JEE Chemistry Chemical Bonding and Molecular Structure MCQs Set B

Practice JEE Chemistry Chemical Bonding and Molecular Structure MCQs Set B provided below. The MCQ Questions for Full Syllabus Chemical Bonding and Molecular Structure Chemistry with answers and follow the latest JEE (Main)/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for JEE (Main) Full Syllabus Chemistry and also download more latest study material for all subjects

MCQ for Full Syllabus Chemistry Chemical Bonding and Molecular Structure

Full Syllabus Chemistry students should review the 50 questions and answers to strengthen understanding of core concepts in Chemical Bonding and Molecular Structure

Chemical Bonding and Molecular Structure MCQ Questions Full Syllabus Chemistry with Answers

Question. The hybridisation state of carbon in fullerene is
(a) sp2
(b) sp3d
(c) sp
(d) sp3

Answer: A

Question. Which of the following statements is true for an ion having sp3 hybridisation?
(a) H-atoms are situated at the corners of tetrahedron
(b) all bonds are co-ordinate covalent
(c) H-bonds are situated at the corners of a square
(d) all bonds are ionic

Answer: A

Question. Which of the following molecule does not have a linear arrangement of atoms ?
(a) H2S
(b) CO2
(c) BeH2
(d) All of these

Answer: A

Question. In which one of the following molecules the central atom said to adopt sp2 hybridization?
(a) BF3
(b) NH3
(c) BeF2
(d) None of these

Answer: A

Question. A sp3-hybrid orbital contains
(a) 25% s-character
(b) 50% s-character
(c) 75% s-character
(d) 25% p-character

Answer: A

Question.  Pick out the incorrect statement from the following
(a) sp3d2 hybrid orbitals are equivalent and are oriented towards corners of a regular octahedron
(b) sp3d3 hybrid orbitals are not equivalent
(c) sp hybrid orbitals are equivalent and are at an angle of 180° with each other
(d) sp2 hybrid orbitals are equivalent and bond angle between any two of them is 120°

Answer: A

Question. All carbon atoms are sp2 hybridised in
(a) 1, 3-butadiene
(b) cyclohexane
(c) CH2 = C = CH2
(d) 2-butene

Answer: A

Question. Which one of the following is not correct in respect of hybridization of orbitals?
(a) Pure atomic orbitals are more effective in forming stable bonds than hybrid orbitals
(b) The orbitals undergoing hybridization have almost equal energy
(c) Promotion of electron is not essential condition for hybridization
(d) The orbitals present in the valence shell only are hybridized

Answer: A

Question. Molecular orbital theory was given by
(a) Mulliken
(b) Kossel
(c) Mosley
(d) Werner

Answer: A

Question.  Atomic orbital is monocentric while a molecular orbital is polycentric. What is the meaning of above statements?
(a) While an electron in an atomic orbital is influenced by one nucleus, in a molecular orbital it is influenced by two or more nuclei depending upon the number of atoms in the molecule
(b) Electron density in atomic orbital is given by the electron distribution around a nucleus in an atom. While in molecular orbital it is given by the electron distribution around group of nuclei in a molecule.
(c) The electron in an atomic orbital is present in one nucleus while in molecular orbital electrons are present on more than one nuclei depending upon the number of atoms in the molecule
(d) All of these

Answer: A

Question. With increasing bond order, stability of bond
(a) Increases
(b) Remain unaltered
(c) Decreases
(d) None of these

Answer: A

Question. The theory capable of explaining paramagnetic behaviour of oxygen is
(a) molecular orbital theory
(b) valence bond energy
(c) V.S.E.P.R. theory
(d) resonance theory

Answer: A

Question. In an anti-bonding molecular orbital, electron density is minimum
(a) between the two nuclei of the molecule
(b) around one atom of the molecule
(c) at the region away from the nuclei of the molecule
(d) at no place

Answer: A

Question. When two atomic orbitals combine, they form
(a) two molecular orbital
(b) four molecular orbital
(c) one molecular orbital
(d) three molecular orbital

Answer: A

Question. Paramagnetism is exhibited by molecules
(a) containing unpaired electrons
(b) carrying a positive charge
(c) containing only paired electrons
(d) not attracted into a magnetic field

Answer: A

Question. The difference in energy between the molecular orbital formed and the combining atomic orbitals is called
(a) stabilization energy
(b) bond energy
(c) activation energy
(d) destabilization energy

Answer: A

Question. Which molecule has the highest bond order?
(a) N2
(b) He2
(c) Li2
(d) O2

