Official NCERT Solutions for Class 7 Science: Chapter 13 Motion and Time
Explore reliable textbook solutions for Chapter 13 Motion and Time tailored for Class 7 learners. Utilizing these Science answers ensures thorough preparation and strengthens foundational knowledge before final NCERT evaluations.
Chapter-wise Solutions for Science: Chapter 13 Motion and Time
View or download the dedicated Chapter 13 Motion and Time solution resource below. Engaging with these textbook answers under focused study conditions ensures continuous academic progress and mastery of the 2026-27 curriculum for Science.
NCERT Solutions for Class 7 Science for chaper 13 Motion and Time
Exercises
1. Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
Answer
(i) Oscillatory motion
(ii)Straight line motion
(iii)Circular motion
(iv) Oscillatory motion
(v)Oscillatory motion
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
Time taken = 4 hrs
Speed of train = Distance/Time taken = 240/4 = 60 km/hr
5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Answer
Initial reading of odometer = 57321.0 km
Final reading of odometer = 57336.0 km
Initial Time = 8:30 AM
Final Time = 8:50 AM
Total distance covered = Final reading of odometer - Initial reading of odometer
=57336.0 - 57321.0 = 15.0 km
20 minutes = 20/60 hrs = 1/3 hrs
6. Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
Answer
Speed of bicycle = 2 m/s
Time taken = 15 mins = 15 × 60 secs = 900 secs
A/q,
Speed = Distance/Time
⇒ Distance = Speed × Time = 2 × 900 metres = 1800 metres = 1.8 km
7. Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.
Answer
(i)The graph will be a straight line passing through the origin.
8. Which of the following relations is correct?
(i) Speed = Distance × Time (ii) Speed = Distance/Time
(iii) Speed = Time/Distance (iv) Speed = 1/Distance × Time
Answer
(ii) Speed = Distance/Time
9. The basic unit of speed is:
(i) km/min (ii) m/min
(iii) km/h (iv) m/s
Answer
(iv) m/s
10. A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
(i) 100 km (ii) 25 km
(iii) 15 km (iv) 10 km
Answer
(ii) 25 km
Firstly, the car is moving with 40km/h for 15 minutes.
Total distance covered = 10 km + 15 km = 25 km
11. Suppose the two photographs, shown in Fig. 13.1 and Fig. 13.2, had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the blue car.
Answer
First, measure the distance with the help of scale and then proceed as given below.
Suppose the distance measured by scale is 2cm.
Multiply 2 with 100 to get the actual distance = 2 × 100 = 200 m. (1cm = 100m)
Interval time between the photos taken = 10 s.
Speed of the blue car = 200/10 m/s = 20 m/s
12. Fig. 13.15 shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?
Answer
Vehicle A is moving faster because it has more slope than vehicle B. In distance-time graph, speed is measured by its slope.
13. Which of the following distance-time graphs shows a truck moving with speed which is not constant?
Option (iii) because the slope of the graph is not a straight line and hence it does not show a uniform motion.
Free study material for Science
Step-by-Step Textbook Answers: Class 7 Science Chapter 13 Motion and Time
Textbook Solutions for Class 7 Science Chapter 13 Motion and Time
Review comprehensive exercise answers for Class 7 Science Chapter 13 Motion and Time. Fully updated to match current NCERT syllabus guidelines, these textbook solutions help students verify their work and maintain accurate study notes.
Mastering Theoretical and Practical Questions
Clear, methodical explanations accompany every challenging problem within the Class 7 Science text. Engaging with these detailed answers lays a solid foundation for advanced learning and improves foundational clarity for upcoming assessments.
Effective Self-Study and Homework Assistance
Frequent review of these structured answers builds strong analytical capabilities and response efficiency. Maximize your academic readiness by combining these textbook solutions with our curated study materials and mock evaluations for Class 7 Science.
FAQs
The complete and updated NCERT Solutions Class 7 Science Chapter 13 Motion and Time is available for free on StudiesToday.com. These solutions for Class 7 Science are as per latest NCERT curriculum.
Yes, our experts have revised the NCERT Solutions Class 7 Science Chapter 13 Motion and Time as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Science concepts are applied in case-study and assertion-reasoning questions.
Toppers recommend using NCERT language because NCERT marking schemes are strictly based on textbook definitions. Our NCERT Solutions Class 7 Science Chapter 13 Motion and Time will help students to get full marks in the theory paper.
Yes, we provide bilingual support for Class 7 Science. You can access NCERT Solutions Class 7 Science Chapter 13 Motion and Time in both English and Hindi medium.
Yes, you can download the entire NCERT Solutions Class 7 Science Chapter 13 Motion and Time in printable PDF format for offline study on any device.