CBSE Class 12 Mathematics Vector Algebra Important Questions Set 01

Official CBSE Study Materials for Class 12 Mathematics

Access comprehensive study materials and useful resources for Chapter 10 Vector Algebra using the CBSE Class 12 Mathematics Vector Algebra Important Questions Set 01. Designed to align with the 2026-27 CBSE academic guidelines, these advanced resources help Class 12 Mathematics students reinforce core concepts beyond standard textbooks.

Advanced Resources for Mathematics

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Very Short Answer Questions:

Question. What is the degree of the following differential equation: \(5x\left(\frac{dy}{dx}\right)^2 - \frac{d^2y}{dx^2} - 6y = \log x\) ? 
Answer: 1

Question. Write the degree of the following differential equation: \(x^3 \left(\frac{d^2y}{dx^2}\right)^2 + x\left(\frac{dy}{dx}\right)^4 = 0\) 
Answer: 2

Question. Write the sum of the order and degree of the following differential equation: \(\left(\frac{d^2y}{dx^2}\right)^2 + \left(\frac{dy}{dx}\right)^3 + x^4 = 0\) 
Answer: 4

Question. Find the product of the order and degree \(x\left(\frac{d^2y}{dx^2}\right)^2 + \left(\frac{dy}{dx}\right)^2 + y^2 = 0\).
Answer: 4

Question. Write the differential equation formed from the equation \(y = mx + c\), where \(m\) and \(c\) are arbitrary constants. 
Answer: \(\frac{d^2y}{dx^2} = 0\)

Question. Write the integrating factor of \((x \log x)\frac{dy}{dx} + y = 2\log x\) . 
Answer: \(\log x\)

Question. Solve : \(e^{dy/dx} = x^2\)
Answer: \(y = 2(x \log x - x) + C\)

Question. State whether \(y = e^{-x}(x + a)\) is the solution of differential equation: \(\frac{dy}{dx} + y = e^{-x}\)
Answer: Yes

Question. Solve : \(\frac{dy}{dx} - \frac{y(x + 1)}{x} = 0\)
Answer: \(y = x e^{x+C}\)

Short Answer Questions–I:

Question. Write the general solution of the differential equation \(\frac{dy}{dx} = \frac{y}{x}\) .
Answer: \(y = C x\)

Question. Write the integrating factor of \(\frac{dy}{dx} + y = \frac{1 + y}{x}\) .
Answer: \(\frac{e^x}{x}\)

Question. Given that \(\frac{dy}{dx} = e^{-2y}\) and \(y = 0\) when \(x = 5\). Find the value of \(x\) when \(y = 3\).
Answer: \(\frac{e^6+9}{2}\)

Question. Find the general solution of the differential equation \(\frac{dy}{dx} = 2^{y-x}\) .
Answer: \(2^{-x} - 2^{-y} = C\)

Question. Find the differential equation of the family of curves \(y = A e^{2x} + B e^{-2x}\).
Answer: \(\frac{d^2y}{dx^2} - 4y = 0\)

Short Answer Questions–II:

Question. Solve the following differential equation: \(\cos^2 x \frac{dy}{dx} + y = \tan x\) 
Answer: \(y = \tan x - 1 + C e^{-\tan x}\)

Question. Solve the differential equation: \((x^2 + 1)\frac{dy}{dx} + 2xy = \sqrt{x^2 + 4}\) 
Answer: \((x^2 + 1)y = \frac{x}{2}\sqrt{x^2 + 4} + 2 \log|x + \sqrt{x^2 + 4}| + C\)

Question. Solve : \((1 + x^2)\frac{dy}{dx} + y = \tan^{-1} x\) 
Answer: \(y e^{\tan^{-1} x} = (\tan^{-1} x - 1) e^{\tan^{-1} x} + C\)

Question. Solve : \((x^2 - 1)\frac{dy}{dx} + 2xy = \frac{2}{x^2 - 1}\) 
Answer: \(y(x^2 - 1) = \log \left| \frac{x - 1}{x + 1} \right| + C\)

