CBSE Class 12 Mathematics Inverse Trigonometric Functions VBQs Set 04

Download CBSE Class 12 Mathematics VBQs: Chapter 2 Inverse Trigonometric Functions

Review targeted competency-based resources with the CBSE Class 12 Mathematics Inverse Trigonometric Functions VBQs Set 04. Built according to official CBSE standards for the 2026-27 academic year, these downloadable Class 12 Mathematics VBQs support holistic learning and critical reasoning for Chapter 2 Inverse Trigonometric Functions.

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Question. If \( \cos \left( \sin^{-1} \frac{2}{5} + \cos^{-1} x \right) = 0 \), then \( x \) is equal to : 
(a) \( \frac{1}{5} \)
(b) \( \frac{2}{5} \)
(c) \( 0 \)
(d) \( 1 \)
Answer: (b) \( \frac{2}{5} \)

 

Question. Which of the following corresponds to the principal value branch of \( \tan^{-1} x \)?
(a) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)
(b) \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] \)
(c) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) - \{0\} \)
(d) \( (0, \pi) \)
Answer: (a) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)

 

Question. The principal value branch of \( \sec^{-1} x \) is:
(a) \( \left[ -\frac{\pi}{2}, \frac{\pi}{2} \right] - \{0\} \)
(b) \( [0, \pi] - \{ \frac{\pi}{2} \} \)
(c) \( (0, \pi) \)
(d) \( \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) \)
Answer: (b) \( [0, \pi] - \{ \frac{\pi}{2} \} \)

 

Question. The principal value of the expression \( \cos^{-1} [\cos (-680^\circ)] \) is :
(a) \( \frac{2\pi}{9} \)
(b) \( -\frac{2\pi}{9} \)
(c) \( \frac{34\pi}{9} \)
(d) \( \frac{\pi}{9} \)
Answer: (a) \( \frac{2\pi}{9} \)

 

Question. The value of \( \cot (\sin^{-1} x) \) is:
(a) \( \frac{\sqrt{1+x^2}}{x} \)
(b) \( \frac{x}{\sqrt{1+x^2}} \)
(c) \( \frac{1}{x} \)
(d) \( \frac{\sqrt{1-x^2}}{x} \)
Answer: (d) \( \frac{\sqrt{1-x^2}}{x} \)

 

Question. The domain of \( \sin^{-1} 2x \) is:
(a) \( [0, 1] \)
(b) \( [-1, 1] \)
(c) \( [-\frac{1}{2}, \frac{1}{2}] \)
(d) \( [-2, 2] \)
Answer: (c) \( [-\frac{1}{2}, \frac{1}{2}] \)

 

Question. The principal value of \( \sin^{-1} \left( -\frac{\sqrt{3}}{2} \right) \) is:
(a) \( -\frac{2\pi}{3} \)
(b) \( -\frac{\pi}{3} \)
(c) \( \frac{4\pi}{3} \)
(d) \( \frac{5\pi}{3} \)
Answer: (b) \( -\frac{\pi}{3} \)

 

Question. The domain of \( y = \cos^{-1} (x^2 - 4) \) is:
(a) \( [3, 5] \)
(b) \( [0, \pi] \)
(c) \( [-\sqrt{5}, -\sqrt{3}] \cap [\sqrt{3}, \sqrt{5}] \)
(d) \( [-\sqrt{5}, -\sqrt{3}] \cup [\sqrt{3}, \sqrt{5}] \)
Answer: (d) \( [-\sqrt{5}, -\sqrt{3}] \cup [\sqrt{3}, \sqrt{5}] \)

 

Question. The domain of the function defined by \( f(x) = \sin^{-1} x + \cos x \) is:
(a) \( [-1, 1] \)
(b) \( [-1, \pi + 1] \)
(c) \( (-\infty, \infty) \)
(d) \( \phi \)
Answer: (a) \( [-1, 1] \)

 

Question. The value of \( \sin [2 \sin^{-1} (0.6)] \) is:
(a) \( 0.48 \)
(b) \( 0.96 \)
(c) \( 1.2 \)
(d) \( \sin 1.2 \)
Answer: (b) \( 0.96 \)

 

Question. The value of \( \tan \left\{ \cos^{-1} \frac{1}{5\sqrt{2}} - \sin^{-1} \frac{4}{\sqrt{17}} \right\} \) is :
(a) \( \frac{\sqrt{29}}{3} \)
(b) \( \frac{29}{3} \)
(c) \( \frac{\sqrt{3}}{29} \)
(d) \( \frac{3}{29} \)
Answer: (d) \( \frac{3}{29} \)

 

