Practice JEE Chemistry Amines MCQs Set B provided below. The MCQ Questions for Full Syllabus Amines Chemistry with answers and follow the latest JEE (Main)/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for JEE (Main) Full Syllabus Chemistry and also download more latest study material for all subjects
MCQ for Full Syllabus Chemistry Amines
Full Syllabus Chemistry students should review the 50 questions and answers to strengthen understanding of core concepts in Amines
Amines MCQ Questions Full Syllabus Chemistry with Answers
Question. –NH2 group in aniline is
(a) o-and p-directing
(b) only p-directing
(c) only o-directing
(d) only m-directing
Answer: A
Question. Strong activating effect of –NH2 group is reduced by using
(a) CH3COCl
(b) CH3ONa
(c) CH3Cl
(d) CH3–CHO
Answer: A
Question. When bromination of aniline is carried out by protecting –NH2. The product is
(a) mixture of o-and p-bromoaniline
(b) p-bromoaniline
(c) 2, 4, 6 tribromoaniline
(d) o-bromoaniline
Answer: A
Question. Hinsberg’s method to separate amines is based on the use of
(a) benzene sulphonyl chloride
(b) benzene sulphonic acid
(c) ethyl oxalate
(d) acetyl chloride
Answer: A
Question. Which of the following statements is not correct regarding aniline?
(a) It is soluble in water
(b) It reacts with sodium to give hydrogen
(c) It can be steam-distilled
(d) It is less basic than ethylamine
Answer: A
Question. Aniline and other arylamines are usually colourless but get coloured on storage due to___________.
(a) atmospheric oxidation
(b) dehydration
(c) hydrolysis
(d) reduction
Answer: A
Question. The acylation reaction of amines is carried out in presence of pyridine because
(i) pyridine is stronger base than amine.
(ii) pyridine is weaker base than amine.
(iii) pyridine removes HCl formed and shifts the equilibrium to the right hand side.
(iv) pyridine removes HCl formed and shifts the equilibrium to the left hand side.
(a) (i) and (iii)
(b) (ii) and (iii)
(c) (ii) and (iv)
(d) (i) and (iv)
Answer: A
Question. N– ethyl benzene sulphonyl amide is strongly acidic and soluble in alkali due to presence of
(a) strong electron withdrawing sulphonyl group
(b) strong electron donating sulphonyl group
(c) weak electron donating sulphonyl group
(d) weak electron withdrawing sulphonyl group
Answer: A
Question. Arrange the following in increasing order of their basic strength?
p–nitroaniline(1); m–nitroaniline (2); 2,6–trimethylaniline(3); 3–methylanline(4).
(a) 1, 2, 4, 3
(b) 2, 3, 4, 1
(c) 1, 3, 2, 4
(d) 3, 1, 2, 4
Answer: A
Question. Diazonium salt is obtained when aniline reacts with
(a) NaNO2 and HCl (0–5°C)
(b) N2O at (0 – 5°C)
(c) cold NaOH
(d) SnCl2 at 10°C
Answer: A
Question. Azo dye is prepared by the coupling of phenol and
(a) diazonium chloride
(b) benzoic acid
(c) chlorobenzene
(d) o-nitroaniline
Answer: A
Question. Which of the following reagents will convert p-methylbenzenediazonium chloride into p-cresol?
(a) H2O
(b) C6H5OH
(c) Cu powder
(d) H3PO2
Answer: A
Question. When phenol and benzene diazonium chloride are coupled, the main product is
(a) p-hydroxyazobenzene
(b) chlorobenzene
(c) aniline
(d) azobenzene
Answer: A
Question. In the diazotization of arylamines with sodium nitrite and hydrochloric acid, an excess of hydrochloric acid is used primarily to
(a) Supress the concentration of free aniline available for coupling
(b) Supress hydrolysis of phenol
(c) Ensure a stoichiometric amount of nitrous acid
(d) Neutralise the base liberated
Answer: A
Question. Which of the following reagent can be used to convert benzenediazonium chloride into benzene?
