Get the most accurate NCERT Solutions for Class 7 Science Chapter 13 Motion and Time here. Updated for the 2025-26 academic session, these solutions are based on the latest NCERT textbooks for Class 7 Science. Our expert-created answers for Class 7 Science are available for free download in PDF format.
Detailed Chapter 13 Motion and Time NCERT Solutions for Class 7 Science
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Class 7 Science Chapter 13 Motion and Time NCERT Solutions PDF
NCERT Solutions for Class 7 Science for chaper 13 Motion and Time
Exercises
1. Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
Answer
(i) Oscillatory motion
(ii)Straight line motion
(iii)Circular motion
(iv) Oscillatory motion
(v)Oscillatory motion
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
Time taken = 4 hrs
Speed of train = Distance/Time taken = 240/4 = 60 km/hr
5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Answer
Initial reading of odometer = 57321.0 km
Final reading of odometer = 57336.0 km
Initial Time = 8:30 AM
Final Time = 8:50 AM
Total distance covered = Final reading of odometer - Initial reading of odometer
=57336.0 - 57321.0 = 15.0 km
20 minutes = 20/60 hrs = 1/3 hrs
6. Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
Answer
Speed of bicycle = 2 m/s
Time taken = 15 mins = 15 × 60 secs = 900 secs
A/q,
Speed = Distance/Time
⇒ Distance = Speed × Time = 2 × 900 metres = 1800 metres = 1.8 km
7. Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.
Answer
(i)The graph will be a straight line passing through the origin.
8. Which of the following relations is correct?
(i) Speed = Distance × Time (ii) Speed = Distance/Time
(iii) Speed = Time/Distance (iv) Speed = 1/Distance × Time
Answer
(ii) Speed = Distance/Time
9. The basic unit of speed is:
(i) km/min (ii) m/min
(iii) km/h (iv) m/s
Answer
(iv) m/s
10. A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
(i) 100 km (ii) 25 km
(iii) 15 km (iv) 10 km
Answer
(ii) 25 km
Firstly, the car is moving with 40km/h for 15 minutes.
Total distance covered = 10 km + 15 km = 25 km
11. Suppose the two photographs, shown in Fig. 13.1 and Fig. 13.2, had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the blue car.
Answer
First, measure the distance with the help of scale and then proceed as given below.
Suppose the distance measured by scale is 2cm.
Multiply 2 with 100 to get the actual distance = 2 × 100 = 200 m. (1cm = 100m)
Interval time between the photos taken = 10 s.
Speed of the blue car = 200/10 m/s = 20 m/s
12. Fig. 13.15 shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?
Answer
Vehicle A is moving faster because it has more slope than vehicle B. In distance-time graph, speed is measured by its slope.
13. Which of the following distance-time graphs shows a truck moving with speed which is not constant?
Option (iii) because the slope of the graph is not a straight line and hence it does not show a uniform motion.
Important Practice Resources for Class 7 Science
NCERT Solutions Class 7 Science Chapter 13 Motion and Time
Students can now access the NCERT Solutions for Chapter 13 Motion and Time prepared by teachers on our website. These solutions cover all questions in exercise in your Class 7 Science textbook. Each answer is updated based on the current academic session as per the latest NCERT syllabus.
Detailed Explanations for Chapter 13 Motion and Time
Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 7 Science chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 7 students who want to understand both theoretical and practical questions. By studying these NCERT Questions and Answers your basic concepts will improve a lot.
Benefits of using Science Class 7 Solved Papers
Using our Science solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 7 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 13 Motion and Time to get a complete preparation experience.
The complete and updated is available for free on StudiesToday.com. These solutions for Class 7 Science are as per latest NCERT curriculum.
Yes, our experts have revised the as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Science concepts are applied in case-study and assertion-reasoning questions.
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