Question. If \( \cot^{-1} \left( -\frac{1}{5} \right) = \theta \), the value of \( \sin \theta \) is :
(a) \( \frac{\sqrt{26}}{5} \)
(b) \( -\frac{5}{\sqrt{26}} \)
(c) \( \frac{\sqrt{5}}{\sqrt{26}} \)
(d) \( \frac{5}{\sqrt{26}} \)
Answer: (d) \( \frac{5}{\sqrt{26}} \)

 

Question. If \( \alpha \le 2 \sin^{-1} x + \cos^{-1} x \le \beta \), then:
(a) \( \alpha = -\frac{\pi}{2}, \beta = \frac{\pi}{2} \)
(b) \( \alpha = 0, \beta = \pi \)
(c) \( \alpha = -\frac{\pi}{2}, \beta = \frac{3\pi}{2} \)
(d) \( \alpha = 0, \beta = 2\pi \)
Answer: (b) \( \alpha = 0, \beta = \pi \)

 

Question. The value of \( \tan^2 (\sec^{-1} 2) + \cot^2 (\text{cosec}^{-1} 3) \) is:
(a) \( 5 \)
(b) \( 11 \)
(c) \( 13 \)
(d) \( 15 \)
Answer: (b) \( 11 \)

 

Question. The value of \( \tan \left[ \frac{1}{2} \cos^{-1} \left( \frac{\sqrt{5}}{3} \right) \right] \) is : 
(a) \( \frac{3 + \sqrt{5}}{2} \)
(b) \( \frac{3 - \sqrt{5}}{2} \)
(c) \( \frac{-3 + \sqrt{5}}{2} \)
(d) \( \frac{-3 - \sqrt{5}}{2} \)
Answer: (b) \( \frac{3 - \sqrt{5}}{2} \)

 

Question. The principal value of \( \tan^{-1} \left( \frac{1}{\sqrt{3}} \right) \) is:
(a) \( \frac{\pi}{2} \)
(b) \( \frac{\pi}{6} \)
(c) \( \frac{\pi}{3} \)
(d) \( \pi \)
Answer: (b) \( \frac{\pi}{6} \)

 

Question. The principal value of \( \sec^{-1} \left( -\frac{2}{\sqrt{3}} \right) \) is :
(a) \( \frac{5\pi}{6} \)
(b) \( \frac{2\pi}{3} \)
(c) \( \frac{\pi}{3} \)
(d) None of the options
Answer: (a) \( \frac{5\pi}{6} \)

 

Question. The inverse of cosine function is defined in the intervals :
(a) \( [-\pi, 0] \)
(b) \( [-\frac{\pi}{2}, 0] \)
(c) \( [0, \frac{\pi}{2}] \)
(d) \( [\frac{\pi}{2}, \pi] \)
Answer: (a) \( [-\pi, 0] \)

 

Question. If \( \sin^{-1} x = y \), then :
(a) \( 0 \le y \le x \)
(b) \( -\frac{\pi}{2} \le y \le \frac{\pi}{2} \)
(c) \( 0 < y < \pi \)
(d) \( -\frac{\pi}{2} < y < \frac{\pi}{2} \)
Answer: (b) \( -\frac{\pi}{2} \le y \le \frac{\pi}{2} \)

 

Question. \( \sin \left( \frac{\pi}{3} - \sin^{-1} \left( -\frac{1}{2} \right) \right) \) is equal to :
(a) \( 1/2 \)
(b) \( 1/3 \)
(c) \( 1/4 \)
(d) \( 1 \)
Answer: (d) \( 1 \)

 

Question. The value of \( \tan^{-1} \left( -\frac{1}{\sqrt{3}} \right) + \cot^{-1} \left( \frac{1}{\sqrt{3}} \right) + \tan^{-1} \left( \sin \left( -\frac{\pi}{2} \right) \right) \) is :
(a) \( \frac{\pi}{6} \)
(b) \( \frac{\pi}{12} \)
(c) \( -\frac{\pi}{12} \)
(d) \( -\frac{\pi}{2} \)
Answer: (c) \( -\frac{\pi}{12} \)

 

Question. The value of \( \tan^{-1} \left[ 2 \sin \left( 2 \cos^{-1} \frac{\sqrt{3}}{2} \right) \right] \) is :
(a) \( \frac{\pi}{3} \)
(b) \( \frac{2\pi}{3} \)
(c) \( -\frac{\pi}{3} \)
(d) \( \frac{\pi}{6} \)
Answer: (a) \( \frac{\pi}{3} \)

 

