CBSE Class 12 Mathematics Integrals MCQs Set 01

Multiple Choice Questions (MCQs) for Class 12 Mathematics: Chapter 07 Integrals

Review structured MCQ sets for Class 12 Mathematics Chapter 07 Integrals. Built according to official CBSE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Practice Chapter 07 Integrals MCQs for Class 12 Mathematics

View or download the dedicated Chapter 07 Integrals MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Question. \( \int e^x (\cos x - \sin x) dx \) is equal to
(a) \( e^x \cos x + C \)
(b) \( e^x \sin x + C \)
(c) \( -e^x \cos x + C \)
(d) \( -e^x \sin x + C \)
Answer: (a) \( e^x \cos x + C \)

 

Question. \( \int \frac{dx}{\sin^2 x \cos^2 x} \) is equal to
(a) \( \tan x + \cot x + C \)
(b) \( (\tan x + \cot x)^2 + C \)
(c) \( \tan x - \cot x + C \)
(d) \( (\tan x - \cot x)^2 + C \)
Answer: (c) \( \tan x - \cot x + C \)

 

Question. If \( \int \frac{3e^x - 5e^{-x}}{4e^x + 5e^{-x}} dx = ax + b \log |4e^x + 5e^{-x}| + C \) then
(a) \( a = \frac{-1}{8}, b = \frac{7}{8} \)
(b) \( a = \frac{1}{8}, b = \frac{7}{8} \)
(c) \( a = \frac{-1}{8}, b = \frac{-7}{8} \)
(d) \( a = \frac{1}{8}, b = \frac{-7}{8} \)
Answer: (c) \( a = \frac{-1}{8}, b = \frac{-7}{8} \)

 

Question. \( \int_{a+c}^{b+c} f(x) dx \) is equal to
(a) \( \int_{a}^{b} f(x - c) dx \)
(b) \( \int_{a}^{b} f(x + c) dx \)
(c) \( \int_{a}^{b} f(x) dx \)
(d) \( \int_{a-c}^{b-c} f(x) dx \)
Answer: (a) \( \int_{a}^{b} f(x + c) dx \)

 

Question. If \( f \) and \( g \) are continuous functions in \( [0, 1] \) satisfying \( f(x) = f(a - x) \) and \( g(x) + g(a - x) = a \), then \( \int_{0}^{a} f(x).g(x) dx \) is equal to
(a) \( \frac{a}{2} \)
(b) \( \frac{a}{2} \int_{0}^{a} f(x) dx \)
(c) \( \int_{0}^{a} f(x) dx \)
(d) \( a \int_{0}^{a} f(x) dx \)
Answer: (b) \( \frac{a}{2} \int_{0}^{a} f(x) dx \)

 

Question. If \( x = \int_{0}^{y} \frac{dt}{\sqrt{1 + 9t^2}} \) and \( \frac{d^2 y}{dx^2} = ay \), then \( a \) is equal to
(a) 3
(b) 6
(c) 9
(d) 1
Answer: (c) 9

 

Question. \( \int_{-1}^{1} \frac{x^3 + |x| + 1}{x^2 + 2|x| + 1} dx \) is equal to
(a) \( \log 2 \)
(b) \( 2 \log 2 \)
(c) \( \frac{1}{2} \log 2 \)
(d) \( 4 \log 2 \)
Answer: (b) \( 2 \log 2 \)

 

Question. \( \int_{0}^{1} \frac{e^t}{1 + t} dt = a \), then \( \int_{0}^{1} \frac{e^t}{(1 + t)^2} dt \) is equal to
(a) \( a - 1 + \frac{e}{2} \)
(b) \( a + 1 - \frac{e}{2} \)
(c) \( a - 1 - \frac{e}{2} \)
(d) \( a + 1 + \frac{e}{2} \)
Answer: (b) \( a + 1 - \frac{e}{2} \)

 

Question. \( \int \frac{\cos 2x - \cos 2\theta}{\cos x - \cos \theta} dx \) is equal to
(a) \( 2(\sin x + x \cos \theta) + C \)
(b) \( 2(\sin x - x \cos \theta) + C \)
(c) \( 2(\sin x + 2x \cos \theta) + C \)
(d) \( 2(\sin x - 2x \cos \theta) + C \)
Answer: (c) \( 2(\sin x + x \cos \theta) + C \)

 

