Official Class 9 Mathematics Worksheets: Area Of Triangles Herons Formula
Explore structured practice materials through the CBSE Class 9 Mathematics Area Of Triangles Herons Formula Worksheet Set 01. Tailored for Class 9 learners, utilizing these Mathematics worksheets ensures thorough preparation and strengthens problem-solving accuracy before final school evaluations.
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Question. The perimeter of an equilateral triangle is 60 m, then its area is:
(a) 10√3m2
(b) 15√3m2
(c) 20√3m2
(d) 100√3m2
Answer: D
Question. The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is
(A) 1322 cm2
(B) 1311 cm2
(C) 1344 cm2
(D) 1392 cm2
Answer: C
Question. An isosceles right triangle has area 8 cm2. The length of its hypotenuse is
(a) √32cm
(b) √16cm
(c) √48cm
(d) √24cm
Answer: A
Question. The length of each side of an equilateral triangle having an area of 9√3cm2 is
(A) 8 cm
(B) 36 cm
(C) 4 cm
(D) 6 cm
Answer: D
Question. If the area of an equilateral triangle is 16√3cm2 then the perimeter of the triangle is
(A) 48 cm
(B) 24 cm
(C) 12 cm
(D) 36 cm
Answer: B
Question. The area of an equilateral triangle with side 2√3cm is
(a) 5.196 cm2
(b) 0.886 cm2
(c) 3.496 cm2
(d) 1.732 cm2
Answer: A
Question. The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude
(a) 16√5cm
(b) 10√5cm
(c) 24√5cm
(d) 28 cm
Answer: C
Question. The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per cm2 is
(A) Rs2.00
(B) Rs2.16
(C) Rs2.48
(D) Rs3.00
Answer: B
Question. The base and the corresponding altitude of a parallelogram are 10 cm and 3.5 cm, respectively. The area of the parallelogram is 30 cm2.
Answer. The base of the parallelogram is 10 cm and the corresponding altitude is 3.5 cm.
Area of || gm = base × corresponding altitude.
= 10 cm × 3.5 cm = 35 cm2.
Hence, the given statement is false.
Question. The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
Answer. Area of Δ = 1/2 X base X height = 1/2 X 4X 6 = 12cm2
Hence, the statement is false.
Question. The area of the equilateral triangle is 20√3cm2 whose each side is 8 cm.
Answer. Area of equilateral = √3/4 (side)2
= √3/4 (8)2 = √3/4 X 64 = 16 √3cm2
Hence, the given statement is false.
Question. The area of a trapezium is 475 cm2 and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
Answer. Area of trapezium = 1/2 × (Sum of the parallel side) × height
⇒ 475 = 1/2 x (x + x + 4) x 19cm
⇒ 2x + 4 = 950/19 = 50
⇒ 2x + 50 - 4 = 46, x = 46 ÷ 2 = 23
Hence, the length of two parallel sides are 23 cm and (23 + 4) cm i.e., 23 cm and 27 cm.
Question. A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3 m, wide space should be left in the front and back each and 2 m wide space on each of other sides. Find the largest area where house can be constructed.
Answer. The length of the rectangular plot = 40 m
And the breath of the plot = 15 m.
As a minimum of 3 m wide space should be left in the front and back 2 m wide space each
of other side, so the largest area where the house can be constructed.
= [40 − 2(3)] [15− 2(2)] = 34 × 11 = 374m2
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Area Of Triangles Herons Formula Printable Worksheets and Exercises for Class 9 Mathematics
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