Refer to CBSE Class 11 Chemistry HOTs Structure of Atom. We have provided exhaustive High Order Thinking Skills (HOTS) questions and answers for Class 11 Chemistry Chapter 02 Structure of Atom. Designed for the 2025-26 exam session, these expert-curated analytical questions help students master important concepts and stay aligned with the latest CBSE, NCERT, and KVS curriculum.
Chapter 02 Structure of Atom Class 11 Chemistry HOTS with Solutions
Practicing Class 11 Chemistry HOTS Questions is important for scoring high in Chemistry. Use the detailed answers provided below to improve your problem-solving speed and Class 11 exam readiness.
HOTS Questions and Answers for Class 11 Chemistry Chapter 02 Structure of Atom
Question. The potential energy of electron present in ground state of Li2+ ion is represented by :
(a) +3e2/4π∈0r
(b) -3e/4π∈0r
(c) -3e2/4π∈0r2
(d) -3e2/4π∈0r
Answer : D
Question. An electron in the ground state of hydrogen was excited to a higher energy level using monochromatic radiations of wave length (λ) 975
Å. The longest wave length that appears in the resulting spectrum is due to transition from:
(a) n4 → n1
(b) n4 → n3
(c) n5 → n4
(d) n5 → n1
Answer : B
Question. Which of the following pairs of nucleides are isodiaphers ?
(a) 136C and 168O
(b) 11H and 21H
(c) 31H and 42He
(d) 5525Mn 6530and Zn
Answer : D
Question. Based on equation E = – 2.178 × 10-18 J (Z2/n2) certain conclusions are written. Which of them is not correct ?
(a) Larger the value of n, the larger is the orbit radius.
(b) Equation can be used to calculate the change in energy when the electron changes orbit.
(c) For n = 1, the electron has a more negative energy than it does for n = 6 which mean that the electron is more loosely bound in the smallest allowed orbit.
(d) The negative sign in equation simply means that the energy or electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.
Answer : C
Question. The velocity of an electron in excited state of Hatom is 1.093 x 106 m/s. What is the circumference of this orbit?
(a) 3.32 x 10–10 m
(b) 6.64 x 10–10 m
(c) 13.30 x 10–10 m
(d) 13.28 x 10–10 m
Answer : C
Question. For Balmer series in the spectrum of atomic hydrogen, the wave number of each line is given by v¯ = RH (1/n12 - 1/n22) where RH is a constant and n1 and n2 are integers. Which of the following statement(s) is (are) correct?
I. As wavelength decreases, the lines in the series converge.
II. The integer n1 is equal to 2.
III. The ionization energy of hydrogen can be calculated from the wave number of these lines.
IV. The line of longest wavelength corresponds to n2 = 3.
(a) I, II and III
(b) II, III and IV only
(c) I, II and IV
(d) II and IV only
Answer : C
Question. If m and e are the mass and charge of the revolving electron in the orbit of radius r for hydrogen atom, the total energy of the revolving electron will be:
(a) 1 e2/2 r
(b) e2/r
(c) me2/r
(d) 1 e2/2 r
Answer : D
Question. What transition in He+ ion shall have the same wave number as the first line in Balmer series of H atom?
(a) 7 → 5
(b) 6 → 4
(c) 5 → 3
(d) 4 → 2
Answer : B
Question. Let mp be the mass of a proton, mn that of a neutron, M1 that of a 2010Ne nucleus and M2 that of a 4020Ca nucleus. Then
(a) M2 = 2M1
(b) M1 < 10(mp + mn)
(c) M2 > 2M1
(d) M1 = M2
Answer : A
Question. The correct representation of wavelength intensity relationship of an ideal black body radiation at two different temperatures T1 and T2 is
Answer : A
Question. Among the following, the incorrect statement is
(a) No two electrons in an atom can have the same set of four quantum numbers
(b) The maximum number of electrons in the shell with principal quantum number, n is equal to n2 + 2
(c) Electrons in an orbital must, have opposite spin
(d) In the ground state, atomic orbitals are filled in the order of their increasing energies
Answer : B
Question. Calculate the minimum and maximum number of electrons which may have magnetic quantum number, m = +1 and spin quantum number, s = - (1/2) in chromium (Cr):
(a) 0, 1
(b) 1, 2
(c) 4, 6
(d) 2, 3
Answer : D
Question. The electrons, identified by quantum numbers n and l,
(I) n = 3, l = 2 (II) n = 5, l = 0
(III) n = 4, l = 1 (IV) n = 4, l = 2
(V) n = 4, l = 0 can be placed in order of increasing energy, as
(a) I < V < III < IV < II
(b) I < V < III, II, IV
(c) V < I < III < II < IV
(d) V < I < II < III < IV
Answer : B
Question. The angular momentum of an electron in a Bohr’s orbit of He+ is 3.1652 × 10–34 kg-m2/sec. What is the wave number in terms of Rydberg constant (R) of the spectral line emitted when an electron falls from this level to the first excited state. [Use h = 6.626 x 10–34 J × s]
(a) 3R
(b) 5R/9
(c) 3R/4
(d) 8R/9
Answer : B
Question. A electron in a hydrogen atom in its ground state absorbs 1.5 times as much energy as the minimum required for it to escape from the atom. What is the velocity of the emitted electron?