(a) H3PO2
(b) LiAlH4
(c) CH3OH
(d) None of these
Answer: A
Question. When benzenediazonium chloride in hydrochloric acid reacts with cuprous chloride, then chlorobenzene is formed. The reaction is called
(a) Sandmeyer reaction
(b) Perkin reaction
(c) Gattermann reaction
(d) Etard reaction
Answer: A
Question. Which of the following compound will not undergo azo coupling reaction with benzene diazonium chloride.
(a) Nitrobenzene
(b) Phenol
(c) Anisole
(d) Aniline
Answer: A
Question. Which of the following cannot be prepared by Sandmeyer’s reaction?
(i) Chlorobenzene (ii) Bromobenzene
(iii) Iodobenzene (iv) Fluorobenzene
(a) (ii) and (iii)
(b) (i) and (iv)
(c) (i) and (ii)
(d) (iii) and (iv)
Answer: A
Question. Read the following statements and choose the correct option.
(i) Nitrogen atom in amines is sp3-hybridised.
(ii) The geometry of amines is pyramidal.
(iii) The angle C–N–C or C–N–H is slightly more than 109.5°.
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (i), (ii) and (iii)
(d) (i) and (iii)
Answer: A
Question. Which of the following statements are correct ?
(i) Lower aliphatic amines are soluble in water.
(ii) Solubility increases with decrease in molar mass of amines.
(iii) Higher amines are insoluble in water.
(iv) Amines are soluble in organic solvents.
(a) (i), (iii) and (iv)
(b) (i) and (iv)
(c) (i), (ii) and (iii)
(d) (ii), (iii) and (iv)
Answer: A
Question. Which of the following statements are correct ?
(i) Primary amines show more intermolecular association than secondary amines.
(ii) Tertiary amines do not show intermolecular association.
(iii) Boiling points of isomeric alkenes follow the order 3° > 2° > 1°
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (i) and (iii)
(d) (i), (ii) and (iii)
Answer: A
Question. Which of the following statements are correct ?
(i) In Sandmeyer reaction nucleophiles like Cl–, Br– and CN– are indroduced in benzene ring in the presence of Cu+ ion
(ii) In Gattermann reaction nucleophiles are introduced in benzene ring in the presence of copper powder and HCl.
(iii) The yield in Gattermann reaction is found to be better than Sandmayer reaction.
(a) (i) and (ii)
(b) (ii) and (iii)
(c) (i), (ii) and (iii)
(d) (i) and (iii)
Answer: A
Question. Assertion : Aromatic 1°amines can be prepared by Gabriel phthalimide synthesis.
Reason : Aryl halides undergo nucleophilic substitution with anion formed by phthalimide.
(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion
(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(c) Assertion is correct, reason is incorrect
(d) Assertion is incorrect, reason is correct
Answer: A
Question. Assertion : Only a small amount of HCl is required in the reduction of nitro compounds with iron scrap and HCl in the presence of steam.
Reason : FeCl2 formed gets hydrolysed to release HCl during the reaction.
(a) Assertion is incorrect, reason is correct
(b) Assertion is correct, reason is incorrect
(c) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(d) Assertion is correct, reason is correct; reason is a correct explanation for assertion
Answer: A
Question. Assertion : Amines are basic in nature.
Reason : Amines have lone pair of electrons on nitrogen atom.
(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion
(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(c) Assertion is correct, reason is incorrect
(d) Assertion is incorrect, reason is correct
Answer: A
Question. Assertion : Acetanilide is less basic than aniline.
Reason : Acetylation of aniline results in decrease of electron density on nitrogen
(a) Assertion is incorrect, reason is correct
(b) Assertion is correct, reason is incorrect
(c) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(d) Assertion is correct, reason is correct; reason is a correct explanation for assertion
Answer: A
Question. Assertion : Nitration of aniline can be conveniently done by protecting the amino group by acetylation.
Reason : Acetylation increases the electron-density in the benzene ring.
