NCERT Solutions Class 3 Mathematics Chapter 14 Rupees and Paise

NCERT Solutions Class 3 Mathematics Chapter 14 Rupees and Paise have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 3 Mathematics have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 3 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 3 Mathematics are an important part of exams for Class 3 Mathematics and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 3 Mathematics and also download more latest study material for all subjects. Chapter 14 Rupees and Paise is an important topic in Class 3, please refer to answers provided below to help you score better in exams

Chapter 14 Rupees and Paise Class 3 Mathematics NCERT Solutions

Class 3 Mathematics students should refer to the following NCERT questions with answers for Chapter 14 Rupees and Paise in Class 3. These NCERT Solutions with answers for Class 3 Mathematics will come in exams and help you to score good marks

Chapter 14 Rupees and Paise NCERT Solutions Class 3 Mathematics

Rupees and Paise

1. One ball and one toy car.
Ans.
Rs. 22.

2. One notebooks and two pencils.
Ans.
Rs. 10.

3. One doll and a ball Rs. 15. One glass of lemon juice and a pocket of biscuits _____
Ans.
Rs. 7.50.

4. One toy giraffe, one copy and a glass of lemon juice Rs. _____.
Ans.
Rs. 15.50.

5. One glass of milk, one packet of biscuits and a banana ______.
Ans.
Rs. 9.

6. One notebook, two pencils, and two erasers _____.
Ans.
Rs. 12.

7. Two tops, three toffees and two bananas _____.
Ans.
Rs. 8.50.

8. What can you buy if you have a twenty-rupee note?
Ans.
1 toy car, 1 lemon juice, 1 banana.
1 ball, 1 doll, 1 notebook.
1 toy car, 1 banana, 1 glass milk.
1 toy car, 1 packet of biscuit, 1 toffee.
1 toy car, 1 toy giraffe, 1 glass milk.

9. Monu prepared the following cash memos:
Check the cash memos and correct them if you find a mistake.

""NCERT-Solutions-Class-3-Mathematics-Chapter-14-Rupees-and-Paise

Ans. Corrected cash memo are given below:

""NCERT-Solutions-Class-3-Mathematics-Chapter-14-Rupees-and-Paise-1

""NCERT-Solutions-Class-3-Mathematics-Chapter-14-Rupees-and-Paise-2

10. Add the following:

(a)
Rs.      12.       50
Rs.    +13.        00
Rs. 
Ans.
Rs.       12.       50
Rs.     +13.       00
Rs.       25.       50

(b)
Rs.       55.       50
Rs.     +14.       00
Rs.
Ans.
Rs.       55.       50
Rs.     +14.       00
Rs.       69.       50

(c)
Rs.       30.      00
Rs.     +31.      50
Rs.
Ans.
Rs.      30.       00
Rs.    +31.       50
Rs.      61.       50

11. Subtract the following:

(a)
Rs.        15.        50
Rs.       -11.        50
Rs.
Ans. 

Rs.        15.        50
Rs.       -11.        50
Rs.        14         00

(b)
Rs.       103.      50
Rs.       -62.       00
Rs.
Ans.

Rs.      103.       50
Rs.       -62.       00
Rs.        41.       50

(c)
Rs.       19.       50
Rs.      – 7.       00
Rs.
Ans.
Rs.       19.       50
Rs.      – 7.       00
Rs.       12.       50

12. You have 30 rupees with you. Find out how much money will be left after buying the following items: One ball, one doll and one toy giraffe. Total cost of Rs. 21.50. Money left
Rs. 8.50.
Ans. Cost of 1 ball = Rs. 7
Cost of 1 doll = Rs. 8
Cost of 1 toy giraffe = Rs. 6.50
So, Total cost = Rs. 7 + Rs. 8 + Rs. 6.50 = Rs. 21.50
Money left = Total Money – Money Spent = Rs. 30 – Rs. 12.50 = Rs. 8.50.

13. Two bananas, one pack of biscuits and two glasses of lemon juice. Total cost Rs. 13.50.
Money left Rs. 16.50.
Ans. Cost of 2 bananas = Rs. 1.50 x 2 = Rs. 3
Cost of 1 pack of biscuits = RS. 4.50
Cost of 2 glasses of lemon juice = Rs. 3 x 2 = Rs. 6
So, Total cost = Rs. 3 + Rs. 4.50 + Rs. 6 = Rs. 13.50
Money left = Total money – Money spent
= Rs. 30 – Rs. 13.50 = Rs. 16.50.