(a) 1.54 x 106 m/s
(b) 1.54 x 108 m/s
(c) 1.54 x 103 m/s
(d) 1.54 x 104 m/s
Answer : A
Question. For a multi-electron atom, the highest energy level among the following is
(a) n = 5, l = 0, m = 0, s = +½
(b) n = 4, l = 2, m = 0, s = +½
(c) n = 4, l = 1, m = 0, s = +½
(d) n = 5, l = 1, m = 0, s = +½
Answer : D
Question. The energies E1 and E2 of two radiations are 25 eV and 50 eV, respectively. The relation between their wavelengths i.e., λ1 and λ2 will be :
(a) λ1 = λ2
(b) λ1 = 2λ2
(c) λ1 = 4λ2
(d) λ1 = (1/2)λ2
Answer : B
Question. Among the following, the correct statement about cathode ray discharge tube is
(a) the electrical discharge can only be observed at high pressure and at low voltages.
(b) in the absence of external electrical or magnetic field, cathode rays travel in straight lines.
(c) the characteristics of cathode rays depend upon the material of electrodes.
(d) the characteristics of cathode rays depend upon the gas present in the cathode ray tube.
Answer : B
Question. The correct order of energy of 2s-orbitals in H, Li, Na and K, is
(a) K < Na < Li < H
(b) Na < Li < K < H
(c) Na < K < H < Li
(d) H < Na < Li < K
Answer : A
Question. Which of the following radial distribution graphs correspond to l = 2 for the H atom ?
Answer : C
Question. A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second? h = 6.62 × 10–34 Js velocity of light = 3 × 108 ms–1
(a) 1.0 × 1019
(b) 1.0 × 1023
(c) 1.0 × 1021
(d) 2.0 × 1023
Answer : C
Numeric Value Answer
Question. An electron has a speed of 30,000 cm sec–1 accurate upto 0.001%. What is the uncertainty in locating it’s position.
Answer : 2
Question. Determine the Bohr orbit of Li2+ ion in which electron is moving at speed equal to the speed of electron in the first Bohr orbit of H-atom.
Answer : 3
Question. An electron with de Broglie wavelength 4 × 10–6 m makes transition to a state with de Broglie wavelength 6 × 10–6 m. The wavelength of photon generated is mc/h X x10-11 m. What is the value of x?
Answer : 576
Question. Calculate the ratio of wavelength of first line of Balmer series of H-atom to the wavelength of first line of Lyman series of 10 times ionized sodium atom.
Answer : 653.4
Question. The energy of the electron in the second and the third Bohr’s orbits of the hydrogen atom is – 5.42 × 10–12 erg and –2.41 × 10–12 erg respectively.
Calculate the wavelength of the emitted radiation when the electron drops from the third to the second orbit.
Answer : 6.604
Question. What is the sum of radial node(s) and nodal plane(s) for 4dz2–orbital?
Answer : 1
Question. A hydrogen atom with an electron in the first shell absorbs ultraviolet light with a wavelength of 1.03 × 10–7 m. To what shell does the electron jump?
Answer : 3
Question. If the energies of two radiations of wavelength 800 nm and 400 nm are E1 and E2 respectively. Then calculate the value of E2/E1.
Answer : 2
Question. To stop the flow of photoelectrons produced by electromagnetic radiation incident on a certain metal, a negative potential of 300 V is required. If the photoelectric threshold of metal is 1500 Å, what is the frequency of the incident radiation (in terms of 1016 Hz)?
Answer : 7.45
Question. Naturally occurring boron consists of two isotopes whose atomic weights are 10.01 and 11.01. The atomic weight of natural boron is 10.81. Calculate the percentage of isotope with atomic weight 11.01 in natural boron.
Answer : 80
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Important Practice Resources for Class 11 Chemistry
HOTS for Chapter 02 Structure of Atom Chemistry Class 11
Students can now practice Higher Order Thinking Skills (HOTS) questions for Chapter 02 Structure of Atom to prepare for their upcoming school exams. This study material follows the latest syllabus for Class 11 Chemistry released by CBSE. These solved questions will help you to understand about each topic and also answer difficult questions in your Chemistry test.
NCERT Based Analytical Questions for Chapter 02 Structure of Atom
Our expert teachers have created these Chemistry HOTS by referring to the official NCERT book for Class 11. These solved exercises are great for students who want to become experts in all important topics of the chapter. After attempting these challenging questions should also check their work with our teacher prepared solutions. For a complete understanding, you can also refer to our NCERT solutions for Class 11 Chemistry available on our website.
Master Chemistry for Better Marks
Regular practice of Class 11 HOTS will give you a stronger understanding of all concepts and also help you get more marks in your exams. We have also provided a variety of MCQ questions within these sets to help you easily cover all parts of the chapter. After solving these you should try our online Chemistry MCQ Test to check your speed. All the study resources on studiestoday.com are free and updated for the current academic year.
You can download the teacher-verified PDF for CBSE Class 11 Chemistry HOTs Structure of Atom from StudiesToday.com. These questions have been prepared for Class 11 Chemistry to help students learn high-level application and analytical skills required for the 2025-26 exams.
In the 2026 pattern, 50% of the marks are for competency-based questions. Our CBSE Class 11 Chemistry HOTs Structure of Atom are to apply basic theory to real-world to help Class 11 students to solve case studies and assertion-reasoning questions in Chemistry.
Unlike direct questions that test memory, CBSE Class 11 Chemistry HOTs Structure of Atom require out-of-the-box thinking as Class 11 Chemistry HOTS questions focus on understanding data and identifying logical errors.
After reading all conceots in Chemistry, practice CBSE Class 11 Chemistry HOTs Structure of Atom by breaking down the problem into smaller logical steps.
Yes, we provide detailed, step-by-step solutions for CBSE Class 11 Chemistry HOTs Structure of Atom. These solutions highlight the analytical reasoning and logical steps to help students prepare as per CBSE marking scheme.