Answer: A

Question. Which one of the following molecules is expected to exhibit diamagnetic behaviour ?
(a) C2
(b) O2
(c) N2
(d) S2

Answer: A

Question. Mark the incorrect statement in the following
(a) the bond energy in a diatomic molecule always increases when an electron is lost
(b) electrons in antibonding M.O. contribute to repulsion between two atoms.
(c) with increase in bond order, bond length decreases and bond strength increases.
(d) None of these

Answer: A

Question. Bond order is a concept in the molecular orbital theory. It depends on the number of electrons in the bonding and antibonding orbitals. Which of the  following statements is true about it ? The bond order
(a) can assume any positive or integral or fractional value including zero
(b) is a non-zero quantity
(c) has always an integral value
(d) can have a negative quantity

Answer: A

Question. In which of the following state of compound the magnitude of H-bonding will be maximum and in which case it will be minimum ?
(a) Maximum = Solid, Minimum = Gas
(b) Maximum = Gas, Minimum = Solid
(c) Maximum = Liquid, Minimum = Gas
(d) Maximum = Solid, Minimum = Liquid

Answer: A

Question. Intramolecular hydrogen bond exists in
(a) ortho nitrophenol
(b) water
(c) diethyl ether
(d) ethyl alcohol

Answer: A

Question. The boiling point of p-nitrophenol is higher than that of o-nitrophenol because
(a) there is intermolecular hydrogen bonding in p-nitrophenol
(b) p-nitrophenol has a higher molecular weight than o-nitrophenol.
(c) intramolecular hydrogen bonding exists in p-nitrophenol
(d) NO2 group at p-position behave in a different way from that at o-position.

Answer: A

Question. Which one of the following is the correct order of interactions ?
(a) vander Waals < hydrogen bonding < dipole < covalent
(b) vander Waals < dipole-dipole < hydrogen bonding < covalent
(c) Dipole-dipole < vander Waals < hydrogen bonding < covalent.
(d) Covalent < hydrogen bonding < vander Waals < dipoledipole

Answer: A

Question. Strongest hydrogen bond is shown by
(a) hydrogen fluoride
(b) water
(c) ammonia
(d) hydrogen sulphide

Answer: A

Question. The low density of ice compared to water is due to
(a) hydrogen bonding interactions
(b) dipole-dipole interactions
(c) dipole-induced dipole interactions
(d) induced dipole-induced dipole interactions

Answer: A

Question. Methanol and ethanol are miscible in water due to
(a) hydrogen bonding character
(b) oxygen bonding character
(c) None of these
(d) covalent character

Answer: A

Question. The hydrogen bond is shortest in
(a) F — H --- F
(b) N — H --- O
(c) S — H --- S
(d) S — H --- O

Answer: A

Question. Hydrogen bonding is maximum in
(a) C2H5OH
(b) CH3OCH3
(c) CH3CHO
(d) All of these

Answer: A

Question. The reason for exceptionally high boiling point of water is
(a) hydrogen bonding in the molecules of water
(b) low ionization of water molecule
(c) its high dielectric constant
(d) its high specific heat

Answer: A

Question. Acetic acid exists as dimer in benzene due to
(a) hydrogen bonding
(b) condensation reaction
(c) presence of carboxyl group
(d) presence of hydrogen atom

Answer: A

Question. Hydrogen bonding is formed in compounds containing hydrogen and
(a) highly electronegative atoms
(b) highly electropositive atoms
(c) metal atoms with d-orbitals occupied
(d) metalloids

Answer: A

Question. Read the following statements and choose the correct sequence of T and F from the given codes. Here T represents true and F represents false statement.
(i) The number of dots in Lewis symbol represents the number of valence electrons.
(ii) Number of valence electrons helps to calculate group valence of element.
(iii) Group valence is given as 8 minus the number of inner shell electrons.

(a) T T F
(b) T T T
(c) T F F
(d) F F F

Answer: A

MCQs for Chemical Bonding and Molecular Structure Chemistry Full Syllabus

Students can use these MCQs for Chemical Bonding and Molecular Structure to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Full Syllabus Chemistry released by JEE (Main). Our expert teachers suggest that you should practice daily and solving these objective questions of Chemical Bonding and Molecular Structure to understand the important concepts and better marks in your school tests.

Chemical Bonding and Molecular Structure NCERT Based Objective Questions

Our expert teachers have designed these Chemistry MCQs based on the official NCERT book for Full Syllabus. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chemical Bonding and Molecular Structure, you should also refer to our NCERT solutions for Full Syllabus Chemistry created by our team.

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