CBSE Class 3 Mathematics Multiplication Assignment

School Assignments for Class 3 Mathematics: Multiplication

Explore structured practice materials through the CBSE Class 3 Mathematics Multiplication Assignment. Tailored for Class 3 learners, utilizing these Mathematics assignments ensures thorough preparation and strengthens foundational knowledge before final CBSE evaluations.

Practice Class 3 Mathematics Assignments: Multiplication

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Multiplication

1) Fill in the blanks :

Question 1. Multiplication is a repeated ____________________.
Answer: addition
In simple words: Multiplication means adding the same number over and over again.

Exam Tip: Remember that multiplication is essentially fast repeated addition.

 

Question 2. The number to be multiplied is called the _____________________.
Answer: multiplicand
In simple words: The multiplicand is the starting number that gets multiplied.

Exam Tip: Learn the terminology: multiplicand, multiplier, and product.

 

Question 3. The number by which we multiply is called the _________________
Answer: multiplier
In simple words: The multiplier tells you how many times to add the multiplicand.

Exam Tip: Multiplier is the second number in a standard multiplication expression.

 

Question 4. ________________is the repeated addition.
Answer: Multiplication
In simple words: Adding 3 four times (\(3 + 3 + 3 + 3\)) is the same as \(4 \times 3\).

Exam Tip: This is the fundamental definition of multiplication.

 

Question 5. The product of ‘0’ and any number is ________________.
Answer: 0
In simple words: Any number multiplied by zero always gives zero.

Exam Tip: Zero property of multiplication: \(a \times 0 = 0\).

 

Question 6. The product of ‘1’ and any number is the _______________.
Answer: number itself
In simple words: Multiplying any number by one leaves the number unchanged.

Exam Tip: Identity property of multiplication: \(a \times 1 = a\).

 

Question 7. We can multiply two numbers in any order, the product will be the ___________________________.
Answer: same
In simple words: Changing the order of numbers in multiplication does not change the answer (\(2 \times 3 = 3 \times 2\)).

Exam Tip: This is known as the commutative property of multiplication.

 

Question 8. \(5 \times 7 =\) ________ \(\times 5\)
Answer: 7
In simple words: The missing number is 7 because order does not matter in multiplication.

 

Question 9. \(8 \times\) ______ \(= 4 \times 8\)
Answer: 4
In simple words: Match both sides to find the missing factor 4.

Exam Tip: Both sides of the equals sign must be balanced.

 

Question 10. \(9 \times 9 =\) ______.
Answer: 81
In simple words: Nine times nine equals eighty-one.

Exam Tip: Memorize multiplication tables up to 10 or 12.

 

Question 11. \(4 \times 0 =\) __________
Answer: 0
In simple words: Four groups of zero is zero.

Exam Tip: Anything multiplied by 0 is 0.

 

Question 12. ______ \(\times 3 = 2 \times 3\)
Answer: 2
In simple words: The missing number is 2 to make both sides equal.

Exam Tip: Compare corresponding positions on both sides.

 

Question 13. \(0 \times 17 =\) ____________
Answer: 0
In simple words: Zero multiplied by any large number is still zero.

Exam Tip: Do not get confused by large numbers when multiplied by 0.

 

Question 14. \(10 \times 10 =\) _____________
Answer: 100
In simple words: Ten times ten is one hundred.

Exam Tip: Count the total number of zeros when multiplying by powers of 10.

 

Question 15. __________ \(\times 7 = 7 \times 4\)
Answer: 4
In simple words: By swapping numbers, the blank must be 4.

Exam Tip: Commutative property makes filling this straightforward.

 

Question 16. \(9 \times\) _________ \(= 6 \times 9\)
Answer: 6
In simple words: The missing factor is 6.

Exam Tip: Check both sides to ensure equality.

 

Question 17. \(5 \times\) _______ \(= 5 \times\) _________
Answer: any number, the same number (e.g., 3, 3)
In simple words: Any number multiplied by 5 equals 5 multiplied by that same number.