Question. \( \int \frac{dx}{\sin (x - a) \sin (x - b)} \) is equal to
(a) \( \sin(b - a) \log \left| \frac{\sin (x - b)}{\sin (x - a)} \right| + C \)
(b) \( \csc(b - a) \log \left| \frac{\sin (x - a)}{\sin (x - b)} \right| + C \)
(c) \( \csc(b - a) \log \left| \frac{\sin (x - b)}{\sin (x - a)} \right| + C \)
(d) \( \sin(b - a) \log \left| \frac{\sin (x - a)}{\sin (x - b)} \right| + C \)
Answer: (a) \( \csc(b - a) \log \left| \frac{\sin (x - b)}{\sin (x - a)} \right| + C \)

 

Question. \( \int \tan^{-1} \sqrt{x} dx \) is equal to
(a) \( (x + 1) \tan^{-1} \sqrt{x} - \sqrt{x} + C \)
(b) \( x \tan^{-1} \sqrt{x} - \sqrt{x} + C \)
(c) \( \sqrt{x} - x \tan^{-1} \sqrt{x} + C \)
(d) \( \sqrt{x} - (x + 1) \tan^{-1} \sqrt{x} + C \)
Answer: (a) \( (x + 1) \tan^{-1} \sqrt{x} - \sqrt{x} + C \)

 

Question. \( \int e^x \left( \frac{1 - x}{1 + x^2} \right)^2 dx \) is equal to
(a) \( \frac{e^x}{1 + x^2} + C \)
(b) \( \frac{-e^x}{1 + x^2} + C \)
(c) \( \frac{e^x}{(1 + x^2)^2} + C \)
(d) \( \frac{-e^x}{(1 + x^2)^2} + C \)
Answer: (c) \( \frac{e^x}{1 + x^2} + C \)

 

Question. \( \int \frac{x^9}{(4x^2 + 1)^6} dx \) is equal to
(a) \( \frac{1}{5x} \left( 4 + \frac{1}{x^2} \right)^{-5} + C \)
(b) \( \frac{1}{5} \left( 4 + \frac{1}{x^2} \right)^{-5} + C \)
(c) \( \frac{1}{10x} (1 + 4)^{-5} + C \)
(d) \( \frac{1}{10} \left( \frac{1}{x^2} + 4 \right)^{-5} + C \)
Answer: (d) \( \frac{1}{10} \left( \frac{1}{x^2} + 4 \right)^{-5} + C \)

 

Question. \( \int \frac{\sin^6 x}{\cos^8 x} dx \) is equal to
(a) \( \frac{\tan^6 x}{5} + C \)
(b) \( \frac{\tan^7 x}{5} + C \)
(c) \( \frac{\tan^7 x}{7} + C \)
(d) None of the options
Answer: (c) \( \frac{\tan^7 x}{7} + C \)

 

Question. \( \int_{-2}^{2} |x \cos \pi x| dx \) is equal to
(a) \( \frac{8}{\pi} \)
(b) \( \frac{4}{\pi} \)
(c) \( \frac{2}{\pi} \)
(d) \( \frac{1}{\pi} \)
Answer: (a) \( \frac{8}{\pi} \)

 

Question. The integral value of \( \int_{0}^{\pi/2} \frac{\tan x}{1 + m^2 \tan^2 x} dx \)
(a) \( \log \left( \frac{m}{m^2 - 1} \right) \)
(b) \( \log \left( \frac{m^2 - m}{2} \right) \)
(c) \( \log 3m \)
(d) 0
Answer: (a) \( \log \left( \frac{m}{m^2 - 1} \right) \)

 

Question. The integral of \( \int \frac{x}{\sqrt{x + 1}} dx \) is equal to
(a) \( 2 \left[ \frac{x\sqrt{x}}{3} - \frac{x}{2} + \sqrt{x} - \log |(\sqrt{x} + 1)| \right] + C \)
(b) \( \frac{x\sqrt{x}}{3} + \frac{x}{2} - \sqrt{x} + \log |(\sqrt{x} + 1)| + C \)
(c) \( \sqrt{x} - \log (\sqrt{x} + 1) + C \)
(d) None of the options
Answer: (a) \( 2 \left[ \frac{x\sqrt{x}}{3} - \frac{x}{2} + \sqrt{x} - \log |(\sqrt{x} + 1)| \right] + C \)

 

