
Answer : B

Question. If n is a positive integer, then 2 . 42n+1 + 33n+1 is divisible by :
(a) 2
(b) 7
(c) 11
(d) 27
Answer : C

Question. If 4n/n+1 < (2n)!/(n!)2, then P(n) is true for
(a) n ≥ 1
(b) n > 0
(c) n < 0
(d) n ≥ 2
Answer : D

Question. If P(n) : 3n < n!, n ∈ N, then P(n) is true
(a) for n ≥ 6
(b) for n ≥ 7
(c) for n ≥ 3
(d) for all n
Answer : B

Question. If p is a prime number, then n p – n is divisible by p when n is a
(a) Natural number greater than 1
(b) Irrational number
(c) Complex number
(d) Odd number
Answer : A

 

Question. When 2301 is divided by 5, the least positive remainder is
(a) 4
(b) 8
(c) 2
(d) 6
Answer : C

Question. By the principle of induction ∀ n ∈ N, 32n when divided by 8, leaves remainder
(a) 2
(b) 3
(c) 7
(d) 1
Answer : D

 

Question. For all n ∈ N, 3.52n + 1 + 23n + 1 is divisible by
(a) 19
(b) 17
(c) 23
(d) 25
Answer : B

Question. For every natural number n, n(n2–1) is divisible by
(a) 4
(b) 6
(c) 10
(d) None of these
Answer : B

Question. For all n ∈ N, 1 + 1/1+2 + 1/1+2+3 +  ..... + 1/1+2+3+ ..... +n  is equal to
(a) 3n/n+1
(b) n/n+1
(c) 2n/n–1
(d) 2n/n+1
Answer : D

Question. For all n ∈ N, 1.3 + 2.32 + 3.33 + ..... + n.3n is equal to
(a) (2n+1) 3n+1+3/4
(b) (2n –1) 3n+1+3/4
(c) (2n+1)3n+3/4
(d) (2n–1)3n+1+1/4
Answer : B

Numeric Value Answer

Question. The remainder when 599 is divided by 13, is ___________.
Answer : 8

Question. For all n ∈ N, 41n – 14n is a multiple of ___________.
Answer : 27

Question. If n ∈ N, then 11n + 2 + 122n+1 is divisible by ___________.
Answer : 133

Question. For every natural number n, 32n + 2 – 8n – 9 is divisible by ___________.
Answer : 16

Question. If m, n are any two odd positive integers with n < m, then the largest positive integer which divides all the numbers of the type m2 – n2 is
___________.
Answer : 8

HOTS for Chapter 04 Principle of Mathematical Induction Mathematics Class 11

Expert teachers of studiestoday have referred to NCERT book for Class 11 Mathematics to develop the Mathematics Class 11 HOTS. If you download HOTS with answers for the above chapter you will get higher and better marks in Class 11 test and exams in the current year as you will be able to have stronger understanding of all concepts. High Order Thinking Skills questions practice of Mathematics and its study material will help students to have stronger understanding of all concepts and also make them expert on all critical topics. You can easily download and save all HOTS for Class 11 Mathematics also from www.studiestoday.com without paying anything in Pdf format. After solving the questions given in the HOTS which have been developed as per latest course books also refer to the NCERT solutions for Class 11 Mathematics designed by our teachers. We have also provided lot of MCQ questions for Class 11 Mathematics in the HOTS so that you can solve questions relating to all topics given in each chapter. After solving these you should also refer to Class 11 Mathematics MCQ Test for the same chapter

Where can I download latest CBSE HOTS for Class 11 Mathematics Chapter 04 Principle of Mathematical Induction

You can download the CBSE HOTS for Class 11 Mathematics Chapter 04 Principle of Mathematical Induction for latest session from StudiesToday.com

Are the Class 11 Mathematics Chapter 04 Principle of Mathematical Induction HOTS available for the latest session

Yes, the HOTS issued by CBSE for Class 11 Mathematics Chapter 04 Principle of Mathematical Induction have been made available here for latest academic session

What does HOTS stand for in Class 11 Mathematics Chapter 04 Principle of Mathematical Induction

HOTS stands for "Higher Order Thinking Skills" in Chapter 04 Principle of Mathematical Induction Class 11 Mathematics. It refers to questions that require critical thinking, analysis, and application of knowledge

How can I improve my HOTS in Class 11 Mathematics Chapter 04 Principle of Mathematical Induction

Regular revision of HOTS given on studiestoday for Class 11 subject Mathematics Chapter 04 Principle of Mathematical Induction can help you to score better marks in exams

Are HOTS questions important for Chapter 04 Principle of Mathematical Induction Class 11 Mathematics exams

Yes, HOTS questions are important for Chapter 04 Principle of Mathematical Induction Class 11 Mathematics exams as it helps to assess your ability to think critically, apply concepts, and display understanding of the subject.