Exam Tip: Any identical value filled in both blanks will satisfy the equation.

 

Question 18. \(1 \times 1 =\) ___________
Answer: 1
In simple words: One times one is one.

Exam Tip: Basic multiplication fact.

 

Question 19. \(4 \times 8 = 8 \times\) _______
Answer: 4
In simple words: The missing number is 4.

Question 21. \(7 \times 9 = 9 \times\) ______
Answer: 7
In simple words: The missing factor is 7.

Exam Tip: Notice the numbering in the source skipped 20; solve sequentially as provided.

 

2) Complete the following :

Question 1. \(3 \times 10 =\) _____________
Answer: 30
In simple words: Multiply 3 by 1 and attach one zero to get 30.

Exam Tip: When multiplying by 10, simply append one zero to the number.

 

Question 2. \(7 \times 1000 =\) ______________
Answer: 7000
In simple words: Multiply 7 by 1 and attach three zeros to get 7000.

Exam Tip: Append three zeros when multiplying by 1000.

 

Question 3. \(4 \times 100 =\) ______________
Answer: 400
In simple words: Multiply 4 by 1 and attach two zeros to get 400.

Exam Tip: Append two zeros when multiplying by 100.

 

Question 4. \(65 \times 10 =\) _____________
Answer: 650
In simple words: Put a zero at the end of 65 to make 650.

Exam Tip: Quick shortcut for multiplying by 10.

 

Question 5. \(141 \times 100 =\) ____________
Answer: 14100
In simple words: Attach two zeros to 141 to get 14100.

Exam Tip: Adding zeros to the right is a fast way to multiply by powers of 10.

 

Question 6. \(76 \times 1000 =\) __________
Answer: 76000
In simple words: Attach three zeros to 76.

Exam Tip: Count zeros carefully.

 

Question 7. \(123 \times 10 =\) _____________
Answer: 1230
In simple words: Append one zero to 123.

Exam Tip: Multiplying by 10 shifts digits one place to the left.

 

Question 8. \(40 \times 100 =\) ______________
Answer: 4000
In simple words: 40 followed by two more zeros gives 4000.

Exam Tip: Total zeros in product = zeros in first number + zeros in second number (\(1 + 2 = 3\) zeros total).

 

Question 9. \(50 \times 10 =\) ________________
Answer: 500
In simple words: 50 with one more zero attached is 500.

Exam Tip: \(5 \times 1 = 5\), plus two zeros (\(50 \times 10\)).

 

Question 10. \(60 \times 1000 =\) _____________
Answer: 60000
In simple words: 60 followed by three zeros equals 60000.

Exam Tip: Total zeros = 1 (from 60) + 3 (from 1000) = 4 zeros.

 

Question 11. \(4 \times 20 =\) ____________
Answer: 80
In simple words: Multiply \(4 \times 2 = 8\) and attach one zero.

Exam Tip: Multiply non-zero digits first, then append trailing zeros.

 

Question 12. \(4 \times 4000 =\) ______________
Answer: 16000
In simple words: Multiply \(4 \times 4 = 16\) and attach three zeros.

 

Question 13. \(30 \times 300 =\) __________________
Answer: 9000
In simple words: Multiply \(3 \times 3 = 9\) and attach three zeros (\(1 + 2\)).

Exam Tip: Count all trailing zeros: 1 from 30 and 2 from 300.

 

Question 14. \(14 \times\) _________________ \(= 1400\)
Answer: 100
In simple words: 14 multiplied by 100 gives 1400.

Exam Tip: Divide 1400 by 14 to find the missing factor.

 

Question 15. \(53 \times 100 =\) ____________
Answer: 5300
In simple words: Attach two zeros to 53.

Exam Tip: Quick multiplication rule for 100.