14. Three notebooks, two pencils and two erasers. Total cost Rs. 22. Money left Rs. 8.
Ans. Cost of 3 notebooks = Rs. 5 3 = Rs. 15
Cost of 2 pencils = Rs. 2.50 x 2 = Rs. 5
Cost of 2 erasers = Rs. 1 x 2 = Rs. 2
Total cost = Rs. 15 + Rs. 5 + Rs. 2 = Rs. 22
Money left = Total money – Money spent = Rs. 30 – Rs. 22 = Rs. 8

15. Three friends wanted to buy a cricket bat and ball. Bina had Rs. 48.50, Raman had Rs. 55. 50 and Venu had Rs. 38.00. How much money did they have in all?
Ans. Money with Bina = Rs. 48.50
Money with Raman = Rs. 55.50
Money with Venu = Rs. 38.00
Total money = Rs. 142.00

16. Hari booked a railway ticket for Rs. 62.50. He gave a 100 rupee note. How much money will he get back with the ticket?
Ans. Total money with Hari = Rs. 100
Money spent on ticket = Rs. 62.50
Money left = Rs. 100 – Rs. 62.50

17. Gita and her friends went shopping. She bought things for Rs. 58, Rs. 37 and Rs. 22.
Gita had a hundred-rupee note. How much money should she borrow from her friends to pay the bill?
Ans. Total money with Geeta = Rs. 100
Money spent by Geeta = Rs. 58 + Rs. 37 + Rs. 22 = Rs. 117
Money to be borrowed = Rs. 117 – Rs. 110 = Rs. 17.

18. Find the cost of tickets:

(a) Bhupen is going from New Jalpaiguri to Alipurduar. That is the cost of his ticket?
Ans. Cost of ticket from New Jalpaiguri to Alipurduar is Rs. 28.00.

(b) Indira has to go from New Jalpaiguri to Goalpara. How much does she pay for the ticket?
Ans. Cost of ticket from New Jalpaiguri to Goalpara is Rs. 49.50.

(c) Debu, Shoma and Gobind are going from New Jalpaiguri to New Mal. What amount will they pay for tickets?
Ans. Fare from New Jalpaiguri to New Mal = Rs. 12. 50
Amount of fare from debu, Shoma and Gobind = Rs. 12. 50 3 = Rs. 37.50
Money given for tickets = Rs. 50
Money spent on tickets = Rs. 37.50
Money got back = Rs. 50 – Rs. 37.50 = Rs. 12.50.

More Study Material

NCERT Solutions Class 3 Mathematics Chapter 14 Rupees and Paise

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The Class 3 Mathematics NCERT Solutions Chapter 14 Rupees and Paise are designed in a way that will help to improve the overall understanding of students. The answers to each question in Chapter 14 Rupees and Paise of Mathematics Class 3 has been designed based on the latest syllabus released for the current year. We have also provided detailed explanations for all difficult topics in Chapter 14 Rupees and Paise Class 3 chapter of Mathematics so that it can be easier for students to understand all answers.

NCERT Solutions Chapter 14 Rupees and Paise Class 3 Mathematics

Class 3 Mathematics NCERT Solutions Chapter 14 Rupees and Paise is a really good source using which the students can get more marks in exams. The same questions will be coming in your Class 3 Mathematics exam. Learn the Chapter 14 Rupees and Paise questions and answers daily to get a higher score. Chapter 14 Rupees and Paise of your Mathematics textbook has a lot of questions at the end of chapter to test the students understanding of the concepts taught in the chapter. Students have to solve the questions and refer to the step-by-step solutions provided by Mathematics teachers on studiestoday to get better problem-solving skills.

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These solutions of Chapter 14 Rupees and Paise NCERT Questions given in your textbook for Class 3 Mathematics have been designed to help students understand the difficult topics of Mathematics in an easy manner. These will also help to build a strong foundation in the Mathematics. There is a combination of theoretical and practical questions relating to all chapters in Mathematics to check the overall learning of the students of Class 3.

Class 3 NCERT Solution Mathematics Chapter 14 Rupees and Paise

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