(a) Assertion is correct, reason is incorrect
(b) Assertion is incorrect, reason is correct
(c) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(d) Assertion is correct, reason is correct; reason is a correct explanation for assertion
Answer: A
Question. Assertoin : Aniline does not undergo Friedel-Crafts reaction.
Reason : –NH2 group of aniline reacts with AlCl3 (Lewis acid) to give acid-base reaction.
(a) Assertion is correct, reason is correct; reason is a correct explanation for assertion
(b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(c) Assertion is correct, reason is incorrect
(d) Assertion is incorrect, reason is correct
Answer: A
Question. Assertion : Acylation of amines gives a monosubstituted product whereas alkylation of amines gives polysubstituted product.
Reason : Acyl group sterically hinders the approach of further acyl groups.
(a) Assertion is correct, reason is incorrect
(b) Assertion is incorrect, reason is correct
(c) Assertion is correct, reason is correct; reason is not a correct explanation for assertion
(d) Assertion is correct, reason is correct; reason is a correct explanation for assertion.
Answer: A
Question. The IUPAC name of diethyl isopropyl amine is
(a) N, N-diethylpropan-2-amine
(b) N, N-diethylpropan-1-amine
(c) N, N-diethylisopropylamine
(d) N, N-diethylaminopropane
Answer: A
Question. Acetamide is treated with the following reagents separately. Which one of these would yield methylamine?
(a) NaOH – Br2
(b) Sodalime
(c) PCl5
(d) None of these
Answer: A
Question. Amine that cannot be prepared by Gabriel phthalimide synthesis is
(a) aniline
(b) methylamine
(c) benzylamine
(d) None of these
Answer: A
Question. A primary amine is formed by an amide on treatment with bromine and alkali. The primary amine has
(a) 1 carbon atom less than amide
(b) 1 carbon atom more than amide
(c) 1 hydrogen atom less than amide
(d) 1 hydrogen atom more than amide
Answer: A
Question. High basicity of Me2NH relative to Me3N is attributed to
(a) effect of solvent
(b) shape of Me2NH
(c) inductive effect of Me
(d) shape of Me3N
Answer: A
Question. Which one of the following is the strongest base in aqueous solution ?
(a) Dimethylamine
(b) Trimethylamine
(c) Methylamine
(d) Aniline
Answer: A
Question. The correct order of the increasing basicity of methyl amine, ammonia and aniline is
(a) aniline < ammonia < methyl amine
(b) aniline < methyl amine < ammonia
(c) ammonia < aniline < methyl amine
(d) methyl amine < aniline < ammonia
Answer: A
Question. Aniline when treated with conc. HNO3 gives
(a) m-Nitroaniline
(b) p-Phenylenediamine
(c) p-Benzoquinone
(d) None of these
Answer: A
Question. Towards electrophilic substitution, the most reactive will be
(a) Aniline
(b) Aniline hydrochloride
(c) N-Acetylaniline
(d) Nitrobenzene
Answer: A
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Important Practice Resources for JEE Mains Chemistry
MCQs for Amines Chemistry Full Syllabus
Students can use these MCQs for Amines to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Full Syllabus Chemistry released by JEE (Main). Our expert teachers suggest that you should practice daily and solving these objective questions of Amines to understand the important concepts and better marks in your school tests.
Amines NCERT Based Objective Questions
Our expert teachers have designed these Chemistry MCQs based on the official NCERT book for Full Syllabus. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Amines, you should also refer to our NCERT solutions for Full Syllabus Chemistry created by our team.
Online Practice and Revision for Amines Chemistry
To prepare for your exams you should also take the Full Syllabus Chemistry MCQ Test for this chapter on our website. This will help you improve your speed and accuracy and its also free for you. Regular revision of these Chemistry topics will make you an expert in all important chapters of your course.
You can get most exhaustive JEE Chemistry Amines MCQs Set B for free on StudiesToday.com. These MCQs for Full Syllabus Chemistry are updated for the 2025-26 academic session as per JEE (Main) examination standards.
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