Question. Solve the differential equation: \(y + x \frac{dy}{dx} = x - y \frac{dy}{dx}\) 
Answer: \(y^2 + 2xy - x^2 = C^2\)

Question. Solve the differential equation: \((x^2 + 3xy + y^2)dx - x^2 dy = 0\) given that \(y = 0\), when \(x = 1\)
Answer: \(y = \frac{x \log|x|}{1 - \log|x|}\)

Question. Solve the differential equation : \((x + 1)\frac{dy}{dx} - y = e^{3x}(x + 1)^3\) 
Answer: \(\frac{y}{x + 1} = \frac{e^{3x}}{3} \frac{(x + 1)^2}{9} + C\)

Question. Solve the following differential equation : \(y^2 dx + (x^2 - xy + y^2)dy = 0\) 
Answer: \(y = C e^{\tan^{-1} \frac{y}{x}}\)

Question. Find the particular solution of the differential equation: \((1 + e^{2x})dy + (1 + y^2)e^x dx = 0\), given that \(y = 1\), when \(x = 0\) 
Answer: \(\tan^{-1} y + \tan^{-1} e^x = \frac{\pi}{2}\)

Question. Find the particular solution of this differential equation \(x^2 \frac{dy}{dx} - xy = 1 + \cos\left(\frac{y}{x}\right) , x \neq 0\). Find the particular solution of this differential equation, given that when \(x = 1, y = \frac{\pi}{2}\) . 
Answer: \(\tan\left(\frac{y}{2x}\right) = -\frac{1}{2x^2} + \frac{3}{2}\)

Question. Find the particular solution of the differential equation \(\frac{dy}{dx} = \frac{xy}{x^2 + y^2}\) given that \(y = 1\), when \(x = 0\). 
Answer: \(-\frac{x^2}{2y^2} + \log|y| = 0\)

Question. Solve the following differential equation: \((x^2 - 1)\frac{dy}{dx} + 2xy = \frac{2}{x^2 - 1}\) 
Answer: \(y = \frac{1}{x^2 - 1} \log \left| \frac{x - 1}{x + 1} \right| + \frac{C}{x^2 - 1}\)

Question. Solve the differential equation \(\frac{dy}{dx} + y \cot x = 2 \cos x\), given that when \(x = \frac{\pi}{2}, y = 0\). 
Answer: \(2y \sin x = -(1 + \cos 2x)\)

Question. Solve the following differential equation: \((1 + x^2)\frac{dy}{dx} + y = \tan^{-1} x\) 
Answer: \(y = (\tan^{-1} x - 1) + C e^{-\tan^{-1} x}\)

Question. Solve the differential equation \((x^2 - yx^2) dy + (y^2 + x^2y^2) dx = 0\), given that \(y = 1\), when \(x = 1\). 
Answer: \(\log|y| + \frac{1}{y} = -\frac{1}{x} + x + 1\)

Question. Solve the differential equation: \(\frac{dy}{dx} = \frac{x + y}{x - y}\) 
Answer: \(\tan^{-1}\left(\frac{y}{x}\right) = \frac{1}{2}\log(x^2 + y^2) + C\)

Question. Solve the differential equation: \((1 + x^2)dy + 2xy dx = \cot x dx\) 
Answer: \(y = \frac{1}{1 + x^2} \log|\sin x| + \frac{C}{1 + x^2}\)

Question. Find the general solution of the differential equation \(x^2 y dx - (x^3 + y^3) dy = 0\). 
Answer: \(\log|y| = \frac{x^3}{3y^3} + C\)

Long Answer Questions:

Question. Solve the following differential equation, given that \(y = 0\), when \(x = \frac{\pi}{4}\) : \(\sin 2x \frac{dy}{dx} - y = \tan x\) 
Answer: \(y = \tan x - \sqrt{\tan x}\)

Question. Find the differential equation for all the straight lines, which are at a unit distance from the origin. 
Answer: \(y = x y' \pm \sqrt{(y')^2 + 1}\)