 

Question 16. \(341 \times 100 =\) _____________
Answer: 34100
In simple words: Attach two zeros to 341.

Exam Tip: Result is 34,100.

 

Question 17. \(120 \times 100 =\) _______________
Answer: 12000
In simple words: 120 with two more zeros is 12000.

Exam Tip: Total zeros = 1 (from 120) + 2 (from 100) = 3 zeros.

 

Question 18. \(42 \times 400 =\) _______________
Answer: 16800
In simple words: Multiply \(42 \times 4 = 168\) and attach two zeros.

Exam Tip: \(40 \times 400 = 16000\) and \(2 \times 400 = 800\); sum is 16800.

 

Question 19. ______________ \(\times\) ______________ \(= 2300\)
Answer: 23, 100 (or other valid combinations like 230, 10)
In simple words: 23 multiplied by 100 equals 2300.

Exam Tip: Any correct factor pair is acceptable.

 

Question 20. \(71 \times 500 =\) ______________
Answer: 35500
In simple words: Multiply \(71 \times 5 = 355\) and attach two zeros.

 

Question 21. ___________ \(\times\) __________ \(= 27000\)
Answer: 27, 1000 (or 270, 100, etc.)
In simple words: 27 multiplied by 1000 equals 27000.

Exam Tip: Look at the trailing zeros to determine the power of 10.

 

Question 22. ______________ \(\times\) __________ \(= 6300\)
Answer: 63, 100 (or 630, 10, etc.)
In simple words: 63 multiplied by 100 gives 6300.

Exam Tip: Identify the base number 63 and two zeros for 100.

 

Question 23. _____________ \(\times\) _______________ \(= 1200\)
Answer: 12, 100 (or 120, 10, etc.)
In simple words: 12 multiplied by 100 gives 1200.

Exam Tip: Standard factor pair is 12 and 100.

 

Question 24. \(65 \times 100 =\) ___________
Answer: 6500
In simple words: Attach two zeros to 65.

Exam Tip: Result is 6500.

 

Question 25. \(30 \times 1000 =\) __________
Answer: 30000
In simple words: 30 followed by three zeros is 30000.

Exam Tip: Total zeros = 1 + 3 = 4 zeros.

 

Question 26. \(123 \times\) ______________ \(= 123000\)
Answer: 1000
In simple words: 123 multiplied by 1000 gives 123000.

Exam Tip: Count the additional three zeros to find the multiplier.

 

Question 27. ___________ \(\times\) __________ \(= 80\)
Answer: 8, 10 (or 80, 1, etc.)
In simple words: 8 multiplied by 10 equals 80.

Exam Tip: Simple multiplication fact.

 

3) Multiply the following :

Question 1. Multiply \(4372 \times 2\)
Answer:
\(2 \times 2 = 4\)
\(2 \times 7 = 14\) (write 4, carry 1)
\(2 \times 3 = 6 + 1 = 7\)
\(2 \times 4 = 8\)
Product = 8744
In simple words: Multiply each digit of 4372 by 2 from right to left.

Exam Tip: Always remember to add any carried-over numbers from the previous column.

 

Question 2. Multiply \(8764 \times 6\)
Answer:
\(6 \times 4 = 24\) (write 4, carry 2)
\(6 \times 6 = 36 + 2 = 38\) (write 8, carry 3)
\(6 \times 7 = 42 + 3 = 45\) (write 5, carry 4)
\(6 \times 8 = 48 + 4 = 52\)
Product = 52584
In simple words: Multiply 8764 by 6 step-by-step with carrying.

Exam Tip: Double-check multiplication tables for 6.

 

Question 3. Multiply \(6087 \times 7\)
Answer:
\(7 \times 7 = 49\) (write 9, carry 4)
\(7 \times 8 = 56 + 4 = 60\) (write 0, carry 6)
\(7 \times 0 = 0 + 6 = 6\)
\(7 \times 6 = 42\)
Product = 42609
In simple words: Multiply 6087 by 7, taking care of zeros and carries.

