BITSAT Chemistry Solutions MCQs

Download BITSAT MCQs for BITSAT Chemistry: Solutions

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Chapter-wise Objective Questions: Solutions

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Question: Raoult’s law becomes a special case of Henry’s law when

a)

BITSAT Chemistry Solutions 1

b)

BITSAT Chemistry Solutions 2

c)

BITSAT Chemistry Solutions 3

d)

BITSAT Chemistry Solutions 4

Answer:

BITSAT Chemistry Solutions 1

 

Question: Identify the correct order of solubilty of Na2S. CuS and ZnS in aqueous medium

a) CuS > ZnS > Na2S

b) ZnS > Na2S > CuS

c) Na2S > CuS > ZnS

d) Na2S > ZnS > CuS

Answer: Na2S > ZnS > CuS

 

Question: Equal weights of NaCl and KCl are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

a) Equal

b) That of NaCl will be less than that of KCl

c) That of NaCl will be more than that of KCl solution

d) That of NaCl will be about half of that of KCl solution

Answer: That of NaCl will be more than that of KCl solution

 

Question: The van’t Hoff factor i for an electrolyte which undergoes dissociation and association in solvents are respectively

a) Greater than 1 and greater than 1

b) Less than 1 and greater than 1

c) Less than 1 and less than 1

d) Greater than 1 and less than 1

Answer: Greater than 1 and less than 1

 

Question: Which of the following metal sulphides has maximum solubility in water?

a) HgS Ksp = 10–54

b) CdS Ksp = 10–30

c) FeS Ksp = 10–20

d) ZnS Ksp = 10–22

Answer: FeS Ksp = 10–20

 

Question: 1.00 g of a non-electrolyte solute (molar mass 250 g mol–1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 K kg mol–1, the freezing point of benzene will be lowered by

a) 0.3 K

b) 0.5 K

c) 0.4 K

d) 0.2

Answer: 0.4 K

 

Question: Coolant used in car radiator is aqueous solution of ethylene glycol. In order to prevent the solution from freezing at – 0.3°C. How much ethylene glycol must be added to 5 kg of water ? (Kf = 1.86 K Kg mol–1)

a) 50 g

b) 55 g

c) 45 g

d) 40 g

Answer: 55 g

 

Question: Which one of the following statements is FALSE?

a) The correct order of osmotic pressure for 0.01 M aqueous solution of each compound is BaCl2 > KCl > CH3COOH > sucrose

b) The osmotic pressure (π) of a solution is given by the equation π = MRT, where M is the molarity of the solution

c) Raoult’s law states that the vapour pressure of a component over a solution is proportional to its mole fraction

d) Two sucrose solutions of same molality prepared in different solvents will have the same freezing point depression

Answer: Two sucrose solutions of same molality prepared in different solvents will have the same freezing point depression

 

Question:  The degree of dissociation of Ca(NO3)2 in dilute aq. solution containing 7.0 g of salt per 100 g of water at 100° C is 70%. If vapour pressure of water at 100° C is 760 mm. The vapour pressure of solution is

a) 735

b) 730

c) 760

d) 746

Answer: 746

 

Question: The volume of water added to 500 ml 0.5 M NaOH so that its strength becomes 10 mg NaOH per ml is :

a) 100 ml

b) 200 ml

c) 250 ml

d) 500 ml

Answer: 500 ml

 

Question: In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking kf for water as 1.85, the freezing point of the solution will be nearest to

a) – 0.360º C

b) – 0.260º C

c) + 0.480º C

d) – 0.480º C

Answer: – 0.480º C

 

Question: The milliequivalent in 60 ml 4M H2SO4 is :

a) 240

b) 480

c) 24

d) 48

Answer: 480

 

Question: The heat of vaporisation of benzene is 7353 cal mol–1. The approximate bpt. of benzene is

a) 77.1° C

b) 87.1° C

c) 101° C

d) 95° C

Answer: 77.1° C

 

Question: Which of the following solution will have lowest boiling point

a) 0.1M NaCl

b) 0.1M KCl

c) 0.1M CaCl2

d) 0.1M glucose

Answer: 0.1M glucose

 

Question: An X molal solution in carbon tetrachloride has the mole fraction of solute equal to 0.23527 . The value of X is

a) 1.55

b) 1.82

c) 2.00

d) 2.16

Answer: 2.00

 

Question: Which of the following solutions will have the highest boiling point?

a) 0.5 molal BaCl2

b) 1.0 molal KBr

c) 1.8 × 1024 glucose molecules per litre.

d) 100 g powdered glucose in one litre water

Answer: 1.8 × 1024 glucose molecules per litre.

 

Question: To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the value of 0.1 M aqueous KOH solution required is

a) 40 mL

b) 20 mL

c) 10 mL

d) 60 mL

Answer: 40 mL

 

Question: The volume of water added to 500 ml 0.5 M NaOH so that its strength becomes 10 mg NaOH per ml is :

a) 100 ml

b) 200 ml

c) 250 ml

d) 500 ml

Answer: 500 ml

 

Question: Which of the following metal sulphides has maximum solubility in water?

a) HgS Ksp = 10–54 

b) CdS Ksp = 10–30

c) FeS Ksp = 10–20

d) ZnS Ksp = 10–22

Answer: FeS Ksp = 10–20

 

Question: Equal weights of NaCl and KCl are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

a) Equal

b) That of NaCl will be less than that of KCl

c) That of NaCl will be more than that of KCl solution

d) That of NaCl will be about half of that of KCl solution

Answer: That of NaCl will be more than that of KCl solution

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FAQs

Where can I access latest BITSAT Chemistry Solutions MCQs?

You can get most exhaustive BITSAT Chemistry Solutions MCQs for free on StudiesToday.com. These MCQs for BITSAT Chemistry are updated for the 2026-27 academic session as per BITSAT examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Chemistry BITSAT material?

Yes, our BITSAT Chemistry Solutions MCQs include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the BITSAT paper is now competency-based.

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By solving our BITSAT Chemistry Solutions MCQs, BITSAT students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.

Do you provide answers and explanations for BITSAT Chemistry Solutions MCQs?

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