Question. If \( \int \frac{x^3}{\sqrt{1 + x^2}} dx = a(1 + x^2)^{3/2} + b\sqrt{1 + x^2} + C \), then
(a) \( a = \frac{1}{3}, b = -1 \)
(b) \( a = \frac{1}{3}, b = -1 \)
(c) \( a = \frac{-1}{3}, b = -1 \)
(d) \( a = \frac{1}{3}, b = -1 \)
Answer: (b) \( a = \frac{1}{3}, b = -1 \)

 

Question. If \( \int_{0}^{a} \frac{1}{1 + 4x^2} dx = \frac{\pi}{8} \) then find value of \( a \).
(a) \( \frac{-1}{2} \)
(b) \( \frac{7}{2} \)
(c) \( \frac{1}{2} \)
(d) 0
Answer: (c) \( \frac{1}{2} \)

 

Question. The integral \( \int \frac{x^9}{(4x^2 + 1)^6} dx \) is equal to
(a) \( \frac{1}{5x} \left( 4 + \frac{1}{x^2} \right)^{-5} + C \)
(b) \( \frac{1}{5} \left( 4 + \frac{1}{x^2} \right)^{-5} + C \)
(c) \( \frac{1}{10x} (5)^{-5} + C \)
(d) \( \frac{1}{10} \left( \frac{1}{x^2} + 4 \right)^{-5} + C \)
Answer: (d) \( \frac{1}{10} \left( \frac{1}{x^2} + 4 \right)^{-5} + C \)

 

Assertion-Reason Questions

 

Question. Assertion (A) : \( \int \frac{1}{1 + x^2} dx = \tan^{-1} x + C \), where \( C \) is an arbitrary constant.
Reason (R) : Since \( \frac{d}{dx} \tan^{-1} x = \frac{1}{1 + x^2} \).
(a) Both A and R are true and R is the correct explanation for A.
(b) Both A and R are true and R is not the correct explanation for A.
(c) A is true but R is false.
(d) A is false but R is true.
Answer: (a) Both A and R are true and R is the correct explanation for A.

 

Question. Assertion (A) : \( \int \frac{1}{2\sqrt{x}} dx = \sqrt{x} + C \)
Reason (R) : \( \int \cos x dx = \sin x + C \)
(a) Both A and R are true and R is the correct explanation for A.
(b) Both A and R are true and R is not the correct explanation for A.
(c) A is true but R is false.
(d) A is false but R is true.
Answer: (b) Both A and R are true and R is not the correct explanation for A.

 

Question. Assertion (A) : If \( f'(x) = x + \frac{1}{1 + x^2} \) and \( f(0) = 0 \) then \( f(x) = \frac{x^2}{2} + \tan^{-1} x \).
Reason (R) : \( \int x^n dx = \frac{x^{n+1}}{n + 1} + C \)
(a) Both A and R are true and R is the correct explanation for A.
(b) Both A and R are true and R is not the correct explanation for A.
(c) A is true but R is false.
(d) A is false but R is true.
Answer: (b) Both A and R are true and R is not the correct explanation for A.

 

Question. Assertion (A) : \( \int_{0}^{\pi/2} \cos x dx = 1 \)
Reason (R) : If \( f(x) \) is continuous in \( [a, b] \) and \( \int f(x) dx = \phi(x) \), then \( \int_{a}^{b} f(x) dx = \phi(b) - \phi(a) \).
(a) Both A and R are true and R is the correct explanation for A.
(b) Both A and R are true and R is not the correct explanation for A.
(c) A is true but R is false.
(d) A is false but R is true.
Answer: (a) Both A and R are true and R is the correct explanation for A.

 

Question. Assertion (A) : \( \int_{0}^{1} \frac{1}{\sqrt{1 - x^2}} dx = \frac{\pi}{2} \)
Reason (R) : \( \int \frac{1}{a^2 + x^2} dx = \frac{1}{a} \tan^{-1} \frac{x}{a} + C \)
(a) Both A and R are true and R is the correct explanation for A.
(b) Both A and R are true and R is not the correct explanation for A.
(c) A is true but R is false.
(d) A is false but R is true.
Answer: (b) Both A and R are true and R is not the correct explanation for A.

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FAQs

Where can I access latest CBSE Class 12 Mathematics Integrals MCQs Set 01?

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Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics Class 12 material?

Yes, our CBSE Class 12 Mathematics Integrals MCQs Set 01 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the CBSE paper is now competency-based.

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