Exam Tip: Multiplying zero by 7 gives 0, but you must add the carried 6.

 

Question 4. Multiply \(6100 \times 5\)
Answer:
\(5 \times 0 = 0\)
\(5 \times 0 = 0\)
\(5 \times 1 = 5\)
\(5 \times 6 = 30\)
Product = 30500
In simple words: Multiply non-zero leading digits and keep the zeros.

 

Question 5. Multiply \(7008 \times 9\)
Answer:
\(9 \times 8 = 72\) (write 2, carry 7)
\(9 \times 0 = 0 + 7 = 7\)
\(9 \times 0 = 0\)
\(9 \times 7 = 63\)
Product = 63072
In simple words: Multiply 7008 by 9 with proper carrying.

Exam Tip: Be careful with zeros in the hundreds and tens places.

 

Question 6. Multiply \(1986 \times 3\)
Answer:
\(3 \times 6 = 18\) (write 8, carry 1)
\(3 \times 8 = 24 + 1 = 25\) (write 5, carry 2)
\(3 \times 9 = 27 + 2 = 29\) (write 9, carry 2)
\(3 \times 1 = 3 + 2 = 5\)
Product = 5958
In simple words: Multiply 1986 by 3 with carries.

Exam Tip: Align columns properly to avoid addition errors.

 

Question 7. Multiply \(8402 \times 4\)
Answer:
\(4 \times 2 = 8\)
\(4 \times 0 = 0\)
\(4 \times 4 = 16\) (write 6, carry 1)
\(4 \times 8 = 32 + 1 = 33\)
Product = 33608
In simple words: Multiply 8402 by 4 digit by digit.

Exam Tip: Check each column calculation carefully.

 

Question 8. Multiply \(8197 \times 8\)
Answer:
\(8 \times 7 = 56\) (write 6, carry 5)
\(8 \times 9 = 72 + 5 = 77\) (write 7, carry 7)
\(8 \times 1 = 8 + 7 = 15\) (write 5, carry 1)
\(8 \times 8 = 64 + 1 = 65\)
Product = 65576
In simple words: Multiply 8197 by 8 with carries.

Exam Tip: Write carries clearly above the digits.

 

Question 9. Multiply \(9876 \times 9\)
Answer:
\(9 \times 6 = 54\) (write 4, carry 5)
\(9 \times 7 = 63 + 5 = 68\) (write 8, carry 6)
\(9 \times 8 = 72 + 6 = 78\) (write 8, carry 7)
\(9 \times 9 = 81 + 7 = 88\)
Product = 88884
In simple words: Multiply 9876 by 9 with proper carrying.

Exam Tip: Notice the repeating 8s in the product.

 

Question 10. Multiply \(76 \times 21\)
Answer:
\(76 \times 1 = 076\)
\(76 \times 20 = 1520\)
Sum = \(76 + 1520 = 1596\)
Product = 1596
In simple words: Multiply 76 by 1, then by 20, and add both results together.

Exam Tip: Remember to put a zero in the ones place when multiplying by the tens digit.

 

Question 11. Multiply \(53 \times 16\)
Answer:
\(53 \times 6 = 318\)
\(53 \times 10 = 530\)
Sum = \(318 + 530 = 848\)
Product = 848
In simple words: Multiply 53 by 6 and by 10, then add the partial products.

Exam Tip: Line up columns properly during addition.

 

Question 12. Multiply \(48 \times 78\)
Answer:
\(48 \times 8 = 384\)
\(48 \times 70 = 3360\)
Sum = \(384 + 3360 = 3744\)
Product = 3744
In simple words: Multiply 48 by 8 and by 70, then add them.

 

Question 13. Multiply \(24 \times 59\)
Answer:
\(24 \times 9 = 216\)
\(24 \times 50 = 1200\)
Sum = \(216 + 1200 = 1416\)
Product = 1416
In simple words: Multiply 24 by 9 and 50, then find their sum.