Question. The value of \( \tan^{-1} \left( \tan \frac{5\pi}{6} \right) + \cos^{-1} \left( \cos \frac{13\pi}{6} \right) \) is :
(a) \( 0 \)
(b) \( \frac{\pi}{3} \)
(c) \( \frac{\pi}{6} \)
(d) \( \frac{2\pi}{3} \)
Answer: (a) \( 0 \)

 

Question. The domain of the function \( \cos^{-1} (2x - 1) \) is :
(a) \( [0, 1] \)
(b) \( [-1, 1] \)
(c) \( (-1, 1) \)
(d) \( [0, \pi] \)
Answer: (a) \( [0, 1] \)

 

Question. The domain of the function defined by \( f(x) = \sin^{-1} \sqrt{x - 1} \) is : 
(a) \( [1, 2] \)
(b) \( [-1, 1] \)
(c) \( [0, 1] \)
(d) None of the options
Answer: (a) \( [1, 2] \)

 

Question. The value of \( \cos^{-1} \left( \cos \frac{3\pi}{2} \right) \) is equal to : 
(a) \( \frac{\pi}{2} \)
(b) \( \frac{3\pi}{2} \)
(c) \( \frac{5\pi}{2} \)
(d) \( \frac{7\pi}{2} \)
Answer: (a) \( \frac{\pi}{2} \)

 

Question. Solve \( \sin (\tan^{-1} x), |x| < 1 \) is equal to :
(a) \( \frac{x}{\sqrt{1-x^2}} \)
(b) \( \frac{1}{\sqrt{1-x^2}} \)
(c) \( \frac{1}{\sqrt{1+x^2}} \)
(d) \( \frac{x}{\sqrt{1+x^2}} \)
Answer: (d) \( \frac{x}{\sqrt{1+x^2}} \)

 

Assertion and Reason Questions

Choose the correct option :
(a) Both (A) and (R) are true and R is the correct explanation A.
(b) Both (A) and (R) are true but R is not correct explanation of A.
(c) A is true but R is false.
(d) A is false but R is true.

 

Question. Assertion (A) : \( \sin^{-1} (\sin 3) = 3 \)
Reason (R) : For principal values \( \sin^{-1} (\sin x) = x \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (d) A is false but R is true.

 

Question. Assertion (A) : The solution of system of equations \( \cos^{-1} x + (\sin^{-1} y)^2 = \frac{p\pi^2}{4} \) and \( (\cos^{-1} x)(\sin^{-1} y)^2 = \frac{\pi^4}{16} \) is \( x = \cos \frac{\pi^2}{4} \) and \( y = \pm 1 \), \( \forall p \in I \).
Reason (R) : \( AM \ge GM \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (a) Both (A) and (R) are true and R is the correct explanation A.

 

Question. Assertion (A) : If \( \sum_{i=1}^{2n} \sin^{-1} x_i = n\pi, n \in N \). Then, \( \sum_{i=1}^{2n} x_i = \sum_{i=1}^{2n} x_i^2 = \sum_{i=1}^{2n} x_i^3 = n \)
Reason (R) : \( -\frac{\pi}{2} \le \sin^{-1} x \le \frac{\pi}{2}, \forall x \in [-1, 1] \)

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (a) Both (A) and (R) are true and R is the correct explanation A.

 

Question. Assertion : The equation \( 2(\sin^{-1} x)^2 - 5(\sin^{-1} x) + 2 = 0 \).
Reason : \( \sin^{-1} (\sin x) = x \) if \( x \in [-1.57, 1.57] \).

(a) (a)
(b) (b)
(c) (c)
(d) (d)
Answer: (d) A is false but R is true.

 

Value-Based Questions (VBQs) for Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions

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FAQs

Where can I find 2026-27 CBSE Value Based Questions (VBQs) for Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions?

The latest collection of Value Based Questions for Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions is available for free on StudiesToday.com. These questions are as per 2026 academic session to help students develop analytical and ethical reasoning skills.

Are answers provided for Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions VBQs?

Yes, all our Mathematics VBQs for Chapter 2 Inverse Trigonometric Functions come with detailed model answers which help students to integrate factual knowledge with value-based insights to get high marks.

What is the importance of solving VBQs for Class 12 Chapter 2 Inverse Trigonometric Functions Mathematics?

VBQs are important as they test student's ability to relate Mathematics concepts to real-life situations. For Chapter 2 Inverse Trigonometric Functions these questions are as per the latest competency-based education goals.

How many marks are usually allocated to VBQs in the CBSE Mathematics paper?

In the current CBSE pattern for Class 12 Mathematics, Chapter 2 Inverse Trigonometric Functions Value Based or Case-Based questions typically carry 3 to 5 marks.

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