Question. Solve the following differential equation: \(\left[y - x \cos\left(\frac{y}{x}\right)\right]dy + \left[y \cos\left(\frac{y}{x}\right) - 2x \sin\left(\frac{y}{x}\right)\right]dx = 0\) 
Answer: \(y^2 - 2x^2 \cos\left(\frac{y}{x}\right) = C\)

Question. Find the particular solution of the differential equation \((1 + x^2)\frac{dy}{dx} = (e^{m \tan^{-1} x} - y)\) given that \(y = 1\), when \(x = 0\). 
Answer: \(y e^{\tan^{-1} x} = (\tan^{-1} x - 1)e^{\tan^{-1} x} + C\)

Question. Find the particular solution of the following differential equation: \(xy \frac{dy}{dx} = (x + 2)(y + 2)\); \(y = -1\) when \(x = 1\) 
Answer: \(\frac{y}{x+1} = \frac{e^{3x}}{3} - \frac{e^{3x}}{9} + C\)

Question. Find the particular solution of the differential equation \(\frac{dx}{dy} + x \cot y = 2y + y^2 \cot y\), \((y \neq 0)\) given that \(x = 0\) when \(y = \frac{\pi}{2}\) . 
Answer: \(x \sin y = y^2 \sin y - \frac{\pi^2}{4}\)

Question. Find the particular solution of the differential equation \(x(1 + y^2)dx - y(1 + x^2)dy = 0\) given that \(y = 1\) when \(x = 0\). 
Answer: \(\frac{x^2 \log|x|}{1 - \log|x|}\)

Question. Find the particular solution of the differential equation satisfying the given conditions \(x^2 dy + (xy + y^2) dx = 0\); \(y = 1\) when \(x = 1\). 
Answer: \(y = \frac{x \log|x|}{1 - \log|x|}\)

Question. \((x^2 + y^2) dy = xy dx\). If \(y(1) = 1\) and \(y(x_0) = e\), then find the value of \(x_0\). 
Answer: \(x_0 = \sqrt{3}e\)

Question. Find the particular solution of the differential equation \((y - \sin x)dx + (\tan x)dy = 0\) satisfying the condition that \(y = 0\) when \(x = 0\).
Answer: \(y^2 - 2x^2 \cos\left(\frac{y}{x}\right) = C\)

Mathematics Class 12 Exam Resources: Chapter 10 Vector Algebra

Essential Notes for Class 12 Mathematics

Review targeted study resources for Chapter 10 Vector Algebra tailored for Class 12 learners. Utilizing these structured notes and quick-revision tools ensures complete alignment with current CBSE evaluation standards.

Verified Solutions for Class 12 Mathematics

Built using official NCERT guidelines for Class 12 Mathematics, these materials provide reliable academic support. Integrating past examination questions and step-by-step solutions helps students understand official CBSE grading criteria.

Enhance Accuracy with Online Tests

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FAQs

Where can I find the most advanced study material for CBSE Class 12 Mathematics for 2026-27?

The latest 2026-27 advanced study resources for Class 12 Mathematics are available for free on StudiesToday.com which includes NCERT Exemplars, high-order thinking skills (HOTS) questions, and deep-dive concept summaries.

What does the 2026-27 Mathematics study package for Class 12 include?

Our exhaustive Class 12 Mathematics package includes chapter wise revision notes, solved practice sheets, important formulas and Concept Maps to help in better understanding of all topics.

Is this study material enough for both CBSE exams and competitive tests?

Yes. For Class 12, our resources have been developed to help you get better marks in CBSE school exams and also build fundamental strength needed for entrance tests including Competency Based learning.

How should Class 12 students use this Mathematics material for maximum marks?

in Class 12, students should use Active Recall method, read the concept summary, then solve the Important Questions section without looking at the answers and then check your answers.

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All CBSE Mathematics study materials are provided in mobile-friendly PDF. You can download and save them on your device.

Are the Class 12 Mathematics resources updated for the latest NEP guidelines?

Yes, our team has ensured that all Mathematics materials for Class 12 are strictly aligned with the National Education Policy (NEP) 2020 and the latest 2026-27 CBSE syllabus.