Exam Tip: Double-check partial products.

 

Question 14. Multiply \(59 \times 73\)
Answer:
\(59 \times 3 = 177\)
\(59 \times 70 = 4130\)
Sum = \(177 + 4130 = 4307\)
Product = 4307
In simple words: Multiply 59 by 3 and 70, then add them up.

Exam Tip: Ensure correct alignment of numbers in addition.

 

Question 15. Multiply \(64 \times 27\)
Answer:
\(64 \times 7 = 448\)
\(64 \times 20 = 1280\)
Sum = \(448 + 1280 = 1728\)
Product = 1728
In simple words: Multiply 64 by 7 and 20, then add the results.

Exam Tip: Check your addition of 448 and 1280.

 

Question 16. Multiply \(23 \times 46\)
Answer:
\(23 \times 6 = 138\)
\(23 \times 40 = 920\)
Sum = \(138 + 920 = 1058\)
Product = 1058
In simple words: Multiply 23 by 6 and 40, then add them.

Exam Tip: Keep your handwriting neat to avoid column confusion.

 

Question 17. Multiply \(94 \times 56\)
Answer:
\(94 \times 6 = 564\)
\(94 \times 50 = 4700\)
Sum = \(564 + 4700 = 5264\)
Product = 5264
In simple words: Multiply 94 by 6 and 50, then add the products.

Exam Tip: Verify carries in multiplication steps.

 

Question 18. Multiply \(65 \times 82\)
Answer:
\(65 \times 2 = 130\)
\(65 \times 80 = 5200\)
Sum = \(130 + 5200 = 5330\)
Product = 5330
In simple words: Multiply 65 by 2 and 80, then add them.

Exam Tip: Add 130 and 5200 carefully.

 

Question 19. Multiply \(214 \times 6\)
Answer:
\(6 \times 4 = 24\) (write 4, carry 2)
\(6 \times 1 = 6 + 2 = 8\)
\(6 \times 2 = 12\)
Product = 1284
In simple words: Multiply 214 by 6 digit by digit.

Exam Tip: Standard 3-digit by 1-digit multiplication.

 

Question 20. Multiply \(378 \times 9\)
Answer:
\(9 \times 8 = 72\) (write 2, carry 7)
\(9 \times 7 = 63 + 7 = 70\) (write 0, carry 7)
\(9 \times 3 = 27 + 7 = 34\)
Product = 3402
In simple words: Multiply 378 by 9 with proper carrying.

Exam Tip: Double check the addition of carries.

 

Question 21. Multiply \(965 \times 8\)
Answer:
\(8 \times 5 = 40\) (write 0, carry 4)
\(8 \times 6 = 48 + 4 = 52\) (write 2, carry 5)
\(8 \times 9 = 72 + 5 = 77\)
Product = 7720
In simple words: Multiply 965 by 8 step-by-step.

Exam Tip: Always add carries immediately after multiplying.

 

4) Word Problems based :

Question 1. There are 68 students in a school. How many students are there in 14 such schools?
Answer:
Number of students in 1 school = 68
Number of schools = 14
Total students = \(68 \times 14\)
\(68 \times 4 = 272\)
\(68 \times 10 = 680\)
\(272 + 680 = 952\)
Total students = 952
In simple words: Multiply the number of students in one school by the total number of schools.

Exam Tip: State each logical step clearly with proper units in word problems.

 

Question 2. The cost of one book is Rs 87. Find the cost of 23 such books?
Answer:
Cost of 1 book = Rs 87
Number of books = 23
Total cost = \(87 \times 23\)
\(87 \times 3 = 261\)
\(87 \times 20 = 1740\)
\(261 + 1740 = 2001\)
Total cost = Rs 2001
In simple words: Multiply the cost of one book by 23.

Exam Tip: Include the currency unit (Rs) in your final answer statement.

