# CBSE Class 6 Mathematics Worksheet Set P Solved

Download printable Mathematics Class 6 Worksheets in pdf format, CBSE Class 6 Mathematics Worksheet Set P Solved has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 6 Assignments and practice them daily to get better marks in tests and exams for Grade 6. Free chapter wise worksheets with answers have been designed by Standard 6 teachers as per latest examination pattern

## Mathematics Worksheet for Class 6

Class 6 Mathematics students should refer to the following printable worksheet in Pdf in Grade 6. This test paper with questions and solutions for Standard 6 Mathematics will be very useful for tests and exams and help you to score better marks

### Class 6 Mathematics Worksheet Pdf

MATHEMATICS (SET-B)

Q.NO1

SECTION A - FILL IN THE BLANKS

(a) The difference between the place values of 6 in 84,65,062 is _______ 59940 1
(b) The number of whole numbers from 475 to 548 is __________ 74 1
(c) The value of 20 + 48 ÷ 8 is _________ 26 1
(d) Name the property : 635 + 478 = 478 + 635 commutative prop under addition

Q.NO2

SECTION B

Place commas correctly and write the number 40056789 in both Indian and International system

(a)  4,00,56,789 –four crores fifty six thousand seven hundred eighty nine
40,056,789 – forty million fifty six thousand seven hundred eighty nine

(b) Find the sum by suitable rearrangement : 278 + 166 + 322 + 1034

(278 + 322) + (166+ 1034)
600 + 1200 = 1800

(c) The population of Ranchi was 5,38,785 in the year 2001. In the year 2011 it was found to be increased by 56835 . What was the population of the city in 2011 ?
Statements (1/2)      Arrangement (1/2)      Ans = 595620 (1)

i) Write the successor of the greatest 6- digit number.
999999 + 1 = 10,00,000

(d) ii) Find the sum of the predecessor and successor of 684000
683999 + 684001 = 13,68,000

(e) Kiran bought 12 tables and 12 chairs . The cost of each table is ₹ 750 and the cost of each chair is ₹ 250 . Find the total amount paid by him for the purchase .
12 x 750 + 12x 250 = 12 x ( 750 + 250 ) = 12 x 1000 = ₹12000

Q.NO

SECTION – C

3 a)Estimate the difference by rounding off each number to the nearest 1000.

12465 - 9898

12000 – 10000 = 2000

b)Estimate the product by rounding off each number to the nearest 100

645 x 178

600 x 200 = 120000

4 Find the value using suitable property : 1435 × 99

1435 x ( 100 – 1)

1435 x 100 – 1435 x 1

143500 – 1435 = 142065

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