 

Question 3. A car travels 75km in one hour. How far will it travel in 52 hours.
Answer:
Distance traveled in 1 hour = 75 km
Total time = 52 hours
Total distance = \(75 \times 52\)
\(75 \times 2 = 150\)
\(75 \times 50 = 3750\)
\(150 + 3750 = 3900\)
Total distance = 3900 km
In simple words: Multiply speed (distance per hour) by total hours.

 

Question 4. There are 174 racks in a library. Each rack contains 9 books. How many books are there in the library?
Answer:
Number of racks = 174
Books in each rack = 9
Total books = \(174 \times 9\)
\(9 \times 4 = 36\) (write 6, carry 3)
\(9 \times 7 = 63 + 3 = 66\) (write 6, carry 6)
\(9 \times 1 = 9 + 6 = 15\)
Total books = 1566
In simple words: Multiply the number of racks by books per rack.

Exam Tip: Check multiplication calculations carefully.

 

Question 5. A book contains 206 pages. How many pages are there in 8 such books.
Answer:
Pages in 1 book = 206
Number of books = 8
Total pages = \(206 \times 8\)
\(8 \times 6 = 48\) (write 8, carry 4)
\(8 \times 0 = 0 + 4 = 4\)
\(8 \times 2 = 16\)
Total pages = 1648
In simple words: Multiply pages per book by 8.

Exam Tip: Write the final sentence clearly specifying total pages.

 

Question 6. One box has 54 blocks. How many blocks are there in 31 boxes?
Answer:
Blocks in 1 box = 54
Number of boxes = 31
Total blocks = \(54 \times 31\)
\(54 \times 1 = 54\)
\(54 \times 30 = 1620\)
\(54 + 1620 = 1674\)
Total blocks = 1674
In simple words: Multiply blocks per box by 31 boxes.

Exam Tip: Double check your addition of partial products.

 

Download Practice Assignments: Class 3 Mathematics Multiplication

Class 3 Mathematics Multiplication Printable Assignments

Access structured practice assignments for Multiplication designed in alignment with the latest CBSE curriculum for Class 3 Mathematics. These printable sets cover objective and descriptive problem types to support thorough revision.

Maximize Exam Scores with Chapter Practice Sets

  • Exam Alignment: Questions strictly follow contemporary CBSE sample papers and grading schemes.
  • Comprehensive Coverage: Features objective drills, case studies, and structured descriptive problems for Multiplication.
  • Pacing & Precision: Regular problem-solving builds critical calculation speed and test-taking accuracy.

Steps to Complete Multiplication Assignments Successfully

  1. Initial Reading: Begin by reading the NCERT book for Class 3 Mathematics to build a baseline understanding.
  2. Independent Testing: Attempt assignment questions unassisted, then verify work using provided answer keys.
  3. Supplementary Aids: Leverage revision notes and worksheets whenever you encounter difficult topics.

FAQs

Where can I download the latest CBSE Class 3 Mathematics Multiplication assignments?

You can download free PDF assignments for Class 3 Mathematics Multiplication from StudiesToday.com. These practice sheets have been updated for the 2026-27 session covering all concepts from latest NCERT textbook.

Do these Mathematics Multiplication assignments include solved questions?

Yes, our teachers have given solutions for all questions in the Class 3 Mathematics Multiplication assignments. This will help you to understand step-by-step methodology to get full marks in school tests and exams.

Are the assignments for Class 3 Mathematics Multiplication based on the 2026 exam pattern?

Yes. These assignments are designed as per the latest CBSE syllabus for 2026. We have included huge variety of question formats such as MCQs, Case-study based questions and important diagram-based problems found in Multiplication.

How can practicing Multiplication assignments help in Mathematics preparation?

Practicing topicw wise assignments will help Class 3 students understand every sub-topic of Multiplication. Daily practice will improve speed, accuracy and answering competency-based questions.

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